ࡱ>  [ bjbj &ΐΐ%& $PK WS#'&"I&I&I&(( ($rH%i)(@())%I&I&9k;k;k;)I&I&k;)k;k;Z;I&̉]g0 z0Az\9\t\/(")k;*)>)(((%%w:((())))\((((((((( : EXPERIMENT No.1 FLOW MEASUREMENT BY ORIFICEMETER 1.1 Aim: To determine the co-efficient of discharge of the orifice meter 1.2 EQUIPMENTS Required: Orifice meter test rig, Stopwatch 1.3 Preparation 1.3.1 Theory An orifice plate is a device used for measuring the  HYPERLINK "http://en.wikipedia.org/wiki/Volumetric_flow_rate" \o "Volumetric flow rate" volumetric flow rate. It uses the same principle as a  HYPERLINK "http://en.wikipedia.org/wiki/Venturi_effect" \o "Venturi effect" Venturi nozzle, namely  HYPERLINK "http://en.wikipedia.org/wiki/Bernoulli%27s_principle" \o "Bernoulli's principle" Bernoulli's principle which states that there is a relationship between the pressure of the fluid and the velocity of the fluid. When the velocity increases, the pressure decreases and vice versa. An orifice plate is a thin plate with a hole in the middle. It is usually placed in a pipe in which fluid flows. When the fluid reaches the orifice plate, with the hole in the middle, the fluid is forced to converge to go through the small hole; the point of maximum convergence actually occurs shortly downstream of the physical orifice, at the so-called  HYPERLINK "http://en.wikipedia.org/wiki/Vena_contracta" \o "Vena contracta" vena contracta point. As it does so, the  HYPERLINK "http://en.wikipedia.org/wiki/Velocity" \o "Velocity" velocity and the  HYPERLINK "http://en.wikipedia.org/wiki/Pressure" \o "Pressure" pressure changes. Beyond the vena contracta, the fluid expands and the velocity and pressure change once again. By measuring the difference in fluid pressure between the normal pipe section and at the vena contracta, the volumetric and mass flow rates can be obtained from  HYPERLINK "http://en.wikipedia.org/wiki/Bernoulli%27s_equation" \o "Bernoulli's equation" Bernoulli's equation. Orifice plates are most commonly used for continuous measurement of fluid flow in pipes. This experiment is process of calibration of the given orifice meter.  HYPERLINK "http://upload.wikimedia.org/wikipedia/commons/b/b8/Blende_eng.png"  INCLUDEPICTURE "http://upload.wikimedia.org/wikipedia/commons/b/b8/Blende_eng.png" \* MERGEFORMATINET  HYPERLINK "http://en.wikipedia.org/wiki/File:Orifice.png"  INCLUDEPICTURE "http://upload.wikimedia.org/wikipedia/commons/0/0f/Orifice.png" \* MERGEFORMATINET  Fig.1. Orifice Plate Pre-lab Questions Write continuity equation for incompressible flow? What is meant by flow rate? What is the use of orifice meter? What is the energy equation used in orifice meter? List out the various energy involved in pipe flow. 1.4 PROCEDURE N.B.: Keep the delivery valve open while start and stop of the pump power supply. 1.4.1 Switch on the power supply to the pump 1.4.2 Adjust the delivery flow control valve and note down manometer heads (h1, h2) and time taken for collecting 10 cm rise of water in collecting tank (t). (i.e. Initially the delivery side flow control valve to be kept fully open and then gradually closing.) 1.4.3 Repeat it for different flow rates. 1.4.4. Switch off the pump after completely opening the delivery valve. 1.5 OBSERVATIONS 1.5.1 FORMULAE / CALCULATIONS 1.5.1.1 The actual rate of flow, Qa = A x h / t (m3/sec) Where A = Area of the collecting tank = lengh x breadth (m2 ) h = Height of water(10 cm) in collecting tank ( m), t = Time taken for 10 cm rise of water (sec) 1.5.1.2 The Theoretical discharge through orifice meter, Qt = (a1 a2 (2g H ) / ( (a12 a2 2 ) m3/sec Where, H = Differential head of manometer in m of water = 12.6 x hm x 10 -2 (m) g = Acceleration due to gravity (9.81m/sec2) Inlet Area of orifice meter in m2 , a1 = ( d12/ 4 , Area of the throat or orifice in m2 , a2 = ( d22/ 4 1.5.1.3 The co-efficient of discharge, Cd = Actual discharge / Theoretical discharge = Qa/Qt 1.5.2 TABULATION Size of Orifice meter : Inlet Dia. d1 = 25 mm , Orifice dia d2 = 18.77 mm, Measuring area in collecting tank A = 0.3 x 0.3 m2 Sl. No. Manometer Reading (cm)Manometer Head H Time for 10 cm rise tActual Discharge QaTheoretical Discharge QtCo-eff. of discharge Cdh1h2hm = h1 - h2m secm3/secm3/sec1.2.3.4.5.6 Average Cd value 1.5.3 GRAPH: Draw Qa Vs Qt .  Find Cd value from the graph and compare it with calculated Cd value from table. POST-LAB QUESTIONS How do you find actual discharge? How do you find theoretical discharge? What do you meant by co-efficient of discharge? Define vena-contracta? List out the Bernoullis applications. 