Orbital period equation
[DOC File]A Practical use for Kepler’s laws:
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We can now rearrange the equation to look like this: Mj = Mass of Jupiter. We will now use this equation to calculate Jupiter’s mass with the given orbital period and mean distance from Jupiter of the moon IO. IO Orbital period (T)= 1.769 Days. IO Mean Distance from Jupiter (r) = 421, 600 km
[DOC File]What is the moon's orbital period
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You can calculate both the sidereal orbital period yourself ! You can calculate the orbital period of any object orbiting the Earth including the moon from the following equation which is simply Kepler's third law of motion (remember? P^2 ~ a^3) expressed by Issac Newton using his gravitational constant, u: P = 2pi * sqrt (a^3 / u) Where P ...
[DOC File]PHYS 228 Astronomy & Astrophysics - Widener University
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Orbital Periods of Planets. Synodic period -time taken by planet to return to same position in sky, relative to Sun, as seen by Earth. Sidereal period- time taken by planet to complete one orbit w/ respect to stars. Equations relating synodic and sidereal periods of a planet:
[DOC File]SyllabusF - University of Massachusetts Dartmouth
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3. Convert the orbital period 27.32 days into units of seconds. 4. Divide the orbital circumference from part 2 by the orbital period from part 3. Your result is the Moon’s velocity v in the required units of meters per second. 5. In Equation 11-4, substitute the velocity v …
[DOC File]Dynamics
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Kepler’s third law states that there is a specific relationship between the orbital period and orbital radius for each planet in the solar system. Specifically, for all planets orbiting the sun the ratio of their orbital period squared divided by their orbital radius cubed, T2/r3, yields the same number.
[DOC File]RECITATION PROBLEMS
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Its orbital distance was measured to be 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD68988? Express your answer in kilograms and in terms of our sun’s mass (mass of the sun is 1.99 x 1030 kg.) Following is the equation for the period …
[DOC File]PT3 Lesson Plan Rubric - ARRL - Home
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Kepler’s 3rd law states that the semi-major axis of a planet’s orbit (average distance to the sun in A. U.’s) is related to the planet’s orbit period (in Earth-years) by the equation: p2 = a3. Where p = orbital period in Earth years and a = distance from sun in A.U.’s.
[DOC File]Calculate the Mass of the Milky Way Galaxy
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Orbital Period of the Sun about the Center of the Milky Way . 2.5E8 years for the Sun to orbit once about the center of the Milky Way Galaxy. Time squared = (2.5E8)^2 = 6.25E16. Newton’s form of Kepler’s Third Law. Mass = (distance)^3 divided by (time)^2. M=(18.7E8)^3 / (2,5E8)^2. M=6.35E27 / 6.25 E 16. M= 1.1 E 11 Solar Masses
[DOC File]Physics -- Circular Motion & Gravitation Study Guide
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The equation for the speed of an object in circular orbit is . What does m represent in this equation? ... 29. What is the orbital period of the planet? (G = 6.673 10 N m/kg) _____ 30. Earth’s mean distance from the sun is 1.50 10 m. The length of one Earth year is …
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