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[DOC File]JustAnswer
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Jul 05, 2011 · =P(Z > (4.8-average)/0.5) ≤ 0.10 Average ≤ 4.8-1.282(0.5) = 4.16 ounces. 37. An insurance company estimates 35 percent of its claims have errors. The insurance company wants to estimate with 90 percent confidence the proportion of claims with errors. What sample size is needed if they wish to be within 5 percentage points of the actual? 0 ...

[DOCX File]Appendix 2.16 - Status Codes - Defense Logistics Agency
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AP2.16.1. Status codes may be alphabetic/alphabetic or alphabetic/numeric and flow from sources of supply to the creator of a requisition or customer asset report, consignee/consignor, or Service-designated control office. Status codes also flow from the Defense Automatic Addressing System (DAAS) to a DAAS subscriber or from storage activities ...

[DOC File]Exam 3 Practice Questions
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Finally, we now use the z-table to find P(Z > 1.79) = 0.0367. 39. D We are not given the distribution of the population we are sampling from and our sample size is only 16 (

[DOC File]CHAPTER SIX
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The P( 1.5 < Z < 1.09) equals. a. 0.4322. b. 0.3621. c. 0.7953. d. 0.0711. e. None of the above answers is correct. 66. The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces. What is the probability that a randomly selected item will weigh more than 10 ounces?

U.S. Army Human Resources Command
, tables 3-1 and 3-2. Unit CDRs should make every effort to recommend all qualified Soldiers to a promotion board or with appropriate counseling for non-recommendation IAW . …

[DOC File]Sample Test Questions -- Test 1
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1= P(0) + P(1) +P(2) 1 =.25 + Q + .25. 1=.5 + Q. Q= 1-.5. Q=.5. A; roman numeral one is true because an extremely large value out in the right-hand tail pulls the mean to the right; roman numeral two is true because the calculation of the mean uses all the numerical values, so unlike the median, it depends on how far observations fall from the ...

[DOC File]Z-Score Practice Worksheet
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For the numbers below, find the area between the mean and the z-score: z = 1.17 .38. z = -1.37 .41. For the z-scores below, find the percentile rank (percent of individuals scoring below):-0.47 31.9 Percentile. 2.24 98.8 Percentile. For the numbers below, find the percent of cases falling above the z-score: 0…

[DOC File]CHAPTER 9—HYPOTHESIS TESTS
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a. H0: p 0.21 Ha: p > 0.21 b. Test statistic Z = 1.96 c. p-value = 0.025 d. p-value = 0.025 < .05; therefore, reject Ho; more than 21% like the new drink. PTS: 1 TOP: Hypothesis Tests 9. In the past, the average age of employees of a large corporation has been 40 years. Recently, the …

[DOC File]ASSIGNMENT Chapter 5
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Find the following probabilities for the standard normal random variable z: a. P (z > 1.46) b. P (z < -1.56) c. P (.67 ( z ( 2.41) d. P (-1.96 ( z ( -.33) e. P (z ( 0) f. P (-2.33 < z < 1.50) g. P (z ( -2.33) h. P (z < 2.33) ANSWERS. 5.28(8 points) Find a value zo of the standard normal random variable z such that. a. P (z ( zo) = .0401. b. P ...

[DOC File]DISTRIBUSI PELUANG
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Terdapat paling banyak 2 buah kategori A, berarti R= 0, 1, 2. Perlu dicari P(R = 0) + P(R = 1) + P(R = 2) = 0,0423 + 0,1409 + 0,2270 = 0,4102. ( = 30 (0,1) = 3 artinya, rata-rata diharapkan akan terdapat 3 benda termasuk kategori A dalam setiap kelompok yang terdiri atas 30. Contoh Aplikasi:

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