ࡱ> }a Ubjbj:K:K K(X!H\X!H\%R!R!R!R!R!f!f!f!8!\"df!@]$^%R(((((T1T1T1#\%\%\%\%\%\%\$d_bzI\R!T1T1T1T1T1I\R!R!((|\999T1R!(R!(#\9T1#\99wPXS(p{3RQ(\]0@]Q$b,4bPSS\bR!wST1T19T1T1T1T1T1I\I\07T1T1T1@]T1T1T1T1bT1T1T1T1T1T1T1T1T1>  : 1MA1 Practice papers Set 3: Paper 3H (Regular) mark scheme Version 1.0 QuestionWorkingAnswerMarkNotes1.(a)  1, 0, 1, 2, 32B2 for all 5 values and no extras (ignore repeats) (B1 for 4 correct values and no extras or all 5 correct values and one incorrect value)(b)x + x + 9 < 60 2x < 51 x < 25.5253M1 for x + x + 9 oe A2 cao (A1 for 25.5) OR M1 for 60 2 (=30) and 9 2 (=4.5) A2 cao (A1 for 25.5) OR M1 for 60 9 (=51) and 51 2 (=25.5) A2 cao (A1 for 25.5) OR M1 for at least 2 trials with correct totals A2 cao (A1 for correct trial of 25 and 26)2.bisector 2M1 for an appropriate pair of arcs or correct line drawn without construction arcs A1 for perpendicular bisector of AB drawn with a pair of construction arcs3.4x + 3y = 695 5x + 2y = 720 8x + 6y = 1390 15x + 6y = 2160 7x = 770 x = 110 y = 85Coffee 1.1(0) Tea 85p5M1 for attempt to use variables for cost of cup of tea and cost of a cup of coffee. A1 for correct equations : 4x + 3y = 695 and 5x + 2y = 720oe M1 for correct process to eliminate either x or y (condone one arithmetic error) could be by multiplication of both equations and then addition/subtraction or by manipulation of one equation and then substitution into second equation M1 (dep) for substituting found value into either equation A1 for correct answers with units4.304M1 for Y: 600 5 3 oe (= 360) M1 for R: 600 25 100 oe (= 150) M1 (dep on M2) for (600 360 150) 2 150 oe A1 cao OR M1 for Y: 3 5 100 (= 60%) M1 for G: 100   60  25 (= 15) and  15 100 600 (= 90) M1 (dep on M2) for  90 2 " 150 A1 cao OR M1 for  EMBED Equation.3  oe M1 for  EMBED Equation.3  M1 (dep on M2) for  90 2 " 150 A1 cao5. 2.5  EMBED Equation.3 2 M1 for 2 500 000 oe e.g. 25  EMBED Equation.3  e.g. 0.25  EMBED Equation.3 or 2.5 10n or A  EMBED Equation.3  where 1 d" A < 10 A1 cao6. 5.323M1  EMBED Equation.3  used M1  EMBED Equation.3  OR M1 for  EMBED Equation.3  (5.704...) and  EMBED Equation.3  (28.298) M1 for  EMBED Equation.3  OR M1 for correct statement of Sine Rule eg  EMBED Equation.3  M1 for correct expression for x e.g.  EMBED Equation.3  A1 for awrt 5.32 (5.319587...)7.(a) (i){p,r,a}1B1 Withhold marks for repeats(ii){p,a,r,i,s,b,u,d,e,t}1B1 Withhold marks for repeats(b)E No letters common to Prague and Lisbon1B1 dep on E in a box Accept general reasons e.g. no letters common to sets A and E or they share no common letters or no intersection (between A and E) or no letters the same or no letters in A are in E. 8.(a) 21 90 = 1890  EMBED Equation.3 432M1 for  EMBED Equation.3  or 1890 seen A1 for an answer in the range 43 43.5 (b)50 =  EMBED Equation.3  2500 = 21d d = 2500 211193M1 for 50 =  EMBED Equation.3  oe or 502 M1 for 21d = 502 oe A1 for an answer in the range 119  119.059.14.43M1 for  6.52 11.5 (= 1526.42...) M1 (dep) for  EMBED Equation.3  A1 for 14.4  14.5 OR M1 for  EMBED Equation.3  or  EMBED Equation.3  or 0.89(23) or 1.12(06896) M1 for  EMBED Equation.3 or  EMBED Equation.3  A1 for 14.4 14.510. EMBED Equation.3  oe  EMBED Equation.3  40p > 28p OR e.g. 200 games 200 40p = 80  QUOTE   200 1 = 56 80 > 56Yes, with justification5M1 or  EMBED Equation.3  or  EMBED Equation.3  or  EMBED Equation.3  M1(dep) for  