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Holiday Revision    A grade A* student can (( (NumberSimplify surds, such as 4(3 + (3) and (2 - (3)(4 + (3) in the form a + b(3Use index notation and index laws for fractional powers such as  EMBED Equation.3 Find the upper and lower bounds of more difficult calculations with quantities given to a various degrees of accuracyAlgebraSimplify harder rational expressions Solve fractional linear equations with the unknown in the denominator such as  EMBED Equation.3 Solve harder quadratic equations (a(1) such as 5x2 -3x + 5 = 0 by using the quadratic formulaSimplify quadratic expressions by completing the squareUse completing the square to solve quadratic equationsUse completing the square to find maximum and minimum valuesSolve a pair of simultaneous equations where one is linear and one is non-linear such as x + 4y = 15 and x2 + y 2 = 9Solve cubic equations by drawing appropriate lines on graphsPlot and sketch graphs of exponential functionsRecognise the shapes of graphs of functionsTransform the graphs of y = f(x), such as linear, quadratic, cubic, sine and cosine functions, using the transformations y = f(x) + a, y = f(x + a), y = f (ax) and y = af(x)Solve simultaneous equations graphically, such as y = 2x 1 and x2 + y 2 = 13ShapeUse trigonometry to find sides and angles in three dimensionsFind the angle between a line and a planeUnderstand the graphs of trigonometric functions for angles of any sizeFind the volume of the frustum of a truncated coneSolve more difficult vector geometry problemshdDraw tree diagrams and use them to find probabilities of successive dependent eventsDerive harder algebraic proofs using reasoning and logic A grade A student can (( (NumberRationalise the denominator of a surd such as  EMBED Equation.3 Use index notation and index laws for simple fractional powers such as  EMBED Equation.3 Use index notation and index laws for simple negative powers such as 2-3AlgebraFactorise harder quadratic expressions (a 1)Solve direct and inverse proportion problemsInterpret the graphs of direct and inverse proportion relationshipsRearrange formulae where the variable appears twiceExplore the gradients of perpendicular straight-line graphsUse the points of intersection of a quadratic graph such as y = x2 - 2x - 4 with lines such as y = 2x + 1 to solve equations like x2 - 2x 4 = 2x + 1 and simplify this to x2 - 4x 5 = 0Solve quadratic equations (a=1) such as x2 -3x + 5 = 0 by using the quadratic formulaSolve a pair of simultaneous equations where one is linear and one is non-linear such as y = 3x 5 and y = x2Construct the graphs of loci, including the circle x2 + y 2 = r2Solve simultaneous equations graphically, such as y = x 1 and x2 + y 2 = 9Shape and SpaceCalculate the lengths of circular arcs Calculate the areas of sectorsCalculate the surface areas of cylinders, cones and spheresCalculate the volumes of cylinders, cones and spheresProve the angle properties of a circleProve the tangent / chord properties of a circle Use and prove the alternate segment theoremEnlarge a shape by a negative scale factorCompare areas and volumes of enlarged shapesFind the upper and lower bounds of more difficult calculations with quantities given to a various degrees of accuracyAdd, subtract and multiply vectors to solve vector geometry problemsUnderstand the relationship between parallel and perpendicular vectorsFind the area of a 2-D shape, given the area of a similar shape and the ratioFind the volume of a 3-D solid, given the volume of a similar solid and the ratioProve that two triangles are congruentProve the construction theoremsUse Pythagoras theorem in 3-D problemsSketch and draw trigonometric graphsUse the sine rule to find the missing sides and missing angles in any triangleUse the cosine rule to find the missing sides and missing angles in any triangleUse the formula for the area of a non right-angled triangleUse the conditions for congruent triangles in formal geometric proofsData HandlingConstruct and interpret a histogram including unequal class intervalsUse stratified sampling methodsUnderstand dependent and independent outcomesUnderstand probabilities associated with mutually exclusive eventsUse tree diagrams to find probabilities of successive independent eventsDerive simple algebraic proofs using reasoning Number/Algebra Non-Calculator Day 1 1. x =  (Read as x = 0.378378378 . . .) (a) Write down the value of 1000x. ..................................................................................................................................... (1) (b) Hence express x as a fraction in its simplest form. ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... (2) Number/Algebra Calculator Day 1 2. In a series of experiments, all measurements are taken correct to 3 significant figures. In one particular experiment, the results recorded are v = 24.5, u = 19.2 and s = 115. Using , what could have been the maximum value for f? .............................................................................................................................................. .............................................................................................................................................. .............................................................................................................................................. .............................................................................................................................................. .............................................................................................................................................. (4) Number/Algebra Non-Calculator Day 2 3. (a) Simplify fully the following expression, leaving your answer in surd form.  ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... (2) (b) Given that 135 = 33 5, simplify the expression  SHAPE \* MERGEFORMAT  Give your answer in surd form. ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... Answer .................................................................. (3) (Total 5 marks) Number/Algebra Calculator Day 2 4. The diagram shows a trapezium The measurements on the diagram are in centimetres The lengths of the parallel sides are x cm and 20 cm The height of the trapezium is 2x cm The area of the trapezium is 200cm2 (a) Show that x2 + 20x = 200 Find the value of x (2) Give your answer correct to 3 decimal places (3) Number/Algebra Non-Calculator Day 3 5. (a) Find the exact value of . Give your answer as a fraction in its simplest form. .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... (2) (b) Make x the subject of the formula y =  .............................................................................................................................................. ............................................................................................................................................. ............................................................................................................................................. ............................................................................................................................................. ............................................................................................................................................. ............................................................................................................................................. (3) (c) You are given that. Show that 2x2 5x + 9 = 0. .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... .................................................................................................................................... (4) Number/Algebra Calculator Day 3 6. y is proportional to x3 (a) When x = 4, y = 80. Find the value of y when x = 8. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. (3) Also, x is inversely proportional to the square root of z. (b) When y = 10, z = 16. Find the value of z when x = 4. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. ................................................................................................................................. (4) Number/Algebra Non-Calculator Day 4 7. (a) Factorise x + 6x + 8 .................................................................................................................................. .................................................................................................................................. (2) (b) Write x + 6x + 8 in the form (x+ a) + b .