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EMBED Equation.DSMT4  C. What is the probability that the average WAIS score of an SRS of 60 people is 105 or higher? Show your work.  EMBED Equation.DSMT4  normalcdf(105,10^99,100,1.9365) = .0049 D. Would your answers to any of A, B, or C be affected if the distribution of WAIS scores in the adult population were distinctly non-Normal? Explain. A would be impossible to calculate if the population werent normal. B and C would remain the same since 60 > 30, so the sampling distribution of sample means is normal, and the equations for the mean and standard deviation are valid. 2. Suppose that 47% of all adult women think they do not get enough time for themselves. An opinion poll interviews 1025 randomly chosen women and records the sample proportion who feel they dont get enough time for themselves. A. Describe the sampling distribution of ADVANCE \d 6EMBED Equation.DSMT4 \* MERGEFORMAT \sADVANCE \u 6. (center, shape, spread) Since it is a SRS(given), and (.47)(1025)> 10 and (.53)(1025)> 10 and 1025 < (.1)(pop.), the Central Limit Theorem applies. So...  EMBED Equation.DSMT4  , and the distribution is normal. B. The truth about the population is p = 0.47. In what range will the middle 95% of the sample results fall?  EMBED Equation.DSMT4  C. What is the probability that the poll gets a sample in which fewer than 45% say they do not get enough time for themselves?  EMBED Equation.DSMT4  normalcdf(0,.45,.47,.01559) = .0998 3. High school dropouts make up 20.2% of all Americans aged 18 to 24. A vocational school that wants to attract dropouts mails an advertising flyer to 25,000 persons between the ages of 18 and 24. A. If the mailing list can be considered to be a random sample of the population, what is the mean number of high school dropouts who will receive the flyer?  EMBED Equation.DSMT4  B. What is the probability that at least 5000 dropouts will receive the flyer? Show your method. 5000 = (.20)(25000), so Im asking what the probability of having a sample proportion of .20 or higher. Since the Central Limit Theorem applies (go through the same conditions as you did in 2A above...Im getting tired), we know the following:  EMBED Equation.DSMT4  So... EMBED Equation.DSMT4  normalcdf(.20,1,.202,.0057) = .6371 4. The Harvard College Alcohol Study interviewed a SRS of 14,941 college students about their drinking habits. Suppose that half of all college students drink to get drunk at least once in a while. That is, p = 0.5. A. What are the mean and the standard deviation of the proportionADVANCE \d 6EMBED Equation.DSMT4 \* MERGEFORMAT \sADVANCE \u 6 of the sample who drink to get drunk? Check conditions: np >10 n(1-p) > 10 n< .1(pop) SRS given Therefore  EMBED Equation.DSMT4  B. Is it permissible to use the normal approximation to find the probability thatADVANCE \d 6EMBED Equation.DSMT4 \* MERGEFORMAT \sADVANCE \u 6 is within a certain range? Why or why not? Yes, because of the conditions checked in 4A. C. Find the probability thatADVANCE \d 6EMBED Equation.DSMT4 \* MERGEFORMAT \sADVANCE \u 6 is between 0.49 and 0.51. Normalcdf(.49,.51,.50,.0041) = .9853 +,CIJK   < > {jUj=/jV  *hzh|B*OJQJUVph)j *hzh|B*OJQJUph *hzh|B*OJQJph *hzh:B*OJQJph *hzhPMvB*OJQJphh_hHOJQJh_h:OJQJh_h_5OJQJ\h_hH5OJQJ\h_hHOJQJmH sH %jh_hHOJQJUmH sH h_h_OJQJmH sH JK! 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