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[DOC File]CBSE CLASS XII MATHS
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Using (1) & (2) we get 4x2 + 4(4x) = 9 4x2 + 16x - 9 = 0 4x2 + 18x - 2x - 9 = 0 (2x - 1) (2x + 9) = 0 x = 1/2, -9/2 From (1) x = 1/2 y = + 2 and x = -9/2 y = imaginary quantity Thus the points of intersection of (1) and (2) are A(1/2, 2) and B (1/2, 2) Also both the curve are symmetrical about x-axis Required Area = Area OBPAO - 2.Area (OPAO ...
cos3x cosx 2cos2x 1 0

[DOC File]TÀI LIỆU ÔN THI ĐẠI HỌC
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a.2cos2x – sinx – 1 = 0 b. 2sin22x – cos2x – 1 = 0 c.cos2x + 9cosx +5 = 0 d.cos4x +7sin2x – 6 = 0 e. cos6x – 7cos3x + 4 = 0 f. cos4x +2cos2x – 3 = 0
2cos2x 4 sin x 1 0

PHÖÔNG TRÌNH LÖÔÏNG GIAÙC
e.sin42x + cos42x = 1 – 2sin4x f. 5/ Phöông trình ñaúng caáp theo sinx vaø cosx : a/ Phöông trình ñaúng caáp baäc hai : asin2x +b sinx cosx + c cos2x = 0 . Caùch 1 : Xeùt phöông trình khi x = + k( . Vôùi x ( + k( chia hai veá cuûa phöông trình cho cos2x roài ñaët t = tgx. Caùch 2: Thay sin2x = (1 – cos 2x ...
2cos 2x cosx sqrt tgx 1 0

[DOC File]phng tr×nh lîng gi¸c
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(2cos(4-2x)cos8x=2cos8xsin4x(2cos8x(sin4x-cos(4-2x))=0 Vậy nghiệm của phương trình (1) là: Bài 5.[Đại học Ngoại Thương 1999]: Giải phương trình:
2cos 2x 2cosx cos2x 1 0

[DOC File]Základné pojmy: jednotková kružnica, π, goniometrická ...
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a) sin4x + cos4x = b) cos 3x + 2 cos x = 0. c) cos 2x + cos 8x = 1 + cos 6x d) cos = sin . 58. Určte definičný obor funkcie: a) f : y = b) f : y = c) f : y = d) f : y = e) f : y = 59. Riešte v R nerovnice: a) sin x > cos x b) tg x + cotg x > ( 3. c) tg3 x + tg2 x ( tg x ( 1 < 0 d) cos 4x + cos 2x < 0. e) sin x + cos x > ( f) cos(sin x) < 0 ...
2cos2x 4 cos x 1 12

[DOC File]İZMİR FEN LİSESİ LİSE 1 MATEMATİK
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Title: İZMİR FEN LİSESİ LİSE 1 MATEMATİK Author: Hasan Korkmaz Last modified by: okul Created Date: 12/31/1987 9:27:00 PM Company: Korkmaz A.S.
1 cos x 2cos 2x 2

[DOC File]WordPress.com
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Feb 06, 2009 · Let 5sin2x ( 12cos2x ( Rsin(2x ( () where R > 0 and ( is an acute angle. (a) Find the values of R and (. (Give 3 significant figures if necessary) (b) Find the maximum values of the following expressions. ... ( 1 ( () 1M ( cos4x + 1A (b) (sin6x + cos6x ( )2 ( (cos4x + ( )2 ( cos24x 1M ...
1 2sin 2x 2cos2x 0 2

[DOC File]A Level Mathematics Questionbanks
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a) cos4x sin4x ( (cos2x sin2x)(cos2x + sin2x) M1 But sin2x + cos2x = 1 B1 So cos4x sin4x ( cos2x sin2x A1
2cos2x 4cos 3pi 2 x 1 0

XI კლასი 23.02.2014 I ...
1.კონუსის ორი მსახველი, რომელთა შორის კუთხე 600 ფუძის წრეწირს ყოფს შეფარდებით 1:2.
cos3x cosx 2cos2x 1 0

[DOC File]1
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Oct 29, 2009 · A = (; hence y = C1e5u + C2e(2u ( e4u = C1(x + 1)5 + C2(x + 1)(2 ( (x + 1)4 1A 5. Let x = u + h, y = v + k where h and k are constants to be determined. dx = du and dy = dv. 1M. The original differential equation will be . Set , on solving, h = 1, k = 1 and the differential equation will be 1M = = --- (*) 1M. Let z =, v = zu ( = z + u
2cos2x 4 sin x 1 0

Cos4x 2cos 2x 1 0