ĐĎॹá>ţ˙ ĆČţ˙˙˙ŔÁÂĂÄĹ˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙˙ěĽÁM đżŠçbjbjâ=â= P‚€W€WE–d˙˙˙˙˙˙l¨¨¨¨dddôX<@<@<@<@T@XŹÖ¤°A°A°A°A°AÝ[Ý[Ý[ËŇÍŇÍŇÍŇÍŇÍŇÍŇ$PŘ pÚbńŇudÝ[ŰYÝ[Ý[Ý[ńŇßq¨¨°A°A+fÖßqßqßqÝ[쨆°Ad°AËŇßqÝ[ËŇßqxßqWrfgĘp.6dOŃ°A¤A ĐčhÚ24ÍXä=<@ÉjX×ĚDOŃ||Ö0ŹÖÍ4ŇÚ!qžŇÚOŃßqXX¨¨¨¨ŮStats Tri 1 Review Chapter 1 Statistics – the science and art of learning from data Data – numbers with a context Probability – the study of chance behavior; The regular pattern of something occurring that becomes clear after many trials; chance behavior is unpredictable in the short run but has regular and predictable patter in the long runl helps us make reasonable conclusions Statistical inference – produced answers to specific questions and statements of how confident we can be that the answer is correct. Available data – data that was produced in the past for some other purpose but may help answer a present question Data beats personal experience because data describes overall pattern not a few instances. Observational study – observes individuals and measure variables of interest but do not attempt to influence their responses. Surveys – popular way to gauge public opinion Experiment – deliberately do something to individuals in order to observe their responses. Cause and effect 3 Characteristics of a GOOD experiment: control group, randomization, and replication. Data Analysis – statistical practice of analyzing distributions of data through graphical displays and numerical summaries; organizing displaying and summarizing data Individuals – the objects described by a set of data; individuals may be people, animals, or things Variable – any characteristic of an individual; can take different values for different individuals Distribution – description of values a variable takes on and how often the variable takes on those values Begin by examining each variable by itself, and then study the relationship among variables. Begin with a graph or graphs, and then add numerical summaries of specific aspects of the data. Categorical Variables – places an individual into one of several groups or categories Distributions list the categories (X) by the count of each or the percent of individuals (Y) Bar graphs and pie charts Ex: Color, Gender, Grade, months, rock band Quantitative variable – takes numerical values for which arithmetic operations such as adding and averaging make sense. Distributions list the values (X) and number of times the variable takes on the value(Y) Dot plots, stem plots, histograms, box plots Ex: goals, score, time Dot plots – for quantitative data X= Goals per game Y= Number of times that occurred (frequency) Stem plots – Quick picture of the shape of the distribution while also including numerical values. Use for SMALL data sets!! You can double the number of stems therefore reducing the number of leaves. Back to back stem plot: when you are comparing 2 sets of data looks like: 4321|1|1234 ALWAYS write the leaf unit!! Unit 1: 31=3|1 Unit 0.1: 3.1= 3|1 Unit 1000: 10,000 and 11,000 = 1|01 Numbers on the far left of the graph show total values up to that point EX: 1 0|1 3 1|34 3 2| 7 3|6778 Histogram – break the range of data values into classes and displays the count or percent of observations that fell into that class [frequency]. Quantitative data Shows shape of data Use with LOTS of data Divide the range of data into equal classes Count observations in each class = frequency BARS SHOULD TOUCH Calculator: Xlist = L1; Freq = L2; to change the number of bars do XCL=[(max-min)/classes]+1; Xmin and Xmax is max/min of data; Ymax is largest frequency of data Bar Graphs – for categorical data Side by side bar graph: compares 2 qualitative variables Pie Charts – for categorical data To show the part compared to the whole. Data equals 100% Summarize Data and graph: Center, Shape, Spread, Outliers Skew: Skewed right: tail to the right (Mean is larger than Median) Skewed left: Tail to the left (Mean is less than Median) Uniform: Square shape (Mean = Median) Approximately normal/symmetric/mound/unimodal: Upside-down U (Mean = Median) Bimodal: M shape Outlier – observations that lie outside the overall pattern of distribution Frequency graph - histogram that shows the total number of times (frequency) of each X value Cumulative frequency graph – adds up all the data from each previous bar. The last bar is the total of all the values. Relative frequency graph – histogram that shows percent of each X value. All bars should add up to 100% Relative Cumulative Frequency Graph/OJIVE – can be line graph or histogram what shows a cumulative percent of all of the data. Last bar should be 100% Time plot – drastically changes due to variations in the Y variable with time. Looks like ^v^^vv^v^ Measures of center: