Cos2x sin2x 2sinx 1 2sin2x
[DOC File]Ekstrēmu uzdevumu risināšanas metodes - LU
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3. Piemērs. Atrast funkcijas f(x)=cos2x(2sinx mazāko vērtību intervālā [ 0; ]. f(x)=cos2x(2sinx= (sin2x(2sin2x+1= ((sinx+1)2+2. No šī pār-veidojuma acīmredzami var nolasīt funkcijas lielāko vērtību 2. Funkcija pieņems mazāko vērtību, ja (sinx+1)2 būs vislielākais.
[DOC File]TÀI LIỆU ÔN THI ĐẠI HỌC - Toancanduoc's Blog
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b.2sin2x + 1 = 2sinx + 1 sin2x = sinx 2sinxcosx – sinx = 0 sinx(2cosx – 1) = 0 (giải tiếp) Ví dụ 2:Giải phương trình sau : Giải : đk : 2cosx – 1 0
[DOC File]2sinx –1 = 0
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3cos 2x – sin 2x – 1 = 0 3(cos2x – sin2x) – 2sin x.cos x – (cos2x + sin2x) = 0. 3cos2x – 3sin2x – 2sin x.cos x – cos2x – sin2x = 0. 2cos2x – 2sin x.cos x – 4sin2x = 0 so 2(cos x – 2 sin x)(cos x + sin x) = 0. tan x = or tan x = – 1 etc. sin 2x + cos x + 3 cos 2x = 3 + 3 sin x 2sc + c + 3(1 – 2s2) = 3 + 3s. 2sc + c ...
[DOC File]Derivatatjafs - Tripod
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sin2x +1/2sinx=-1. x2+3x=1. 2logx=10/3 etc. För att kunna lösa dem krävs kunskaper om logaritmlagar, trigonometriska formler etc. Det kan vara bra att kunna kvadratkomplettera antingen för att lösa ekvationen eller för att skriva om ett uttryck så att det lättare går att behandla. Logaritmekvationer
[DOC File]A Level Mathematics Questionbanks
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b) cos2x ( 1 2sin2x B1. 3 (1 2sin2x) + sinx = 1 M1. 6sin2x sinx 2 = 0 (3sinx 2)(2sinx + 1) = 0 M1 A1. sinx = or - x = 41.8, 138.2, -30, -150 A3 (-1 eeoo) [7] 8. a) M1. M1. But sin2x + cos2x (1 and sinxcosx ( sin2x …
[DOC File]İZMİR FEN LİSESİ LİSE 1 MATEMATİK
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Title: İZMİR FEN LİSESİ LİSE 1 MATEMATİK Author: Hasan Korkmaz Last modified by: okul Created Date: 12/31/1987 9:27:00 PM Company: Korkmaz A.S.
[DOC File]PHƯƠNG TRÌNH LƯỢNG GIÁC
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c) sin( + 2x) + sin(π – 2x) = 1 d) cos2x - sin2x = 1 + sin2x Bài 5. a) sin2x + 2sinx.cosx – 2cos2x = b) 3sin2x – sin2x – cosx = 0. c) 6sin2x – sinx.cosx – cos2x = 3 d) 4sin2x – 3sin2x – 2cos2x = 4 Bài 6. a) cosx = m + 1 b) mtan2x – 2tanx + 2 = 0 c) (m2 + 2)sin2x + 4msinx.cosx = m2 + 3 d) mcosx – (m + 1…
[DOC File]XTEC
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sin x - = 1 ( sin x – 1 = ( (sin x – 1)2 = ()2 ( sin2x-2sinx+1= 3(1-sin2x) ( 4sin2x-2sinx-2= 0 ( 2sin2x-sinx-1= 0 Resolem l’eq. de 2n grau: sin x = 1 ( x= 90º i y= 30º. sin x = - ½ ( x ja que al 1r quadrant els sinus són + b) sin2 x + cos2 y = 1. cos2 x – sin2 y = 1 Fes cos2 y = 1 – sin2 y i cos 2 x = 1 – sin2 x.
[DOC File]Открытый урок
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5sin²x+21sinx+4=0 5sin²x-7cosx+1=0 8tg²x+10tgx+3=0 cosx-2sinx=0 cos²x+4cosx=0 sin3x-sin7x=0 7sin2x-2sinx=0 sin2x+10cos²x=0 5cos2x-14cos²x+8=0 3cos2x-14cosx+7=0 11sin2x+6cos²x+6=0 16cosx-11sinx-4=0 Вариант 3 2cos²x-11cosx+5=0. 3cos²+7sinx-5=0. 18tg²x+3tgx-10=0. 5cosx-2sinx=0. 4cos²x+3cosx=0. cos3x-cosx=0. 2sin2x+3cosx=0. 5sin2x ...
[DOC File]Основні способи розв'язування тригонометричних рівнянь
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1) 1 – cos2x = 2sinx; 2) cos2x = 3 + 7cosx. 498. Розв'язати рівняння, яке є однорідним відносно синуса і косинуса:
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