How to find sq ft

    • [PDF File]Wastewater Math Concepts - American Water College

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      The clarifier is 52 feet in diameter and has a depth of 8 feet. Find the solids loading in this clarifier in lb/day/sq. ft. 2. A round clarifier handles a flow of 2.9 MGD and suspended solids of 3,400 mg/L. The clarifier is 50 feet in diameter and has a depth of 8 feet. Find the solids loading in this clarifier in lb/day/sq. ft.

    • [PDF File]Appendix A Measuring Lake Surface Area

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      Find the AREA of the square paper cutout (to scale). For instance, if the map’s scale equates 1 inch with 1000 feet, then one side of the 3-inch cutout square represents 3000 feet. Consequently, that 3-inch square piece of paper represents 9,000,000 sq ft of surface area. (See below.) 3,000 ft X 3,000 ft = 9,000,000 sq ft

    • [PDF File]Calculating Radiator Output - Express Radiant

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      1. sq. ft. radiation per section for column type radiators design or average water temperature heat emission rates btuh per sq. ft. design or average water temperature heat emission rates btuh per sq. ft. 110º f 30 180º f 170 120º f 50 185º f 180 130º f 70 190º f 190 140º f 90 195º f 200 150º f 110 200º f 210

    • [PDF File]HOW TO MEASURE AN AREA - Simplot

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      A = 0.7854 x 15 x 15 = 58.9 sq. ft. IRREGULARLY-SHAPED AREA Method I. Determination of a very irregularly shaped area can be obtained by establishing the longest line possible lengthwise throug the center of the area. Numberous lines are then established perpendicular to this center line. The

    • [PDF File]**Approximate guide for finding tank & drainfield size ...

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      * Step # 3 - To find drainfield size (non-mound), divide gallons per day by a loading rate under column “C” or “D”. Use column A & B as a guide. * Your figures will be a vague guide. Exact drainfield size will be determined by the Health Dept. after a complete site evaluation. TABLE III For Sizing of Drainfields Other Than Mounds

    • [PDF File]SINGLE FAMILY DWELLING ELECTRICAL LOAD CALCULATION (O M

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      2800 sq. ft. X 3 VA = 8,400 VA (VA = volt amperes) Step 2: Add in 1500 VA for each 2-wire, 20-amp small appliance branch circuit and the laundry circuit . 1,500 VA X 3 = 4,500 VA. Step 3: Add in the appliances loads at nameplate value. Range 14,000 VA. Water heater . 3,000 VA. Clothes dryer . 5,000 VA ...

    • [PDF File]Square Footage List - PVO 2020 - We Print Wraps

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      Make Model Year Side Width Side Height Side Sq Ft Back Width Back Height Back Sq Ft Hood WidthHood Length Hood Sq Ft Roof WidthRoof Length Roof Squ Ft Total Sq Foot Acura CSX 4 Door Sedan 2006-2011 49.0 172.0 68.0 67.0 42.0 24.3 54.0 27.0 13.8 50.0 65.0 27.6 201.7 Acura EL Series 4-Door 2001-2002 175.2 48.0 68.0 68.0 44.7 26.1 50.0 40.0 17.9 43 ...

    • [PDF File]9.7 Quadratics - Rectangles

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      Find the side of the original square. 3) A rectangular lot is 20 yards longer than it is wide and its area is 2400 square yards. Find the dimensions of the lot. 4) The length of a room is 8 ft greater than it is width. If each dimension is increased by 2 ft, the area will be increased by 60 sq. ft. Find the dimensions of the rooms.

