Cos4x cos2x sin4x sin2x cot3x
[PDF File]Maths Assignment – 2016-2017 - CBSE Today
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3 Q.41 Prove that : i. 2 3 4 6 2 1 cot7 ii. 4 2 2 2 1 4 1 tan11 iii. 2 2 3 6 2 1 tan142 Q.42 Prove that : 1 cos2 2 2 cos sin4 Q.43 Prove that : cos3 2 3cos2 4 cos sin6 Q.44 Prove that : tan tan 60 tan tan 60 tan 60 tan 60 3.
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cos4x = cos2x cos4x - cos2x = 0 We know that We use this identity cos 4x - cos 2x = -2sin3xsinx -2sin3xsinx = 0 sin3xsinx=0 So, by this we can that either sin3x = 0 or sinx = 0 3x = x = x = x = Therefore, the general solution is. Question:6 . Find the general solution of the following equation . Answer: We know that
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ĐỀ CƯƠNG TOÁN LỚP 11 – HK I 6 12) cos x 1 2 + 3cot2x = 5. 13) tan2x + 9. cosx 3 14) tanx + 4 tanx =1. 15) sin4x + cos4x + sin 2x 4 3 2 = sin2x. 16) 5sinx 2 = 3(1 sinx).tan2x. 17) 7 0. sin x 1 4 sin x sin x
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A)cot6x B)tan6x C)cot3x D) tan3x E) sin3x sin4x sin6x sin8x cos4x cos6x cos8x 11. 3tanx ñ3 olduðuna göre, x aþaðýdakilerden hangisi olabilir? A)30° B)60° C)90° D)120° E)150° 12. sinx cosx 0 olduðuna göre, x aþaðýdakilerden hangisi olabilir? A)15° B)30° C)45° D)60° E)135° 14. x (0,2 ) olmak üzere, 2cosx 1
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1) y = sin2x5 2) y = cos4x2 3) y = tan4x4 4) y = csc4x5 5) y = sec5x4 6) y = cot3x4 7) y = cot2x4 × (-5x2 + 2) 8) y = tan-1-x2 9) y = cos-1x3 10) y = cot-14x2 11) y = csc-12x3 12) y = sin-1-x4 13) y = sec-1-5x2 For each problem, find all points of absolute minima and maxima on the given interval. 14) y = 2cot (x); [-p 3, - p 4] 15) y = -csc (x ...
Giáo viên : V Ng c Thành THPT M ƯỜNG SO SƯU T ẦM 500 PH ƯƠ ...
Giáo viên : V ũ Ng Sưu t ầm trên các di ễn đàn toán h ọc Vi ệt Nam + = + + + + = + + + = ...
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1cos2x1 cos2x 1 cos2x 1 cos2x 1 cos2x 2. 1cos2x 1cos2x 2 1cos2x2sin2x 1 cos2x 2sin2x 1 cos2x 2. 1cos2x 1cos2x 2 1 cos2x 4sin2x 2. 1cos2x1cos2x . l). ysinxcosx 44 2 131 1sin2x cos4x. 244 / 31 1 1// yʹ cos4x cos4x sin4x . 4x sin4x. 44 4 4 m). 2 ycos2x 4 . Áp dụng cosu / với 2 u2x 4 / 22 2 / yʹ sin2x . 2x sin2x .22x .2x 44 4 44 2 42x .sin2x ...
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sin4x 4 1 x 16 1 [3 ⎟ + ⎠ ⎞ ⎜ ⎝ ⎛ − + 70. ∫ dx 2 x cos6. sin x C ] 3 1 sin2x 4 3 4sin x 2 5x 8 1 [3 ⎟+ ⎠ ⎞ ⎜ ⎝ ⎛ + + − 71. ∫ dx sec3x xsinx 2 2. cos4x C ] 16 1 cos2x 8 1 [ 2 − 2 + 72. ∫ + + dx x 1 xtan x 1 2 2. 2 + + [ ln |sec x 1| C ] 73. ∫ dx x tan(lnx) [ ln | sec(lnx) | + C ] 74. ∫ 2 ( sin2 cos2 ) d θ ...
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sin4x — sin2x verify the identity. — —cot3x cos4x — cos2x 62. sin3x + sin5x + sin8x = SECTION 6.5 For Exercises 63-70, d. cos— a. Write the solution set for the general solution. b. Write the solution set on the interval [0, 27). 63. O
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1 + sinx + cos3x = cosx + sin2x + cos2x (1) BT2: Giải phương trình cos2x – cosx = 2sin2 BT3: Giải phương trình sin4x + 3sin2x = tanx (ĐK: cosx 0) II.Phƣơng trình bậc hai đối với một hàm số lƣợng giác Phƣơng pháp chung
[PDF File]Math 201-103-RE Derivatives with Trigonometric Functions
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Math 201-103-RE Practice Assignment 4 (79) Use logarithmic differentiation to find y′(0) if y = (6x+1)2 4 √ 2x2 +1 e1−cosx (80) Use logarithmic differentiation to find y′(0) if y = sin4x e3 sinx 3
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