Mean – Population mean= ź; Sample mean = Xbar ; very NONresistant to outliers; Average value; is the  balancing point of a density curve if it were made of a solid material. Median   Q2 or  M ; RESISTANT to outliers; Typical value; divides the area under a density curve in half Measures of spread: Range: High-low; Very nonresistant Quartiles: Inter-Quartile Range; Resistant to measures of spread {IQR=Q3-Q1} Q1 = Median of bottom 50% Q3 = Median of top 50% Outlier Test “1.5 IQR RULE” Q1-1.5IQR or Q3+1.5IQR Standard of Deviation: The average distance of all data points away from the mean Sample Standard of deviation = Sx Population Standard of deviation = Ą Equals zero when the data is one value Variance: Var; The squared standard of deviation; the larger the distance a value is from the mean in EITHER direction, the larger the variance. NOT on calculator so SQUARE Sx!! Sx2 or Ą2 5 Number Summary = Min-Q1-Med-Q3-Max; use 1-Var Stats Box Plot MIN-Q1-MED-Q3-MAX |-------- | ----------| {25%}{ 50% }{25%} Modified Box Plot MIN-Q1-MED-Q3-MAX Outlier |-------- | ----------| x Linear Transformations - when converting units, the measure of center and spread will change. HOWEVER linear transformations will only change center and spread but not shape. Multiplying each observation by b multiplies mean, median, IQR, and range Adding b to each observation adds b to mean, median, IQR but does not affect spread. Chapter 2 Standardized Value – one way to describe relative position in a data set is to tell how many Sx’s above or below the mean the observation is. Z-Score – How many standard of deviations away from the mean the value is. Z=(X-Xbar)/(Ą/"n) +Z is above mean; -Z is below mean The larger Z the larger the spread of data (roughly between -3 and 3) Percentiles  Measure of relative standing Pth percentile is value with P% of observations AT or BELOW is Ex: Jenny scored an 86% 22/25 scores are d" 86% Jenny is the 22/25 = 88th percentile Chebyshev s Inequality  Density Curve  An idealized description of the overall pattern of a distribution. An area underneath =1 representing 100% of observations Area (Total) = Portion, Probability, Percentage of data Normal Density Curve = Mound/Bell; Mean=Median Mean = ź Uniform Distribution = Rectangle/Box shape Sx is at the inflection points 68-95-99.7 Rule 68% of data falls between -1 and 1 Z 95% falls between -2 and 2 Z 99.7% falls between -3 and 3 Z Standard Normal Distribution  mean of zero and a Sx of 1; N(0,1) or N(ź, Ą); when given the N() use the numbers to construct your graph Z-score table in front of book  given Z-Score of 2.85 look for 2.8 on left and .05 on top; find where they meet and that is the area to the LEFT of that z-score Any value in table that is off of the chart is assumed .0001 or .9999 Solving Z-Score Problems!! State the problem in terms of X; DRAW A PICTURE and shade area of interest Standardized and Draw a picture Write X in terms of Z-Score and show calculations Write as Ex: P(Z>2.33) = 1-.9901 = .0099 Write answer in context of the problem. Assessing Normality Construct a Histogram or Stem plot (Look at shape, check mean=median, compare to 68-95-99.7) Construct a Box plot and check for any skewness or outliers Construct a normal probability plot/Quartile Plot (must look like a straight line) Calculator: Graph info by selecting Statplot (Last graph option); Zoom 9 Calculator instead of Z table: 2nd; VARS Normalcdf(Z1, Z2) Gives area between 2 Z-Scores Normalcdf(X1, X2, ź, Ą) Gives area between 2 X values given Mean and Sx If the X value is off the graph to the right or left use X1 = -1EE99 X2 = 1EE99 EE = 2nd comma InvNorm(Area) = Z Score InvNorm(Area, ź, Ą) = X Chapter 3 Response Variable  Measures the outcome of the study; Dependant Variable; Y value Explanatory Variable – Helps explain or influence changes in the response variable; Independent Variable: X value Scatter plot – Shows the relationship between 2 QUANTATIVE* variables measured on the same individuals *(so that you can calculate r) Interpreting: Look for overall pattern and any striking deviations Describe Direction (+/-), Form (linear for Ch. 3), Strength (Strong/Moderate/Weak) Look for outliers and effect on correlations Association: X^=Y^ XÇ=YÇ X^=YÇ Insert sequence into L1 given an equation: 2nd List; OPS; Seq(equation, variable, start, # of numbers) Sto L1 Correlation  measures strength and direction Correlation Coefficient: R; is between (-1,1) ONLY measures LINEAR VERY nonresistant to outliers Doesn’t account for X or Y; doesn’t matter which is which Doesn’t change if X and Y are multiplied by a constant No unit of measurement Coefficient of determination: R2; “what percent of the variation in Y is explained by the least squares regression line?” The bigger the R the better fit for the line Regression Line – line that describes how a response variable y changes as the explanatory variable X changes Interpolation – makes assumptions/predictions inside the range of the data Extrapolation – makes them outside of the data y=a+bx Least Squares Regression Line (LSRL) – y on x is the line that makes the sum of the squared vertical distances of the data points from the line as small as possible. Linear only! Point (Xbar, Ybar) is any point ON THE LINE! = centroid w=a+bx a = y intercept = Ybar-b(Xbar) b = slope = r (Sy/Sx) *In your packet Calculator for equation: Stat; calc; #8; LinReg(a+bx) L1, L2, Y1 Invalid dim? Check your lists for uneven lists R doesn t appear? 