Ft lb to kip ft
How many pounds are in a kip?
A kip is a US customary unit of force. It equals 1000 pounds-force, used primarily by American architects and engineers to measure engineering loads. Although uncommon, it is occasionally also considered a unit of weight, equal to 1000 pounds, i.e., one half of a short ton.
How much is Kip in lbs?
kip [1] an informal unit of force, sometimes used by engineers to express the amount of weight borne by a structure. One kip equals 1000 pounds (453.59 kilograms) of force or about 4.4482 kilonewtons.
What is a kip foot?
Kip-in/ft is the same moment capacity as kip-in, it's just convenient when dealing with slabs or walls to consider a single 12" wide section, so the moment becomes kip-in per foot of wall or per foot of slab. Put it in imperial terms.
[PDF File]Lori's Web
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1 kip/ft 4 ft g + (544) — - 218 . 13-7 Relationships Among Load, Shear, and Moment load intensits Loading Diagram ... 120 lb/ft 12 ft 2000 lb.ft 900 1b 4 ft Solution. 6 ft solve rea*ons A F qoo 1b E E 1201b 1b FED— 2000 — (16+4) 900 770 3z44.- 110 O 233 . tzo 5.5333 1570 670 10/300
[PDF File]HW 10 SOLUTIONS
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30 kip • ft or the maximum shear is V 8 kip. max max Determine the largest intensity w of the distributed load the beam will support. = 4w; 6 ft 6 ft Thus, w = 2 kip/ft -30= …
[PDF File]5–19. P
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V = 8.00 kip 6 ft 6 x … 10 ft M = {-x2 + 30.0x - 216} kip # ft +©M NA = 0; M + 216 + 2xa x 2 b- 30.0x = 0 V = {30.0 - 2x} kip + c©F y = 0; 6 ft 4 ft 30.0 - 2x - V = 0 0 … x 6 6 ft 6–18. Draw the shear and moment diagrams for the beam, and determine the shear and moment throughout the beam as functions of x. 2 kip/ft 8 kip x 10 kip 40 ...
[PDF File]HW 19 SOLUTIONS - University of Utah
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8 kip 3 kip,ft 5 ft *6—20. Draw the shear and moment diagrams for the beam, and determine the shear and moment throughout the beam 10 kip 2 kip/ft g Kip 8 kip 40 kip.ft as functions of x. Support Reactions: As shown on FBD. Shear and Moment Function: For o s x 6 n: V- {300—2t) kip For rt: 0 kip ft V /0-x V-8.OOkip —M M kip-ft
APPENDIX 1: Conversion Factors - ASCE Library
1 kilo-pound (kip) (force) 4.448 kilo-newtons (kN) 1 kip-foot (kip-ft) 1.356 kilo-newton-meters (kN-m) 1 kip per foot (kip/ft) 14.59 kilo-newtons per meter (kN∕m) 1 horsepower (HP) 745.7 watts (W=Joule∕second) Nautical Units 1 nautical mile = 1.151 statute miles = 6076.1 ft = 1.852 km 1 knot = 1.151 miles per hour = 1.688 ft/s = 0.515 m/s
[PDF File]List of Symbol Definitions
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kip-ft, N-m, kN-m) Mn nominal flexure strength with the full section at the yield stress for LRFD beam design (lb-ft, kip-ft, N-m, kN-m) Mp (also Mult) internal bending moment when all fibers in a cross section reach the yield stress (lb-ft, kip-ft, N-m, kN-m) Mu maximum moment from factored loads for LRFD beam design (lb-ft, kip-ft, N-m, kN-m)
[PDF File]Chapter 2. Design of Beams – Flexure and Shear
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2 / 8 = 1.42 x 302 / 8 = 159.75 kip-ft. Step II. Select the lightest section from the AISC Manual design tables. From page of the AISC manual, select W16 x 26 made from 50 ksi steel with φbMp = 166.0 kip-ft. Step III. Add self-weight of designed section and check design wsw = 26 lbs/ft Therefore, wD = 476 lbs/ft = 0.476 lbs/ft.
