How to find p from t value

    • [DOCX File]Math One - Home

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      A population of insects, in thousands, can be modeled using the function p(t) = 1.75(0.97)t, where t is time in months. Which statement . best. ... The function f(x) = 2,500(0.97)x models the value of an investment after x months. Which statement is true about the .

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    • [DOC File]Paper Reference(s)

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      The constants p, q and r each represent probabilities associated with the three separate regions outside B. The events A and B are independent. (a) Find the value of p. (3) Given that , (b) find the value of q and the value of r. (4) (c) Find . (2) May 2013 (R) 7.

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    • [DOC File]Interpreting SPSS Output for T-Tests and ANOVAs (F-Tests)

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      Look at the enlarged numbers under the column that says “t” for the t-value, “df” for the degrees of freedom, and “Sig. (2-tailed) for the p-value. (Notice that the p-value of .539 is greater than our “.05” alpha level, so we fail to reject the null hypothesis.

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    • [DOC File]DeKalb County School District

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      (b) Find the P-value using Table C. Then obtain a more precise P-value from your calculator. 71. One-sided test Suppose you carry out a significance test of H0: μ = 5 versus Ha: μ < 5 based on a sample of size n = 20 and obtain t = −1.81. (a) Find the P-value for this test using Table C or technology.

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    • [DOC File]Example SPSS Output for T-Test for Difference in Means

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      Summary: To find the p-value for the hypothesis test for the difference in means, look in the column labeled “Sig. (2-tailed)” in the “t-test for Equality of Means” section, and in the second row (labeled “Equal variances not assumed”). Note that since the p-value given by SPSS is 2-tailed, you need to divide it in half for a 1-tailed test. In the above example the 1-tailed p-value would be .001.

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    • [DOC File]California State University, Northridge

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      The moment balance gives P(6 ft) = FR(yCP – 10 ft). Note that we have to correct the value of yCP to make it relative to the location of the hinge instead of the value we have which is relative to the top of the wall. We can thus find P = (2.11x104 lbf) (3.23 ft) /(6 ft). P =1.14x104 lbf

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