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[DOCX File]osvita.ua
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cos x-3 0 0 2 =0; tg x+3 0 0 2 =1; x-3 0 0 2 = П 2 + П n,n ∊ z ; x+3 0 0 2 = П 4 +П k,k ∊ z ; x= 7П 6 +2 П n,n ∊ z ; x= П 3 +2П k,k ∊ z. Відповідь: x=± 5 П 6 +2 П t , t ∊ z .
sin7pi 2 x 2cos2x 1

[DOC File]CBSE CLASS XII MATHS
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Integral Calculus. Two mark questions with answers. Q1. dx Ans1. dx = dx = dx = dx = (sec2x + secx tanx) dx = tanx + secx + c Q2. Ans2. = dx = dx = dx = c = c Q3. 3 cotx - 2 tanx)2 dx Ans3. (3 cotx - 2 tanx)2 dx = (9 cot2x + 4 tan2x - 12) dx = [9(cosec2x - 1) + 4(sec2 x - 1) - 12] dx = (4 sec2x + 9 cosec2x - 25) dx = 4 tanx - 9 cotx - 25x + c Q4. dx Ans4. dx = dx = dx = = + c Q5. (1 - sinx) dx ...
2cos 2x cosx sqrt tgx 1 0

[DOC File]KAJI LATIH – 1
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MATEMATIKA. TRIGONOMETRI Jika dan x sudut tumpul maka . Jika maka . 0,6 0,8 0,75 – 2. 1 2 Jika dan x sudut lancip maka . 0 1 sin2 1680o = … sec x + tan x
2cos2x 4 cos x 1 12

[DOC File]BAB III 78-jkt.sch.id
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sinx + cosx = 1 ; tanx + 1 = secx ; cotx + 1 = cosecx . cos 2x = 2 cos -1 = 1 - 2 sinx. sin 2x = 2 sinx cosx. sehingga soal menjadi bentuk persamaan kuadrat atau bentuk pemfaktoran. Contoh : Tentukan himpunan penyelesaian dari : 1. cos 2x – 3 cos x + 2 = 0; 0 < x < 360. Jawab : 2. sin 4x – 2cos 2x. sin x = 0 ; 0 < x < 180. jawab :
cosx 2cos2x 1 0

[DOC File]phng tr×nh lîng gi¸c
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(2cos(4-2x)cos8x=2cos8xsin4x(2cos8x(sin4x-cos(4-2x))=0 Vậy nghiệm của phương trình (1) là: Bài 5.[Đại học Ngoại Thương 1999]: Giải phương trình:
2cos2x 4 sin x 1 0

[DOC File]A Level Mathematics Questionbanks
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sinx (2cosx 1) = 0 M1 A1. sinx = 0 or cosx = x = 0, 180, 60, 300 A3 (-1 eeoo) [6] b) From (a), have 2x = 0, 180, 60, 300 M1. x = 0, 90, 30, 150 A2 ft [3] 2. a) cos2x + sin2x ( 1 ( cosA =, cosB = M1 A1. sin(A+B) ( sinA cosB + cosA sinB B1
2cos 2x cos2x 1 0

[DOC File]A Level Mathematics Questionbanks
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= 0, , 2 or = M1 (sin-1, 1 ans) A2 (all correct) [5] b) (2cos + 1)(cos 1) = 0 M1. cos = - or cos = 1 A1 (either) , or 0 A2 (all) (A1 for 2) [4] 3. a) cos2x = 1 sin2x B1. 3sin2x (1 sin2x) (4sin2x –1 M1 A1 cao
2cos2x 2cosx cos2x 1 0

[DOC File]Formulas
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sin2x = ½ [ 1 - cos(2x) ] cos2x = ½ [ 1 + cos(2x) ] sinh x = ½ [ e x - e-x ] cosh x = ½ [ e x + e-x ] eiy = cos y + i sin y e-iy = cos y - i sin y . sin x = [ eix - e-ix ] cos x = ½ [ eix + e-ix ] Geometry. Circles: Area = (r2 Circumference = 2(r. Spheres: Volume = (r3 Surface Area = 4(r2
2 cos 2 x 1 0

The Student Room
cot 2x(cot 2x–1)= 0 or cot 2x = 1 Attempt to factorise or solve a quadratic (See rules for factorising quadratics) or cancelling out cot 2x from both sides. dM1. cot 2x = 0 or cot 2x = 1 Both cot 2x = 0 and cot 2x = 1. A1. cot 2x = 0 (tan 2x→ ∞) 2x = 90, 270. Candidate attempts to divide at least one of their principal anglesby 2.
sin7pi 2 x 2cos2x 1

2cos 2x 2 cosx 2 1 0