Cos2x sin2x tg2x 1 0
[DOC File]İZMİR FEN LİSESİ LİSE 1 MATEMATİK
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Title: İZMİR FEN LİSESİ LİSE 1 MATEMATİK Author: Hasan Korkmaz Last modified by: okul Created Date: 12/31/1987 9:27:00 PM Company: Korkmaz A.S.
[DOCX File]Уроци по Математика за 1 - 12 клас | Подготовка за матури
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sin5x+sinx sin5x-sinx = 2 -tg2x ⇔ 2sin3xcos2x 2sin2xcos3x =- cos2x sin2x , откъдето tg3x=-1 и x=- π 13 + π 3 .n, n∈Z. От дефиниционната област на даденото уравнение имаме x ≠πq, q∈Z,
[DOC File]FORMULE - Weebly
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FORMULE TRIGONOMETRICE. Formula fundamentala: Formule provenite din formula fundamentala: Funcţii trigonometrice: Paritatea si imparitatea functiilor trigonometrice:
[DOC File]Основні способи розв'язування тригонометричних рівнянь
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7) cos2x – (2а + 1)cosx + а2 + а = 0; 8) sin4x – (2a + l)sin2x + а 2 + а – 2 = 0? 525. Знайти, при яких значеннях параметра b рівняння має розв'язки:
[DOC File]BAB 6 TURUNAN (DERIVATIVE)
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b. y = c, dengan c adalah konstanta turunannya y’ = 0. Contoh : y = 5 ( y’ = 0. c. y sebagai fungsi trigonometri: y = sin x turunannya y’ = cos x. y = cos x turunannya y’ = -sin x. y = tg x turunannya y’ = sec2x ... Contoh : y = tg2x = sin2x. cos2x. U = sin2x , U’ = 2cos2x. V = cos2x , V’ = -2sin2x. y’ = 2cos2x.cos2x – sin2x ...
[DOC File]Goniometria III - GT12
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2cos2x = sin x + 1. 2 + 2cos x = 3sin2 x. cos2x + cos x = sin2 x. 2cos2x = 3sin x. 2sin2x – 3cos x = 0. sin x + cos 2x = 1. 2cos2x + sin x = 1. tg2x – 7tg x + 10 = 0. tg x – cotg x = 1. 2tg x – 3cotg x = 5. cos2x + cos x = 0. ... cos x = sin 2x . cos x. sin 2x = tg x. cos2x – sin2x = – 0,5 . sin x + sin 3x = sin 2x + sin 4x. sin2x ...
[DOC File]XTEC
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Trobeu el valor numèric de: cos2x – sin2x + tg2x per a x = (/3 rad. R.: 5/2. Trobeu el valor numèric de: (1 / cos2x) + (1 / sin2x) – 5tg2x + (1 / tg2x) per a x = (/4 rad. R.: 0. Simplifiqueu les expresions següents: R.: a) sin a b) cos a. Simplifiqueu les expressions següents: R.: a) 1 + cos a b) sin a + cos a. ...
[DOC File]Transformari identice ale expresiilor algebrice
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a) sin2x - cos2x = 0; c) 5sin2x + 5sinxcosx = 3; b) sin2x + sin2x - 3cos2x = 0; d) Rezolvare. a) Ecuatia a) reprezinta o ecuatie trigonometrica omogena de gradul intai. Se multiplica cu si se obtine ecuatia liniara in raport cu tg2x
[DOC File]Analiza I: 3. kolokvij - plonkec
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cos2x = 1/2 (1+cos2x) sin2x = 1/2 (1-cos2x) y sin y cos y ˝(-x cos x sin x (+x -sin x -cos x (-x sin x -cos x 3x 3sin(x)-4sin3x 4cos3x-3cosx -x -sin x cos x
[DOC File]Analiza I: 3. kolokvij - plonkec na A4
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cos2x = 1/2 (1+cos2x) sin2x = 1/2 (1-cos2x) y sin y cos y ˝(-x cos x sin x (+x -sin x -cos x (-x sin x -cos x 3x 3sin(x)-4sin3x 4cos3x-3cosx -x -sin x cos x
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