EMBED Equation.3  A1 for  EMBED Equation.3  oe M1 for  EMBED Equation.3  1 OR  EMBED Equation.3  n 1 and n 40p C1 f.t. (dep on M3) for correct conclusion with fully correct justification based on expected profit per game or expected profit for a particular number of games 11.36% depreciation3M1 for 0.8 0.8 (= 0.64) M1 for 1 0.64 (= 0.36) C1 for 36% (depreciation) oe or compares cost with 40% reduction OR (uses a trial value, e.g. 1000) M1 for 1000 (0.8)2 (= 640) M1 for (1000 640) 1000 (= 0.36) C1 for 36% (depreciation) oe or compares cost with 40% reduction OR M1 for 0.2 0.2 (= 0.04) M1 for 0.2 + 0.2 0.04 (= 0.36) C1 for 36% (depreciation) oe or compares cost with 40% reduction OR C1 only for identifying the 2nd 20% reduction is off the reduced amount at the end of the first year12.85.64M1 for 360 5 (= 72) M1 (dep) for  EMBED Equation.3  62 sin"72" (= 17.12) M1 for completing full method to find total area of pentagon A1 for 85.5 " 85.6 OR M1 for 360 10 (= 36) or  EMBED Equation.3 (180 " 360 5) (= 54) M1(dep) for e.g. 6 sin"36" 6 cos"36" (= 17.12) or  EMBED Equation.3  6 sin"54" 6 cos"54" (= 8.55) M1 for completing full method to find total area of pentagon A1 for 85.5 " 85.613.y = 2x " 14M1 for  EMBED Equation.3  oe M1 for  EMBED Equation.3 oe (= 2) M1(dep on previous M1) for using y =  2 x + c with their coordinates for the midpoint used correctly to find c A1 for y = 2x " 1 oe14.(a)  EMBED Equation.3 2M1 d = k c or 25 = k 280 A1 oe(b)202M1  EMBED Equation.3  A1 cao OR M1 25 280 350 oe A1 cao15.0.7 to 0.93M1 for drawing a tangent to the curve at 20 minutes M1 (dep) for  EMBED Equation.3  e.g.  EMBED Equation.3  A1 (dep on M1M1) for answer in range 0.7 to 0.9 (condone a negative answer)16.  Comparison of data2C1 for comparison of medians or stating the range or interquartile range are the same. Values stated must be correct. C1 for comparison relating the results in a context i.e. including the median and a measure of spread  With Without Median 1.8 kg 1.4 kg Range 1.1 kg 1.1 kg IQR 0.4 kg 0.4 kg 17.(a) 28.51B1 for 28.5 or 2850 cm or 28.499 or 28.49 or 28.49 recurring oe(b)2 (147.5 + 28.5)3523B1 for upper bound of length = 147.5 or 14750 cm or 147.49 recurring oe M1 for 2 (upper bound width + upper bound length) where these are not the given values. A1 cao 351.999 " 35218.  EMBED Equation.3  61 383 130281 51 240 000 " 49 897 623 = 13423771 300 0005M1 for correct method to work out 84% of 61 million e.g.  EMBED Equation.3  61 or digits 5124 seen A1 for 51.2(4) million oe M1 for 383 130281 or digits 4989....seen M1 (dep on at least 1 previous M1) for  51.24 "  49.89&  A1 1 300 000  1 350 000 oe 19. c = 60 + 90  2 60 90 cos130 c = 3600 + 8100  10 800  0.6427876 c = 11 700 + 6942.106 c = 18642.106 c = "18642.106 = 136.536 Perimeter = 60 + 90 + 136.536286.54M1 for substituting values correctly into cosine rule formula e.g. 60 + 90 2 60 90 cos130 M1 for correct order of evaluation A1 for finding value of missing side in range 136 to 137 A1 for answer in range 286 to 28720.F 90 126 144 120 60 543455M1 for use of F = FD Int width A1 for any 3 Fs correct M1 for  EMBED Equation.3  or  EMBED Equation.DSMT4  (= 288) M1  EMBED Equation.3 or  EMBED Equation.DSMT4  (= 57) A1 cao21.5(2x +1) = (4x + 5)(5x 1) 5(4x + 4x + 1) = 20x + 21x 5 20x + 20x + 5 = 20x + 21x 5 20x + 5 = 21x 5 x = 10x = 105M1 for intention to multiply