Y 3x 3 x 7 x

    • [PDF File]HOMEWORK SOLUTIONS MATH 114 1 Solution. - University of California ...

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      3. Find the Galois group of x6 −3x2 +1 over Q. Solution. Let y = x2. Then y is a root of y3 −3y + 1, whose Galois group is Z3. Consider three roots α1,α2 and α3 of y3 −3y +1. Then ± √ α1,± √ α2,± √ α3 are the roots of x6 − 3x2 + 1. Now note that α 1,α2,α3 are real, their sum is zero and their product is −1. Therefore ...


    • [PDF File](3x+3)(6x () x2 −2x - University of Alaska Southeast

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      6. Solve: logx 9 =2 7. Graph: h()=log3x 8. Use the properties of logarithms to expand as much as possible: y 3 log4 9. How long will it take $850 to be worth $1,000 if it is invested at 12% interest compounded quarterly? X. Systems of Equations & Matrices 1. Solve the system: 6 1 2 3 7 −= + = x y x y 2. Solve the system: 0 2 3 6 2 2 2 3 − ...


    • [PDF File]Factoring and solving equations - Wellesley College

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      Now sub. x = 0, x = 2 into one of y=3-2x the given equations ( y = 3 - 2x is easier) to get y 's : x=o x=2 y=3-x 2 y=3-2(0) = 3 y=3-2(2)=-1 - The points of intersection are (0,3) and (2,-1) . (2,-1 krcises 11 C Solve the following systems of equations. 1. -x + y = -1 2. 3x + y = 10 3. y=3-x 2 x+y= 3 4x + 5y = -16 y = -2x 4. 3x + 5y = 11 5. x=5-y2


    • [PDF File]y = 3x (x + 4) (x ­ 2) (x ­ 5)

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      y = 3x3(x + 4)2(x ­ 2)3(x ­ 5)4. b 07 graph poly.notebook May 14, 2019 X XXXX X X Last day Mr. Seymour will collect old work and test/quiz ... y = ­2x5(x + 1)2(x ­ 6)(x ­7)3 will hit the x­axis. b 07 graph poly.notebook May 14, 2019 Everyone take out a half sheet of ...


    • [PDF File]1 INTERMEDIATE ALGEBRA READINESS DIAGNOSTIC TEST PRACTICE Directions

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      3x y. −. x y = 3x−x y = 2x y. Problems 1-5: Find the sum or difference as indicated (reduce if possible): 3. 1. 4 7 + 2 7 = 4. x+2 x. 2 +2x. −. 3y. 2. xy. 2 = 2. 3 x−3. −. x x−3 = 5. 3a b + 2 b. −. a b = 3. b−a b+a. −. a−b b+a = If denominators are different, find equivalent fractions with common denominators: Problems 11-16 ...


    • [PDF File]Handout - Derivative - Chain Rule Power-Chain Rule

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      3x + 26 a = 7 u = 3x+26 ⇒ du dx = 3 ⇒ y0 = 7 3x+26 ·3 Ex3e. Find the derivative of y = 8ln 2x2 +9x+26 Answer: y0 = 8(4x + 9) 2x2 + 9x + 26 a = 8 u = 2x2 +9x+26 ⇒ du dx = 4x+9 ⇒ y0 = 8 2x2+9x+26 · 4x+9 Ex3f. Find the derivative of y = 7log 9x5/2 +5x5/3 Answer: y0 = 7 · 45x3/2 2 + 25x2/3 3 · 1 9x5/2 + 5x5/3 a = 7 u = 9x5/2 +5x5/3 ⇒ ...


    • [PDF File]Exercise Set 1.1 1. y = 2x + 4 2. y = -3x 3. y = -2 4. y = ½x + 1/4 5 ...

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      43. (a) y = -6/5 (b) x = 3 44. (a) y = -6 (b) x =-14 45. y = 1, y = -7 46. x = 8, x = -4 47. no slope 48. 7/5 49. -8/5 50. 0 51. no slope 52. ½ 53. -7 54. 24 55. -2 56. 0 57. no slope 58. 4/7 59. x = 1 60. 7x - 5y = 59 61. 8x + 5y = 0. 62. y = 4 63. x = 12 64. y = ½x + 3 65. 14x + 2y = 3 66. y = 24x-9 67. y = -2x 68. y = -5 69. x = ½ 70. 71 ...


    • [PDF File]CHAPTER Solutions Key 3 Linear Systems

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      3a. 7x y = 11 3y = 21x + 33 y = 7x + 11 y = 7x + 11 consistent, dependent; infinite number of solutions b. x + 4 = y 5y = 5x + 35 y = x + 4 y = x + 7 inconsistent; no solution 4. Step 1 Write an equation for costs with each calling card. [then “Let x represent....” ending with “Card B”


    • [PDF File]Standard Form of Linear Equations (A) - Math-Drills

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      1. 9y 9x = 1 2. x 7 = y 3. 9x = 3+9y 4. 8y = 9x+9 5. y = 7+5x 6. 3y x = 9 7. 2x = 7y 8 8. y +3x = 9 9. 4x = 9 7y 10. 9 = 9x+y Math-Drills.com. ... 7. 3 = 3y +3x 8. x = 2y +2 9. 4+2y = 7x 10. 7y 4x = 8 Math-Drills.com. Standard Form of Linear Equations (G) Answers Write each equation in standard form. Identify the values for A, B and C.


