Finding acceleration with only distance and time
[DOC File]Speed, Velocity, & Acceleration Lab
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With only one photogate the timer measures the time that the light beam is broken. As the car passes through the photogate, the beam is broken for the width of the wing (5 cm). The velocity of the car is the width of the wing (distance traveled) divided by the time it takes to pass through the light beam. The computer will calculate it for you.
[DOC File]PapaCambridge
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The gradient of a distance-time graph represents speed. The gradient of a speed-time graph represents acceleration. The area under a speed-time graph represents distance. Motion under free-fall: The acceleration due to the gravitational pull of the earth is always constant and its value is 9.81 m/s2 .
[DOC File]Intro to Physics
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For position (distance) vs. time motion graphs, the steeper the slope of the plotted line, the faster the speed. Item 1’s slope is steepest, so item 1 fell fastest, followed by item 2 and item 3. The curvature on the slopes indicates acceleration. Only item 3 appears to have reached a constant velocity, from 1.4 second to 2.2 seconds.
[DOC File]1
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1) EXPLAIN the difference in motion represented by a straight line and a curving line on a “distance vs. time” in terms of constant or changing speed. _____ 2) Changing speed is called “acceleration” (speeding up) or deceleration (slowing down). Describe the shape of an acceleration line on a Distance vs. Time graph of acceleration.
[DOC File]Physics 20 - SharpSchool
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Speed = distance/ time . Velocity = displacement/time. Finding Resultants (displacement, velocity . or force) Step 1 – Draw each vector starting from the center of the grid. Step 2 – Sketch each vector separately and find its components. Step 3 – Add all the x’s together and all the . y’s together. Step 4 – Sketch the two vectors ...
[DOC File]Changing Velocity
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Find its acceleration over the time period after about 1.05 s when its acceleration is constant by determining the slope of the straight line that best fits the data. Report the acceleration with units. What is the acceleration of the object when its velocity is –2 m/s? +2 m/s? 0 m/s? Write your calculations and results below the graph.
[DOC File]A method for finding the average amount of cars a ...
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My assumptions included an abrupt change in the acceleration from constant linear acceleration to constant angular acceleration. For a roundabout that is relatively small I don’t believe that the distance between the source and first exit will differ too much. Reaped from a website was an average acceleration of cars (3-4 m/s/s).
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