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[DOC File]Chapter 5
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Known : p1 5 kPa p2 15 kPa. m 5 kg Cp 1.0 kJ/kgK. T1 300 K 1.4. Diagrams : To find : Change in entropy. Analysis : S2 S1 m. By applying the state equation. Since V2 V1 . Also R Cp Cv 0.286 kJ/kgK. Substituting these values we get. S2 S1 5
kg m2 to pascal

[DOC File]California State University, Northridge
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We are given the density of the fluid as 1000 kg/m3, so its specific weight, = g = (1000 kg/m3)(9.80655 m/s2) (1 N(s2/kg(m) = 9807 N/m3. pin < –3.759x104 Pa = –37.6 kPa 8.20 Oil flows through the horizontal pipe shown in Figure P8.20 (copied from the text at the right) under laminar conditions.
kg m 2 s 2 to pascal

[DOC File]CHAPTER 5 - GASES
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If mass in kg and acceleration in m/s2, force = kg.m/s2 = Newton (N) Pressure = = N/m2 = Pa (Pascal, SI unit for pressure) Atmospheric Pressure or Barometric Pressure? The atmosphere contains a mixture of gases, mainly N2 and O2. Gas molecules constantly colliding with the Earth’s surface and results in the atmospheric pressure.
kg ms 2 to kpa

[DOC File]Gas Pressure: 1 atm = 760 torr (mmHg) = 14
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If mass = kg, and acceleration = m/s2, Force = kg.m/s2 = Newton (N) If Area = m2, Pressure = (kg.m/s2)/m2 = N/m2 = Pascal; (1 Pa = 1 N/m2) Gas Pressure: 1 atm = 760 torr (mmHg) = 14.70 psi = 101.3 kPa = 1.013 x 105 Pa. Exercises #1: 1. A person with a mass of 70.0 kg stands squarely on ice in the ice-skating ring. The person is wearing a pair ...
pascal to kg

[DOC File]Chapter 2
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P = gh = (1000 kg/m3)(9.8 m/s2)(30 m); P = 196 kPa *15-55. Water flows through the pipe shown in Fig. 15-22 at the rate of 30 liters per second. The absolute pressure a pint A is 200 kPa, and the point B is 8 m higher than pint A. The lower section of pipe has a diameter of 16 cm and the upper section narrows to a diameter of 10 cm. (a) Find ...
kpa to kg m3

Kpa to kg m s2