2nd catalog diagnostics ON Influential Points Outlier becomes an influential point when it substantially changes the R of the regression line C = Centroid If the Y value of the centroid is changed, the slope of the LSRL stays the same but r becomes closer to zero because the line has shifted away from the bulk of the points. Y intercept changes. If the influential point is way off of the data randomly, it makes r closer to zero If the influential point is on the LSRL but further out, the r value significantly increases.  Lurking Variables – there is some other variable that has a relationship with both variables compared that shows the two compared variables don’t have anything to do with each other. Ex: Ice cream sales increases; Drowning increase; Lurking Variable = Temperature increase/Summertime Residual – the difference between an observed variable of the response variable and the value predicted by the LSRL Residual = y- w or Observed y  Predicted y Every point has a residual Tells how appropriate the model is for the data If there is no pattern then it s a good model MUST do a new regression line calculation to update a residual graph after making data changes. Stat plot; 2nd graph option; make Ylist: RESID by doing 2nd Stat RESID Graph X value (X) by Resid (Y) and give title!! Chapter 4 *** X is typically L1 Y is L2 Log X is L3 Log Y is L4 Linear Equation – y=a+bx LinReg(X, Y, Y1) COMMON DIFFERENCE: y2-y1 H" y3-y2 etc r, r2 **ONLY linear! Exponential Equation  y=abx (Exponential Graph) Linearized Equation: LinReg(X, Logy, Y1) => log w = a+bx (Makes a linear graph) Linear relationship between X and LogY, but the relationship between X and Y is exponential Inverse Transformations: w = 10a(10b)x *OR* ExpReg(X, Y, Y1) = w = abx Makes exponential graphs Notice: 10a H" a 10b H" b When you calculate LinReg or ExpReg, you get r and r2 COMMON RATIO: y2/y1 H" y3/y2 etc Power Equation  y=axb (Power Graph) Linearized Equation: LinReg(LogX, LogY, Y1) => log w = a+b(logx) (Makes a linear graph) Linear relationship between LogX and LogY, but the relationship between X and Y is power Inverse Transformations: w = 10axb *OR* PwrReg(X, Y, Y1) = w = axb Makes power graphs Gives you r and r2 (0,0) usually makes sense in the context of the problem Do Transformations graphically… (Log) Y1= a+bx or (Log)Y1=a+b(Logx) Y2= 10^Y1 Use Residual graphs to check for fit of the equation and r2 Exponential or Power? Check for Common Ratio, (0,0), or the context of the question (what it asks for) If the explanatory variable is ‘years’ you may use ‘years since…’ so the numbers are smaller Relationship between two categorical Variables To analyze categorical data we use counts or percents of individuals that fall into various categories 2 way tables Bar graphs (side by side bar graph?) Marginal Distribution – totals of each row or column in the bottom and right side of the graph Conditional Distribution – comparing the percent of “infected and inoculated” with “Infected and not inoculated” and if there were more inoculated options, compare those too No graph (such as scatter plot) can show the relationship between two categorical variables. No single numerical measure (such as correlation) can summarize the strength of the association either. Simpsons Paradox – An association or comparison that holds for all of several groups can reverse direction when the data are combined to form a single group. Each group has positive association but when they are all together they form a negative association. CAUSATION: In the absence of experimental evidence, good evidence of causation requires: Strong association that appears consistently in many studies Clear explanation for the alleged casual link Careful examination of possible lurking variables Causation – when X definitely causes Y to happen; the variables are correlated Common Response – there is a lurking variable Z that relates X and Y; X and Y are correlated; Ice Cream and drownings example Confounding – Either X or Z causes Y or a combination of the two; X and Y are correlated; Visiting