Kg mol to kg
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15. Hemoglobin has a molecular mass of 64,500 u. Find the mass (in kg) of one molecule of hemoglobin. 1 u = 1.6605 x 10-27 kg. 64500 u = 64500 u (1.6605 x 10-27 kg/u) = 1.07 x 10-22 kg. Alternative solution. Hemoglobin is 64,500 g/mol. Number of molecules per mol is Avogadro’s number = 6.022 x 1023 particles/mol
[DOC File]Chapter 13 worksheet #1
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Mass of water = mass of solution – mass of NaOH = 1000 g – (0.300 mol)(40 g/mol) = 1000 g – 12 g = 988 g. Molality = 0.300 mol/0.988 kg = 0.304 m. Notice that the molality is a little bigger than molarity. Why are these two numbers similar and why is molality always greater than molarity?
PERCENTAGE COMPOSITION WORKSHEET
7. Calculate the mass of aluminum (in kg) in 200. kg of aluminum oxide. Use percentage composition AND gravimetric factor!! 200. kg Al2O3 x 53.96 kg Al = 106 kg Al. 101.96 kg Al2O3 % Al = MAl x 100 = 53.96 g Al x 100 = 52.92 % Al. MAl2O3 101.96 g Al2O3. 200. kg Al2O3 x 52.92 kg Al = 106 kg Al
[DOC File]AP Chemistry study guide for Solutions (Chapter 11)
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(The molal freezing-point depression constant, Kf, for camphor is 40.0 kg-K-mol¯1.) (c) When 1.570 grams of the compound is vaporized at 300 °C and 1.00 atmosphere, the gas occupies a volume of 577 milliliters. What is the molar mass of the compound based on this result?
[DOCX File]UCSB Campus Learning Assistance Services - Home
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moles solute kg solvent . 12.5 g CH. 3. OH. x. 1 mole 46 g = 0.272 mole CH. 3. OH ⇒ molality = 0.272 mole CH 3 OH 0.0875 kg of water = 3.1mol/kg. 3. Calculate the molality and mole fraction of an aqueous solution that is 8 M NaCl, the density of the solution is 1.18 g/ml. If you have 1 L of solution there are 8 . mol. of . NaCl ⇒ since the ...
[DOC File]AP Chemistry – Chapter 3, Stoichiometric Relationships ...
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(The molal freezing-point depression constant, Kf, for camphor is 40.0 kg-K-mol¯1.) (c) When 1.570 grams of the compound is vaporized at 300 °C and 1.00 atmosphere, the gas occupies a volume of 577 milliliters. What is the molar mass of the compound based on this result?
[DOC File]Productivity Calculations SOLUTIONS
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5 kg C/ m2-year * 10,000 kJ / kg C = 50,000 kJ/m2-year . Imagine we run an experiment on the algae Cladophora glomerata. We place equal amounts of algae into a light bottle and a dark (covered) bottle. ... (1 mol C / 1 mol O2 ) = 15 x 10-5 moles of C/L-wk. Then we work with the light bottle: Start = 10 mg O2/L After 1 week = 11 mg O2/L.
[DOC File]CHAPTER 5 - GASES
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The molar mass of N2 is 2.8 x 10-2 kg/mol. (R = 8.314 J/mol.K; J = kg.m2.s-2) (Answer: urms = 493 m/s) 2. At a certain temperature and pressure, 6.2 mg of N2 gas effuses through an opening in 90. seconds. How much of H2 gas would effuse through the same opening in 90. seconds under the same condition? (Answer: 1.7 mg of H2)
[DOC File]Home - Brooklyn City School District
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925 g x 0.870 g/ml = 805 g = 0.805 kg m = 2.50 mol / 0.805 kg = 3.11 m 6. How many moles of argon are there in a two-gas solution in which the mole fraction of helium (the other gas) is 0.31?
[DOC File]Molarity Practice Worksheet
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6) a solution that contains .500 mol HC2H3O2 in 0.125 kg H2O. 7) a solution that contains 63.0 g HNO3 in 0.500 kg H2O. Other: 8) What mass of water must be used to dissolve 0.500 kg C2H5OH to prepare a 3.00 m solution? Molarity and Molality Practice Worksheet. Find the molarity of the following solutions:
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