Joules to million electron volts

    • [DOC File]Chapter 28

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      Aug 12, 2011 · the minimum energy required to release an electron from a metal . Equations and Symbols where. E = energy of a photon. c = speed of light = 3 x 108 m/s. f = frequency of light. λ = wavelength of light. Wo = work function of a photoemissive

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    • [DOC File]CCR Template

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      “MeV” means one mega electron volt, or one million electron volts. One MeV is the amount of energy acquired by a particle with one electron charge in passing through a potential difference of one million volts in a vacuum. One MeV is equivalent to 1.60×10-16 joules. “Minor” …

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    • [DOC File]NAME:_________________________ MC

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      a) What is the kinetic energy (in electron volts) of the electron as it leaves the accelerator? b) What is this energy in Joules? c) What is the speed of the electron? The electron now reaches a region with a uniform electric field directed downward and of magnitude E = 5,000 N/C, which extends 5 cm in the horizontal direction.

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    • [DOC File]U235: A Lesson in Plausibility & Proportion

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      So, how many joules of energy do we get from our 0.695 kg of fissioned U235? The calculation is simple. You recall that one U235 atom yielded 200 million eV or 0.000000000032 joules of energy. Therefore we multiply that number by our 1.78 trillion trillion atoms to get 57 trillion joules. But a number like that is conceptually awkward.

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    • [DOC File]Chapter 22 Worksheet #2 Name

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      For a single nucleus, the magnitude of the binding energy is typically between 10-10 to 10-12 J. (For convenience, nuclear binding energies are sometimes expressed in mega electron volts (MeV), where 1 MeV = 106 eV = 1.60 x 10-13 J) A more useful quantity for comparing the stability of nuclides is the binding energy per nucleon:

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    • [DOC File]6

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      The velocity of the electron in the hydrogen atom is approximately 2 x108 cm/sec = 1/137 of the speed of light. And remember, the centrifugal force depends on the square of this velocity. That is what is needed to overcome the strong electric attraction. Here is the great irony. Once the hydrogen atom is formed, the electron and the proton are ...

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    • [DOC File]1.2 UNITS OF MEASUREMENT

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      (l) The most popular soft drink in the World is currently Coca Cola(. More than 210 million _____ were consumed each day in 1990. (m) The largest diamond in the world was mined from South Africa in 1905 and weighs 3,106 _____ . (n) Earth is the densest of the …

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    • [DOC File]Extreme_Light.doc - StealthSkater

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      In the past few years, laser-driven electron and proton accelerators have produced beams with energies greater than 50 million electron-volts (MeV), comparable to a single stage (a few meters long) of a conventional accelerator. The laser system achieves the same energy in a millimeter! Prompt acceleration with high gradients has advantages.

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    • [DOC File]TAP525-0: Binding energy

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      6 Start with the mass of an electron in atomic mass units. Convert to kilograms. Write down the mass of an electron–positron pair. Use Erest = mc2 to get the rest energy of the pair in joules. Then use E = hf. 7 Do this one in the same way as question 1. 8 Erest = mc2 again. But now use the electron charge to get to electron volts and MeV.

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    • [DOC File]Chapter 38

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      38-11. The energy E of a photon in joules is found from the product hf. Often we are given the wavelength of light and need to find its energy in electron volts. Show that. such that if is in nanometers, E will be the energy in electron volts.; = eV(nm. When is in nm , E will be in J: 38-12.

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