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[DOC File]三角函数的图象和性质·典型例题
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(2)y=cos4x+sin4x=(cos2x+sin2x)2-2sin2xcos2x =|cosx|+|sinx|=f(x) 正周期． (x+T)|+|cos(x+T)|=|sinx|+|cosx|都成立．特别当x=0时，有|sinT|+|cosT|=sinT 【例8】求下列各函数的最大值、最小值，并且求使函数取得最大值、最小值的x的集合． ∴使y取得最大值的x的集合为{x|x=(2kπ+1)π，k∈Z}
sin4x 1 cos4x cos2x 1 cos2x tanx

PHÖÔNG TRÌNH LÖÔÏNG GIAÙC
c. 2cosx.cos2x = 1+cos2x + cos3x d. 2(sin4x + cos4x) = 2sin2x – 1 e.sin42x + cos42x = 1 – 2sin4x f. 5/ Phöông trình ñaúng caáp theo sinx vaø cosx
1 2 cos2x sin2x cos 2x cosx

[DOC File]CHƯƠNG I HÀM SỐ LƯỢNG GIÁC VÀ
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u. cos3x – sin2x = 0 v. sin3x + sin5x = 0 . Bài 2: Giải các phương trình sau: a. sin(2x -1) = sin(x+3) b. sin3x= cos2x c. sin4x + cos5x = 0 d. 2sinx + sin2x = 0 e. sin22x + cos23x = 1 f. sin3x + sin5x = 0 . g. sin(2x +500) = cos(x +1200) h. cos3x – sin4x = 0
sin6x cos4x sin4x cos6x 0

[DOC File]TÀI LIỆU ÔN THI ĐẠI HỌC
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a. sinx +cosx = 2 b.cos2x +sin2x = 1 c. cos4x – (sin2x +cos2x)2 = 0 d. 2cos2x + sin2x = 3 . 2. Giải các phương trình sau : a. (cosx – sinx)(cosx+sinx) + 2sinxcosx = 1 b. cosx + sinx = 2cos2x. c. 2cos6x +2cos4x - cos2x = sin2x + d. (2cos2x +cosx – 2 ) + (3 – 2cosx)sinx = 0. e. 2cos2x +2sinxcosx + 1 = 3sinx +3cosx . 3. Phương ...
1 cos2x 1 cos2x 2sin2x sin4x

[DOC File]CBSE CLASS XII MATHS
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Integral Calculus. Two mark questions with answers. Q1. dx Ans1. dx = dx = dx = dx = (sec2x + secx tanx) dx = tanx + secx + c Q2. Ans2. = dx = dx = dx = c = c Q3. 3 cotx - 2 tanx)2 dx Ans3. (3 cotx - 2 tanx)2 dx = (9 cot2x + 4 tan2x - 12) dx = [9(cosec2x - 1) + 4(sec2 x - 1) - 12] dx = (4 sec2x + 9 cosec2x - 25) dx = 4 tanx - 9 cotx - 25x + c Q4. dx Ans4. dx = dx = dx = = + c Q5. (1 - sinx) dx ...
cos5x cos4x cos3x cos2x 0

[DOC File]Chuyªn ®Ò :ph¬ng tr×nh lîng gi¸c
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Phương trình LG biến đổi về tích bằng 0 . 1/ cos2x- cos8x+ cos4x=1 2/sinx+2cosx+cos2x-2sinxcosx=0. 3/sin2x-cos2x=3sinx+cosx-2 4/sin3 x+2cosx-2+sin2 x=0. 5/ 3sinx+2cosx=2+3tanx 6/ sin2x+cos2x+cosx=0 . 7/ 2sin2x-cos2x=7sinx+2cosx-4 8/
cos3x sin2x sin2x sin4x cosx

[DOCX File]Уроци по Математика
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Получаваме cos3x=0 и cos4x+sin2x=0. От cos3x=0 намираме x= π 6 + π 2 . k 1 , От cos3x=0 намираме x= π 6 + π 2 . k 1 , k 1 ∈Z.
4sin 2x 1 cos2x 1 cos2x

[DOC File]WordPress.com
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Feb 06, 2009 · F.4 Additional Mathematics Quiz (Trigonometry I) Name: _____ F.4___ ( ) 2009-02-06 Full. mark: 38. FORMULAE. 1. Let 5sin2x ( 12cos2x ( Rsin(2x ( () where R > 0 and ...
cos2x sin2x 0 25

[DOC File]INTEGRAL
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sinx ( sinx cos2x + C. cosx ( cos sin2x + C (Madas Umptn 91 Rayon B) = sin4x + C. cos4x + C (cos2x + C. sin2x + C ( sin4x + C (Madas Umptn 91 Rayon A) Jika dan , maka f(x) = … x3 + 6x2 ( x ( 6 . x3 ( x2 + 6x ( 6. x3 ( 6x2 + x ( 6. x3 ( x2 ( 6x ( 6. x3 + x2 + 6x ( 6 (Madas Umptn 94 Rayon B) Jika dan , maka f(x) = … 2x3 + 2x2 ( 5x ( 6. 4x3 ...
sin4x 1 cos4x cos2x 1 cos2x tanx

[DOC File]A Level Mathematics Questionbanks
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a) cos4x sin4x ( (cos2x sin2x)(cos2x + sin2x) M1. But sin2x + cos2x = 1 B1. So cos4x sin4x ( cos2x sin2x A1 [3] b) (cos2 : 5 + 2tan2 = 4sec2 M1 A1. 1 + tan2 ( sec2 5 + 2tan2 = 4(1 + tan2 ) M1. tan2 = A1
1 2 cos2x sin2x cos 2x cosx

Cos4x cos2x sin4x sin2x 0