Planet orbital period calculator

    • [DOC File]Astro 18 - Planets and Planetary Systems - Winter 2002

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      (Hint: The numerical calculations for this problem are so simple that you will not need a calculator.) a) Imagine another solar system, with a star of the same mass as the Sun. Suppose there is a planet in that solar system with a mass twice that of Earth, orbiting at a distance of 1 AU from the star. What is the orbital period of the planet?

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    • [DOC File]Determining Planet Properties

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      Clicking on the planet's name will bring up the full fact sheet for that planet. The important properties are given in the table. Formulae. Planet mass = (4 2/G) × [distance3/(moon's orbital period)2] - moon's mass. The moon's mass can usually be ignored. Planet diameter = 2 × (distance to the planet) × (planet's angular size in degrees)/360°.

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    • [DOC File]Student Exploration Sheet: Growing Plants

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      Analyze: What happens to the period as the orbital radius increases? _____ _____ Calculate: Kepler discovered a very interesting relationship between the cube of each planet’s orbital radius and the square of its period. Use a calculator to find the cube of each planet’s orbital radius, and record these values in the “R 3” column of the ...

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    • [DOC File]Student Exploration Sheet: Growing Plants

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      Which planet has the longest Rotation (Day/Night cycle) _____ Calculate: Kepler discovered a very interesting relationship between the cube of each planet’s orbital radius and the square of its period. Use a calculator to find the cube of each planet’s orbital radius, and record these values in the “R 3” column of the table.

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    • [DOCX File]walterfreeman.github.io

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      Period: How long it takes the planet to go around its star Eccentricity: A measure of how ``stretched-out'' an ellipse is. The minimum value is 0 (this is just a circle); the maximum value is 1.Eccentricity can be calculated from perihelion and aphelion distances as e = a+p a-p Note that the computer will do this for you; you won’t need to do ...

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    • [DOC File]Lick Observatory

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      What (approximately) is the orbital period of this planet? Explain your answer. Answer: The orbital period of the planet would be approximately the same as that of the earth (1 year). Kepler's law considers only the sum of the object masses. In comparison with the mass of the star, the mass of the planet can be neglected.

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    • [DOC File]Student Exploration Sheet: Growing Plants

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      The path of each planet around the Sun is determined by two factors: its current . velocity (speed and direction) and the . force. of . gravity. on the planet. You can manipulate both of these factors as you investigate planetary orbits in the Orbital Motion – Kepler’s Laws Gizmo™. On the CONTROLS pane of the Gizmo, turn on . Show trails ...

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    • [DOC File]MATH HELP SHEET - Lawrence University

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      Where P is the orbital period of a planet about the Sun (measured in years) and a is the semi-major axis of the planet’s orbit (measured in AU’s—the average distance between the Earth and the Sun). The semi-major axis is basically the average distance a planet is from the Sun. ... (try it with a calculator: the sine of 1 radian is 0.84 ...

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    • [DOCX File]northstarscience.weebly.com

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      Kepler discovered an interesting relationship between the cube of each planet’s orbital radius and the square of its period. Use a calculator to find the cube of each planet’s orbital radius and record these values in the R3 column of the data table in Observation question 5.

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