Cos6x cos5x sin6x sin5x 1
[DOC File]CHUYÊN ĐỀ 1: LƯỢNG GIÁC
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9) cos6x+sin6x=cos4x 11) cos8x+sin8x= 10) sinx+sin2x+sin3x+sin4x= cosx+cos2x+cos3x+cos4x 12) (sinx+3)sin4-(sinx+3) sin2+1=0 3.Giải phương trình lượng giác đưa về dạng tích
PHÖÔNG TRÌNH LÖÔÏNG GIAÙC
e.sin42x + cos42x = 1 – 2sin4x f. 5/ Phöông trình ñaúng caáp theo sinx vaø cosx : a/ Phöông trình ñaúng caáp baäc hai : asin2x +b sinx cosx + c cos2x = 0 . Caùch 1 : Xeùt phöông trình khi x = + k( . Vôùi x ( + k( chia hai veá cuûa phöông trình cho cos2x roài ñaët t = tgx. ...
[DOC File]urok.1sept.ru
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Приложение №2. Вариант 1. 5cos²x+7cosx-6=0 8cos²x-10sinx-11=0 10tg²x+11tgx-6=0 cosx-3sinx=0 2sin²x-sinx=0 sin3x-sin5x=0 2sin2x+5sinx=0 sin2x+4cos²x=0 5cos2x-6cos²x=0 9cos2x+3cosx-1=0 5sin2x-18cos²x+14=0 3cosx+11sinx+9=0 Вариант 2
[DOC File]Урок 1, 2
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3) sin6x + cos4x = 1 – 6sinx(cosx [Формулы синуса тройного и двойного аргументов; sin2x = 0 или sin2x = 1 или sin2x = –1,5; ]. 4 Устно: используя единичную окружность (на …
[DOC File]§Ò sè 1 - Yola
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§Ò sè 1. C©u1: (2,5 ®iÓm) Cho hµm sè: y = -x3 + 3mx2 + 3(1 - m2)x + m3 - m2. 1) Kh¶o s¸t sù biÕn thiªn vµ vÏ ®å thÞ cña hµm sè trªn khi m = 1. 2) T×m k ®Ó ph¬ng tr×nh: -x3 + 3x2 + k3 - 3k2 = 0 cã 3 nghiÖm ph©n biÖt. 3) ViÕt ph¬ng tr×nh ®êng th¼ng ®i qua 2 ®iÓm cùc trÞ cña ®å thÞ hµm sè trªn.
[DOC File]Математика
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10. Найдите производную функции f(x) = sin5x cos6x – cos5x sin6x A)-sinx. B)-cosx. C) cosx . D) sinx . E) 1. 11. В прямоугольном треугольнике катеты равны 3 и 4 соответственно. Найдите длины отрезков, на которые делит ...
[DOC File]Chuyªn ®Ò :ph¬ng tr×nh lîng gi¸c
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1/ 2sin15x+cos5x+sin5x=k với k=0 và k=4 với k=0 . 2/ a : b: ... 9/ cos6x+sin6x=cos4x 10/ sinx+sin2x+sin3x+sin4x= cosx+cos2x+cos3x+cos4x . 11/ cos8x+sin8x= 12/ (sinx+3)sin4-(sinx+3) sin2+1=0 . DANG 7 : Phương trình LG biến đổi về tích bằng 0 . 1/ cos2x- cos8x+ cos4x=1 2/sinx+2cosx+cos2x-2sinxcosx=0 ...
[DOC File]Atsauksme - LU
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Aplūkojamā funkcija ir augoša, tāpēc tā savas ekstremālās vērtības sasniedz dotā intervāla galapunktos, t. i., ymin = y(–1) = , ymax = y(16) = . 2. uzdevums. Atrast funkcijas vērtību kopu. Anniņa. Zemsaknes izteiksmēm jābūt nenegatīvām. (1 – x > 0, 2x + 4 > 0) ( – 2 < x < 1.
[DOC File]ТЕСТЫ ПО КАЗАХСКОМУ ЯЗЫКУ 10 КЛАСС 1 ЧЕТВЕРТЬ …
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4 1 3 2 5 Укажите слово с ударением на третьем слоге: поняла понять понявший поняли поняло Укажите словосочетание, в котором есть слово с приставкой
[DOC File]Chuyªn ®Ò :ph¬ng tr×nh lîng gi¸c
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1/ 2sin15x+cos5x+sin5x=k víi k=0 vµ k=4 víi k=0 . 2/ a : b: ... 9/ cos6x+sin6x=cos4x 10/ sinx+sin2x+sin3x+sin4x= cosx+cos2x+cos3x+cos4x . 11/ cos8x+sin8x= 12/ (sinx+3)sin4-(sinx+3) sin2+1=0 . Dang 7 : Ph¬ng tr×nh LG biÕn ®æi vÒ tÝch b»ng 0 . 1/ cos2x- cos8x+ cos4x=1 2/sinx+2cosx+cos2x-2sinxcosx=0 ...
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