T statistic significance level 2
[DOC File]1
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It was decided to use a level of significance of a = 0.02 to decide whether or not to reject the null hypothesis. The sample data produced a standard deviation of s = 15.6 based on 12 sample values. ... The t statistic for comparing the mean prices is 2.1. What can we say about the value of the P-value? A) P-value < 0.01 B) 0.01 < P-value < 0.05.
[DOC File]Example SPSS Output for T-Test for Difference in Means
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The p-value is labeled as “Sig.” in the SPSS output (“Sig.” stands for significance level). To find the correct “Sig.”, look in the section of the “Independent Samples Test” output labeled “t-test for Equality of Means” and you will find a column labeled “Sig. (2-tailed).” This is the correct column, not the column ...
[DOC File]Hypothesis Test for a Population Mean
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Significance Level: = .05. Test Statistic: t = Rejection Region: For =.05, we reject H0 if t > t where t = 1.671. Calculations: t == 2.93. Conclusion: Using =.05 we reject H0. There is sufficient evidence to conclude that the mean life for the new brand of bulbs is greater than 900.
[DOC File]CHAPTER 11
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This is very little evidence against H0; the null is not rejected at any reasonable significance level. (iii) The t statistic for is about 2.11, and the two-sided p-value is about .04. Therefore, the null is rejected at the 5% level, although it is not much stronger than that. (iv) The joint test underlying Okun’s Law gives F = 2…
[DOC File]CHAPTER 2
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The critical region for significance level .05 and sample size 400, under a one-tailed alternative, is given by: P[t399 > 1.645] = .05. Since our calculated t-value falls into the critical region, we can reject the null hypothesis at the 5% level of significance. c) The calculated value of our t-statistic would now be:
[DOC File]2-sample t-test
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Step 2: significance level is usually taken to be =0.05. Step 3: test statistic = Step 4: p-value = Step 5: Conclusion: Since the p-value < significance level, we reject and conclude that Ginkgo does improve the memory score. 1 5
[DOC File]Answer Key : Practice Final Examination
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With the p-value 0.006 and the significance level 0.01, we conclude that customers who use the Q-Mart card charge, on average, more than those who use another charge card, i.e., Reject H0 at = 1%. Notice that the reported t-statistic 2.925 means that the difference in the two sample means is 2.925 standard deviations above the hypothesized ...
[DOC File]The Practice of Statistics
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one-sample t statistic. two-sample t statistic. robust. power. pooled Calculator Skills: normalpdf (X) tpdf (X, df) ShadeNorm (leftendpoint, rightendpoint) Shade_t (leftendpoint, rightendpoint, df) TInterval. T-Test. 2-SampTTest. 2-SampTInt 12.1 Tests About a Population Mean. Under what assumptions is s a reasonable estimate of ? In general ...
[DOC File]Chapter 7 Section 2
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(a) A significance test for comparing two means gave t = -3.69 with 9 degrees of freedom. Can you reject the null hypothesis that the (’s are equal versus the two-sided alternative at the 5% significance level? P(t < -3.69) = 0.0025. Thus, the p-value = 2(0.0025) = 0.005 Yes the result is significant at 5%.
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