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) (c) Sketch the graph of y = x + 6x + 8. Show how your answers to part (a) and (b) are related to your sketch.  .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (3) Number/Algebra Calculator Day 4 8. x +  = 3 (a) Show that this equation can be re-arranged as x 3x + 1 = 0. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) (b) Solve this equation to find the values of x correct to 2 decimal places. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (3) Number/Algebra Non-Calculator Day 5 9. (a) The diagram shows the graph of y = sin x for 0 x 360.  On the axes below sketch the graph of (i) y = 2 sin x for 0 x 360  (1) (ii) y = sin 2x for 0 x 360  (1) (iii) y = sin x + 2 for 0 x 360  (1) (b) The graph of function y = f(x) passes through the points A( 4, 0) and B(0, 2).  The function y = f(x) is transformed to y = 3f(x 2) The points A and B are transformed to the points A and B by this transformation. Give the coordinates of (i) A, .. (1) (ii) B. .. (1) Number/Algebra Calculator Day 5 10. Given x=2p y=2q (a) Express in terms of x and/or y, (i) 2p+q (ii) 22q (iii) 2p-1 (3) xy = 32 and 2xy2 = 32 Find the value of p and the value of q (2) Shape, Space and Measures Non-Calculator Day 6 11. AT and BT are tangents to the circle, centre C. P is a point on the circumference as shown. Angle BAT = 65  Calculate the size of (a) x, .................................................................................................................................. .................................................................................................................................. (2) (b) y, .................................................................................................................................. .................................................................................................................................. (2) (c) z. .................................................................................................................................. .................................................................................................................................. (2) Shape, Space and Measures Calculator Day 6 12. A gardener pegs out a rope, 19 metres long, to form a flower bed.  Calculate (a) the size of the angle BAC; ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... (2) (b) the area of the triangular flower bed. ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... ..................................................................................................................................... (4) Shape, Space and Measures Non-Calculator Day 7 13. OABC is a quadrilateral. M, N, P and Q are the mid-points of OA, OB, AC and BC.  OA = a, OB = b, OC = c (a) Find, in terms of a, b and c expressions for (i)  ...... ...... (1) (ii)  ...... ...... (1) (iii)  ...... ...... (2) (b) What can you deduce about the quadrilateral MNQP? ........ ........ (1) Shape, Space and Measures Calculator Day 7 14. The sloping sides of a flower bowl are part of a cone as shown. The radius of the top of the bowl is 10 cm and the radius of the bottom of the bowl is 5 cm. The height of the full cone is 24 cm.  (a) Calculate the volume of the full cone. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) (b) By using similar figures, calculate the volume of the flower bowl. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (4) Shape, Space and Measures Non-Calculator Day 8 15. The grid below shows a triangle ABC and a triangle ABC.  (a) Draw the triangle ABC which is an enlargement of ABC with a scale factor withcentre (2, 1). (2) (b) Describe fully the transformation that takes triangle ABC to triangle ABC. (2) Shape, Space and Measures Calculator Day 8 16.  AB is a chord of the circle, centre O, radius 10 cm. AB = 16 cm. (a) Calculate the size of angle x. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) (b) Calculate the area shaded  in the diagram. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (3) (c) Calculate the area shaded  in the diagram. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (4) Handling Data Non-Calculator Day 9 17. Alan, Bob, Charles, David, Evelyn and Fay are asked their ages. Alan says 23, Bob says 61, Charles says 57 and David says 21. Evelyn and Fay refuse to give their ages. It is known that two of the men are older than Evelyn and Fay and the other two are younger. It is known that the median value of all the ages is 42. (a) How do you know that the sum of the ages of Evelyn and Fay is 84? .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) (b) Fay then says that she is twice as old as Evelyn. How old is Evelyn? .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (3) Handling Data Calculator Day 9 18. A football team has to play two games. The first game is played away. The second game is played at home. The probability that the team will win the away game is 0.3 If the team wins the away game, then the probability that it will win the home game is 0.6 If the team does not win the away game, then the probability that it will win the home gameis0.45 Calculate the probability that the team (a) wins both games, (2) (b) wins only one game. (5) Handling Data Non-Calculator Day 10 19. Jonathan counted the number of cars arriving at his school in the 50 minutes just before schoolstarted.  (a) Draw a histogram to show this information.  (3) (b) Using your histogram to estimate the time by which half of the cars had arrived. Show your working. .................................................................................................................................. .................................................................................................................................. .................................................................................................................................. (2) Handling Data Calculator Day 10 20. A company employs 200 men and 320 women. Each persons job is given a grade (A, B, C or D). The diagrams show the proportions by grade for men and for women. Men (200 employees)  Women (320 employees)  The company wishes to survey a 10% sample of the employees, stratified by sex and by grade. Complete the table to show how many of each group should be sampled. ABCDMenWomen............................................................................................................................................... ............................................................................................................................................... ............................................................................................................................................... ............................................................................................................................................... (4)  Study Leave Revision    Number/Algebra Non-Calculator Answers Day 1 1. x =  (Read as x = 0.378378378 . . .) (a) Write down the value of 1000x. 378.378(378...) (NB If x = 0.4545454545 you would find the value of 100x) (1) (b) Hence express x as a fraction in its simplest form. 1000x = 378.378(378...) x = 0.378378378 (If you subtract x from 1000x you will eliminate the decimals) 999x = 378 M1 378/999 gets M1 (378 & 999 are divisible by 3! 3+7+8=18; 9+9+9=27; both 18 and 27 are divisible by 3) x =  EMBED Equation.3  A1 must be in simplest form (2) Number/Algebra Calculator Answers Day 1 2. In a series of experiments, all measurements are taken correct to 3 significant figures. In one particular experiment, the results recorded are v = 24.5, u = 19.2 and s = 115. Using, what could have been the maximum value for f? NB. All measurements are correct to 3 significant figures. Variables v and u are also correct to 1 decimal place (0.1) and s is correct to the nearest whole number (1). To find the maximum and minimum values for these variables Max v = 24.5 + (0.1 2) = 24.5 + 0.05 = 24.55; Min v = 24.5 - (0.1 2) = 24.5 0.05 = 24.45 Max u = 19.2 + (0.1 2) = 19.2 + 0.05 = 19.25; Min u = 19.2 - (0.1 2) = 19.2 0.05 = 19.15 Max s = 115 + (1 2) = 115 + 0.5 = 115.5; Min s = 115 - (1 2) = 115 0.5 = 114.5 To find the maximum value for f, we would need the following values Max v, Min u and Min s Max v = 24.55 M1 (Not 24.54; Round 24.549999.. up to 24.55) Min u = 19.15 M1(Not 19.14; Round 19.149999..up to 19.15) Min s = 114.5 M1(Not 114.4; Round 114.4999.. up to 114.5) fmax =...