Water specific gravity lb ft3
[DOC File]CE 170: Environmental Engineering
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P = power (ft-lb/s) n = rotational speed (rev/s) D = diameter of paddle (ft) ( = specific weight of water (lb/ft3) g = acceleration due to gravity (32.17 ft/s2) KT = empirical constant = 2.4 for Phipps and Bird jar test mixer used in this lab (KT was calculated from data provided by Phipps and Bird.)
[DOC File]Chapter 2
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Specific gravity: ; Specific gravity = 0.75 *15-22. A 20-g piece of metal has a density of 4000 kg/m3. ... Seawater has a weight density of 64 lb/ft3. This water is pumped through a system of pipes (see Fig. 15-23) at the rate of 4 ft3/min. Pipe diameters at the lower and upper ends are 4 and 2 in., respectively. The water is discharged into ...
[DOC File]Conversion Sheet Page 1 - California State Water Resources ...
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1 cubic foot of water weighs 62.3832 lb. 1 gallon of water weighs 8.34 lb. 1 liter of water weighs 1,000 gm. 1 mg/L = 1 part per million (ppm) 1% = 10,000 ppm. ft2 = square feet and ft3 = cubic feet. 1 mile = 5,280 feet (ft) 1 yd3 = 27ft3 and 1 yard = 3 feet. 1 acre (a) = 43,560 square feet (ft2) 1 …
[DOC File]CE 319F, Elementary Fluid Mechanics
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The specific gravity of mercury is 13.55. Take the specific weight ( ) of water at 4oC (39.2oF) as 9810 N/m3 or 62.4 lb/ft3. SI units English units Hg = patm = Note that patm is not equal to standard atmospheric pressure. Now calculate air. Recall that pa = RTa, where the sub-a indicates absolute.
[DOC File]PRESSURE
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The standard density for water is 1.00 g/cm3 which occurs at 3.98 ºC D4º = 62.4 lb/ft3 = 9810 N/m3 and 4º = 1.00 g/cm3 = 1000 kg/m3 = 1.94 slug/ft3 Standard Atmospheric Pressure at sea level is: 14.696 lb/in2 = 2116 lb/ft2 = 1.01325 105 N/m2 (Pa) = 1.01325 106 dyn/cm2 = 101.325 kPa = 1 atm = 760 mmHg.
[DOC File]Set #1 - CCSF
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Specific weight of fresh water is 62.4 lb/ft3 (1000 kg/m3) Specific weight of concrete is 150 lb/ft3 (2400 kg/m3 ) answer: a) H = 10.11 kips to the right V = 79.8 kips upward
[DOC File]WordPress.com
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where Asis the cross-sectional area of stem, S – specific gravity of the liquid. 55. For a hydrometer, derive a formula for the float position h as a function of the specific gravity, the weight of the hydrometer, the diameter of the stem, and the specific weight of pure water. h …
[DOC File]California State University, Northridge
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The specific weight of the top fluid is found by multiplying its specific gravity of 0.8 times the specific weight of water water= 9.80 kN/m3 from Table 1. on the inside front cover. This gives top = 7.84 kN/m3.
[DOCX File]Dr Jorge Ibarra
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A flowrate measuring device is installed in a horizontal pipe through which water is flowing. A U-tube manometer is connected to the pipe through pressure taps located 3 in. on either side of the device. The gage fluid in the manometer has a specific weight of 112 lb/ft3.
[DOC File]California State University, Northridge
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For both the initial water and the second fluid with a specific gravity of 1.10, the weight of the hydrometer, W, is balanced by the buoyant force which is the specific gravity of the fluid times the submerged volume of the hydrometer. The difference between these two volumes is 6.73x10-4 ft3 – 6.12x10-4 ft3 = 0.61x10-4 ft3.
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