ࡱ> ?A>S5@ ?bjbj22 gkXX 7xxxx|||4!4!4!4!,`!LGu!!!!("kkkttttttt$3vRxt|k ` kkktxx!("=u_s_s_skx!p|("t_skt_s2_ss:Ft,2J|t("! `[4!nrt tu0Gu|t yrytxxxxy|t$kk_skkkkktt4!_s4!VI. SPHERICAL TRIGONOMETRY A. Introduction Useful in measuring distance and angles in Spherical surfaces like: 1. Spherical Boilers 2. Distance measurements on earth surface. a. Navigation b. Surveying 3. Satellite observations and calculations 4. Astronomy 5. Other Spherical Problems. B. Definitions Relating To Sphere  Pole  Plane   r   Plane  R = radius  Line  Arc < semi-circle  Pole  Axis 1. Circle - when a plane intersect with the sphere. a. Great circle - Formed when the plane intersect the center of the sphere. b. Small Circle - when a plane intersect the sphere other than the center. Radius of the Great Circle = Radius of the sphere r< Rc =Rs 2. Axis - A line through the center of the sphere perpendicular to the plane of the circle. 3. Poles - The point where the axis pierce the sphere. 4. Straight line - the shortest distance in the space between two points on a sphere. This line does not lie on the surface of the sphere. 5. Arc - the shortest path on the sphere between two points. 6. Length of the arc - the distance bet. the two points - This is expressed in angular unit = to the angle which the arc subtends at the center of the sphere. this can be converted to linear measurement if the radius is known. = ( R C. The Spherical Triangle - is the part of the surface of a sphere bounded by 3 arcs of great circles.  C a  O b  B A c Six Parts: 3 sides: a = BOC 3 Angles: A = B-AO - C b = AOC B = A - BO - C c = AOB C = A -CO -B Note: All the angles and sides are less than 1800 . Although possible to have more than 1800. For Triangles whose side and angle less than 1800. 1. a + b + c < 3600  2. 1800 < A +B + C < 5400 Spherical Excess E = A + B + C - 1800 Characteristics of Spherical Triangle: 1. If the sum of any two sides is greater than the third side, their difference is less than the third side. 2. If two side are equal, The angle opposite are equal. 3. If two angles are equal , the sides opposite are equal. 4. If two sides are unequal, the angle opposites are unequal, and the greater angle opposite the greater side. 5. if two angles are unequal, the sides opposite are unequal and the greater side opposite the greater angle. Spherical Polygon - Part of the surface of the sphere bounded by 3 or more arcs of great circles. For n sides can be divided in (n-2) triangles. E = (A + B + C + D . . .) - (n-2)1800  D. Polar Triangles A' A c' b' c b B C  B' C' a' ABC is a Polar triangle of A'B' C' A'B' C' is a Polar triangle of ABC  Characteristics of Polar triangle: Each angle of the spherical triangle is the suplement of the corresponding side of the polar triangle. A + a' = 1800 A' + a = 1800 B + b' = 1800 B' + b = 1800 C + c' = 1800 C' + c = 1800 Formulas Relating To Right Spherical Triangle  B E sin a = EF/OE = sin FOE a sin c = sin EOD = ED/OE  O F c sin a/sin c = (EF/OE)(OE/ED) C = sin D = sinA  D b sin A = sin a/sinc A sin a = sin A sin c F= C = 900 , D = A, E = B  Right triangles: ODE OFE ODF DFE 10 Formulas for Spherical Triangle: 1. sin a = sin c sin A Theorem of right Spherical Triangle 2. tan a = sin b tan A 1. In a right spherical triangle, any side and the opposite 3. tan a = tan c cos B angle terminate in the same quadrant. 4. sin b = sin c sin B 5. tan b = sin a tan B 2. If any two of the three parts a, b, c terminate in the 6. tan b = tan c cos A same quadrant, the third terminates in the first 7. cos c = cos a cosc quadrant; if any two terminate in different quadrant 8. cos c = cot A cot B the third terminate in the second quadrant. 9. cos A = cosa sin B 10. cos B = cos b sin A F. Napier's Rule  Co-B  a Co-B  co-c a  Co-c Co-A b  Co-A b Napier's Rule: 1. The sine of any middle part is equal to the product of tangents of the adjacent parts 2. The sine of any middle parts is equal to the product of cosines of the opposite sides. Middle part - any of the five. Adjacent parts - 2 next to the middle parts. Opposite parts - 2 remaining parts. Examples: 1. A = 690 50.8', c = 720 15.4', C = 900 Find B, a, b 2. C =900 , A 1200, a = 1000 Find the other parts 3. C = 900, B = 360 42.2, b = 300 17.5' G. Isosceles And Quadrantal Triangle 1. Isosceles Spherical triangle - two sides and two angle equal. This may be solve by dividing it into two right symmetrical triangle.  F B  e d c a  D G E A b C f E = D C = 900 , c = e, b = 1/2 f , A = D = E, B = 1/2 F e = d Example: Find the other parts: F, e = d given: D=E = 800 27', f = 760 42' 2. Quadrantal Triangles: is a spherical triangle having a side equal to 900. The polar triangle of a quadrantal triangle is right triangle. - the solution will based on its polar triangle which is right spherical triangle. Example: c= 900, b =500 A = 700 Find C, B, and a Oblique Spherical Triangle Spherical triangle with no right angle . H. Law of Sine:  C C b h a b a h  A c D B A c B D sin a = sin b = sin c sin A sin B sin C I. A.Law of Cosine for side.  C C b h a b a h  A m c-m m-c c D B A c B D m cos a = cos b cosc + sin b sin c cos A cos b = cosc cosa + sinc sina cos B cos c = cos a cos b + sina sin b cosC B. Law of Cosine for Angles: Cos A = -cosB cosC + sinB sinC cosa Cos B = -cosC cosA + sin Csin C cosb Cos C = -cosA cosB +sinA sinB cosc. Law of Tangents: Tan (A-B) = tan (a-b) Tan (A+B) tan (a+b) Half-Angle Formula: Tan A = tan r/sin(s-a) Tan B = tan r/sin(s-b) Tan C = tan r/sin(s-c) Where:  s = (a +b +c) Half Side Formula: Tan a = tanR cos(S-A) Tan b = tan R cos(S-B) Tan c = tan R cos (S-C)  Where S = (A+B+C) Napiers Analogies:   Tools in solving spherical triangle 1. Law Of Sine 2. Law Of Cosine For Sides And Angle 3. Napier's Analogy 4. Area Of Spherical Triangle ( R2 E A = 1800 Where: R = the radius of the sphere E = Spherical Excess = A + B + C - 180 for any triangle.  tan 1/4 E = tan 1/2 s tan 1/2(s-a) tan 1/2 (s-b) tan 1/2(s-c) s = 1/2(a+b+c) - for any triangle. E = Sum of all angles - (n-2)1800 - for n- no. of angles. Example: 1. C = 900, B = 360 42.2', A = 680 12.2' , R = 20 m Find the area 2. a = 510 35.6', b = 300 17.5', c = 570 33' R = 50 m Find the area M. 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