1.7 INFERENCES 1.8 RESULT The co-efficient of discharge of orifice meter = . From Calculation The co-efficient of discharge of orifice meter = . From Graph EXPERIMENT No.2 FLOW MEASUREMENT BY VENTURIMETER 2.1 Aim: To determine the co-efficient of discharge of the venturimeter 2.2 EQUIPMENTS Required: Venturimeter test rig, Stopwatch 2.3 PREPARATION 2.3.1 THEORY  INCLUDEPICTURE "http://www.ustudy.in/imagebrowser/view/image/3463/_original" \* MERGEFORMATINET  Fig.2. Venturimeter In a Venturi meter there is first a converging section in which the cross sectional area for flow is reduced. Then there is a short section at the reduced diameter, known as the throat of the meter. Then there is a diverging section in which the cross sectional area for flow is gradually increased to the original diameter. The velocity entering the converging section is where the pressure is P1. In the converging section the velocity increases and the pressure decreases. The maximum velocity is at the throat of the meter where the minimum pressure P2 is reached. The velocity decreases and the pressure increases in the diverging section. There is a considerable recovery of pressure in the diverging section. However, because of frictional effects in the fluid, the pressure leaving the diverging section is always less than P1, the pressure entering the meter. PRE-LAB QUESTIONS 2.3.2.1 Differentiate mass and volume flow rate? Which property is remains same in the incompressible flow? 2.3.2.3 What is meant by discharge? 2.3.2.4 What is the use of venturimeter? 2.4 PROCEDURE: N.B.: Keep the delivery valve open while start and stop of the pump power supply. 2.4.1. Switch on the power supply to the pump 2.4.2. Adjust the delivery flow control valve and note down manometer heads (h1, h2) and time taken for collecting 10 cm rise of water in collecting tank (t). (i.e. Initially the delivery side flow control valve to be kept fully open and then gradually closing.) 2.4.3. Repeat it for different flow rates. 2.4.4. Switch off the pump after completely opening the delivery valve. 2.5 OBSERVATIONS 2.5.1 FORMULAE / CALCULATIONS 2.5.1.1 The actual rate of flow, Qa = A x h / t (m3/sec) Where A = Area of the collecting tank = lengh x breadth (m2 ) h = Height of water(10 cm) in collecting tank ( m), t = Time taken for 10 cm rise of water (sec) 2.5.1.2 The Theoretical discharge through venturimeter, Qt = (a1 a2 (2g H ) / ( (a12 a2 2 ) m3/sec Where, H = Differential head of manometer in m of water = 12.6 x hm x 10 -2 (m) g = Acceleration due to gravity (9.81m/sec2) Inlet Area of venturimeter in m2 , a1 = ( d12/ 4 , Area of the throat in m2 , a2 = ( d22/ 4 2.5.1.3 The co-efficient of discharge, Cd = Actual discharge / Theoretical discharge = Qa/Qt 2.5.2 TABULATION: Inlet Dia. of Venturimeter (or) Dia of Pipe d1 = 25 mm Throat diameter of Venturimeter d2 = 18.79 mm Area of collecting tank , A = Length x Breadth = 0.3 x 0.3m2 Sl. No.Manometer Reading (cm)Mano-meter Head H Time for 10 cm rise tActual Discharge QaTheoretical Discharge QtCo-eff. of discharge Cdh1h2hm = h1 - h2m secm3/secm3/sec1.2.3.4.5. Average Cd value 2.5.3 GRAPH: Draw Qa Vs Qt .  Find Cd value from the graph and compare it with calculated Cd value from table. POST-LAB QUESTIONS How do you find actual and theoretical discharge? What do you meant by throat of the venturimeter? List out the practical applications of Bernoullis equation? 2.6.4 What is the use of U-tube manometer? 2.7 INFERENCES 2.8 RESULT The co-efficient of discharge of Venturi meter = . From Calculation The co-efficient of discharge of Venturi meter = . From Graph EXPERIMENT No.3 VERIFICATION OF BERNOULLIS THEOREM 3.1 Aim: To verify the Bernoullis theorem 3.2 EQUIPMENTS Required: Bernoullis Theorem test set-up, Stopwatch 3.3 PREPARATION 3.3.1 THEORY Bernoullis Theorem According to Bernoullis Theorem, in a continuous fluid flow, the total head at any point along the flow is the same. Z1 + P1/ (g +V12/2g= Z2 + P2/ (g +V22/2g , Since Z1 Z2 = 0 for Horizontal flow, h1 +V12/2g= h2 +V22/2g ( Pr. head, h = P1/ (g ). Z is ignored for adding in both sides of the equations due to same datum for all the positions. Pre-lab Questions State Bernoullis theorem? What is continuity equation? What do you meant by potential head? What do you meant by pressure head? What do you meant by kinetic head? 3.4 PROCEDURE N.B.: Keep the delivery valve open while start and stop of the pump power supply. 3.4.1 Switch on the pump power supply. 