Binomial expansion equation
[DOC File]Maths Genie - Free Online GCSE and A Level Maths Revision
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Solve the following equation, for 0 ( x ( (, giving your answers in terms of (. sin 5x – cos 5x = cos x – sin x. (8) 2. In the binomial expansion of (1 – 4x) p, (x( < , the coefficient of x2 is equal to the coefficient of x4 and the coefficient of x3 is positive. Find the value of p. (9) 3. The curve C has parametric equations
[DOC File]Sums of Integer Powers--The Faulhaber Expansion
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(a) Find the first 3 terms, in ascending powers of x, of the binomial expansion of (2 – 9x)4, giving each term in its simplest form. (4) f(x) = (1 + kx)(2 – 9x)4, where k is a constant. The expansion, in ascending powers of x, of f(x) up to and including the term in x2 is. A – 232x + Bx2, where A and B are constants. (b) Write down the ...
[DOC File]IB HL Math Homework #2: Logs, Binomial Theorem and …
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D. Use the binomial expansion equation where n = 3, x = 2, p = 0.75, q = 0.25. The answer is 0.422, or 42.2%. C15. A. 100% because they are genetically identical. B. Construct a Punnett square. We know the parents are heterozygotes because they produced a blue-eyed child.
[DOC File]January 2005 - 6664 Core C2 - Question paper
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Stirling’s Expansion in terms of Binomial Coefficients An alternative expression of Sp(n) as a sum of binomial coefficients of increasing magnitude, for which the coefficients are the Stirling coefficients of the second kind, will be found in Abramowitz & Stegun, Handbook …
[DOC File]Past paper - June 2002
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Find the first 3 terms, in ascending powers of x, of the binomial expansion of (2 – 3x)5, giving each term in its simplest form. (4) 2. Find the values of x such that. 2 log3 x – log3(x – 2) = 2 (5) 3. Figure 1. The circle C with centre T and radius r has equation. x2 + y2 – …
Binomial Theorem - Terms, Term, Equation, and Expansion ...
In the binomial expansion of (1 + x)40, the coefficients of x4 and x5 are p and q respectively. (b) Find the value of . (3) January 2011. 7. The second and third terms of a geometric series are 192 and 144 respectively. For this series, find (a) the common ratio, (2) (b) the first term, (2) (c) the sum to infinity, (2)
[DOC File]Paper Reference(s) - Maths Tallis
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5) Find the coefficient of x in the expansion of . Solution. To get the coefficient of x, we need to find the (integer) value of k such that. 2k – 20 = 1. 2k = 21. But by this step we can clearly see that no integral k satisfies this equation. This means that NONE of the terms in the expansion are an x term. Thus, the desired coefficient is 0.
[DOC File]Paper Reference(s) - Maths Genie
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3. a) Using binomial expansion M1. M1 = A1A1(4) b) Sub in: 1 – 0.01 –= 0.9899495 M1. equating M1. M1 = 1.4142 (5 s.f.) A1 (4) 4. a) Integration by parts M1. I = M1A1 ( I = –x cos x – = –x cos x + sin x + c A1. A1(5) b) I2 = M1A1. I2 = x2 sin x – = x2 sin x – 2I M1 =
[DOC File]E1
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Find the first three terms, in ascending powers of x, of the binomial expansion of (3 + 2x)5, giving each term in its simplest form. (4) 2. The points A and B have coordinates (5, –1) and (13, 11) respectively. (a) Find the coordinates of the mid-point of AB. (2) Given that AB is a diameter of the circle C, (b) find an equation for C. (4) 3.
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