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[DOC File]CE523 HOMEWORK 5 solution
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Solution: The density of the seawater is 1023kg/m3 at 25 C., so the mass flow rate of the input water is: 10.64kg/s. Osmotic pressure . C = [NaCl] = ; CT (Na+, Cl-) = 1.18M. During continuous operation, salt concentration will increase to 1.18/0.2 = 5.9 M (Nobody had realized the salt concentration before the membrane is the same as the brine ...
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[DOC File]CHEM 211 Laboratory
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The purpose of this experiment is to determine the density and concentration of an unknown salt solution. Procedure and Observations: ... (density + b that relates the NaCl molarity to the NaCl(aq) density. Take the density of water to be 1.00 g/mL and the molar mass of NaCl to be 58.5 g/mol. How does your experimental value for the slope m and ...
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[DOC File]IIT JEE Syllabus - KEEEL
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5 g of NaCl is dissolved in 1000 g of water. If the density of the resulting solution is 0.997 g per cc, calculate molality, molarity, normality and mole fraction of the solute. Solution: Mole of NaCl = = 0.0854 (Mol. wt. of NaCl = 58.5) Molality = = = 0.0854 m Volume of the solution…
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[DOC File]Weebly
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Jan 31, 2014 · A solution is made by dissolving 25g of NaCl in enough water to make 1.00L of solution. Assume that the density of the solution is 1.00g/cm3. Calculate the mass percent, molarity, molality, and mole fraction of NaCl. A solution of phosphoric acid was made by dissolving 10.0g H3PO4 in 100.0mL water. The resulting volume was 104mL.
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[DOC File]Molarity Problems - Chemistry Geek
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Determine the mass percent of a LiBr solution that contains 5.9 g LiBr and 40.0 g water. 2. Determine the mass % of a NaCl solution if 58.5 grams of NaCl was dissolved in 50 ml of water (assume the density of water to be 1 g/ml).
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[DOC File]Sample Problems:
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25 ml of 0.5% solution of drug X (NaCl equivalent = 0.31), how many mg of NaCl are needed to render the solution isotonic? Amount of drug in 25 ml = 0.5 X 25 X 1000 / 100 = 125 mg. NaCl equivalent = 125 X 0.31 = 38.75 mg. NaCl needed if used alone = 25 X 0.9 / 100 = 225 mg. NaCl needed to make the solution isotonic = 225 – 38.75 = 186.25 mg
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Chapter 12: Physical Properties of Solutions
The salts that remain (mostly NaCl) have a mass of 3.85 g. Calculate the original concentration of NaCl, in g per liter, in the water sample. Ans: 38.5 g/L. Category: Easy Section: 12.3. 10 The solubility of oxygen in water is about 4.5 10–2 g/L. The water portion of an adult's total blood supply is about 5 liters.
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Density of 5 nacl solution