Frequency from sine equation
[DOC File]Name That Frequency
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2. The amplitude of this sine wave is 0.087. 3. The phase shift for the sine curve is -c/b. Thus if b = 8.989 we can solve for c given the beginning of any cycle of the sine curve. For example if the sine curve began its cycle at x =1.183 and y = .883 then the phase shift would be 1.183 and c = -10.661, and the vertical displacement d = .883. 4.
[DOC File]Math II Unit 6
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The frequency and period are reciprocals of each other so the period = . Since , we can replace the period with and solve for k. If , then . The cosine function with a frequency of 4 is f(θ)=cos(8πθ) . Find the equation of a sine graph with a frequency of 6 and amplitude of 4. Applications of Sine and Cosine Graphs Learning Task:
[DOC File]Applications of Sine and Cosine Graphs Learning Task:
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Write a sine equation that models the initial behavior of the vibrations of the note G above middle C given that it has amplitude 0.015 and a frequency of 392 hertz. Write a sine equation that models the initial behavior of the vibrations of the note D above middle C given that it has amplitude 0.25 and a frequency of 294 hertz.
[DOC File]Amplitude and Period for Sine and Cosine Functions Worksheet
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Sine Equation _____ Sine Equation _____ Cosine Equation _____ Cosine Equation _____ Sketch the graph of the function over the interval –2( ≤ x ≤ 2(. 11. y = 4 sin x 12. y = 2 cos x. 13. y = 2 sin 2x 14. y = – cos 2x 15. y = 3 cos x 16. y = – 2 sin (4x) Determine the amplitude, period, phase shift, and …
[DOC File]Graphing Sine and Cosine – Worksheet #1
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Graphing Sine and Cosine Fill in the blanks and graph. 9) 10) Domain: Range: Domain: Range: Amplitude: 2 Period: Amplitude: 1 Period: π . Phase shift: N/A Vertical shift: Up 1 Phase shift: Right Vertical shift: N/A ...
[DOC File]Normalize so that L = 1
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N can initially be calculated for an input PSD of 1 G^2/Hz. Then the PSD can be scaled accordingly to satisfy equation 2 for a given amplification factor Q, sine amplitude S and coefficient (. Set according to Reference 2. (3) This means that the sine response will be equal to the random response 1.9-sigma level.
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