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Mark your answers to the multiple-choice questions on a Scantron answer sheet. Show all of your work on the test papers (no other scratch paper is allowed). Turn in these test pages with your Scantron answer sheet at the end of the hour. Each question is worth 4 points. Equations and conversion factors that may be useful:  EMBED Equation.3  1. If the net work done on an object is zero, which of the following must be true? 1. The object's speed is zero. 2. The object's speed is constant. 3. The final speed of the object must equal its initial speed. 4. The acceleration of the object is zero. 2. A satellite of mass m is in a circular orbit at an altitude h above the Earth. The work done by gravity in one orbit is: 1. zero 2. mgh 3. 2(mg(h + REarth) 4. none of the above 3. A rubber ball and ball of clay both have the same mass and are thrown with the same speed at a wall. Which one gives a greater impulse to the wall? 1. The rubber ball 2. The ball of clay 3. The impulse is the same for both balls. 4. The answer cannot be determined without knowing the time of contact. 4. When would momentum NOT be conserved in the case of a two-car collision? 1. If there is friction 2. If the road is not level 3. If the cars deform 4. If the cars do not move after they collide 5. Which of the following situations is NOT possible for a one-dimensional collision between two objects with the same mass: 1. one mass has a final speed of zero while the other is moving 2. both objects have final speeds equal to zero 3. the final velocity of one object equals that of the other 4. one object has a final speed that is twice the final speed of the other 5. all of the above are possible 6. Consider a child who is swinging. What is the direction of the net force acting on her when she is at the lowest point in her swing? 1. up 2. down 3. forward 4. backward 7. A satellite is in a circular orbit at an altitude above the Earth equal to twice the radius of the Earth. What is the weight of this satellite compared to its weight on Earth, W? 1. W/2 2. W/3 3. W/4 4. W/9 5. zero 8. If the following objects are released from rest and allowed to roll down the same inclined plane, rank the order that they will reach the bottom of the ramp: 1. roll of masking tape, hockey puck, golf ball, full can of soda 2. golf ball, full can of soda, hockey puck, roll of masking tape 3. full can of soda, hockey puck, golf ball, roll of masking tape 4. full can of soda, golf ball, hockey puck, roll of masking tape 9. Which factor is most important in determining the rotational inertia of an object? 1. the object's mass 2. distribution of the object's mass relative to the axis of rotation 3. the center of gravity 4. the torque applied to the object 10. In the whirlygig demonstration, a ball is swung in a horizontal circle by means of a string that is attached to the rotating ball and passes through a low-friction handle to a heavy mass that provides a constant tension. If the radius of the spinning ball is doubled, what will happen to its angular speed? 1. The angular speed will double. 2. The angular speed will increase by about 40%. 3. The angular speed will be cut in half (50% less). 4. The angular speed will decrease by about 30%. 11. A bowling ball is supported by a 3.0-m cable attached to the ceiling. If the ball is released from rest when the cable makes an angle of 30 degrees from vertical, what is the maximum speed of the ball? 1. 2.8 m/s 2. 5.4 m/s 3. 6.5 m/s 4. 7.1 m/s 12. A 40-N crate starts from rest and slides all the way down a rough ramp that is 3.0 m long and inclined at an angle of 30° to the horizontal. The frictional force between the crate and ramp is 6.0 N. What will be the speed of the crate at the bottom of the incline? 