ࡱ> !# o  bjbj ".jjl^ ^ ^ ^ D $ 2    6888888$m \  \_  q___ .  6_ 6_`_6 UZ^  60 ,; ;6_ Name: ________________________ Hour: ____ Date: _______________ Chemistry: Molar Mass and Percentage Composition Calculate the molar masses and percentage composition of each of the following compounds. Show your work and always include units. 1. Ca3P2 2. Ca(OH) 2 3. Na2SO4 4. CaSO4 5. (NH4) 2SO4 6. Zn3(PO4) 2 7. Mg(NO3) 2 8. KCl Answers: 1. 182.3 g, 66.0% Ca, 34.0% P 5. 132.1 g, 21.2% N, 6.1% H, 24.3% S, 48.4% O 2. 74.1 g, 54.1% Ca, 43.2% O, 2.7% H 6. 386.2 g, 50.8% Zn, 16.1% P, 33.1 % O 3. 142.1 g, 32.4% Na, 22.6% S, 45.0% O 7. 116.3 g, 20.9% Mg, 24.1% N, 55.0% O 4. 136.2 g, 29.4% Ca, 23.6% S, 47.0% O 8. 74.6g, 52.4% K, 47.6% Cl Chemistry: Molar Mass and Percentage Composition KEY Calculate the molar masses and percentage composition of each of the following compounds. Show your work and always include units. 1. Ca3P2  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  2. Ca(OH) 2  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  3. Na2SO4  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  4. CaSO4  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  5. (NH4) 2SO4  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  6. Zn3(PO4) 2  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  7. Mg(NO2) 2  EMBED Equation.3   EMBED Equation.3   EMBED Equation.3   EMBED Equation.3  8. 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"2v5\too`!v5\too @ "xmK@߽Kms-X`TKzPWA:ѥb--Z(\/ppQNTw.J/\>o1px,)5]#dF (Z6尖쌊a"-⡊h #ZMÝYF~BGfg=pTtu~(/͓fF7G|4G]5IdsIM=}J -T˲5k5/A$Ǜ WQq+r;c2kzւr("1vʲqB||F p"%F&'()*+,-./0132457698:;<=>?@ABCDGEHiIKJMLNOPQRSTVUXWYZ\[]^_`abcdefgjhlknmqrstuvwxyz{|}~Root Entry F0»8$IData 6TWordDocument".ObjectPool@Ǚ_ _1136535097^'FǙ0NOle CompObjfObjInfo  !"#$%(+,-03458;<=@CDEFGHILOPQTWXY\_`adghijklmpstux{|} FMicrosoft Equation 3.0 DS Equation Equation.39q[UPD 3 Ca @ 40.1 g/mol = 120.3 g2 P @ 31.0 g/mol = 62.0 g Equation Native q_1136532565 Fp[p[Ole  CompObj f      Ca 3 P 2   =  182.3 g FMicrosoft Equation 3.0 DS Equation Equation.39q[D % Ca = 120.3 g 182.3 ObjInfo Equation Native _1136532638 F⟚⟚Ole g100         66.0% Ca FMicrosoft Equation 3.0 DS Equation Equation.39q[a % P = 62.0 g 182.3 gCompObjfObjInfoEquation Native _1136535104Fhh100         34.0% P FMicrosoft Equation 3.0 DS Equation Equation.39q[ 1 Ca @ 40.1 g/mol = 40Ole CompObjfObjInfoEquation Native .1 g2 O @ 16.0 g/mol = 32.0 g2 H @   1.0 g/mol =  2.0 g     Ca(OH) 2   =  74.1 g FMicrosoft Equation 3.0 DS Eq_1136532767FPuOle &CompObj'fObjInfo)uation Equation.39q[8_b % Ca = 40.1 g 74.1 g100         54.1% Ca FMicrosoft Equation 3.0 DS EqEquation Native *_1136532822,FOle .CompObj /fuation Equation.39q[D % O = 32.0 g 74.1 g100         43.2% O FMicrosoft Equation 3.0 DS EqObjInfo!1Equation Native 2_1136532838$F00Ole 6CompObj#%7fObjInfo&9Equation Native :_1136701811OE)F puation Equation.39q[H % H = 2.0 g 74.1 g100         2.7% H FMicrosoft Equation 3.0 DS EqOle >CompObj(*?fObjInfo+AEquation Native Buation Equation.39qHO 2  Na @ 23.0 g/mol = 46.0 g1  S @  32.1 g/mol =  32.1 g4 O @  16.0 g/mol =  64.0 g       Na 2 SO 4   =  142.1 g FMicrosoft Equation 3.0 DS Equation Equation.39q[( % Na = 46.0 g 142.1 g_1136533041"6.FOle JCompObj-/KfObjInfo0MEquation Native N_11367018443FOle RCompObj24Sf100         32.4% Na FMicrosoft Equation 3.0 DS Equation Equation.39qHH!