ࡱ> #` Fbjbj5G5G >W-W-`/:::8:tl;R,=:f=(===>>>QQQQQQQ$ShUQ>>>>>Q==4R>E>E>E>h==Q>E>Q>E>EGH= = `jjU:*AGiHL R0RG,VBVHVHd>>>E>>>>>QQDd>>>R>>>>3\7d\7 Name: _____________________________________ CH225H MT 2: 55 minutes KEY You may use a calculator and a periodic table. Part I. Multiple choice. [4 pts each] 1.Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH3COONa (molar mass = 82.0 g/mol) in water? The density of the solution is 1.09 g/mL.A)7.26 10  6 MB)0.207 MC)1.07 MD)2.26 ME)2.99 M 2.Assuming complete dissociation of electrolytes, which of the following aqueous solutions has the lowest freezing point? A)0.18 m KClB)0.15 m Na2SO4C)0.12 m Ca(NO3)2D)pure waterE)0.20 m sucrose (a non-electrolyte) 3.It takes 42.0 min for the concentration of a reactant in a first-order reaction to drop from 0.45 M to 0.32 M at 25C. How long will it take for the reaction to be 90% complete?A)13.0 minB)86.0 minC)137 minD)222 minE)284 min 4.Nitric oxide gas (NO) reacts with chlorine gas according to the equation NO + Cl2 NOCl. The following initial rates of reaction have been measured for the given reagent concentrations. Expt. # Rate (M/hr) NO (M) Cl2 (M) 1 1.19 0.50 0.50 2 4.79 1.00 0.50 3 9.59 1.00 1.00 Which of the following is the rate law (rate equation) for this reaction?A)rate = k[NO]B)rate = k[NO][Cl2]1/2C)rate = k[NO][Cl2]D)rate = k[NO]2[Cl2]E)rate = k[NO]2[Cl2]2 5.The activation energy for the reaction CH3CO CH3 + CO is 71 kJ/mol. How many times greater is the rate constant for this reaction at 170.0C than at 150.0C? (R = 8.31 J / Kmol)A)0.40B)1.1C)2.5D)4.0E)5.0 6.An increase in temperature causes an increase in the rate of reaction. The best explanation for this behavior is that as the temperature increases,A)the concentration of reactants increases.B)the activation energy decreases.C)the collision frequency increases.D)the fraction of collisions with total kinetic energy > Ea increases.E)the activation energy increases. 7.The rate law for the reaction 2NO2 + O3 N2O5 + O2 is rate = k[NO2][O3]. Which one of the following mechanisms is consistent with this rate law?A)NO2 + NO2 N2O4 (fast) N2O4 + O3 N2O5 + O2 (slow)B)NO2 + O3 NO5 (fast) NO5 + NO5 N2O5 + (5/2)O2 (slow)C)NO2 + O3 NO3 + O2 (slow) NO3 + NO2 N2O5 (fast)D)NO2 + NO2 N2O2 + O2 (slow) N2O2 + O3 N2O5 (fast) 8.With respect to the figure below, which choice correctly identifies all the numbered positions?  1. 2. 3. 4. A)catalyst intermediate transition state product B)reactants transition state intermediate product C)reactants transition state catalyst product D)reactants intermediate transition state product E)reactants intermediate transition state catalyst  9.Which is the correct equilibrium constant expression for the following reaction? Fe2O3(s) + 3H2(g)  2Fe(s) + 3H2O(g)A)Kc = [Fe2O3] [H2]3 / [Fe]2[H2O]3B)Kc = [H2] / [H2O]C)Kc = [H2O]3 / [H2]3D)Kc = [Fe]2[H2O]3 / [Fe2O3] [H2]3E)Kc = [Fe] [H2O] / [Fe2O3] [H2] 10.Which of the following is a true statement about chemical equilibria in general?A)At equilibrium the total concentration of products equals the total concentration of reactants, that is, [products] = [reactants].B)Equilibrium is the result of the cessation of all chemical change.C)There is only one set of equilibrium concentrations that equals the Kc value.D)At equilibrium, the rate constant of the forward reaction is equal to the rate constant for the reverse reaction.E)At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. 