ࡱ> GIF7 0bjbjUU *{7|7|%l ( ( (  ppp8Ld 7d```vZZZ....A^.T2T7$8 ;N*7u( Z88"ZZ*7, `v7, , , Z ` 8`., Z., , &VW-@  .`X x pB- .707-xc;&c;., < J 6  Experiment 10PRIVATE  Moment of Inertia A rigid body composed of concentric disks is constrained to rotate about its axis of symmetry. The moment of inertia is found by two methods and the results are compared. In the first method, the moment of inertia is determined theoretically by applying the formula for the moment of inertia of a single disk to each of four disks and adding the results. In the second method, the moment of inertia is determined experimentally by measuring the acceleration produced by a constant torque on the body.  seq Figure \* Arabic1Figure 1. The body consists of four concentric disks. The experimental determination of the moment of inertia is only valid if friction is negligible. In Part III of the experiment, an estimate of the angular acceleration due to friction is obtained. The validity of the above approximation is the examined. Theory, Part I Consider a pulley made of four disks. The moment of inertia of a homogeneous disk about the axis of symmetry is EMBED Equation.3 seq Equation \* Arabic1 where M is the mass of the disk and R is the radius. The moment of inertia of a rigid system of concentric disks is then EMBED Equation.3seq Equation \* Arabic2 (1) where the sum extends over all disks, each of which has mass Mi and radius Ri. If the mass density, r, is uniform (i.e., constant throughout the body), the mass of each disk is given by EMBED Equation.3 seq Equation \* Arabic3 where Vi is the volume of each disk and wi is the width. Substituting this into (1), the moment of inertia of each disk is then EMBED Equation.3seq Equation \* Arabic4 (2) and the total theoretical moment of inertia of the rotating body is EMBED Equation.3seq Equation \* Arabic5 (3) If the density together with the width and the radius of each disk are known, then the moment of inertia of the body can be computed. The moment of inertia determined in this manner will be referred to as the theoretical value (Itheo).  seq Figure \* Arabic2 Figure 2. Experimental determination of moment of inertia. Theory, Part II The experimental value of the moment of inertia can also be found by exerting a constant torque on the body. A mass, m, is attached to a string which is wrapped around the body at some radius, R. (Refer to Figure 2.) R will be one of the disk radii, Ri. If m is released from rest and falls a distance, d, during a time, t, the acceleration of m is given by EMBED Equation.3seq Equation \* Arabic6 (4) Once the value of the acceleration is known, the moment of inertia is determined by EMBED Equation.3seq Equation \* Arabic7 (5) assuming that friction in the supports is negligible. Theory, Part III A rough measure of friction in the supports can easily be found. Suppose the body (without the mass) is initially spun and N revolutions occur during the time TN required for the body to come to rest. Assuming the angular acceleration due to the resistance is constant, its magnitude is then given by EMBED Equation.3seq Equation \* Arabic8 (6) This should be approximately true for the apparatus. The expression (6) represents, in reality, the average value of the angular acceleration due to friction. The magnitude of the average resistive torque due to friction in the supports is tf =Iaf. Including this torque in the derivation of the experimental moment of inertia (5), the corrected result is EMBED Equation.3seq Equation \* Arabic9 (7) This is assuming the resistive torque is constant. In the experimental determination of the moment of inertia, when m is attached to the body, the resistive torque will have an additional contribution that is proportional to the tension of the string, which connects m to the body. This contribution is negligible, however, if m< MM9 #dy=#&`$d%d&d'd+Dd.</xNOPQ $ 0da$4:dy=#&`$d%d&d'd+D.</xNOPQ8 dy=#&`$d%d&d'd+D.</xNOPQ     6 7 8 9 >   ֿἬֿ|pka5@CJ\aJ@CJ<@CJmHnHu <@CJj<@CJU jf@U 6@H*] 6@]>*@ j@Uj;p? CJOJQJUVaJ@0J;@0J;<@mHnHu 0J;<@j0J;<@U j@U jC@Uj;p? CJOJQJUVaJ&  9 dy=&`$d%d&d'd+D.</xNOPQ $ 0da$!:$ 0dyt&`+D.x/]^a$$ 0dyt&`+D.x/a$ ,"#PQbcyz#$%&'>?@AF~ 123¼°«¼°«5@CJ\aJ j@Uj;p? CJOJQJUVaJ0J;@0J;<@mHnHu 0J;<@j0J;<@U j@Uj;p? 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