the elderly with tea and improving mood  1) 1) 2) 3) Chapter 5 Observational Studies – Chapter 1 Experiment – Chapter 1 Population – entire group you desire data from Sample – Part of the population (CAN be the whole population too) Census – attempts to contact every individual in the entire population; a sample of the WHOLE population Sampling – studying a part of the population in order to gain information about it as a whole. Biased Sampling – systematically favors certain outcomes Voluntary response sampling – people who choose themselves by responding to general appeal. People who volunteer usually have a strong opinion, especially negative. Convenience Sample – choosing individuals who are easiest to reach Probability Sampling – sample chosen by chance Simple Random Sample (SRS) – each individual from the population has the same chance of being selected. Larger random samples gives us more accuracy than smaller samples Uses table of random digits Lable – assign numbers to individuals Table – select labels at random Stopping rule – indicate when to stop Identify Sample – Identify subjects of the selected labels Write out EVERYTHING!! Stratified Random Sample – divide population into groups (Strata) and choose an SRS from EACH stratum (You aren’t randomly selecting which stratum, just smaller samples from each stratum). Each stratum contains similar individuals; each stratum has different individuals than the other strata; every person within each stratum has the same chance as another person in the same stratum of being chosen. Like blocking in Experiments Cluster Sample – divides the population into groups or clusters. Some clusters are randomly selected. Then ALL of the individuals in the chosen cluster are selected to be in the sample. Each cluster has the same probability as the other clusters of being chosen. Systematic Random Sample – divide the population into the same number of groups you want. Randomly select a number from one group and that number individual from each group is chosen. 1 4 7 10 SRS 2 2 5 8 11 3 6 9 12 Multistage Sample – SRS a country then SRS a state then SRS a city then SRS a subdivision… Bias (WE RUN) Wording Effect Response Bias – interviewer or interviewee may respond differently when being studied. Situation or lying Under coverage – individuals not represented by the sample Nonresponse – individuals who cannot be reached, who don’t respond, or who don’t cooperate Experiment Experimental Units/Subjects – Objects/People being experimented on Factors – Explanatory Variable (Ex. Color paints) Treatment – Experimental condition applied to the units (Ex: Red, Blue, Green, Yellow) Levels – (Ex: Amount of paint and Brand of paint) Each has its own box corresponding to another level from another factor: L1 L2 ----|---- Placebo – dummy treatment to eliminate bias Control Group – overall effort to minimize variability in the way the experimental units are obtained and treated Randomization – the rule used to assign experimental units to treatments ***LABLE IN CHART! <=> Principles of Experimental Design Control the effects of lurking variables on the response, most simply by comparing two or more treatments Replicate each treatment on many units to reduce chance variation on the results Randomize use impersonal chance to design experimental units to treatments Statistically Significant – an observed effect so large that it would rarely occur by chance. Block Design – Group of experimental units or subjects that are known before the experiment to be similar in some way that is expected to systematically affect the response to the treatment. Matched pairs design – compares two treatments on two similar subjects to eliminate differences or compare two treatments on one subject. Randomization occurs when giving the subjects which treatment or giving the one subject which treatment first or second. Random numbers on the calculator – Math Prob RandInt(first number, last number, # of numbers desired) Chapter 6 Relative Frequency – Number of times an event occurs when PERFORMING it (5 heads 6 tails) Probability Model – Theoretical Probability (50/50 Chance you get heads or tails) Simulation – not actually doing the act but simulating it in some way (On calculator) Probability of Finite samples  the probability of any event is the sum of the probabilities of the outcomes making up the event. OR = Ĺ = Add AND = #Ŕ = Multiply Use Tree Diagrams and Venn Diagrams for probabilities!! At Least 1/One Or More = 1-NONE Probability that B occurs given A occurs& . Use P(B|A) Conditional Probablity P(A|B) = P(AŔB)/P(B) **In Packet Mutually Exclusive  Two events have no outcomes in common Independence  The probability of one event doesn t effect the probability of another. If something