Lbm ft3 to psi

    • [DOC File]1 - University of Washington

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      1. Standard conditions in ventilation are: T = 70ºF, P = 29.9in Hg, air density = 0.075 lbm/ft3. Express the temperature in degrees C, R and K. Express the pressure in the following units: mm Hg, inches of water, atm and psi. What change in temperature or pressure is needed to make a …

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    • [DOC File]The International System of Units (SI)

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      In oilfield units, p = change in fluid pressure, lbf/in2 or psi = density, lbm/ft3. g = acceleration of gravity, ft/s2 h = change in height of fluid, ft. and the pressure gradient (psi/ft) is. Notice that the units check because. EXAMPLE: Calculate the pressure gradient for a fluid having a density of 65 lbm/ft3…

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    • [DOC File]Natural Gas Pipeline Flow Calculations

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      Note that the density of air at 60oF and 14.7 psi is 0.0764 lbm/ft3. Solution: The gas density can be calculated with equation (1). gas = (0.65)(0.0764) = 0.050 lbm/ft3 Molecular Weight - The molecular weight of a gas is the mass per mole. The value is the same in any of the commonly used units, lbm/lbmole, g/mole, or kg/kgmole.

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    • [DOC File]Course Overview

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      Density has units of kg/m3 or lbm/ft3. To determine the mass of an entire thermodynamic system, it is necessary to integrate the density over the entire volume according to the following relationship: (1.7) Specific Volume (v) The specific volume is the reciprocal of the density and is defined as follows: Specific volume has units of m3/kg or ...

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    • [DOC File]ICS FLUID FLOW

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      ’lbm’ is a mass unit called ‘pounds mass’. It is numerically equal to ‘lbf’, (1 lbm = 1 lbf), but they are not the same. ‘lbf’ is a unit of force. If you use lbm units for ( in calculating Re, then use a ( = 6.74E-4 lbm(ft-1(s-1, as shown below. You will need to convert the mass density from slug/ft3 to lbm/ft3. Note that 1 …

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    • [DOC File]California State University, Northridge

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      Table A-1E gives the gas constant for air as R = 0.3704 psia∙ft3/lbm∙R. The mass that left the tank is simply the difference between the initial and final mass: mout = m1 – m2 = 20.95 lbm – 8.38 lbm = 12.57 lbm. We can use the ideal gas properties for air from Table A-17E. Since T1 = T2 = Tout= 120oF = 579.69 R, we have u1 = u2 =98.90 ...

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