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[DOCX File]Activity 3.7 Statistical Analysis with Excel Answer Key
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Statistical Analysis with Excel Answer Key. In this activity you will collect data of the height of students and use Microsoft Excel to perform statistical analyses and create a statistical chart to display your data.

[DOC File]Statistics 231B SAS Practice Lab #1
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However the value 1.9067 is less than the Bonferroni critical value 3.23149. We conclude case 16 is not an outlier. (b) since 2p/n=2*4/25=0.32 and leverage values greater than 2p/n are considered to indicate outlying cases with regard to their X values, case 2 (H value=0.3420) and case 7 (H value=0.3501) are concluded as outlying X observations.

[DOC File]CHAPTER 11
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(ii) The t statistic for testing is about .60, which gives a two-sided p-value of about .55. This is very little evidence against H0; the null is not rejected at any reasonable significance level. (iii) The t statistic for is about 2.11, and the two-sided p-value is about .04.

[DOC File]Problem Set 4, ECON 30331
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Using a t-test, and a 95% confidence level, test the hypothesis that the coefficient on state_tax =1, H0:β1=1. What is the correct degree of freedom for the t-test? Search the web and find the CORRECT critical value for the t-statistic (the book table only gives values for 40 and 60 degrees of freedom). 4. Suppose you have a regression of the form

[DOC File]CLRES 2020 Lab 1
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We do this by calculating what the probability is of observing that t-statistic or something even more extreme, if we assume the null hypothesis. This probability value is called the “p-value”. We also decide on an α level to compare our p-value to, in order to decide whether it small enough to be considered to come from an “unusual ...

[DOC File]Bivariate Correlation, SPSS
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To test the null hypothesis that phi is zero in the population, we need to convert the phi to a chi-square statistic. Make that conversion with this formula: . You could use the CDF function in SPSS to get a p value for this test statistic, but I am going to show you another way to do so.

Answers to Practice Problems - Robert F. Borkenstein Courses
We now draw our t-distribution and identify our regions for rejecting the null hypothesis, show our critical t-values and show the computed t value: The computed t statistic is determined from: From this we conclude that we reject the null hypothesis and p < 0.05. The 95% confidence interval for the mean paired difference (δ) is found from:

[DOC File]Practice Midterm Exam - Statistical Science
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The p-value equals the area under the t-curve with 14 degrees of freedom to the right of 5.15, which is a very small number (less than .0001). Hence, we reject the null hypothesis. It does appear that the population average height of cross-fertilized plants is larger than …

[DOC File]Z-Score Practice Worksheet
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Three students take equivalent stress tests. Which is the highest relative score (meaning which has the largest z score value)? C has the highest z - score. A score of 144 on a test with a mean of 128 and a standard deviation of 34..47. A score of 90 on a test with a mean of 86 and a standard deviation of 18. .22

[DOCX File]Summary: Which test should I use?
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Choose an appropriate statistical analysis: how can we convert the data and question to a test statistic and P-value? Draw conclusions: what do the null and significant results mean, respectively? The second step is the most important part of statistical inference, and it is what you need to spend the most time reviewing before Test #3.

Convert t statistic p value