3.4.2 Fix a steady flow rate by operating the appropriate delivery valve and drain valve 3.4.3. Note down the pressure heads (h1 h8) in meters 3.4.4. Note down the time taken for 10 cm rise of water in measuring (collecting) tank. 3.4.5. Switch off the power supply. 3.5 OBSERVATIONS 3.5.1 FORMULAE / CALCULATIONS 3.5.1.1 Rate of flow Q = Ah /t. Where A: Area of measuring tank = Length x Breadth (m2) h: Rise of water in collecting tank (m) .. (i.e. h = 10 cm ) t: Time taken for 10 cm rise of water in collecting tank (sec) 3.5.1.2 Velocity of flow, V = Q/a , Where a Cross section area of the duct at respective peizometer positions (a1 - a8) 3.5.1.3 Hydraulic Gradient Line (HGL): It is the sum of datum and pressure at any point HGL = Z + h 3.5.1.4 Total Energy Line (TEL): It is the sum of Pressure head and velocity head TEL = Z + h +V2/2g 3.5.2 TABULATIONS Area of measuring tank = 0.3 x 0.3 m2 Assume Datum head Z = 0 Diameter at the sections of the channel dCross Section Area a = ( d2/ 4Time for 10 cm rise tDischarge Q=Ah/tVelocity V=Q/aVelocity Head V2/2gPiezometer Reading i.e. Pr. Head (h=P/(g )Total Head Z +h+ V2/2gmx10-3 m2secm3/secm/secmmmd1 = 0.04295 1.448d2 = 0.03925 1.209d3= 0.03555 0.992d4= 0.03185 0.796d5 = 0.02815 0.622d6= 0.02445 0.469d7= 0.02075 0.338d8= 0.01705 0.228 GRAPH Draw the graph: Distance of channel (Locations 1-8) Vs HGL, TEL  POST-LAB QUESTIONS What do you meant by velocity head? What do you meant by HGL? What do you meant by datum head? What is the use of piezometer? Define TEL? What is the reason for the slight decrease in the total energy head between the successive locations in the duct? 3.7 INFERENCES 3.8 RESULT The Bernoullis theorem is verified. EXPERIMENT No.4 DETERMINATION OF PIPE FRICTION FACTOR 4.1 Aim: To determine the friction factor for the given pipe. 4.2 EQUIPMENTS Required: Pipe friction EQUIPMENTS, Stop watch 4.3 PREPARATION 4.3.1 THEORY The major loss in the pipe is due to the inner surface roughness of the pipe. There are three pipes (diameter 25 mm, 20 mm and 15 mm) available in the experimental set up. The loss of pressure head is calculated by using the manometer. The apparatus is primarily designed for conducting experiments on the frictional losses in pipes of different sizes. Three different sizes of pipes are provided for a wide range of experiments. 4.3.2 Pre-lab Questions 4.3.2.1. What do you meant by friction and list out its effects? What do you meant by major loss in pipe? Write down the Darcy-Weisbach equation? What are the types of losses in pipe flow? 4.4 PROCEDURE N.B.: Keep the delivery valve open while start and stop of the pump power supply. 4.4.1. Switch on the pump and choose any one of the pipe and open its corresponding inlet and exit valves to the manometer. 4.4.2. Adjust the delivery control valve to a desired flow rate. (i.e. fully opened delivery valve position initially) 4.4.3 Take manometer readings and time taken for 10 cm rise of water in the collecting tank 4.4.4 Repeat the readings for various flow rates by adjusting the delivery valve. (i.e. Gradually closing the delivery valve from complete opening) 4.4.5 Switch of the power supply after opening the valve completely at the end. 4.5 OBSERVATIONS 4.5.1 FORMULAE / CALCULATIONS 4.5.1.1 The actual rate of flow Q = A x h / t (m3/sec) Where A = Area of the collecting tank = lengh x breadth (m2 ) h = Height of water(10 cm) in collecting tank ( m), t = Time taken for 10 cm rise of water (sec) 4.5.1.2 Head loss due to friction, hf = hm ( Sm Sf)/ (Sf x 100) in m hf = hm (13.6 1 ) x 10 -2 (m) Where Sm = Sp. Gr. of manometric liquid , Hg =13.6 , Sf = Sp. Gr. of flowing liquid, H2O = 1 hm = Difference in manometric reading = (h1-h2) in cm 4.5.1.3 The frictional loss of head in pipes (Darcy-Weisbach formula) hf = 4f L V2 2 g d Where f = Co-efficient of friction or friction factor for the pipe (to be found) L = Distance between two sections for which loss of head is measured = 3 m V = Average Velocity of flow = Q/a (m/s), Area of pipe a= ( d2/ 4 (m2), d = Pipe diameter = 0.015 m g = Acceleration due to gravity = 9.81 m/sec2 4.5.2 TABULATION Length between Pressure tapping, L = 3 m Pipe Diameter, d = 0.015 m, Measuring tank area, A= 0.6 x 0.3m2 , Sl.No.Pipe DiaManometer Reading Head lossTime for 10 cm rise DischargeVelocity Frictional factordh1h2hm = (h1-h2)hftQV=Q/afmcmmsecm3/sm/s12345 Average friction factor, f  GRAPH Draw the graph: Q Vs hf  POST-LAB QUESTIONS What is the relationship between