1. 3.3 m/s 2. 4.5 m/s 3. 5.5 m/s 4. 6.2 m/s 13. A certain car with a mass of 1500 kg can accelerate from 0 to 60 mph in 7.0 seconds. What is the average power delivered by this car’s engine? 1. 78 hp 2. 103 hp 3. 386 hp 4. 517 hp 14. A ballistic pendulum consists of a 1.5-kg block of wood that is suspended by strings. A bullet with a mass of 5.0 g is fired horizontally at the block and becomes imbedded in it. Find the initial speed of the bullet if the block and bullet rise together to a final height of 4.5 cm. 1. 17 m/s 2. 130 m/s 3. 265 m/s 4. 280 m/s 15. A 90-kg halfback running north at 10 m/s is tackled by a 120-kg opponent running south at 4 m/s. What is the velocity of both players just after the tackle? 1. 2 m/s north 2. 3 m/s north 3. 2 m/s south 4. 3 m/s south 16. What is the maximum speed that a 1000-kg car can safely negotiate a turn on a level road with a radius of 100 m. Assume the coefficients of static and kinetic friction for this scenario are 0.8 and 0.6 respectively. 1. 24 m/s 2. 28 m/s 3. 31 m/s 4. 36 m/s 17. A ball with a mass of 25 g is held by a string and swung at a constant angular speed of 3.0 rad/s in a horizontal circle of radius 0.50 m. What is the tension in the string? 1. 0.11 N 2. 0.13 N 3. 0.27 N 4. 0.36 N 18. A meter stick balances at the 33-cm mark when a mass of 100 g is hung near the 0 cm mark. The mass of the meter stick is approximately 1. 50 g 2. 100 g 3. 200 g 4. 300 g 19. A bowling ball has a mass of 7.0 kg, a moment of inertia of 0.022 kg-m2 and a diameter of 0.20 m. If it rolls down the lane without slipping at a linear speed of 4.0 m/s, what is its total kinetic energy? 1. 46 J 2. 56 J 3. 60 J 4. 74 J 20. A door has a mass of 15 kg and measures 2.0 m high by 0.8 m wide. If this door is fully open (angle between door and door frame is 90 degrees), what is the minimum initial angular speed to overcome the door's frictional torque of 1.8 N-m and just barely close (so that its final angular speed equal is zero)? 1. 0.7 rad/s 2. 1.3 rad/s 3. 1.8 rad/s 4. 2.7 rad/s 21. 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`„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.h„Š„˜žĘŠ^„Š`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.„ „\žĘ ^„ `„\žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.h „Š„˜žĘŠ^„Š`„˜žOJQJo(·šh „ „˜žĘ ^„ `„˜žOJQJo(oh „p„˜žĘp^„p`„˜žOJQJo(§šh „@ „˜žĘ@ ^„@ `„˜žOJQJo(·šh „„˜žĘ^„`„˜žOJQJo(oh „ą„˜žĘą^„ą`„˜žOJQJo(§šh „°„˜žĘ°^„°`„˜žOJQJo(·šh „€„˜žĘ€^„€`„˜žOJQJo(oh „P„˜žĘP^„P`„˜žOJQJo(§šh„Š„˜žĘŠ^„Š`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜žo(.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.h„Š„˜žĘŠ^„Š`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜žo(.„Š„0żĘŠ^„Š`„0żo(..„Š„0żĘŠ^„Š`„0żo(... „Š„0żĘŠ^„Š`„0żo( .... „8„ČūĘ8^„8`„Čūo( ..... „8„ČūĘ8^„8`„Čūo( ...... „ „`śĘ ^„ `„`śo(....... „ „`śĘ ^„ `„`śo(........„8„˜žĘ8^„8`„˜žo(.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.h„Š„˜žĘŠ^„Š`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„¤„\žĘ¤^„¤`„\žo(.h„Š„˜žĘŠ^„Š`„˜ž.h„ „˜žĘ ^„ `„˜ž.’h„p„L’Ęp^„p`„L’.h„@ „˜žĘ@ ^„@ `„˜ž.h„„˜žĘ^„`„˜ž.’h„ą„L’Ęą^„ą`„L’.h„°„˜žĘ°^„°`„˜ž.h„€„˜žĘ€^„€`„˜ž.’h„P„L’ĘP^„P`„L’.„h„˜žĘh^„h`„˜ž.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø `„˜ž.€„x„˜žĘx^„x`„˜ž.‚„H„L’ĘH^„H`„L’.€„„˜žĘ^„`„˜ž.€„č„˜žĘč^„č`„˜ž.‚„ø„L’Ęø^„ø`„L’.„8„˜žĘ8^„8`„˜žo(.„h„˜žĘh^„h`„˜ž.„h„˜žĘh^„h`„˜ž.„Š„˜žĘŠ^„Š`„˜žo(.€„ „˜žĘ ^„ `„˜ž.‚„p„L’Ęp^„p`„L’.€„@ „˜žĘ@ ^„@ `„˜ž.€„„˜žĘ^„`„˜ž.‚„ą„L’Ęą^„ą`„L’.€„°„˜žĘ°^„°`„˜ž.€„€„˜žĘ€^„€`„˜ž.‚„P„L’ĘP^„P`„L’.„8„˜žĘ8^„8`„˜žo(.€„„˜žĘ^„`„˜ž.‚„Ų „L’ĘŲ ^„Ų `„L’.€„Ø „˜žĘØ ^„Ø 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