[PDF File]Conversion Factor Table
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kg / m3 0.062428 lbm / ft3 kgf 9.80665 newton (N) kip 1000 lbf kip 4448 N kJ 1 1 kPa·m3 kJ 1000 N·m kJ 0.94782 Btu kJ 737.56 ft·lbf kJ / kg 1000 m2 / s2 kJ / kg 0.42992 Btu / lbm kJ / kg·K 0.23885 Btu / lbm·°R kJ / kg·ºC 1 kJ / kg·K kJ / kg·ºC 1 J / g·ºC
Conversion Table - Wiley Online Library
ft m 0.30480 mft 3.28084 Area in. 2mm 645.160 mm 2in. 0.00155 ft 2m 0.09290 m 2ft 10.76391 Force kip force kN 4.448 lb N 4.448 kN kip 0.2248 Stress ksi MPa 6.895 MPa ksi 0.145 Moment ft-kip kN-m 1.356 kN-m ft-kip 0.7376 Uniform loading kip/ft kN/m 14.59 kN/m kip/ft 0.06852 kip/ft 2kN/m 47.88 kN/m 2kip/ft 0.02089 psf N/m2 47.88
[DOC File]RENSSELAER POLYTECHNIC INSTITUTE
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= 11,472 ft ( lb 11.47 ft ( kip Ans. (b) = -86,827 ft ( lb -86.8 ft ( kip Ans. Problem 4 (25 Points) Three couples are applied to a bent bar as shown in the figure. Determine: a. The magnitude of the resultant couple C and the direction angles ( x, y, z) associated with the resultant couple vector. b. The scalar component of the
[DOCX File]1 Having a minimum durometer hardness of 50 and utilizing ...
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The double tee girder flange is designed to carry the load of the cast-in-place slab, the flange weight and a 50 lb./sq. ft. construction dead load. (or a 3000 lb. concentrated construction load per IBC). ... Span Length in ft BMD in Kip-inch Mu 0 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45 48 51 54 57 60 0 2290.0320000000002 4339.0080000000007 ...
[DOC File]STEM curriculum for K-12 - TeachEngineering
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A steel rod that is 5.5 ft long stretched 0.04 in when a 2-kip (2,000 lb) tensile load is applied to it. Knowing that E = 29,000,000 psi, determine (a) the smallest diameter rod that should be used, (b) the corresponding stress caused by the load.
[DOC File]Set #1 - CCSF
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answer: a) R = 1800 lb xbar =10.80 ft. b) A =1800 lb upward MA = 19.44 kip-ft ccw. 2. Determine the reactions at the beam supports for the given loading. answer: A= 270 N upward. B =720 N downward . 3. Determine the reactions at the beam supports for the given loading. answer: A= 1600 lb upward. B =800 lb …
[DOC File]EGR 280 – Mechanics Problem Set 1 - Oakland University
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Cx = 75 lb. Cy = 100 lb 5.3 . The front of the car is to be lifted using a rigid 10-ft long board. The car weighs 3,500 lb with center of gravity at G. Determine the position x of the fulcrum so that an applied force of 100 lb at E will lift the front of the car. Ans: x = 9.43 ft. 5.4 . The engine hoist is used to support the 200-kg engine.
[DOCX File]Bentley
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Current Date: 12/28/2015 8:55 AM Units system: English. Steel connections. Results. Connection name: Fixed uniaxial major axis BP. Connection ID: 1. Family: Column - Base (CB)
[DOC File]Lecture 41 Equilibrium of Rigid Bodies STUDENT …
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la (AC X W) = [(2/3) i + (2/3) j (1/3) k] ( 5400 lb ft) k = 1800 lb ft 1800 lb ft = la (AE X T) Using the commutative property for the mixed triple product: 1800 lb ft = T (la X AE) This shows that the projection of T onto the vector (la X AE) is constant, thus T will be minimized when it …
[DOC File]1
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Mp-x = Zx Fy = 189.26 x 50 = 9462.93 kip-in. = 788.58 kip-ft. Design strength according to AISC Chapter F= bMp= 0.9 x 788.58 = 709.72 kip-ft. Reading Assignment – AISC Specification Chapter F. 5.2 Local buckling of beam section – Compact and Non-compact
1
Span Lb (ft.) Cb Mu (kip-ft.) Mu/Cb (kip-ft.) AB 12 1.67 550.6 329.7 BC 8 1.0 (assume) 550.6 550.6 CD 10 1.67 524.0 313.8 It is important to note that it is possible to have different Lb and Cb values for different laterally unsupported spans of the same beam. Step III. Design the beam and check all laterally unsupported spans
[DOC File]Test Problem Summary
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8. A 5 ft diameter 100 ft long concrete pipe with square edge and headwall has its inlet invert at 100.00 elevation. If the slope of the pipe is 1% and the tail water is 7 ft, what is the required centerline elevation if a minimum of 5 ft is required between the maximum water elevation and the centerline elevation? Assume Q=200 cfs and ke=0.2. 9.
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