friction head loss and pipe diameter? What is the relationship between friction head loss and flow velocity? What is the relationship between friction head loss and pipe length? How is the flow rate and head loss related? If flow velocity doubles, what happen to the frictional head loss? 4.7 INFERENCES 4.8 RESULT The friction factor for the given pipe diameter of m is = __________ EXPERIMENT NO.5 PERFORMANCE TEST ON GEAR PUMP 5.1 Aim: To study the performance of gear oil pump. 5.2 EQUIPMENTS Required: Gear pump test rig, Stopwatch 5.3 Preparation 5.3.1 Theory A gear pump uses the meshing of gears to pump fluid by displacement. They are one of the most common types of  HYPERLINK "http://en.wikipedia.org/wiki/Pump" \o "Pump" pumps for  HYPERLINK "http://en.wikipedia.org/wiki/Hydraulic_machinery" \o "Hydraulic machinery" hydraulic fluid power applications. Gear pumps are also widely used in chemical installations to pump fluid with a certain viscosity. There are two main variations; external gear pumps which use two external  HYPERLINK "http://en.wikipedia.org/wiki/Gear" \o "Gear" spur gears, and internal gear pumps which use an external and an internal spur gear. Gear pumps are  HYPERLINK "http://en.wikipedia.org/wiki/Positive_displacement_pump" \o "Positive displacement pump" positive displacement (or fixed displacement), meaning they pump a constant amount of fluid for each revolution. Some gear pumps are designed to function as either a  HYPERLINK "http://en.wikipedia.org/wiki/Hydraulic_motor" \o "Hydraulic motor" motor or a pump. The gear oil pump is works based on the squeezing action of the two meshing gears (internal or external gears). The gear pump is one of the positive displacement pump and the reduction in volume inside the pump results in increase in pressure of fluid. As the gears rotate they separate on the intake side of the pump, creating a void and suction which is filled by  HYPERLINK "http://en.wikipedia.org/wiki/Fluid" \o "Fluid" fluid. The fluid is carried by the gears to the discharge side of the pump, where the meshing of the gears displaces the fluid. The mechanical clearances are small in the order of 10 m. The tight clearances, along with the speed of rotation, effectively prevent the fluid from leaking backwards. The rigid design of the gears and houses allow for very high pressures and the ability to pump highly  HYPERLINK "http://en.wikipedia.org/wiki/Viscosity" \o "Viscosity" viscous fluids. Fig.3. External Gear pump PRE-LAB QUESTIONS 5.3.2.1 What is the purpose of gear pump? What do you meant by internal and external gears? What are the applications of gear pump? What do you meant by gears? 5.4 PROCEDURE N.B. : NEVER operate the pump with closed delivery valve during start and stop of the pump power supply. The violation leads to damage of the pipe line and the pump. Ensure the complete opened position of delivery valve. Measure height of the pressure gauge above the vacuum gauge. Switch on the pump. Vary the flow rate (discharge) by closing the delivery valve. Adjust the delivery valve accordingly the pressure gauge reading of 1kg/cm2. Note down vacuum gauges reading. Note down time taken for h cm rise of oil (10 cm) in collecting tank. Note down the time taken for n revolutions for energy meter disc (3 rev). Repeat the procedure for 1 kg/cm2 incremental by closing the delivery valve gradually, (i.e. 1.0, 1.5, 2.0, 2.5 and 3.0 kg/cm2 ). Switch off the power supply after opening the delivery valve completely. 5.5 OBSERVATIONS 5.5.1 FORMULAE / CALCULATIONS 5.5.1.1 Total head H = [ P + (V/760 ] x 105/(( g) + Z (m) Where P = Pressure gauge reading in kg/cm2, V = Vacuum gauge reading in mm Hg, N.B.: Unit Conversion: For V, 1 mm Hg/ 760 = 1 bar & for P, 1 bar = 1 kg/ cm2 . 5.5.1.2 Discharge, Q = (A x h ) / t (m3/s) , Where A = Area of tank in m2 , h = Rise oil level in collecting tank (m), t = Time taken for the rise of oil 10 cm in collecting tank (sec) 5.5.1.3 Output in Watts, OP = ( g Q H / 1000 (kW) Where (= Density of oil = 860 kg/m3 g = Acceleration due to gravity = 9.81 m/sec2 5.5.1.4 Input in kWatts , IP = (n x 3600 x (m ) / (Ec x T) (kW) Where Ec = Energy meter constant in Rev /kWh = 1200 Rev / kWh n = Number of revolution taken in energy meter = 3 T = Time required to complete n revolution in sec (m = Efficiency of motor = 0.80 5.5.1.5 Efficiency, ( = (Output / Input ) x 100% = (OP/IP) x 100% 1.5.2 TABULATION Measuring Area in collecting tank = 0.3 x 0.3 m2 Datum head Z = 0.3 m. Density of oil, ( = 860 kg/m3 Sl. No. P V  Z  HTime for 10 cm rise (t)Flow rate QTime for 3 rev of Energy meter (T)Input IPOutput OPEfficiency (kg/cm2mm Hg Mmsecm3/secseckWkW%11.021.532.042.553.063.5 GRAPH Draw the graph: Discharge vs Head, Output Power, Efficiency.  