Q1 median q3
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minimum < Q1 < median < Q3 < maximum 6 < 7.25 < 10.5 < 12.75 < 14 2.7 Find the measures of central tendency for the number of imperfections in a sample of 50 bolts
[DOC File]1
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Write a statement about Q1,Q3, Median, and the Mean. Boys: Girls: ̅ x = 9.6 . ̅ x = 13 Q1 = 7 Q1= 10 median = 9 median= 12.5 Q3 = 12 Q3= 16The mean number of shoes is higher for girls than for boys. The Q1 and Q3 for girls . is. higher than the Q1 and Q3 for boys. The median for girls is higher than the median …
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Variable N Mean SE Mean StDev Minimum Q1 Median Q3 Maximum Damage 50 22.39 3.60 25.45 0.00 2.23 12.66 41.63 88.60 Give the five-number summary, …
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First Quartile = Q1 = median of observations that fall below the median. Third Quartile = Q3 = median of observations that fall above the median. Notes When the number of observations is odd, the middle observation is the median. This observation is not included in either of the two halves when computing Q1 and Q3.
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The first quartile Q1 is the 25th percentile, 25 percent of the observations in a list are smaller than Q1. The second quartile, Q2 is the 50th percentile, or the median. About half the data are less than this value Q2. The third quartile, Q3 is the 75th percentile, about 75 percent of the observations are below this value Q3.
Interpret all statistics for Boxplot - Minitab Express
Q3 = the upper quartile. We can estimate Q1, Q2, Q3 from the cumulative frequency and calculate them with the formula. Median corresponds to the 50th percentile, Q1 corresponds to the 25th percentile, Q3 corresponds to the 75th, i.e. Q2 = P50 , Q1 = P25 , Q3 = P75 . By Formula (The Median = median = the lower boundary of median = the sum of data
[DOC File]1 - Franklin Township Public Schools
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Lower Quartile(Q1 ): The smallest 25% of the data. It can also be computed finding the median of the smallest n/2 observations if n is even and median of the smallest (n+1)/2 observations if n is odd. Your textbook calls this as lower fourth. Upper Quartile(Q3 ): The smallest 75% of the data.
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