is mutually exclusive, it CANNOT be independent. Visa Versa applies P(AĹB) = P(A)+P(B) (MUTUALLY EXCLUSIVE events) P(AĹB) = P(A)+P(B)-P(AŔB) (INDEPENDENT events) P(AŔB) = P(A)+P(B) (INDEPENDENT events) P(AŔB) = P(A|B)P(B) (Not independent  calculated from P(A|B) Equation) Try to use a table to further understand conditional probability: Event AEvent BTotalsEvent C51015Event D152035Totals203050P(A|C) = 5/15 P(B|D) = 20/30 P(AŔC) = 5/50 Stats Tri 2 Review Chapter 7 Discrete Random Variable  X has a countable (Integer 1, 2, 3) number of possible variables. Probability Distribution: lists the values and their probabilities and a histogram 0d"P(x)d"1 Sum of all P(x) = 1 Expected Value = Mean of discrete random variable Calculator: 1-Vars Stat L1, L2 (L1=X; L2=P(x)) Continuous Random Variable – X has a measurable (all Real numbers +/- decimals etc) number of possible variables. Probability distribution: Density curve (doesn’t have to be normal) A fraction makes sense as an answer Xd"A = X<A Lines have no area/value INDEPENDENCE??? Below źx+y=źx+źy Ąx+y=" Ąx2+ Ąy2 Ą2x+y= Ąx2+ Ąy2 źx-y=źx-źy Ąx+y=" Ąx2+ Ąy2 Ą2x+y= Ąx2+ Ąy2 źax+b=aźx+b Ąax+b=aĄx Ą2ax+b= a2(Ąx2) Find Mean and SD of Y=.9x-.2 given the mean and SD of X. źy=.9(źx)-.2 Ąy=.9(Ąx) Chapter 8 Binomial Setting Conditions Each observation falls into one of two categories: Success or fail The n observations are independent. That is, knowing the result of one observation tells you nothing about the other observation. The probability of success, p, is the same for each observation Fixed number n Binomial Distribution – the distribution of the count X of successes in the binomial setting with parameters n and p. the parameter n is the number of observations and p is the probability of a success on any one observation. The possible values of X are the whole numbers from o to n (discrete). as an abbreviation we say that X is B(n,p). Sampling Distributions of a Count – choose an SRS of size n from a population with proportion p of successes. When the population is much larger than the sample, the count X of successes in the sample has approximately the binomial distribution with parameters n and p. p = success q = fail ź = np Ą = "npq *Given in packet Binomial probability: P(X=r) = (nCr)(pr)(qn-r) **5C5 =1 so you can do just (pr)(qn-r) Calculator: P(X=r) = Binpdf(npr) P(Xd"r) = Bincdf(npr) P(X<r) = Bincdf(np(r-1)) P(Xe"r) = 1-Bincdf(np(r-1)) P(X>r) = 1-Bincdf(npr) Normal approximation to Binomial Distributions: You can use Normalcdf when ne"30; N(np, "npq) Geometric Setting Conditions Each observation is a success or fail Independence Same probability of success for each observation The variable of interest is the number of trials required to obtain the first success Xbar = 1/p (Expected Value) Var = q/p2 Ą = "q/p2 Geometric Probability  if X has a geometric distribution with a probability p of success and q of failure on each observation, the probability that the first success occurs on the nth trial is P(X=n) = qn-1p Graph is always skewed right because the first nth success could be infinity. X`"0 Never can have first success after 0 tries Probability that it akes more than n trial sto see first success: P(X>n) = qn All cdfs have the same trend as binomial except it is: geocdf(P,r) geopdf(p,r) Calculator Strokes: (for binomial) P(X=r) binpdf(n,p,r) P(Xd"r) bincdf(n,p,r) P(X<r) bincdf(n,p,r-1) P(Xe"r)1-bincdf(n,p,r-1) P(X>r)1-bincdf(n,p,r) Calculator Strokes: (for geometric) P(X=r) geopdf(p,r) P(Xd"r) geocdf(p,r) P(X<r) geocdf(p,r-1) P(Xe"r)1-geocdf(p,r-1) P(X>r)1-geocdf(p,r) Chapter 9 Parameter  a number that describes a POPULATION. In stats the value of the parameter is unkown because we cannot examine the entire population ź, Ą, Ą2, N, P Statistic  a number that can be computed from a simple random sample Xbar, Sx, Sx2, n, phat Sampling Distribution  like meta analysis; the distribution of values taken by the statistic in all possible samples of the same size from the same population Unbiased  P= Phat or źphat = Phat As n increases, the distribution gets taller and narrower Sample n=100 (short wide mound) Sample n=500 (medium mound) Sample n=1000 (Tall thin mound) Short Answer Steps for Mean and Proportion Problems: Rule of Thumb 1: N>10n Rule of Thumb 2: npe"10 ; nqe"10 ; OR ne"30 Problem Statement: P(Phat, Xbar e" #) Z-score Draw/shade curve Calculate Conclusion RESTATE QUESTION Cut variation (Ą) in half? 4n = .5 Variation Ą/"n & . Ą/"4n = Ą/2"n Mean Problem Given Ą Conditions: SRS Normality: Problem Says so OR Graph OR ne"30 Independence: N>10n Statistic (Xbar, Ą/"n) Parameter (ź,Ą) Z= (Xbar- ź)/(Ą/"n)  xbar= Ą/"n P(Xbare"d"#) when n>1 P(Xe"d"#) when n=1  A Proportion Problems P is like ź Phat is like Xbar  phat="pq/n Conditions: SRS Normality: Problem Says so OR Graph OR npe"10 and nqe"10 Independence: N>10n Phat = r/n (R= number of successes; n= Number in sample) Z= (Phat  P)/("pq/n) P(Phate"d"#) always Bias has to do with center not spread of a sampling distribution Parameters are fixed, while statistics vary depending on which sample is chosen Chapter 10  estimating where ź is with confidence Statistical Inference  provides methods for drawing conclusions about population from sample data Confidence interval  A level C confidence interval for a parameter has 2 parts A confidence interval calculated from the data usually in the form: estimate ą margin of error = C A confidence level C which gives the probability that the interval will capture the true parameter (mean or proportion) value in repeated samples. Therefore the confidence level is the success rate for the method. Critical Values: z* and t* with the probability of p lying to its right under the standard normal curve called the upper p critical value Margin of Error – indicates how much error can be expected because of chance variation in randomized data production. It doesn’t account for other errors such as undercoverage or nonresponse. “Find it within” or “with a margin of error of”; always given; ROUND UP; length of the interval = 2(Margin of Error); decreases when… z* decreases/C decreases Ą decreases n increases Toolbox: Parameter: Identify the population of interest and the parameter you want to draw concludions about. Conditions: SRS Normality (ne"30; np>10, nq>10; graph, or it s stated, EXPLAIN and draw graph) Independence (10nd"N) Calculations Interpretation:  we are % confident that the true population mean of ___ lies within the interval (__,__) Mean Problems; [One Sample] Z Distributions: Known Ą z* Find using Invnorm(area below) ne"(z* Ą/m)2 m = Margin of error C = (Xbar ą z*( Ą/"n) Calculator: ZInterval Margin of Error = z*( Ą/"n) Mean Problems; [One Sample] T Distributions: UNKNOWN Ą t* find using t* table in packet and df (n-1); CRITICAL VALUE ne"(t* Sx/m)2 C = (Xbar ą t*( Sx/"n) Calculator: TInterval With data use calculator to get Xbar and Sx Margin of Error = t*( Sx/"n) STANDARD ERROR = Sx/"n (The estimated SD from given data; we guess it because its not given) T Distributions always have a slightly larger spread than a normal distribution due to standard error (Estimated SD) and therefore more variation. As degrees of freedom increases, the density curve approaches the normal distribution. Paired T Procedure – used to compare the responses of two treatments in a matched pairs design or before-and-after measurements on the same subjects, apply one-sample T procedure to the observed difference Proportion Problems: Unknown Ą; You don t need it Normality (of test): npe"10; nqe"10 Normality (of confidence interval): nphate"10; nqhate"10 C = phat +-z*("phatqhat/n) Calculator: 1PropZInt( X = nphat Round to nearest whole # ne"(z*/m)2p*q* p* is given from a previous study otherwise its .5 Margin of Error = z*("phatqhat/n) Outliers strongly influence Xbar therefore can skew CInterval If Xbar is in the range of confidence it will ALWAYS contain ź Chapter 11 Null Hypothesis  (Ho) Statement being tested in a significance test; significance test is designed to assess the strength of the evidence against the null; ź=# Alternative Hypothesis  (Ha) Claim about the population that we are trying to find evidence for; ź(>,<,`")# Ho and Ha always use the same # Two sided: doesn t specify if null is more or less than ź ; Ex:  test if different than ź or  or true in your school P-values  Probability computed assuming that Ho is true, that the observed outcome would take a value as extreme or as more extreme that that actually observed. The smaller P-value is, the stronger the evidence against the null provided by the data; area above Z (or Xbar) P<ą (reject the null) P>ą (Fail to reject null) 2 Tailed test: Find Z using Xbar given and calculate P (area from Z to tail) then double it for both tails = 2P (Alpha is half and P is doubled when calculated this way) If given a Pvalue and an alpha, divide both in half Significance level  (ą) Fixed value; Use for when you want an exact reject or fail to reject answer (factory setting); means we reject the null; Same as Type 1 Error; “Not likely to happen by chance” If we aren’t given alpha….. P<.01 Strong evidence to reject Ho .01.1 Fail to reject Ho Inference Toolbox: Define: Population, Parameter, Ho/Ha Conditions for significance Test: SRS (say so? Assumed? Elaborate.) Normality (ne"30, Graph [skewness/outliers?], says so. Elaborate/restate the obvious) Independence (10n<N) Calculations: (Calculator: Ztest(& )) ZTEST!!! Probability Statement Test Statistic: Z= (Xbar- ź)/( Ą/"n) (LIKE XBAR) Z* = Alpha area P-value = normalcdf(Z, 