5.6 POST-LAB QUESTIONS 5.6.1. What is the squeezing in gear pumps? What is the type of gears used in gear pumps? List out the different pressure heads used in gear pump? What is mechanical efficiency of pump? 5.7 INFERENCES 5.8 RESULT The performance characteristics of the given gear oil pump is studied. EXPERIMENT No.6 PERFORMANCE TEST ON SUBMERSIBLE PUMP 6.1 Aim: To study the performance characteristics of submersible pump. 6.2 EQUIPMENTS Required: Submersible pump test rig, Stop watch 6.3 PREPARATION 6.3.1 Theory A submersible pump (or electric submersible pump (ESP)) is a device which has a  HYPERLINK "http://en.wikipedia.org/wiki/Hermetic_seal" \o "Hermetic seal" hermetically sealed  HYPERLINK "http://en.wikipedia.org/wiki/Electric_motor" \o "Electric motor" motor close-coupled to the pump body. The whole assembly is submerged in the fluid to be pumped. The main advantage of this type of pump is that it prevents  HYPERLINK "http://en.wikipedia.org/wiki/Cavitation" \o "Cavitation" pump Cavitation, a problem associated with a high elevation difference between pump and the fluid surface. Submersible pumps push fluid to the surface as opposed to jet pumps having to pull fluids. Submersible pumps are more efficient than  HYPERLINK "http://en.wikipedia.org/wiki/Eductor-jet_pump" \o "Eductor-jet pump" jet pumps Pre-Lab Questions What is the submersible pump? What is the working principle of submersible pump? What are applications of submersible pump? What is the value of suction head in submersible pump? Is priming necessary in submersible pump? PROCEDURE N.B. : NEVER operate the pump with closed delivery valve during start and stop of the pump. The violation leads to damage of the pipe line and the pump. Start the pump and run it at particular head on it. Ensure the complete opening of the delivery valve provided. The pressure gauge reading to be noted for the pressure of 0.5 kg/cm2. The time is to be noted for collecting 10 cm rise of water in the collecting tank. The time is to be noted for 3 revolution of Energy meter disc. Repeat the procedure for 0.5, 1.0, 1.5, 2.0, 2.5, 3.0 kg/cm2 delivery pressures. by closing the delivery valve. Open the delivery valve completely and then Switch off the power supply. 6.5 OBSERVATIONS 6.5.1 FORMULAE / CALCULATIONS 6.5.1.1 Total Head, H = P x 105/ (( g) in m Where P Pressure gauge reading in kg/cm2, g = Gravitational acceleration = 9.81 m2/s ( = Density of fluid (water) = 1000 kg/m3 6.5.1.2 Discharge, Q = (A x h ) / t (m3/sec) Where A = Area of tank in m2 (A( = l x b h = Rise of water level in collecting tank = 0.10 m t = Time taken for 10 cm rise of water in the collecting tank 6.5.1.3 Output in kW, OP = ( g QH / 1000 6.5.1.4 Input in kW, IP = (n x 3600 (m ) / (N x T) Where N = Energymeter constant in Rev /kW hr = 1200 rev / kWh n = Number of revolution taken in energymeter T = Time required to complete n revolution in sec (m = Efficiency of motor = 0.8 6.5.1.5 Efficiency, ( = Output / Input x 100% 6.5.2 TABULATION Measuring tank of size = 0.6 x 0.6 m2 Sl. No. Pressure gauge P Total Head HTime for 10 cm rise of water t Discharge QTime for 3 rev of Energy Meter Disc T Input IP Output OP Efficiency (kg/cm2msecm3/secseckWkW%10.521.031.542.052.563.0 6.5.3 GRAPH: Draw the graph Q Vs H, OP and (  Post-Lab Questions How do you measure actual flow rate? What is the output power of the pump? List out the different heads used in submersible pump? What is advantage of submersible pump over jet pump? What is mechanical efficiency? What do you meant by cavitaion? How do you prevent cavitaion in pump? What is advantage of submersible pump over centrifugal pump? 6.6.9 Is priming necessary in submersible pump? 6.7 INFERENCES 6.8 RESULT The performance characteristics of the given submersible pump are studied. EXPERIMENT No.7 PERFORMANCE TEST ON RECIPROCATING PUMP 7.1 Aim: To study the performance of Reciprocating pump. 7.2 EQUIPMENTS Required: Reciprocating pump test rig, Stop watch 7.3 PREPARATION 7.3.1 Theory A reciprocating pump is a positive plunger  HYPERLINK "http://en.wikipedia.org/wiki/Pump" \o "Pump" pump. It is often used where relatively small quantity of  HYPERLINK "http://en.wikipedia.org/wiki/Liquid" \o "Liquid" liquid