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PHÖÔNG TRÌNH LÖÔÏNG GIAÙC
2cos2x +5sinx – 4 = 0 , b. 2cos2x – 8cosx +5 = 0 c. 2cosx.cos2x = 1+cos2x + cos3x d. 2(sin4x + cos4x) = 2sin2x – 1 e.sin42x + cos42x = 1 – 2sin4x f.
2cos2x 2cosx cos2x 1 0

[DOC File]MHF 4U Exam Review - Mrs. Samson
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a) 4cos2x = 3 – 2sin2x b) sin4x + cos4x = sin2x(csc2x – 2cos2x) c) d) (cot x)(csc x)(tan x)(cos x) = cos 2x + 2sin2x. 6. If and , determine an exact value for sin[2(x - y)]. 7. A mass on the end of a spring is pulled so that its distance from the rest position is initially 3 cm.
2 cos 2 x 1 0

[DOC File]Goniometria III - Gymnázium Trebišovská 12, Košice
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tg(x – ) = – 1. cotg(x + ) = – 1 . cos(– 2x) = – 1. cotg( + ) = –1 2cos2x + 5cos x – 3 = 0. 2sin2x – 7sin x + 3 = 0. 2cos2x = sin x + 1. 2 + 2cos x = 3sin2 x. cos2x + cos x = sin2 x. 2cos2x = 3sin x. 2sin2x – 3cos x = 0. sin x + cos 2x = 1. 2cos2x + sin x = 1. tg2x – 7tg x + 10 = 0. tg x – cotg x = 1. 2tg x – 3cotg x = 5 ...
2cos 2x 5 cos x 30

[DOC File]Bab 2. Fungsi - jawahirnatsir
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sin2x = 2 sin x cos x. cos2x = cos2x – sin2x = 2cos2x - 1 = 1 – 2sin2x. sin2() = (1 - cos x) ... 0 X (0,4) 4x – 3y + 12. y=-3x+1. y=3x+1. 1 0 1/3 -1/3 . 1 y. x. Gambar 2.11. Gambar 2.12. x. y. ... 4 3 2 1 0 Cos x. 0o. 30o. 45o. 60o. 90o. 4 3 2 1 0 Sin x. 0 -1 1 cos x. sin x (/2 (3(/2. 2(-(/2-(-3(/2-2
2cos 2x 2 cosx 2 1 0

[DOC File]Analiza I: 4. kolokvij - plonkec
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sinxcosx= 1/2 sin2x. cos2x = cos2x-sin2x = 2cos2x-1. cos2x = 1/2 (1+cos2x) sin2x = 1/2 (1-cos2x) ... -1 cos x -sin x arccos x 1/((1-x2) tg x cos-2x arctg x (1+x2)-1 ctg x -sin-2x ch x sh x ex ex sh x ch x ax ax ln a th x ch-2 x ln x x-1 f-1x 1/f'(f-1x) Rollov ... 6/1/2000 12:41:00 PM
cos4x 2cos2x 1 0

[DOC File]A Level Mathematics Questionbanks
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[4] 3. a) cos2x = 1 sin2x B1. 3sin2x (1 sin2x) (4sin2x –1 M1 A1 cao. a = 4 b = -1 A1 ft [4] b) 4sin2x = 2 M1. sinx = A1 cao. x = (45o, (135o A3 (-1 eeoo) [5] 4. sin x = ( cos x = M1 A1. 90
2cos 2x cosx sqrt tgx 1 0

[DOC File]A Level Mathematics Questionbanks
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[4] 4. a) cos 3A ( cos(2A+A) M1. cos3A ( cos2A cosA sin2A sinA B1. But cos2A ( cos2A sin2A and sin2A ( 2sinAcosA B1 ... 2cos2x 1=cosx B1 (2cosx + 1)(cosx 1) = 0 M1 A1. cosx = - or 1. x = 120, 240, 0 A2 (-1 eeoo) [5] b) From a), have x = 120, 240, 0 M1 ...
1 2sin 2x 2cos2x 0 2

[DOC File]Trigonometry Review
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a) cos2 b) 2sin2x + sin x – 1 = 0 c) 10cos2(2x) + 7cos(2x) = 6. d) 4cos2(2x) – 1 = 0 e) 3tan2x = 1 f) 2tan2x + tan x – 3 = 0. g) 6cos2x – sin x – 4 = 0 h) 2cos x = 1 – sin2 x i) 2sin2 x = -cos x + 1. 9. a) Convert 330( to radians b) Convert radians to degrees. 10.Use compound angles to determine the exact value for
2cos2x 4 sin x 1 0

The Student Room
22. f(x) = 12 cos x – 4 sin x. Given that f(x) = R cos(x + α), where R 0 and 0 α 90°, (a) find the value of R and the value of α. (4) (b) Hence solve the equation. 12 cos x – 4 sin x = 7. for 0 x 360°, giving your answers to one decimal place. (5) (c) (i) Write down the minimum value of 12 cos x – 4 sin x. (1)
2cos2x 2cosx cos2x 1 0

2cos2x 4 cos x 1 12