Static equilibrium equations lever

    • [DOC File]Chapter 9

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      Jul 12, 2012 · equilibrium. a rigid body is in equilibrium if the net force and net torque acting on the body are . both zero. lever arm or moment. the distance between the line of action of a force acting on a body and the axis of . rotation. torque. the vector product of a force acting on a body and the lever arm at which it acts. Equations and Symbols ...

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    • [DOC File]THINGS TO DO WORK

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      5. Write and solve equations of static equilibrium* for diagram drawn in step 4. From geometry : FDEx=FDEcos =0.832FDE. FDEy=FDEsin =0.5546FDE. where : Fy=0=4.417-FDEy=4.417-0.5546FDE. FDE=7.963 kips (COMPRESSION) Ans. (3 pts for determining FDE) 6. Move to an adjacent joint and repeat steps 4-5 until entire truss is solved

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    • [DOC File]Statics—the investigation of forces

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      C. For static equilibrium, a truss must meet the following two conditions: 1. The forces at each joint (or nodal point) must sum to zero. 2. The moments about any joint must sum to zero. D. Analyzing forces within a simple truss ABC with equal-length sides, load F at node C, and support at nodes A and B: Sum of the moments about A yield

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    • [DOC File]Static Equilibrium of Rigid Bodies: Torques

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      where d is the lever arm, which is the perpendicular (shortest) distance between the axis . of rotation and the line of force. Static Equilibrium: In order for a rigid body to stay in equilibrium, the net force and the net torque on the object must both be zero.

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    • [DOCX File]Physics 12: Torque and Static Equilibrium Worksheet

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      Physics 12: Torque and Static Equilibrium Worksheet, What a Treat! 1. Two forces are acting on a lever, both to the right of the pivot. If the sum of their two torques is zero, and neither force is parallel to the lever, what must be true? (more than one may apply) a. Both forces point in the same direction. b. The forces point in opposite ...

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    • [DOC File]Lecture 4﷓1 ﷓ Equilibrium of Rigid Bodies STUDENT …

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      Equilibrium of a Rigid Body in Two Dimensions Figures 4.2 and 4.3: 1. For a two dimensionsal system, the equations of equilibrium are. simplified by the following: Fz = 0 Mx = My = 0. 2. Thus we are left with the following three equations of equilibrium: Σ Fx = 0 Σ Fy = 0 Σ Mz = 0. 3.

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