    • [PDF File]KEYS TO CALCULUS PRIMER PROBLEMS dY/dX = -3X =3/X

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      dY/dX=1 /3*( X-.33 -1 )= 1/3*(X-1.33 )= 1/3X 1.33 1.7) Y=e-x dY/dX= e-x 1.8) Y=ln X dY/dX =1/X 1.9) Y=8x*9x 2 dY/dx=8x * 18x + 8* 9x 2 = 144 x 2 + 72 x 2 = 216 x 2 1.10) Y=4X/3X 2 dY/dX= -4* 3X 2 -4X*6X = -12/9X 2= -4/3X 2 (3X 2) 2 1.11) Y=100x 3-6x 2 dY/dX =300X 2-12X


    • [PDF File]Practice problems — Solutions - University of Illinois Urbana-Champaign

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      The profit for a new product is given by Z = 3X−Y −5, where X and Y are independent random variables with Var(X) = 1 and Var(Y) = 2. What is the variance of Z? ... Given that E(X) = 5, E(X2) = 27.4, E(Y) = 7, E(Y2) = 51.4 and Var(X + Y) = 8, find Cov(X +Y,X +1.2Y). Solution: By definition,


    • [PDF File]Algebra Name 3.1 K System of Equations Date

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      16) Edwin drove 261 miles from city X to city Y in 4.5 hours. He continued driving at the same average speed and drove another 145 miles from city Y to city Z. What is the total amount of time Edwin spent driving from city X to city Z? A) 4.9 hours B) 6.3 hours C) 7 hours D) 9 hours


    • [PDF File]G.SRT.A.1: Line Dilations

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      1) 3x−4y =9 2) 3x+4y =9 3) 4x−3y =9 4) 4x+3y =9 18 The equation of line h is 2x+y =1. Line m is the image of line h after a dilation of scale factor 4 with respect to the origin. What is the equation of the line m? 1) y =−2x+1 2) y =−2x+4 3) y =2x+4 4) y =2x+1 19 The line y =2x−4 is dilated by a scale factor of 3 2 and centered at the ...


    • [PDF File]7.3 Volumes of Revolution: the Shell Method - Battaly

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      7.3 Volumes of Revolution: the Shell Method Homework Part 2 Consider: y = x3 ­ 3x + 3, x = 0, y = 0, x = 2 1 2 3 Could divide into 3 regions. For Region 1: We have x, but we need an integrand to match the dy. Title: match variable in integrand (5 of 16)


    • [PDF File]MA 109 College Algebra Name: Sec.: EXAM 3 - REVIEW 1. In the picture ...

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      13. Suppose that the graph of y = f(x) contains the point (-2,7). Find a point on the graph of y = 5f(x+3). 14. Let P(x) = 4x2 +3x+35. Find the y-intercept of the graph of y = P(x). 3. 15. Find a formula for the parabola with vertex (6,−1)and that passes through the point (7,−4). 16.


    • [PDF File]MATH 171 - Derivative Worksheet Differentiate these for fun, or practice ...

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      x. −− = −. 7. 3 3274 2 x x x fx x − +− = 8. 27 3 2 58 3 x x hx x x + − = −. 9. sx x x( ) 2 sec( )= −3 10. f x xe() 3= 4 x. 11. f x xe() 7=−3x 12. fx x x() 5 cos()= 2. 13. hx e x() 2= x 14. f x x x xe() 4 5 2= − +43 2 x. 15. 2 tan( ) 21 x fx x = + 16. sin( ) x 5 x gx e = + 17. 2 32 3 xx fx x −+ = + 18. 2 2 x x e fx xe = − ...


    • [PDF File]STAT515, Review Worksheet for Final Exam 1. - UMass

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      3 2. (1) Suppose that Xhas density function given by f(x) = (2x; 0 x 1; 0; elsewhere: Find the probability density function for Y = eX. Solution. Note that the function y= ex is strictly increasing and hence invertible, and its inverse is given by x= h(y) = lny.


    • [PDF File]Calculus I, Homework 5 Solutions, 2/9/7 - University of Pittsburgh

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      { For y = f(x), the slope at x = 2 of the tangent line is f0(2) = 3 and the line goes through the point of tangency, (2;f(2)) = (2;3), so the equation of the tangent line is: y 3 = 3(x 2) = 3x 6; y = 3x 3: { For y = g(x), the slope at x = 2 of the tangent line is g0(2) = 1 and the line goes through the point of tangency, (2;g(2)) =


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