Cosx sin2x cos3x 1

    • [DOC File]TÀI LIỆU ÔN THI ĐẠI HỌC - Toancanduoc's Blog

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      a. sinx + sin2x + sin3x = 0 b. cosx – 2cos2x + cos3x = 0 c. 4cos3xcosx – 2cos2x = d. 2sinxsin3x + sin=1 B. Phương trình lượng giác thường gặp


    • [DOC File]Открытый урок

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      5sin²x+21sinx+4=0 5sin²x-7cosx+1=0 8tg²x+10tgx+3=0 cosx-2sinx=0 cos²x+4cosx=0 sin3x-sin7x=0 7sin2x-2sinx=0 sin2x+10cos²x=0 5cos2x-14cos²x+8=0 3cos2x-14cosx+7=0 11sin2x+6cos²x+6=0 16cosx-11sinx-4=0 Вариант 3 2cos²x-11cosx+5=0. 3cos²+7sinx-5=0. 18tg²x+3tgx-10=0. 5cosx-2sinx=0. 4cos²x+3cosx=0. cos3x-cosx=0. 2sin2x+3cosx=0. 5sin2x ...


    • [DOC File]İZMİR FEN LİSESİ LİSE 1 MATEMATİK

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      34. tg² x – (1+)tgx+=0 denklemini çözünüz. 35. sin2x=2cos3x denklemini çözünüz. 36. sin² x+2sinxcosx-2cos² x= denklemini çözünüz. 37. sinx+sin2x+sin3x=4coscosxcos. denklemini çözünüz. 38. 2sin3x=3cosx+cos3x denklemini çözünüz. 39. tgx+tg2x=tg3x denklemini çözünüz. 40. 1+sinx+sin2x+sin3x=cosx – cos2x+cos3x ...



    • 4ege.ru

      Cosx=1 4) x = - π 2 +2πn, nϵZ 5)x = πn, nϵZ . Наибольший отрицательный корень уравнения 2cosx +1 = 0 равен: ... 1) sin2x = 2sinxcosx 2) sin x 2 = ± 1 ... Выражение sinx + sin 3 x cosx+cos3x тождественно равно: 1) 2cosx; 2) tgx; 3) ctgx; 4) sin²x. 18. ...


    • [DOC File]Ekstrēmu uzdevumu risināšanas metodes - LU

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      4. Piemērs. Noteikt funkcijas y=sinx(cos3x(sin3x(cosx lielāko vērtību. y=sinx(cos3x(sin3x(cosx=sinx(cosx(cos2x(sin2x)=sin2x(cos2x=sin4x. Tā kā vērtību apgabals ir (1 ( sin4x ( 1, tad dotās funkcijas lielākā vērtība ir . 5. Piemērs. Noteikt funkcijas mazāko vērtību. 1. paņēmiens. Apzīmējam sin2x=a; aplūkojam apgriezto ...



    • [DOC File]BÀI GIẢI

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      sin3x + cos3x – sinx + cosx = cos2x ( sin3x – sinx + cos3x + cosx = cos2x ( 2sinxcos2x + 2cos2xcosx = cos2x ( cos2x = 0 hay 2sinx + 2cosx = ( cos2x = 0 hay ( x = hay x = hay x = (với k ( Z). Câu 3: ( ( hay ( hay ( hay hay . Câu 4:. Đặt u = x ( du = dx. dv = (1 + sin2x)dx, chọn v = x – cos2x. I = = Câu 5: Hạ AH vuông góc A/B ...


    • [DOCX File]Уроци по Математика

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      Да се реши уравнението . 2 2cos4x+1 cosx=1. Разкриваме скобите . 4cos4x.cosx+2cosx=1 и изразът 4cos4xcosx преобразу- ... Получаваме cos3x=0 и cos4x+sin2x=0. От cos3x=0 намираме x= π 6 + π 2 . k 1 , k 1 …


    • [DOC File]Téma č - edu

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      riešte rovnice: a) sin2x - cos3x . sin2x = 0. b) c) (tgz)-1 - 2(sinz)-1 = -tgz. 12. V . R. riešte rovnice: a) sinx + cosx = 2. b) sinx + sin3x = sin2x + sin4x 13. V . R. riešte rovnice: a) b) Title: Téma č Author: Pavol Petrovský Last modified by: Gymnázium sv. Moniky Created Date: 10/14/2004 2:25:00 PM


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