Log sinx 1 cos2x cos4x 0

    • [DOC File]CBSE CLASS XII MATHS

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      Two mark questions with answers. Q1. Differentiate y = xx, x > 0. Ans1. y = xx logy = x log x (1/y)(dy/dx) = x.(1/x) + logx.1 (dy/dx) = y(1 + logx) = xx(1 + logx).

      sin4x cos4x cos2x 0


    • [DOC File]Deriveringsregler - Tripod

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      sin2x + cos2x (=1 trigonometriska ettan) 0 (2sinxcosx +2cosx-sinx) (2sinxcosx - 2sinxcosx) = 0-5cos x -5*-sinx. 5 sinx. x/3 -0,2cosx 1/3 - 0,2*-sin x. 1/3 + 0,2 * sin x. 1-x =(1-x)0,5 0,5(1-x)-0,5 * -1-0,5 * 1/ (1-x)0,5-1/2 * 1/ (1-x) ... 10x och log. 10x=5. log10x=log5. x=log 5 (log 5 är den exponent som 10 skall upphöjas till för att man ...

      3cos4x 4sin2x cos2x sin4x 0


    • [DOC File]SAMPLE PAPER – I – (2002)

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      -1 -4 -1 1 2 4 6 2. Find a 2x2 matrix B such that B 1 -2 = 6 0 1 4 0 6. 3. Show that the binary operation * defind by a * b = ab+1 on Q is commutative and associative. 4. Find the principle value of cot-1 [-1/3] 5. Find second derivative of y = log[x2/ex] 6.

      sin2x sin4x sin6x cos2x cos4x cos6x


    • [DOCX File]Kathmandu Engineering College

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      (iv) dx sin2x - sinx Ans:I= 1 6 log 1+cosx + 1 2 log 1-cosx - 2 3 log 1-2cosx +c . Worked out example-IV: ... Solution: Let I= 0 π 2 sin 4 x dx = 0 π 2 sin 2 x 2 dx = 0 π 2 1 - cos2x 2 2 dx = 1 4 0 π 2 1 - cos2x+ cos 2 2x dx = 1 4 0 π 2 1 - cos2x+ 1+cos4x 2 dx = 1 4 x - sin2x+ x 2 + sin4x 8 0 π 2 = 3π 16 . ∴ 0 …

      sin2x sin6x sin4x 0


    • [DOC File]JustAnswer

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      6232E Part 5. 1. I like Trigonometry as it compels me to think seriously while solving problems. Analyzing capability increases. 2. Plot of y = cosx between 0 and 360 degrees will be as given below.

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    • [DOC File]Вариант 1

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      e) (-(; -1) ( (-1; 0). 19. Второй член арифметической прогрессии равен 9, а ее третий член больше первого на 12.

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    • [DOC File]CBSE CLASS XII MATHS

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      Integral Calculus. Two mark questions with answers. Q1. dx Ans1. dx = dx = dx = dx = (sec2x + secx tanx) dx = tanx + secx + c Q2. Ans2. = dx = dx = dx = c = c Q3. 3 cotx - 2 tanx)2 dx Ans3. (3 cotx - 2 tanx)2 dx = (9 cot2x + 4 tan2x - 12) dx = [9(cosec2x - 1) + 4(sec2 x - 1) - 12] dx = (4 sec2x + 9 cosec2x - 25) dx = 4 tanx - 9 cotx - 25x + c Q4. dx Ans4. dx = dx = dx = = + c Q5. (1 - sinx) dx ...

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    • [DOC File]Новая кодовая шпаргалка по математике для ЕНТ 2013

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      06 (–1)n+1arcsin0,6+(n,n(Z. (sinx=–0,6) 060 1/8 |у=sinx•cosx, осью 0х, х=π/6, х=0| 060235 1 06023505 1 06131501230555125064 11 061411501251304415 25. 062 4/3 {tgα, sinα =0,6 . π /2< a < π. 0620513141 [1/4; 1/3] 062056229844534 –3,441. 0623060 (–3;0) 062518 125. 0625182212121 1,25.

      sin2x cos2x cos4x 0


    • [DOCX File]Математик

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      4sin α ∙ sin π 3 - α sin π 3 +α =4sinα ∙ 1 2 cos2α - cos 2π 3 =2sinα 1 - 2 sin 2 α+cos π 3 =2sinα - 4 sin 3 α+sinα=.3sinα - 4 sin 3 α =sin3 α тул sin π 7 =sin 3π 21 =4sin π 21 ∙ sin ⁡ ( π 3 - π 21 ) ∙ sin ⁡ …

      sin4x cos4x cos2x 0



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