How to find probability using z score
Calculate probability of a range using Z Score
Find the z-scores corresponding to each of the following values: A score of 60, where the mean score of the sample data values is 40. Z=2. A score that is 30 points below the mean. z=-3. A score of 80, where the mean score of the sample data values is 30. Z=5. A score of 20, where the mean score of the sample data values is 50. Z=-3
[DOC File]Lecture 6 – Z scores
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Z score = X – Mean. SD. where X is the raw score on the scale that you want to convert to a Z score. You got an 80 on a history exam (M = 83, SD = 5). What was your Z score? Z score = (80-83) / 5 = -0.6, meaning you scored 0.6 standard deviations below average. You got a 71 on an organic chemistry exam (M = 57, SD = 14). What is your Z score?
[DOC File]Probability and One-sample Z tests
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Convert sampling mean to a Z score (using a modified Z score formula) Use Z table to find the probability of finding a Z that is more extreme. Note: This is no different than what we have been doing, except we use a different formula for Z when we have a sample mean instead of an individual score. Individual Score Sample of Scores Z = (X – μ ...
[DOC File]Z-Score Practice Worksheet
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Math English Biology your score 90 85 93 Mean 85 82 94 Standard deviation 5 2 1 z-score 1. Find the following probabilities using Appendix A page 469-473: z < 1.56 z < -.68 z > 2.34 z between 0 and 2.1 z between –1.23 and .90. 2. What proportion of all young women are less than 68 inches tall?
[DOC File]Z-scores and Standardized Distributions
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Using z-scores and percentiles lead to the equivalent results and the same conclusion.. Using the specified normal distribution X~N(3.0, 0.7) and Y~N(80, 10) give the same probabilities and percentiles as are obtained by using the Z score with the standard normal distribution, Z ~ N(0, 1) CHAPTER 6: THE NORMAL PROBABILITY DISTRIBUTION: PRACTICE
[DOC File]Z-scores and Probability
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A z-score of 1.25 is at the 89.44 percentile level leaving a 10.56% chance of selecting 1 person at random whose score is 65 or greater. Using the multiplication rule for independent events would give:
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