1 to 200 dilution calculation
[DOC File]Dilution of Solutions
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Step 1) Calculate the mass of sodium hydroxide required. Step 2) Add ~800 mL of COLD distilled water to a 1.0 liter volumetric flask. Step 3) Carefully, wearing safety goggles and rubber gloves, add 200 g of NaOH to volumetric flask. Step 4) Rinse the NaOH powder off the neck of the volumetric flask with distilled water from a squirt . bottle.
[DOC File]Jillian Burrows - Claremont Colleges
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1:100 Dilution 1:200 Dilution Dr. Smith’s Calculations (1:100) A260 1.313 1.304 1.695 A280 0.671 0.639 0.829 Table 1: These numbers indicate the A260 and A280 numbers for each of the different dilutions of the genomic DNA.
[DOC File]QUALITY ASSURANCE MANUAL
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Add 1-2 mL of starch solution and continue to titrate to first disappearance of the blue color. .(200 mL of original dilution water is equal to 201 mL of dilution water plus …
[DOC File]DILUTIONS AND STANDARDS
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For example, a 1:2 serial dilution is made using a 1 mL volume of serum. This expression indicates that 1 mL of serum is added to 1 mL of H20 and then mixed. This initial dilution is 1:2. Then, 1 mL of this dilution is added to 1 mL of H20 further diluting the sample. This same process is continued.
[DOC File]Determination of Biochemical Oxygen Demand (BOD5)
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5. Transfer 203 ml of sample into a white 500 ml casserole dish and titrate with 0.0250N sodium thiosulfate to a pale straw color. Add 1-2 ml of starch solution and continue to titrate to first disappearance of the blue color. (200 ml of original dilution water is equal to 203 ml of dilution water plus reagents.) Titrate two of the three samples.
[DOC File]Materials & Methods
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1:5 dilution, so final concentration = 0.965 × 5 = 4.83 mg/ml. Total amount of protein = concentration × volume of CE = 4.83 × 8.5 = 41.1 mg. Appendix 2 – Activity Calculations and Formulas. A: Specific Activity Sample Calculation. Absorbance of 0.1 ml 1:200 CE (4.83 mg/ml) dilution = 0.5617. Molar extinction coefficient of ONP = 4800 M-1 cm-1
[DOCX File]WORKSHEET ON SOLUTION CONCENTRATIONS
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200 mL of 0.8 M sodium carbonate solution. 300 mL of 4 M sodium hydroxide solution. How many grams of NaOH must be used to make 250 mL of a 1.842 M solution of NaOH? a. Start with what you know, the final volume and concentration of the solution. Arrange these factors to calculate the . moles . of . NaOH . needed. b. Change moles of NaOH to ...
[DOC File]Colony Count Calculations
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1 in 100 dilution (99 + 1 = 100) or. Dilution factor of 100 or. 10-2 dilution ( 1 ( 100 = 0.01 = 10-2) Colony information : 1/10 ml of the dilution was plated = 142 colonies grew. To calculate the CFU per 1/10 ml in the original sample: Multiply the no. of colonies by the dilution factor or. 142 x 100 = 14 200. colonies. Divide by the dilution ...
[DOC File]Calculations
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Step 1: To make up 200 mL of the anhydrous sodium citrate you need to weigh out 10 g (5 % (w/v) is 5 g/100 mL and you have 200 mL). Step 2: How many moles of citrate does this represent? It is 10/(294 – 36) = 10/258 = 0.0387 moles.
[DOC File]Iris Automated Urinalysis: iQ® 200 Analyzer SW 7.0 Template
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Urine Dilution Code labels [800-3211] Room temperature 1 set; 1 each/test as needed. Use as needed. 16x100mm glass tubes [660-0036] or polystyrene plastic tubes Room temperature Box of 200; 1 each/test. Use daily. Sample Patient Preparation: Give patient instructions to collect a “clean catch” urine specimen in a clean and/or sterile container.
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