is to be handled and where delivery  HYPERLINK "http://en.wikipedia.org/wiki/Pressure" \o "Pressure" pressure is quite large. Reciprocating pumps are now typically used for pumping highly viscous fluids including concrete and heavy oils, and special applications demanding low flow rates against high resistance. Pre-Lab Questions What is the working principle of reciprocating pump? What is type of suction and delivery valves in reciprocating pump? What do you meant by slip in reciprocating pump? What do you meant by single and double acting pump? 7.3.2.5 List out the parts of reciprocating pump. 7.4 PROCEDURE N.B. : NEVER operate the pump with closed delivery valve during start and stop. Never operate the pump above the gauge pressure of 3 kg/cm2. Start the pump and run it at particular head on it. Ensure the complete opened position of delivery valve. Vary the flow rate (discharge) by closing the delivery valve in order to maintain certain pressure gauge reading i.e.0.5 kg/cm2. Note down pressure gauge reading (0.5 kg/cm2) and vacuum gauges readings. Measure height of the pressure gauge above the vacuum gauge (Datum level) Note down time taken (t) for h cm rise of water (10 cm) in collecting tank. Note down the time taken (T) for n revolutions for energy meter (3 rev) disc. Repeat the procedure for 0.5, 1.0, 1.5, 2.0, 2.5 kg/cm2 in the Pressure gauge reading by closing the delivery valve. Switch off the power supply after opening the delivery valve completely. 7.5 OBSERVATIONS 7.5.1 FORMULAE / CALCULATIONS 7.5.1.1. Total head, H = [P + (V/760) ] x 105 / (( g ) + Z (m) Where, P Pressure gauge reading in kg/cm2, V- Vacuum gauge reading in mm Hg, Z Datum level between Pressure gauge and Vacuum gauge g = Gravitational acceleration = 9.81 m2/s ( = Density of fluid (water) = 1000 kg/m3 N.B.: For V, 1 mm Hg/ 760 = 1 bar & for P, 1 bar = 1 kg/ cm2 7.5.1.2. Discharge, Q = (A h)/ t (m3/sec) Where A- Collecting tank area = l x b in m2, t - time for 10 cm rise of water level in the collecting tank (sec) h Rise of water level in the collecting tank = 0.10 m 7.5.1.3. Output in kW, OP = ( g QH / 1000 7.5.1.4. Input in kW, IP = (n rev of energy meter x 3600 x Efficiency of motor) / (Energy meter constant in Rev/kW-hr x Time for n revolutions) = (n x 3600 x (m ) / (Ec x T) Where Ec = Energymeter constant in Rev /kW hr = 1200 rev / kWh n = Number of revolution taken in energy meter = 3 T = Time required to complete n revolution in sec (m = Efficiency of motor = 0.8 7.5.1.5. Efficiency of Pump, ( = (Output / Input) x 100 % 1.5.3 TABULATION: Area of Measuring tank A : 0.3 x 0.3 m2 , Motor Efficiency (m : 0.8 Energymeter Constant : 1200 Rev/kW-hr Z Datum level between Pressure gauge and Vacuum gauge = 0.75 m Sl. No.Pressure Gauge reading PVacuum Gauge reading VTotal Head HTime for 10 cm rise TDischarge Q x10-4 Time for 3 rev of EM disc TInput Power IPOutput Power OPEfficiency (kg/cm2mm HgmSecm3/secseckWkW%1.0.52.13.1.54.25.2.56.3 GRAPH: Disharge Vs head, Output, Efficiency.  Post-Lab Questions List out the different heads used in reciprocating pump? What is the use of air vessel? Why the delivery valve should be kept open always? What do you meant by indicator diagram and its use? What do you meant by percentage slip and negative slip? 7.6.6 In what situations, the reciprocating pump is desired? 7.7 INFERENCES 7.8 RESULT The performance test on reciprocating pump is conducted and the performance characteristics are drawn. EXPERIMENT No.08 PERFORMANCE TEST ON JET PUMP 8.1 Aim: To study the performance test on the jet pump 8.2 EQUIPMENTS Required: Jet pump test rig, stop watch 8.3 Preparation 8.3.1 Theory Jet pumps, also referred to as ejectors, are devices for the conveyance, compression or mixing of gases, vapours, liquids or solids in which a gaseous or liquid medium serves as the motive force. They operate by the conversion of pressure energy into velocity in suitable nozzles. They are "pumps without moving parts." The basic principle of jet pumps consists in the liquid or gas jet being emitted by a nozzle at high speed entraining and accelerating the surrounding liquid, gas or solid matter. The result of this action is a mixture of the driving and entrained (sucked) fluids, the velocity of which is reduced and the pressure increased in a second nozzle.  