1E99, ź, Ą/"n) ****OR [2](-1E99, -Z& ) Draw Graph Conclusion  State: Fail to reject/reject null that ź=#; include meaning of variables (from problem) because P>< ą; and say strong/moderate/weak evidence if no alpha is given. Confidence Intervals  Reject the null if the confidence interval doesn t contain the mean (Very simple to find, use logic and Z values or Xbars) Type 1 Error  We reject the null when the null is true; ą; ( Type 2 Error  We fail to reject the null when the null is false; ˛; ( Power  We reject the null and the null is false; 1- ˛; ( Increase power: Increase ą Decrease Ą Increase distance źa is away Increase n Xbar = Z* (Ą/"n)+ źo Calculating Beta: Right Tailed (ź>) Normalcdf(-1E99, Xbar, źa, Ą/"n) Left Tailed (ź<) Normalcdf(Xbar,1E99, źa, Ą/"n) Two Tailed (ź`") Normalcdf(Xbar1, Xbar2, źa, Ą/"n) When performing a significance test& . Want to asses the strength of P-value, compare to .01, .05, .1 values of ą Chapter 12 SO much like Chapter 11. All the same concepts except we are including mean tests (Z and T), proportion tests (Z), and matched pairs test (L1-L2 = calculate using L3); Uses Chapter 9 also Mean Problems: Z-Test (use on calculator to get Z and P) Given Ą Z-Score = (Xbar-ź)/(Ą/"n) Pvalue = normalcdf T-Test (use on calculator to get T and P) NOT given Ą, must use Sx T-Score = (Xbar-ź)/(Sx/"n) Uses Degrees of Freedom (n-1) Find Pvalue: tcdf(t1,t2,df) Confidence Interval: Use df and C on t-table to find P Proportion Problems: 1-PropZTest (use on calculator to get Z and Phat) Phat (like xbar) and qhat = (1-phat) NOT given Ą (you don t need it) Ho: P=Po Ha: P ><`" Po ALWAYS Z-score = (Phat-P)/ "(PoQo/n) Pvalue = normalcdf Confidence Interval: Use 1-PropZInt (X is number of successes) Normality (of confidence interval): nphate"10; nqhate"10 Matched Pairs (L1-L2 = Calculate stuff using L3) Parameter:  True mean difference/population proportion difference of ____ between (L1) and (L2) œ(L1)-(L2) P(L1)-(L2) May be a Mean (Z or T) or Parameter (Z) Problem Conclusion: [Fail to] reject the null that the true mean/proportion difference between L1 and L2 is ___ Confidence Interval: We are C% confident that the actual mean/proportion difference… is in the interval Use already stated calculator strokes for confidence interval depending on Mean or Proportion problems Chapter 13 Comparing the difference between two population means 2 Proportion Z Test Population Parameter: P1= (Population 1) Proportion of … (Ex: people who experience adverse symptoms taking ibuprofen) P2= (Population 2) Proportion of & (Ex: people who experience adverse symptoms taking acetaminophen) Ho: P1=P2 Ha: P1`"><P2 Conditions (must do conditions for both populations P1 and P2) P1 SRS? Normality: (n1)(Phatc) e" 10 (n1)(Qhatc) e" 10 Independence: 10n1<N1 P2 SRS? Normality: (n2)(Phatc) e" 10 (n2)(Qhatc) e" 10 Independence: 10n2<N2 Calculations: 2 Proportion Z test Phatc = (R1+R2)/(N1+N2) **R=number of successes **Just Phat on calculator Z= [(Phat1-Phat2)  (P1-P2)]/"[(Phat1Qhat1/n1)+(Phat2Qhat2/n2)] **P1-P2 usually is 0 Conclusion: [fail to] reject null that there is no difference between P1 and P2 Confidence Interval: Conditions: SRS (Same as above); Independence (Same as above); Normality: (n1)(Phatc) e" 5 (n1)(Qhatc) e" 5 (n2)(Phatc) e" 5 (n2)(Qhatc) e" 5 Calculations: (Phat1-Phat2) ą Z* "[(Phat1Qhat1/n1)+(Phat2Qhat2/n2)] Conclusion: the true difference in P1 and P2 is in the interval& 2 Sample Z test Population Parameter: True mean difference between ź1 and ź2 Ho: ź1= ź2 Ha: ź1<>`" ź2 Conditions (x2): SRS Normality: n1e" 30 Independence: 10n1<N1 SRS Normality: n2e" 30 Independence: 10n2<N2 Calculations: (Xbar2-Xbar1)/"(Ą12/n1)+( Ą22/n2) P(Z><`"#) Confidence Interval: (Xbar2-Xbar1) ą Z* "(Ą12/n1)+( Ą22/n2) 2 Sample T test: Same as Z test except replace Ą with Sx and Z with T Use DF!!! Either given on calculator (more exact) or take the smallest n value of both populations and subtract one df = n-1 Chapter 14 Goodness of Fit Test A goodness of fit test is used to help determine whether a population has a certain hypothesized distribution, expressed as proportions of individuals in the population falling into various outcome categories. Observed Counts – always whole numbers; L1 Expected Counts – should be a percent of whole and will be the same for every category; L2 Chi Square – L3 = (L1-L2)2/(L2) then 1var stat L3 and Ç2="x L3=Components of Ç2 Chi Square Test Statistic  measures how well observed counts match/fit expected counts assuming the null is true. Ç2= "(Obs  Exp)2/(Exp) Ç2="L3 Degrees of freedom = (Categories-1) Ç2 distribution is a density curve – total area under the curve is 1 Curve begins at zero and is SKEWED RIGHT ALWAYS and therefore its NOT a normal distribution As the degrees of freedom increase, the