5 1 universal gravitation answer key

    • [DOC File]CHAPTER 5 - Circular Motion; Universal Gravitation

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      Mean Radius of Orbit = 1.5 x 1011 m 1 mile = 1.61 km. Mass of Sun = 1.99 x 1030 kg G = 6.67 x 10-11. 12. (I) Calculate the force of gravity on a spacecraft 12,800 km (2 earth radii) above the Earth’s surface if its mass is 1400 kg. 13. (I) A hypothetical planet has a mass 2.5 times that of Earth, but the same radius. What is g near its surface?

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    • [DOC File]Universal Gravitation, - Weebly

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      Name _____Answer Key_____ 1 Definitions. Projectile - Objects that are thrown or launched into the air and are subject only to the force of gravity . Trajectory - the path that a projectile follows . The path can best be described as ____parabolic_____. Shooting at a ___45o__ angle will result in the maximum range. Draw the trajectory for each ...

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    • [DOC File]WORKSHEET -- UNIVERSAL GRAVITATION

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      Saturn ( 5.68 x 1026 kg Uranus ( 2.61 x 107 m. sun ( 1.99 x 1030 kg Venus ( 6.05 x 106 m. Uranus ( 8.74 x 1025 kg. Venus ( 4.89 x 1024 kg. distance from Earth to the sun ( 1.50 x 1011 m distance from Saturn to the sun ( 1.43 x 1012 m. distance from Earth to the moon ( 3.84 x 108 m 1 pound = 4.545 newtons 1 meter = 3.28 feet 1 mile = 1609 meters

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    • [DOCX File]Gravity Force Simulation Activity.docx

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      Explain why the Earth orbits the Sun (you must use both the terms gravity and inertia in your answer). Earth is an object in motion so according to newton the Earth would keep travelling forward forever until it runs into another object or is disturbed by an unbalanced force.

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    • [DOC File]PHYSICS CHAPTER 8 : Universal Gravitation

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      Saturn 5.820 e7 5.680e26 1.427e12. Uranus 2.350 e7 8.680e25 2.870e12. Neptune 2.270 e7 1.030e26 4.500e12. Pluto 1.150 e6 1.200e22 5.900e12. Pluto was drummed out of planet status in 2006 by the IAU because it does not meet all 3 requirements to be considered a planet – it does not clear the neighborhood around its orbit. Use example problem 8 ...

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    • [DOC File]Physics -- Circular Motion & Gravitation Study Guide

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      A new planet is discovered orbiting a star with a mass 3.5 10 kg at a distance of 1.2 10 m. Assume that the orbit is circular. 29. What is the orbital period of the planet? (G = 6.673 10 N m/kg) _____ 30. Earth’s mean distance from the sun is 1.50 10 m. The length of one Earth year is 3.16 10 s.

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    • [DOCX File]POGIL:

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      1. and . m. 2. and inversely proportional to the square of the distance . d. between the masses. This relationship is summed up by the equation. F = G m 1 m 2 d 2 . G. is a constant of proportionality, called the Universal Gravitational Constant, equal to 6.67×10−11 N-m2/kg2. This equation is known as Newton’s Law of Universal Gravitation.

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    • [DOC File]Lesson 1 | Gravity and Friction

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      LESSON 1. Gravity and Friction. Key Concept What is the law of universal gravitation? This diagram represents a star orbited by two planets—planet A and planet B. The star is also orbited by a mysterious object, object X, that entered into the star’s gravitational field. Directions: Use the diagram to answer each question or respond to each ...

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    • [DOCX File]WORKSHEET -- UNIVERSAL GRAVITATION

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      WORKSHEET – Universal Law of Gravitation For an object to have weight, it must interact with another object. In other words, weight is dependent upon the surroundings. Any two masses will exert a mutual, attractive force, upon each other, called the gravitational force.

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    • [DOC File]Universal Gravitation - St. Louis Public Schools

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      Solve for the universal gravitation constant, G and compare it to published values. Remember significant digits! Mass Object 1 Mass Object 2 Distance Force Gravitation Constant,G. 56.30 kg 72.20 kg 4.0m Average value of G: _____ Units of G: _____

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