INCLUDEPICTURE "http://www.fao.org/docrep/010/ah810e/AH810E117.gif" \* MERGEFORMATINET  Fig.5 Jet Pump PRE-LAB QUESTIONS What is the purpose of jet pump? What is the working principle of jet pump? What are applications of jet pump? 8.3.2.4 List out the parts of jet pump. PROCEDURE Start the pump and run it at particular head on it. Ensure the complete opened position of delivery valve. Vary the flow rate (discharge) by closing the delivery valve in order to maintain certain pressure gauge reading i.e.0.5 kg/cm2. Note down pressure gauge reading (0.5 kg/cm2) and vacuum gauges readings. Measure height of the pressure gauge above the vacuum gauge (Datum level) Note down time taken (t) for h cm rise of water (10 cm) in collecting tank. Note down the time taken (T) for n revolutions for energy meter (3 rev) disc. Repeat the procedure for 0.5, 1.0, 1.5, 2.0, 2.5 kg/cm2 in the Pressure gauge reading by closing the delivery valve. Switch off the power supply after opening the delivery valve completely. 8.5 OBSERVATIONS 8.5.1 FORMULAE / CALCULATIONS 8.5.1.1 Total Head, H = P x 105/ (( g) in m Where P Pressure gauge reading in kg/cm2, g = Gravitational acceleration = 9.81 m2/s ( = Density of fluid (water) = 1000 kg/m3 8.5.1.2 Discharge, Q = (A x h ) / t (m3/sec) Where A = Area of tank in m2 (A( = l x b h = Rise of water level in collecting tank = 0.10 m t = Time taken for 10 cm rise of water in the collecting tank 8.5.1.3 Output in kW, OP = ( g QH / 1000 8.5.1.4 Input in kW, IP = (n x 3600 (m ) / (N x T) Where N = Energymeter constant in Rev /kW hr = 1200 rev / kWh n = Number of revolution taken in energymeter T = Time required to complete n revolution in sec (m = Efficiency of motor = 0.8 8.5.1.5 Efficiency, ( = Output / Input x 100% 8.5.2 TABULATION Energy meter constant N = 1200 Rev/kW-hr Measuring Area in collecting tank=0.3 x0.3m2 Sl. No.Pressure gaugeTotal HeadTime for 10 cm riseDischarge Time for 3 rev of EMInputOutputEfficiencyPHtQTIPOP(kg/cm2Msecm3/secseckWKw%10.521.031.542.052.5 8.5.3 GRAPH: Draw Q Vs H, OP and (  POST-LAB QUESTIONS How do you measure actual flow rate? What is the output power of the pump? List out the different pressure heads used in jet pump? 8.6.4 What is mechanical efficiency? 8.6.5 What is overall efficiency? INFERENCES RESULT The performance of the given jet pump is studied. EXPERIMENT No.9 DETERMINATION OF MINOR LOSSES DUE TO PIPE FITTINGS 9.1 Aim: To study the various losses due to the pipe fittings 9.2 EQUIPMENTS Required: Minor losses test rig, Stopwatch PREPARATION 9.3.1 THEORY The various pipe fittings used in the piping applications are joints, bends, elbows, entry, exit and sudden flow area changes (enlargement and contraction) etc. The energy losses associated with these types of pipe fittings are termed as the minor losses due its lesser values compared to the major loss (pipe friction) in the pipe. The loss of head is indicated by the manometer connected across the respective pipe fitting. 9.3.2 PRE-LAB QUESTIONS List out the various types of pipe fittings? What do you meant by minor losses? What are the types of losses in pipe flow? What do you meant by entry loss? What do you meant by exit loss? 9.4 PROCEDURE N.B.: Keep the delivery valve open while start and stop of the pump power supply. Switch on the pump. Adjust the delivery valve to a desired steady flow rate. Note down the time taken for 10 cm rise of water level in the collecting tank. Choose any one of the pipe fittings (2 bends, one enlargement and one contraction). e.g. Bend-1 Open the levers (cocks) of respective pipe fitting to the manometer. Ensure other fitting levers should be closed. e.g. Open the entry and exit levers of Bend-1( left & right side cocks at the top of the panel) Note down the manometer head levels (e.g. h1 & h2 for bend-1) Now open the other two entry and exit levers of next pipe fitting. Then close the levers of first chosen pipe fitting. (e.g. Open the 2nd left & right levers for Bend-2 and close the top levers of Bend-1) Note down the manometer for the second pipe fitting. (e.g. h1 & h2 for bend-2) Repeat this procedure by opening the respective levers of sudden enlargement fitting after closing other levers( i.e. for sudden enlargement by opening the next down left & right cocks of sudden enlargement and then close the previous left & right cocks of Bend-2). Repeat this procedure by opening the respective levers of sudden contraction fitting after closing other levers( i.e. for sudden contraction by opening the next down left & right cocks of sudden contraction and then close the previous left & right cocks of Sudden enlargement). Ensure the readings taken for all pipe