= 1.03 (3sf) M1 (4) Number/Algebra Non-Calculator Answers Day 2 3. (a) Simplify fully the following expression, leaving your answer in surd form.  Hint look for square numbers 75 = 25 x 3 (25 = 5 x 5) 12 = 4 x 3 (4 = 2 x 2) EMBED Equation.3= EMBED Equation.3xEMBED Equation.3= 5EMBED Equation.3 EMBED Equation.3= EMBED Equation.3xEMBED Equation.3= 2EMBED Equation.3  B1 Either  or  =  B1 (2) (b) Given that 135 = 33 5, simplify the expression  SHAPE \* MERGEFORMAT   =  EMBED Equation.3 = 3 or 3 B2 Give your answer in surd form.  B2 =  B1 (3) Number/Algebra Calculator Answers Day 2 4. The diagram shows a trapezium The measurements on the diagram are in centimetres The lengths of the parallel sides are x cm and 20 cm The height of the trapezium is 2x cm The area of the trapezium is 200cm2 (a) Show that x2 + 20x = 200  Area of trapezium =  EMBED Equation.3 x h 200 =  EMBED Equation.3 x 2x 200 =  EMBED Equation.3  400 = 40x + 2x2 200 = 20x +x2 or x2 + 20x = 200 (2) Find the value of x Give your answer correct to 3 decimal places Methods: completing the square / using the quadratic formula to solve x2 + 20x 200 = 0 Completing the square (see question 8b notes on how to solve using the quadratic formula) (x + 10)2 = (x + 10)(x + 10) = x2 + 20x + 100 You need x2 + 20x 200 So (x + 10)2 300 = 0 (x + 10)2 =300  x + 10 =  EMBED Equation.3  x = -10 -  EMBED Equation.3  or x = -10 +  EMBED Equation.3  x = -27.3205080 or x = 7.3205080.. x = -27.321 cm or 7.321 cm (3 decimal places) (3) Number/Algebra Non-Calculator Answers Day 3 5. (a) Find the exact value of . Give your answer as a fraction in its simplest form. 64S! =  = 4; 196- = =  4 x  =  =   (2) (b) Make x the subject of the formula y =  y (x + 2) =4x Now expand the bracket and collect together the x s on one side of the equation yx + 2y = 4x M1 or yx 4x = 2y 2y = 4x yx 2y = x(4 y) Factorise M1 or x(y 4) = 2y = x (divide both sides by (4 y) x =  or x =  A1 cao (3) (b) You are given that . Show that 2x2 5x + 9 = 0. First find the lowest common multiple of the fraction denominators. This is simply the denominators multiplied together (x + 2)(2x 5) Next multiply throughout by (x + 2)(2x 5) 3(2x 5) 2(x + 2) = (x + 2)(2x 5) Now expand the brackets B2 6x 15 2x 4 = 2x2 5x + 4x 10 Collect together like terms 4x 19 = 2x2 x 10 Collect all terms on the RHS 0 = 2x2 5x + 9 OR 2x2 5x + 9 = 0 A2 (4) Number/Algebra Calculator Answers Day 3 6. y is proportional to x3 (a) When x = 4, y = 80. Find the value of y when x = 8. First find the constant k by forming an equation and substituting in the given values y = kx3 M1 80 = k x 43; 80 = k x 64 = k; k = 1.25 A1 Using this value of k = 1.25 and x = 8; substitute into the formulae y = kx3 y = 1.25 x 83 y = 640 A1 (3) Also, x is inversely proportional to the square root of z. (b) When y = 10, z = 16. Find the value of z when x = 4. We have now two equations From part (a) y = 1.25x3 From part (b) x = EMBED Equation.3 ; We need to substitute the value of x from part (b) into the equation in part (a)to find the value of the second constant k in part (b) If y = 1.25x3 and y = 10; then 10 = 1.25x3  EMBED Equation.3 = x3; 8 = x3; Thus x = 2 Now given x = EMBED Equation.3 ; and z = 16, using x = 2 we can calculate the value for k 2 = EMBED Equation.3 ; 2 = EMBED Equation.3 ; Thus k = 8 Now given x = 4 and using k = 8 we can find the value of z 4 = EMBED Equation.3 ; 4 EMBED Equation.3 = 8;  EMBED Equation.3 = 2 Hence z = 4 (4) Number/Algebra Non-Calculator Answers Day 4 7. (a) Factorise x + 6x + 8 (x + 2)(x +4) B1 B1 (2) (b) Write x + 6x + 8 in the form (x + a) + b (x + 3)2 Now expand the bracket (x + 3)2=(x + 3)(x + 3) = x2 + 6x + 9 We need x + 6x + 8 so if we subtract 1 to the above expression this should do it!! (x + 3)2 - 1 = x + 6x + 8 (x + 3)2 - 1 (2) (c) Sketch the graph of y = x + 6x + 8. Show how your answers to part (a) and (b) are related to your sketch.  (3) Number/Algebra Calculator Answers Day 4 8. x +  = 3 (a) Show that this equation can be re-arranged as x 3x + 1 = 0. First multiply the equation throughout by x to eliminate the fraction x2 + 1 = 3x Therefore x 3x + 1 = 0. (2) (b) Solve this equation to find the values of x correct to 2 decimal places. Methods: completing the square(see question 4b)/ using the quadratic formula to solve x2 - 3x + 1 = 0 This approach will use both; first by using the quadratic formula with equations in the form ax + bx + c = 0 and the formula x =  EMBED Equation.3 to solve x 3x + 1 = 0. (Remember a is the coefficient of x2, b is the coefficient of x and c is the constant) Substituting a = 1, b = 3, c = 1 into formula x =  EMBED Equation.3  x =  EMBED Equation.3  x =  EMBED Equation.3  x =  EMBED Equation.3  x =  EMBED Equation.3  or x =  EMBED Equation.3  x = 2.61803 or x = 0.381966 x = 2.62 or x = 0.38(correct to 2 decimal places) (3) Number/Algebra Non-Calculator Answers Day 5 9. (a) The diagram shows the graph of y = sin x for 0 x 360.  On the axes below sketch the graph of y = 2 sin x for 0 x 360  Graph with max at (90, 2), and min at (270,-2), crossing axis at 0,180,360. (1) (ii) y = sin 2x for 0 x 360  Sine graph with 2 cycles. Max at (45, 1) and (225, 1) Min at (135,  1) and (315,  1) crossing axis at 0, 90, 180, 270, 360 (1) (iii) y = sin x + 2 for 0 x 360  Translation of sine graph by (0,2) (1) (b) The graph of function y = f(x) passes through the points A(4, 0) and B(0, 2).   The function y = f(x) is transformed to y = 3f(x 2) The points A and B are transformed to the points A and B by this transformation. Give the coordinates of A (2, 0) B (2, 6) (2) Number/Algebra Calculator Answers Day 5 10. Given x=2p y=2q (a) Express in terms of x and/or y, (i) 2p+q = 2p x 2q = xy (ii) 22q = (2q)2 = y2 (iii) 2p-1=  EMBED Equation.3 =  EMBED Equation.3  (3) xy = 32 and 2xy2 = 32 Find the value of p and the value of q xy = 32; xy2 =16; xy x y = 16 32 x y = 16 y = 0.5 xy = 32 0.5x = 32 x = 64 (2) Shape, Space and Measures Non-Calculator Answers Day 6 11. AT and BT are tangents to the circle, centre C. P is a point on the circumference as shown. Angle BAT = 65 Calculate the size of (a) x, tangent-chord In all parts, Ms can be awarded M1 65 for clear intent or reason. A1 cao (2) (b) y, angle at centre = twice angle at circumference M1 130 A1 cao (2) (c) z. sum of angles in quadrilateral M1 50 A1 cao (2) Shape, Space and Measures Calculator Answers Day 6 12. A gardener pegs out a rope, 19 metres long, to form a flower bed.  Calculate the size of the angle BAC; 62 = 52 + 82 2x5x8cosBAC M1 BAC = 48.5 A1 (2) (b) the area of the triangular flower bed. Area = 1/2 5 8 sin48.5cm2 M2 = 14.98cm2 A2 or h = 5sin48.5cm (M1) =3.745cm (A1) area = 1/2 8 3.745cm2 (M1) = 14.98cm2 (A1) (4) (4) Shape, Space and Measures Non-Calculator Day 8 Triangle ABC has vertices at A (0, 2), B (2, 5), C (6, 4). Shape, Space and Measures Calculator Answers Day 7 13. OABC is a quadrilateral. M, N, P and Q are the mid-points of OA, OB, AC and BC.  OA = a, OB = b, OC = c (a) Find, in terms of a, b and c expressions for Hints Put information from the question onto the diagram first, put 'a' and an arrow on OA, 'b' and an arrow on OB, 'c' and an arrow on OC. Always follow a path that you know and remember that if you go backwards down an arrow the vector is negative e.g. AO = -a  c b (or -b + c ) (1) (ii)  You will need to use your answer to BC for this question Follow the path that you know, to get from N to Q, go from N to O, then O to C and finally C to Q NQ = -b OC = c BC = c - b CB = b - c CQ is half of CB CQ = b - c So NQ = -b + c + b - c = c (1) (iii)  You will need to work out AC first AC = -a + c MP = MA + AP MA = a AP = AC = ( -a + c ) MP = a + ( -a + c ) = c M1,A1 M1 for attempt to add appropriate vectors. A1 answer (2) (b) What can you deduce about the quadrilateral MNQP? Opposite sides have the same vectors, MP = NQ so the lines must be equal in length and parallel so MNQP must be a Parallelogram B1 Or equivalent Shape, Space and Measures Calculator Answers Day 7 14. The sloping sides of a flower bowl are part of a cone as shown. The radius of the top of the bowl is 10 cm and the radius of the bottom of the bowl is 5 cm. The height of the full cone is 24 cm.  (a) Calculate the volume of the full cone. Remember to look at the formula page for volume of a cone Volume of a cone = S! p r2 h cm3 = S! p 102 24 cm3 M1 = 2513.27 cm3 A1 (2) (b) By using similar figures, calculate the volume of the flower bowl. Radius small cone : radius large cone is M1 A1 1: 2 This is the linear scale factor. If we are finding a new volume then we need the volume scale factor Linear factor is 1: 2 Area factor is 12 : 22 is 1 : 4 Volume factor is 13 : 23 is 1 : 8 So the small volume of the small cone is one eighth of the volume of the large cone = 2513.27 8 = 314.16 cm3 So the volume of the flower bed = 2513.27.-.314.16 M1 = 2199.11 cm3 = 2200 cm3 A1 [4] (4) Shape, Space and Measures Non-Calculator Answers Day 8 15. The grid below shows a triangle ABC and a triangle ABC.  Remember that a scale factor of will make the shape smaller (half the size) and half as far from the centre of enlargement. Remember that a negative scale factor will mean that the image is on the opposite side of the centre of enlargement to the object, it will be inverted ( turned upside down ) (i) Triangle with coordinates at (3,1),(4, 1) and (4, -) M1, A1 M1 for attempt to enlarge at (2,1), A1 for answer (cao) When describing a transformation ALL details are needed, usually three details for a rotation ( centre, direction, angle) and two for an enlargement (centre, scale factor) (2) (ii) Enlargement s.f 2 about (2, -1) B1, B1 B1 for enlargement s.f. 2, B1 centre f.t. on their answer if first M1 awarded. eg enlargement s.f at (2,1) is Enlargement s.f.2, centre (2,7) withcentre (2, 1). (2) Shape, Space and Measures Calculator Answers Day 8 16.  AB is a chord of the circle, centre O, radius 10 cm. AB = 16 cm. (a) Calculate the size of angle x. Label the sides of the triangle with hypotenuse; opposite and adjacent in shorthand form, Remember this is a right-angled triangle so this is BASIC TRIGONOMETRY We know the sin x =  EMBED Equation.3  (remember to half AB) sin x = 0.8 x = sin1 0.8 x = 53.1 M1 A1 (2) (b) Calculate the area shaded  in the diagram. We are finding the area of a sector so we need the angle at the centre of the shaded part of the circle (Reflex angle BOA see diagram) 360 - (2 x 53.1) = 253.8 Area of sector is a fraction of the area of the circle in this case =  EMBED Equation.3 x p r2  = =  EMBED Equation.3 x p x 102 M1 M1 = 220.96 cm2 A1 (3) (c) Calculate the area shaded  in the diagram. Area of segment = area of full circle - area of sector - area of triangle  Area of sector = 220.96 cm2 Area of triangle = 0.5 x 16 x 6 = 48 cm2 M1 A1 Area of circle = p x 102 M1 So the shaded area = p x 102 - 220.96 - 48 = 45 cm2 accepted answers from 44.7  45.2 (4) Handling Data Non-Calculator Answers Day 9 17. Alan, Bob, Charles, David, Evelyn and Fay are asked their ages. Alan says 23, Bob says 61, Charles says 57 and David says 21. Evelyn and Fay refuse to give their ages. It is known that two of the men are older than Evelyn and Fay and the other two are younger. It is known that the median value of all the ages is 42. (a) How do you know that the sum of the ages of Evelyn and Fay is 84? Order of ages : 21 23 E F 57 61 M1 Median = 84/2 = 42 2 but not 2 42 = 84 A1 (2) (b) Fay then says that she is twice as old as Evelyn. How old is Evelyn? E + F = 84 F = 2E M1 E + 2E = 84 M1 E = 28 A1 (3) Handling Data Calculator Answers Day 9 18. A football team has to play two games. 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Show your working. between 36 and 37 minutes M1 A1 (2) Handling Data Calculator Answers Day 10 20. A company employs 200 men and 320 women. Each persons job is given a grade (A, B, C or D). The diagrams show the proportions by grade for men and for women. Men (200 employees)  Women (320 employees)  The company wishes to survey a 10% sample of the employees, stratified by sex and by grade. Complete the table to show how many of each group should be sampled. ActualABCDMen68325842Women12880644810% Stratified (rounded)ABCDMen7364Women13865(4) Top 3 grade 6/7 topics I need to study further are: Top 3 grade 7/8 topics I need to study further are:      PAGE 21 20-4-5 20 minutes for 5 days Higher Level A and A* Topics 12 75 135 - 10-4-10 Ten minutes for ten days Higher Level A and A* Topics 12 75 135 - You will need to know this formula!! 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