more the curve resembles the normal distribution Toolbox: Population Parameter: Ho: The actual population proportions are equal to the hypothesized proportions; There is no difference/association/dependence/relationship Ha: At least one of the actual population proportions differ from their hypothesized proportions; there is at least 1 difference between observed and expected values. Conditions: All expected counts are at least 1 No more than 20% of expected counts are less than 5 List the numbers if possible to prove that they meet conditions or write out expected matrix Calculations: GOODNESS OF FIT TEST Ç2= "(Obs  Exp)2/(Exp)& Write out a couple examples to prove you know what to do. Df = (Categories-1) ALWAYS Right tailed test: P(Ç2>#) Ç2cdf(Ç2,1E99,df) = Pvalue Conclusion: [fail to] Reject the null that there is no difference& Two Way Table  Chi Square Test for Independence Counts are the elements of a matrix with r rows and c columns. This is called an r*c Table THE ONLY DIFFERENCES: Make sure Observed counts are in a 2 way table Make a 2 way table for expected counts: Each cell is calculated individually. Expected Count = Row total*Column total/Table total Can be done on calculator: Plug Observed counts into matrix [A]; Stat, tests, Ç2tests; Observed matrix is the matrix you filled in (In this case matrix [A]) and Expected matrix is the matrix you want the expected data to be put into (This case [B] makes sense). Calculate To find Expected Matrix go to matrix, select [B] and hit enter. Fill in data Count cells by counting from right to left, top to bottom We compute the row or column percents by dividing the cell count by the row or column total Chi Square Matrix Same number of cells as Observed and Expected tables/matrix Each cell is individually calculated using the formula (Obs – Exp)2/(Exp) and then every cell value is added up to get Ç2="cells. This can all be done on the calculator using the Ç2test The component that is the most significant is the one with the largest value The toolbox is the same as the Goodness of fit test. The only difference is the change in how to organize observed and expected data and calculate chi square. The only extra addition of work is under the Calculations portion of the toolbox, add in the formula: Expected Count = Row total*Column total/Table total to prove you know how to calculate the expected value and give an example calculation. Note: a matrix with an r or c value of 1 cannot exist, if this is the case; use a goodness of fit test, not two way tables. Chapter 15 How is this different from Chapter 3? We use a sample of data and calculate a regression line and test if the sample slope (b) is a good estimator of the true population slope (˛) (Do a T-Test to reject or fail to reject the slope) How is this different from chapter 14? We are testing association between two Quantitative variables rather than two categorical variables. Given data, carry out a significance test (Just like before) Parameter: Ho: ˛=0 There is no association between x and y Ha: ˛`",>,<0 There is An/positive/negative association between x and y *Use `" if it doest specifically say +/- association Conditions: Repeated responses y are independent of each other The true relationship is linear (w=a+bx makes sense and residual plot shows no pattern) The standard deviation about the true regression line is constant For any fixed value of x, the response y varies according to a normal distribution (a normal probability plot of the residuals is linear) Calculations: LinRegT-Test (On calculator) t = b/SEb ** simplified from t = (b- ˛)/SEb df = n-2 Pvalue = P(T`",<,>t) Calculate on calculator using LinRegT-Test **OR** use tcdf(t1,t2,df) Draw graph! Conclusion: Since Pvalue = ___ we [fail to] reject the null that there is no association between (x value in context of the problem) and (y value in context of the problem) Confidence Interval: bąt*SEb For t* find the df and use the table in your packet we conclude that we are __% confident that the true association between (x value in context of the problem) and (y value in context of the problem) is in the interval (__,__) Other calculations to know: w=a+bx is a statistic; źy=ą+˛x is a parameter ą H" a (a approximates ą) ˛ H" b (b approximates ˛) Ą H" s (s approximates Ą) r = correlation the sign of it (ą) is the same as the sign of b Interpret correlation: State linearity, strength, and direction s="[("RESID2)/(n-2)] s is the standard error of the regression line and/or residuals Interpret s:  average distance between the actual y values and the estimated w values for each x value SEb=s/""(x-xbar)2 SEb is the standard error of the true slope of the regression line Interpret SEb: 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