    • [PDF File]Conversion Factors and Tables - USDA

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      1 Acre = 43,560 sq. ft. Acres = area in square feet 43,560 Rectangular or Square Fields Acres = Length x Width (in feet) 43,560 Triangular Fields Acres = Base x Height (in feet) 2 x 43,560 Parallelogram Fields (opposite sides parallel) Acres = Base x Height (in feet) 43,560

    • [PDF File]Useful Conversions - USDA

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      • lbs per sq. ft. x 43,560 = lbs per acre • 1 acre = 0.405 hectares • 1 mile = 1.61 km • parts per million (ppm) x 0.00136 = tons per acre-foot To convert a soil test from ppm to lbs per acre. 1. Determine the depth of soil in inches that the soil represents 2. Divide this depth by 3

    • [PDF File]HVAC Rule of Thumb Calculator - Engineering Pro Guides

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      1 ft. hd = 2.99 Pa 1 Pa = 3.34 x10-4 ft. hd 1 psi = 6.89 x10-3 MPa 1 MPa = 145.04 psi 1 psi = 27.68 in. wg 1 in. wg = 0.036 psi 1 psi = 2.31 ft. hd 1 ft. hd = 0.043 psi 1 lb/ft3 = 16.018 kg/m3 1 kg/m3 = 0.062 lb/ft3 1 Btu = 0.293 watthour 1 watthour = 3.412 Btu ...

    • [PDF File]Formula/Conversion Table for Water Treatment and Water ...

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      Filtration Rate or Backwash Rate, GPM/sq. ft. = Flow, GPM Filter Surface Area, sq. ft. lbs/day Chemical Feed MGD Flow mg/ Dose 8.34 lbs/gal . E I R P . E I . Davidson Pie Chart • To find the quantity above the horizontal line: multiply the pie wedges below the line together and divide by thepurity,

    • [PDF File]Material Weights and Conversions

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      48 ft : 3: or 1.7 yd : 3: Conversion Factors : 1 truckload = 74 drums : 1 tank truck = 4,500 gallons . 1 ton = 2,000 pounds 1 metric ton = 2,204 pounds : 1 liter = 0.264 gallons : 1 cubic foot = 7.482 gallons 1 cubic foot = 0.037 cubic yards : 1 cubic yard = 202.018 gallons . 1 kilogram = 2.200 pounds

    • [PDF File]Load Calculations

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      Dr. M.E. Haque, P.E. (Load Calculations) Page 5 of 6 3. Column A4 Tributary area, A T = 20 x 15 = 300 sq ft Corner column without cantilever slab, Influence area, A

    • [PDF File]Determining Static Pressure

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      1. CFM = 48 x 15 inches divided by 144 (sq. in. in one sq. ft.) = 5 sq. ft. x 100 FPM = 500 CFM. 2. Static pressure of the hood is given as 0.25 inch WG. 3. Using a duct calculator or the charts below, find the resistance for 500 CFM moving through 100 ft. of 8-in. diameter duct = 0.45 in. SP per 100 ft. 4.

    • [PDF File]HOW TO FIND A FILTER CARTRIDGE REPLACEMENT USING THE ...

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      4-5/8"15" / semi-circular handle 1763 oz40 sq. ft. top load - Dimension One Spas 4CH-940 / 1-1/2” male thread/MPT 4-5/8" 16" / molded cone handle 1453 oz35 sq. ft. top load 4CH-35

    • [PDF File]7555-20190219172743 - NCSU

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      of 100 ft. Assuming no sag in the string, find the rate at which the kite is moving when 125 ft of string has been released. 8. The ends of a water trough 10 ft long are equilateral triangles whose sides are 3 ft long. If water is pumped into the trough at a rate of 5 ft3/min, find the rate at which the water level is rising when the depth is 1 ...

    • [PDF File]CALCULATING OCCUPANT LOAD - NFPA

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      40 ft x 30 ft = 1,200 ft2/6 rooms = 200 ft2 per room 200 ft2/30 ft per person = 6.66 people Round up: 7 people per room 7 x 6 = 42 people. CALCULATING OCCUPANT LOAD CONTINUED This material contains some basic information about NFPA 101, Life Safety Code. It identifies some of the requirements in these documents as

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