Ft lbs to psi calculator
[DOC File]PML Exploration Services, LLC
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(.465 psi/ft for salt water) (.433 psi/ft for fresh water) Now equating the water pressure to equivalent formation depth by: De = P/(S/D) Where. De = equivalent depth. P = pressure exerted by the water. S/D = overburden stress (depth of water + depth of interest (from chart) Programming this into a pocket calculator creates a accurate and ...
[DOC File]EXAMPLE 5 - HUD User Home Page | HUD USER
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= 19.4 ft. Determine the span, L, of the tributary load (1/2 of the jack rafter span) at the top of the rafter: L = 1/2 (13.71 ft)* = 6.86 ft *The clear span does not include the wall thickness of 3.5 inches. Determine the uniform load at the top end of the hip rafter (bottom end is 0 plf): w = 2L(uniform roof design load) = 2(6.86 ft)(25 psf ...
[DOC File]FORMULA SHEET - Homestead
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PSI = Ft. Head x Specific Gravity Ft Head = (PSI x 2.31 ... / 1.8 Gallons Liters 3.785 HP KW 0.7457 Inch mm 25.4 lbs. Kg 0.4535 lb.-ft. Nm 1.356 PSI Bar 0.06896 In. of HG PSI 0.4912 In. of H20 PSI 0.03613 ... To save time when converting velocity pressure into air velocity, the Dwyer Air Velocity Calculator may be used. A simple slide rule, it ...
[DOC File]STRENGTH OF MATERIALS
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Apply load to the beam by placing weights onto the loading pans in 200 lbs. increments (the weights are 50 lbs. apiece). With the level arms setup for a load factor of 10, this will produce incremental loads of 2000, 4000 and 6000 lbs. Make readings of all the electrical and mechanical strain gages, and the deflection gage between each loading ...
[DOC File]Florida Building
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R404.1.2.3.1 Compressive strength. Reserved.The minimum specified compressive strength of concrete, f’c, shall comply with Section R402.2 and shall be not less than 2,500 psi (17.2 MPa) at 28 days. [S4555] R404.1.4 Seismic Design Categories D0, D1 and D2 – Change to read as shown.
[DOC File]Cornerstone Robotics
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Figure 2: A Pressure of 20 psi Acting upon a 100 in2 Surface. To keep the surface at rest, the 20 psi pressure must be equalized with a force in the opposite direction. F = P x A. F = 20 lbs/in2 x 100 in2. F = 2000 lbs . Figure 3: The Force Needed to Equalize the 20 psi Pressure over 100 in2
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