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[DOC File]Factoring #6 – Factoring By Grouping Worksheet
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1) x2 + 3x + 2x + 6 2) x2 +5x + 4x + 20. 3) x2 + 3x – 5x – 15 4) x2 + 2x + 5x + 10. 5) 2x3 –x2 – 10x + 5 6) x3 + 10x2 + 5x + 50. 7) x3 + 4x + x2 + 4 8) 2x3 + x2 + 8x + 4. 9) 15x3 + 5x2 + 3x + 1 10) 20n3 + 12n2 + 25n + 15. 11) 9p3 + 3p2 + 15p + 5 12) 6x3 + 10x2 + 3x + 5. 13) 4n3 – 12n2 + 3n -9 14) 2m3 – m2 + 4m – 2
3x 2 x 8 0

[DOCX File]Brainly
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1) Which equation is best represented by the graph above? A)(x+1)(x-3)(x+2) B(x-1)(x+3)(x+2) C (x-1)(x-3)(x+2) D (x+1)(x+3)(x-2) 2) Shown below is the graph of y=x^3-3x^2-6x+8
4 x 3 2 x 2 0

[DOC File]Polynomial Functions and End Behavior
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U5 Day 2 Multiplying Polynomials (Section 6.2) WARM UP. 1-2 Evaluate 3-4 Simplify. 1. 2. 3.) x – 2(3x-1) 4.) 5.) 6.) WARM UP Part 2. Multiply. Multiplying Polynomials. Distribute the x and then distribute the 2. Combine like terms and simplify. Try These. If you are interested in using the Alternate Method (see example below), I set up the ...
x 3 4x 2 x 4 0

[DOC File]ALGEBRA II – SUMMER PACKET
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3x - 15 < 4 - 2 + 2x -2x - 12 ≥ 4 3x - 15 < 2 + 2x -2x ≥ 16 x - 15 < 2 x ≤ -8 is the solution. x < 17 is the solution. Note: Dividing both sides by -2 changed the direction of the inequality.
x 4 x 3 solve

[DOC File]Ch - Mr. Wallace's Math Classes
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4. Which equation describes the line that passes through (2, 1) and (0, 5)? F y x 5 H y x 5 G y 3x 5 J y 3x 5 5. Which equation describes the line passing through (4, 2) with a slope of ? A y x 2 C y x 4 B y x 4 D y x …
x 4 3x 2 4 0 factor

[DOC File]Solving and Graphing Inequalities
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5) 3x – 4 < 2 6) ½ x – 7 > -8 7) 2(5x – 3) > 14 8) 8 – 3x < 17 THE ONE DIFFERENCE BETWEEN SOVING EQUATIONS AND INEQUALITIES When you multiply or divide on both sides by a negative number, you must turn the inequality around.
x 4 3x 2 4 0

[DOC File]Remainder & Factor Theorems
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1 < x < 6 x < 2 or x > 4. For intersections, 1 < x < 2 or 4 < x < 6. 9 x2 + 3kx + 2k = x ( 10 has real and distinct roots. x2 + (3k ( 1)x + 2k + 10 = 0. Discriminant > 0 (3k ( 1)2 ( 4(1)(2k + 10) > 0. 9k2 ( 6k + 1 ( 8k ( 40 > 0. 9k2 ( 14k ( 39 > 0 (9k + 13)(k ( 3) > 0. k < (1 or k > 3. For the equation to have equal roots, discriminant = 0 ( k ...
solve x 4 3x 2 4 0

2 x 2 3x 4