each side by 4x + 5 M1 for attempt to expand (2x + 1)2 or 5(2x + 1)2 or (4x + 5)(5x 1), at least 3 out of 4 terms correct A1 for 20x2 + 20x + 5 or 20x2 + 21x 5 oe A1 for 20x2 + 20x + 5 = 20x2 + 21x 5 oe A"#$MNqruvwz      ӽӧӊӊzk[kLEzk[k h.hsmh:EhsmCJOJQJaJhdZhsm6CJOJQJaJhdZhsmCJOJQJaJh@hsm5CJOJQJaJ h.ht+hhM8Z5CJOJPJQJaJnH tH +hh^i5CJOJPJQJaJnH tH +hh t5CJOJPJQJaJnH tH +hht5CJOJPJQJaJnH tH +hh\5CJOJPJQJaJnH tH MNW_fkqruojZ$(($Ifa$gdsmFfkd$$IfTl4q44  t 0444 lap yt\T$(($Ifa$gd uyz{ $(($Ifgdsm$$(($Ifa$gdsm    1!!$(($Ifa$gdsmkd$$IfTl ֈNq49  t0444 laytsmT  " # . / 5 6 J K N O l o E F G J K L ཨ~o`QhKhKCJOJQJaJh.~hKCJOJQJaJh@hKCJOJQJaJh@hK5CJOJQJaJ h.hsm%h:EhsmB*CJOJQJaJph(h$zhsm5B*CJOJQJaJph%h$zhsmB*CJOJQJaJphh:Ehsm5CJOJQJaJh:EhsmCJOJQJaJh:Ehsm6CJOJQJaJ - 5 > A C W ^ l o  ! 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t0444 layt{t=T@-B-E-I-M-Q-T-W-[-]-~---7.>.$(($Ifa$gd{t= (($Ifgd{t=------------------ . ......jT?)j7 hH-h{t=CJEHOJQJUaJ+jlZ hH-h{t=CJOJQJUVaJ)jhH-h{t=CJEHOJQJUaJ+jkZ hH-h{t=CJOJQJUVaJ hH-h{t=CJEHOJQJaJhH-h{t=CJOJQJaJh{t=CJOJQJaJ%jhH-h{t=CJOJQJUaJ)j>hH-h{t=CJEHOJQJUaJ+jZ hH-h{t=CJOJQJUVaJ..).*.+.,.-.2.3.=.>.?.C.D.G.H.P.n.p.q.x.y.....ʵrcTBTTBTBTBTB"hh{t=6CJOJQJ]aJhh{t=CJOJQJaJh.~h{t=CJOJQJaJ"h.~h{t=5CJOJQJ\aJ h.h{t=hZ h{t=OJQJh{t=CJOJQJaJ%jhH-h{t=CJOJQJUaJ)j"hH-h{t=CJEHOJQJUaJ+jmZ hH-h{t=CJOJQJUVaJ hH-h{t=CJEHOJQJaJhH-h{t=CJOJQJaJ>.?.C.D.1$$(($Ifa$gd{t=kd%$$IfTlPֈNq49  t0444 laytH-TD.....// /;/m//// $(($Ifa$gd{t= (($Ifgd{t=.....................// /5/6/V/W/\/^/d/e/j/m/r/s/z/{////////////////////////////IJIJĢIJĢIJIJIJIJIJIJIJIJIJhIh{t=CJH*OJQJaJ"hIh{t=6CJOJQJ]aJhIh{t=CJOJQJaJ"hh{t=6CJOJQJ]aJh{t=CJOJQJaJhh{t=CJOJQJaJ@//// :=>³yq[H[;h"h\CJOJQJ%h\5B*CJOJQJ\^Jph+h"h\5B*CJOJQJ\^JphhfSh"I5h`5CJOJQJ\aJ"hc>hi5CJOJQJ\aJ"hc>ht5CJOJQJ\aJ h.h{t=hh{t=CJOJQJaJh?Ch{t=CJOJQJaJUh{t=CJOJQJaJhIh{t=CJOJQJaJ"hIh{t=6CJOJQJ]aJ1 for 10  National performance data from Results Plus Qu NoSpecPaperSessionQuTopicMax scoreMean % allALLA*ABCDE15MM22F1211Q24Solve inequalities5331.632.972.301.8022MB03H1511Q6Construction2521.032.001.251.551.310.790.7035AM11H1306Q21Simultaneous equations5693.474.984.904.242.150.500.3145MM22F1406Q27Ratio4321.282.581.901.0855MM22H1211Q14Standard form2801.602.001.951.851.390.860.5664MA01F1401Q15Trigonometry3451.342.221.150.4274MA01F1405Q19Sets3461.391.981.360.9785AM22H1306Q07Compound measures5763.784.944.654.002.901.740.4491MA02H1311Q24Volume3391.172.882.561.810.680.090.02105AM22H1306Q20Probability5462.284.103.452.310.980.260.00112MB03H1511Q13Percentages3551.660.002.502.551.771.680.80122MB03H1506Q17Area of pentagon4421.673.603.011.830.670.190.05132MB02H1506Q16Graph of straight line4401.603.873.352.060.720.180.06145AM22H1311Q22Derive expressions4321.283.422.561.170.330.110.25155AM22H1406Q15Gradient of a curve3310.932.661.640.650.140.020.00165AM11H1411Q19Box plots2190.381.221.000.460.170.050.001713802H1006Q21Bounds4291.143.031.960.930.320.080.02185AM11H1111Q13Percentages5402.001.332.432.871.140.430.001913802H1203Q20Sine and cosine rule4140.553.301.700.360.040.000.00202MB01H1506Q13Histogram5361.794.644.072.440.920.160.032113802H1203Q24Solve algebraic fraction equations5110.543.611.440.350.060.010.0180     PAGE 2 P44584A This publication may only be reproduced in accordance with Pearson Education Limited copyright policy. 2014 Pearson Education Limited. 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