11.Consider the following equilibria: 2SO3(g)  2SO2(g) + O2(g) Kc = 2.3 10-7 2NO3(g)  2NO2(g) + O2(g) Kc = 1.4 10-3 Calculate the equilibrium constant for the reaction SO2(g) + NO3(g)  SO3(g) + NO2(g).A)78B)1.3 10-2C)1.6 10-4D)3.2 10-10E)6.1 103 12.For the following reaction at equilibrium, which one of the changes below would cause the equilibrium to shift to the left? 2NOBr(g)  2NO(g) + Br2(g), DHrxn = +30 kJ/molA)Increase the container volume.B)Remove some NO.C)Remove some Br2 .D)Add more NOBr.E)Decrease the temperature. 13.The equilibrium constants (expressed./<>FIL  [ ^ _      . 0 6 8 D F Z \ b j p r v x | p v ЅЖЖ}hTHBhTHB5hj'hTHBhTHB5B*phhTHBhphTHBB*H*ph!hphTHBB*OJQJ^JphhTHBB*phhphTHBB*ph h"H*h"h:h༸~hFoh"5H* h"H*h"B*H*phh">*B*ph h"H*hFoh"5h"OJQJ^Jhj'h"hTHBB*phhphTHBB*H*phhphTHBB*phhTHBhTHBhTHB5B*phhTHBhTHB5B*H*ph1 D HJkd$$If<0t$ 4 <a<$$$1$7$8$H$Ifgd)5 $$$1$7$8$H$IfJkdv$$If<0t$ 4 <a<D F H J P EEkd$$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$1$7$8$H$Jkdv$$If<0t$ 4 <a< `Hkd$$If<0t$ 4 <a<Hkdq$$If<0t$ 4 <a<$$$1$7$8$H$If &6`Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfHkdg$$If<0t$ 4 <a<68:<Bzzzz$$$$1$7$8$H$Ifa$K$$$$1$7$8$H$If$$$$1$7$8$H$Ifa$1$7$8$H$Hkd]$$If<0t$ 4 <a<  $$$$1$7$8$H$Ifa$K$kkd$IfK$L$<4\ Taf4#($$$$1$7$8$H$Ifa$K$kkdl $IfK$L$<4\ Taf4()+05:$$$$1$7$8$H$Ifa$K$kkd $IfK$L$<4\ Taf4:;<>Ekd( $$If<0$!4 <a<$$$1$7$8$H$Ifkkd $IfK$L$<4\ Taf4`Hkd $$If<0t$ 4 <a<$$$1$7$8$H$IfHkd $$If<0t$ 4 <a<`Hkd $$If<0t$ 4 <a<$$$1$7$8$H$IfHkd $$If<0t$ 4 <a<$% 4BhjAJ78[\`a  46<>"$&(0268>@BDLN h"6] h">*hh"OJQJ^Jhj' h"H* h"H*h"hFoh"5hFoh"5H*LHEkd $$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$1$7$8$H$Hkd $$If<0t$ 4 <a<"$*24:B`Hkd$$If<0t$ 4 <a<Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfBDJRTZb`Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd{$$If<0t$ 4 <a<bdfhnLMPzHEkd$$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$1$7$8$H$Hkdq$$If<0t$ 4 <a<z{~`Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfHkdg$$If<0t$ 4 <a<4`Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd]$$If<0t$ 4 <a<4567: HEkd$$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$1$7$8$H$HkdS$$If<0t$ 4 <a<NRZjltvxz  "$,.2:BDNPRTZ\^`rz~޻޻hFoh"56]hFoh"5OJQJ^JhFoh"5H*hFoh"5h"OJQJ^J h"H* h"6]h"J ^`f>~`Hkd$$If<0t$ 4 <a<HkdI$$If<0t$ 4 <a<$$$1$7$8$H$If ~  `XXF$$$$1$7$8$H$Ifa$1$7$8$H$Hkd$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd?$$If<0t$ 4 <a<%?Ov efghpquvwԲԲhFoh"5H* h"H*j,h4RCJH*UaJ hs5hFoh"5hsj5h4RCJUaJhj' h"6] h"H*h"Ep^$$$$1$7$8$H$Ifa$kkd7&$IfK$L$<4\af4$$$$1$7$8$H$Ifa$K$$$$1$7$8$H$If'/$$$$1$7$8$H$Ifa$K$$$$1$7$8$H$IfEkd&$$If<0$!4 <a</01259*$$$1$7$8$H$IfHkd'$$If<0t$ 4 <a<$$$$1$7$8$H$Ifa$kkdF'$IfK$L$<4\af45?Q^fghm$$$$1$7$8$H$Ifa$kkdU($IfK$L$<4\af4$$$$1$7$8$H$Ifa$K$hilv$$$$1$7$8$H$Ifa$K$$$$1$7$8$H$IfHkd($$If<0t$ 4 <a<9*$$$1$7$8$H$IfHkd)$$If<0t$ 4 <a<$$$$1$7$8$H$Ifa$kkdd)$IfK$L$<4\af4m$$$$1$7$8$H$Ifa$kkds*$IfK$L$<4\af4$$$$1$7$8$H$Ifa$K$$$$$1$7$8$H$Ifa$K$$$$1$7$8$H$IfHkd+$$If<0t$ 4 <a<     9111$7$8$H$Hkd,$$If<0t$ 4 <a<$$$$1$7$8$H$Ifa$kkd+$IfK$L$<4\af4 cPHkd1$$If<0t$ 4 <a<Ekd1$$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$ `Hkd2$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd2$$If<0t$ 4 <a< !'(FJoy$FHPRZ\jl|~h"H*OJQJ^Jh"OJQJ^Jj6h4RCJH*UaJ h"6]hj' h"H* h"H*h"hFoh"5H*hFoh"5hFoh"5H*>#$%&*{`XXF$$$$1$7$8$H$Ifa$1$7$8$H$Hkd3$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd 3$$If<0t$ 4 <a<{|IbHkd{4$$If<0t$ 4 <a<$$$1$7$8$H$IfEkd4$$If<0$!4 <a<IJM"`Hkdq5$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd4$$If<0t$ 4 <a<"$*`XXXX1$7$8$H$Hkdg6$$If<0t$ 4 <a<$$$1$7$8$H$IfHkd5$$If<0t$ 4 <a<@` EkdD$$If<0$!4 <a<$$$1$7$8$H$If$$$$1$7$8$H$Ifa$ n p ! 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