Planck s constant problems

    • [DOC File]Name_________________________________________ Period ...

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      Use the frequency and Planck’s constant to calculate the energy of the light. Answer the discussion questions in detail. Metal Ion Tested Atomic Number Color of Flame Wavelength (nm) Frequency (1/s) Energy (J) Lithium Copper Calcium Sodium Barium Strontium Potassium Discussion Questions: Why did some flames appear the wrong color at various times during the tests? What are some of the ...


    • [DOC File]Photoelectric effect 2

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      More advanced problems – many involving equations . Speed of light (c) = 3x108 ms-1 Planck’s constant (h) = 6.3 x 10-34 Js. Mass of an electron = 9x10-31 kg. 1. The maximum wavelength that can cause emission of electrons from a certain metal plate is 500nm. Find the maximum velocity with which electrons are emitted if light of 400 nm is incident on its surface. 2. If a sodium surface in a ...


    • [DOC File]Photoelectric Effect Practice Problems

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      Photoelectric Effect Practice Problems Name: AP Physics Period: 1. Basic wave theory predicted that a blackbody should put out more energy at higher frequencies. In reality, above the peak frequency a real blackbody emits less radiation with increasing frequency. Planck was able to explain this contradiction by assuming that light energy is quantized and that higher frequencies of light have a ...


    • [DOC File]Worksheet frequency/wavelength/Energy

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      h = Planck’s constant = 6.63 x 10-34 J-s ( = wavelength in meters ( = frequency in Hz (waves/s or 1/s or s-1. Draw a wave of light with high frequency Draw a wave of light with low frequency. How many Joules of energy are there in one photon of orange light whose wavelength is 630nm? (Work required) Violet light has a wavelength of 4.10 x 10-12 m. What is the frequency? If an X-ray machine ...


    • [DOC File]Practice Problems

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      h = Planck’s constant = 6.63 x 10-34 J-s ( = wavelength in meters ( = frequency in Hz (waves/s or 1/s or s-1) Title: Practice Problems Last modified by: Lindsay Parson Created Date: 5/24/2016 10:43:00 AM Company: Education Other titles: Practice Problems ...


    • [DOC File]Photoelectric effect 2 - schoolphysics

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      More advanced problems – many involving equations . Speed of light (c) = 3x108 ms-1 Planck’s constant (h) = 6.3 x 10-34 Js. Mass of an electron = 9x10-31 kg. 1. The maximum wavelength that can cause emission of electrons from a certain metal plate is 500nm. Find the maximum velocity with which electrons are emitted if light of 400 nm is incident on its surface. 2. If a sodium surface in a ...


    • [DOCX File]Planck’s Equation Practice Problems

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      Planck’s Equation Practice Problems . Equations and constants: E = h and E = hc/E = energy of one photon with a frequency of . c = f c/ = fc = speed of light = 3.0 x 108 m/s (meters per second) h = Planck’s constant = 6.63 x 10-34 J-s = wavelength in meters. f = frequency in Hz (waves/s or 1/s or s-1)n = number of photons (energy level) A photon has a frequency of 2.68 x 106 Hz. Calculate ...


    • [DOC File]Photoelectric effect

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      Speed of light (c) = 3x108 ms-1 Planck’s constant (h) = 6.63 x 10-34 Js. Mass of an electron = 9x10-31 kg. 1. What is the photoelectric effect? 2. What property must the incoming radiation have to cause photoelectric emission from a surface? 3. What property of the incoming radiation determines the energy of the emitted photoelectrons? 4. What property of the incoming radiation determines ...


    • [DOCX File]Practice Problems - Manchester High School

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      Practice Problems . Chem-432. A photon has a frequency of 2.68 x 106 Hz. Calculate its energy. Ans: E = 1.78 x 10 -27. J. Calculate the energy (E) and wavelength of a photon of light with a frequency of 6.165 x 1014 Hz.Ans: E = 4.1 x 10-19 J = 4.87 x 10-7 m. Calculate the frequency and the energy of blue light that has a wavelength of 400 nm (h = 6.62 x 10-34 J-s).Ans: = 7.5 x 1014 HzE = 4.97 ...


    • [DOC File]Physics 201: Experiment #2 The Photo-electric Effect

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      where h is Planck’s constant, is the frequency of the light, λ is the wavelength of the light, and c is the velocity of light in vacuum. Following this assumption, the photoelectric effect is then the result of each photon transferring its entire energy to an electron in the metal. [It is possible for only part of the energy to be transferred (Compton effect) or for multiple photons to be ...


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