# % S = 32.1 g 142.1 gObjInfo5UEquation Native V_11365331178F𪰚𪰚Ole Z100         22.6% S FMicrosoft Equation 3.0 DS Equation Equation.39q[  % O = 64.0 g 142.1 gCompObj79[fObjInfo:]Equation Native ^_1136701831=F11100         45.0% O FMicrosoft Equation 3.0 DS Equation Equation.39qHa,j 1  Ca @ 40.1 g/mol = 4Ole bCompObj<>cfObjInfo?eEquation Native f0.1 g1  S @  32.1 g/mol =  32.1 g4 O @  16.0 g/mol =  64.0 g       CaSO 4   =  136.2 g FMicrosoft Equation 3.0 DS Eq_1136533265BF>>Ole nCompObjACofObjInfoDquation Equation.39q[ę % Ca = 40.1 g 136.2 g100         29.4% Ca FMicrosoft Equation 3.0 DS EqEquation Native r_1136701842;cGFpŶpŶOle vCompObjFHwfuation Equation.39qH'|C % S = 32.1 g 136.2 g100         23.6% S FMicrosoft Equation 3.0 DS EqObjInfoIyEquation Native z_1136533312LFҹҹOle ~CompObjKMfObjInfoNEquation Native _1136535137|QFPY߼uation Equation.39q[1L % O = 64.0 g 136.2 g100         47.0% O FMicrosoft Equation 3.0 DS EqOle CompObjPRfObjInfoSEquation Native Suation Equation.39q[7p-LJ 2 N @ 14.0 g/mol = 28.0 g8 H @   1.0 g/mol =   8.0 g1 S @ 32.1 g/mol  =  32.1 g4O @  16.0 g/mol =  64.0 g   (NH 4 ) 2 SO 4   =  132.1 g FMicrosoft Equation 3.0 DS Equation Equation.39q_1136533835JYVFffOle CompObjUWfObjInfoXEquation Native _1136533871[FsĚOle CompObjZ\f[ % N = 28.0 g 132.1 g100         21.2% N FMicrosoft Equation 3.0 DS Equation Equation.39qObjInfo]Equation Native _1136533985Tr`FƚʚOle [t  % H = 8.0 g 132.1 g100         6.1% H FMicrosoft Equation 3.0 DS Equation Equation.39qCompObj_afObjInfobEquation Native _11367018731weFШ͚Ш͚[ % S = 32.1 g 132.1 g100         24.3% S FMicrosoft Equation 3.0 DS Equation Equation.39qOle CompObjdffObjInfogEquation Native H?G % O = 64.0 g 132.1 g100         48.0% O FMicrosoft Equation 3.0 DS Equation Equation.39q_1136535150jFp/ϚКOle CompObjikfObjInfolEquation Native _1136534240oF<Қ<ҚOle CompObjnpf[LM 3 Zn @ 65.4 g/mol = 196.2 g2  P @  31.0 g/mol =  62.0 g8 O @  16.0 g/mol =  128.0 g    Zn 3 (PO 4 ) 2   =  386.2 g FMicrosoft Equation 3.0 DS Equation Equation.39q[P % Zn = 196.2 g 386.2 g100         50.8% ZnObjInfoqEquation Native _1136534273mtFI՚I՚Ole  FMicrosoft Equation 3.0 DS Equation Equation.39q[$ % P = 62.0 g 386.2 g100         16.1% PCompObjsufObjInfovEquation Native _1136701886yF0Wؚ0WؚOle CompObjxzfObjInfo{Equation Native  FMicrosoft Equation 3.0 DS Equation Equation.39qHx A % O = 128.0 g 386.2 g100         33.1% O_1136535173h~FٚpdۚOle CompObj}fObjInfo FMicrosoft Equation 3.0 DS Equation Equation.39q[PD. 1  Mg @ 24.3 g/mol = 24.3 g2  N @  14.0 g/mol =  28.0 Equation Native _1136534624FܚqޚOle CompObjfg4 O @  16.0 g/mol =  64.0 g    Mg(NO 2 ) 2   =  116.3 g FMicrosoft Equation 3.0 DS Equation Equation.39qObjInfoEquation Native _1136534656FPߚPߚOle [x % Mg = 24.3 g 116.3 g100         20.9% Mg FMicrosoft Equation 3.0 DS Equation Equation.39qCompObjfObjInfoEquation Native _1136534711F[XL % N = 28.0 g 116.3 g100         24.1% N FMicrosoft Equation 3.0 DS Equation Equation.39qOle CompObjfObjInfoEquation Native [yD % O = 64.0 g 116.3 g100         55.0% O FMicrosoft Equation 3.0 DS Equation Equation.39q_1136535184FOle CompObjfObjInfoEquation Native m_1136534815F Ole CompObjf    !"%$[Q@\ 1   K @  39.1 g/mol = 39.1 g1  Cl @  35.5 g/mol =  35.5 g         KCl  =  74.6 g FMicrosoft Equation 3.0 DS Equation Equation.39q[t % K = 39.1 g 74.6 g100         52.4% K FMicrosoft Equation 3.0 DS EqObjInfo Equation Native  _1136534848F0GOle CompObjfObjInfoEquation Native 1Table;uation Equation.39q[' % Cl = 35.5 g 74.6 g100         47.6% ClOh+'0\H, YOx/梜aTWvm?;;HϤ_Ω:8Xbm6/ys)4'K|/#鳋[KP]5OI4-E.@=CtŰWL^\Dd J  C A? 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