fittings and then switch off the pump. 9.5 OBSERVATIONS 9.5.1 FORMULAE / CALCULATIONS 9.5.1.1. Discharge, Q = (A x h ) / t .. (m3/s) A = Area of tank in m2 , h = 0.10 m // Rise water level in collecting tank (m), t = Time taken for the 10 cm rise of water in collecting tank (sec) 9.5.1.2. Velocity, V = Discharge / Area of pipe = Q/A (m/s) Where A = ( d2/4 , d Dia of pipe in m 9.5.1.3. Actual loss of head, hf = ( h1 h2 ) x 12.6 x 10-2 (m) 9.5.1.4. Theoretical Velocity loss heads for pipe fittings Velocity head loss for bend and elbow hv = V2 / (2g) Velocity head loss for sudden enlargement hv = ( V1 V2 )2 / (2g) Velocity head loss for sudden contraction hv = 0.5 (V2)2 / (2g) Where V2= velocity of smaller pipe 9.5.1.5. Loss co-efficient K = Theoretical Velocity head /Actual loss of head = hv / hf 9.5.2 TABULATION Collecting Tank area, A = 0.6 m x 0.3 m, Pipe Diameter , d = 0.02 m Pipe fittingsManometer Reading (cm)Time for 10 cm rise (sec)Discharge (m3/s)Velocity (m/s)Actual Loss of head, (m)Loss of head (Theoretical) (m)Loss co-efficient K h1h2hmtQVhfhv hv / hfBend-1Bend-2Sudden Enlarge (20-40 mm)Sudden Contraction (40-20 mm) POST-LAB QUESTIONS What is the equation for head loss due to sudden enlargement? What is the equation for head loss due to sudden contraction? What is the equation for head loss due to bend? What is the equation for head loss at entry of pipe? What is the equation for head loss at exit of pipe? Which Newtons law is applicable to impulse turbine? 9.7 INFERENCES 9.8. RESULT The various minor losses in pipe fittings are determined. EXPERIMENT No.10 PERFORMANCE TEST ON PELTON TURBINE 10.1 AIM: To study the performance of Pelton turbine. 10.2 EQUIPMENTS Required: Pelton Turbine test rig, Stop watch, Weights & Tachometer 10.3 PREPARATION 10.3.1 THEORY The Pelton wheel is an impulse turbine which is among the most efficient types of  HYPERLINK "http://en.wikipedia.org/wiki/Water_turbines" \o "Water turbines" water turbines. The Pelton wheel extracts energy from the impulse ( HYPERLINK "http://en.wikipedia.org/wiki/Momentum" \o "Momentum" momentum) of moving water, as opposed to its weight like traditional overshot  HYPERLINK "http://en.wikipedia.org/wiki/Water_wheel" \o "Water wheel" water wheel. The water flows along the tangent to the path of the runner. Nozzles direct forceful streams of water against a series of spoon-shaped buckets mounted around the edge of a wheel. As water flows into the bucket, the direction of the water velocity changes to follow the contour of the bucket. When the water-jet contacts the bucket, the water exerts pressure on the bucket and the water is decelerated as it does a "u-turn" and flows out the other side of the bucket at low velocity. In the process, the water's momentum is transferred to the turbine. This " HYPERLINK "http://en.wikipedia.org/wiki/Impulse" \o "Impulse" impulse" does  HYPERLINK "http://en.wikipedia.org/wiki/Work_(physics)" \o "Work (physics)" work on the turbine. For maximum power and efficiency, the turbine system is designed such that the water-jet velocity is twice the velocity of the bucket. Often two buckets are mounted side-by-side, thus splitting the water jet in half. This balances the side-load forces on the wheel, and helps to ensure smooth, efficient momentum transfer of the fluid jet to the turbine wheel. Because water and most liquids are nearly incompressible, almost all of the available energy is extracted in the first stage of the hydraulic turbine. Therefore, Pelton wheels have only one turbine stage, unlike gas turbines that operate with compressible fluid. Pelton turbine is preferred for water source has relatively high  HYPERLINK "http://en.wikipedia.org/wiki/Head_(hydraulic)" \o "Head (hydraulic)" hydraulic head at low flow rate.  INCLUDEPICTURE "http://re.emsd.gov.hk/english/other/hydroelectric/images/image010.gif" \* MERGEFORMATINET  Fig.4 Pelton Turbine Pre-Lab Questions What are the types of hydraulic turbines? What is the purpose of turbine? What is the use of nozzle? Define water hammer. What is the purpose of surge tank? Classify the hydraulic turbines. Differentiate impulse and reaction turbines. TECHNICAL SPECIFICATIONS 10.3.3.1 Turbine Rating Power output 1 kW, Supply head 25 m, Normal speed 1000 rpm, Flow rate 500 lpm, runaway speed 1500 rpm. 10.3.3.2 Pump Rating: Discharge 500 lpm, Power input 5 hp, Normal Speed 2880 rpm. 10.4 PROCEDURE 10.4.1 SAFETY PRECAUTIONS 10.4.1.1. Remove any weights (loads) on the turbine shaft. 10.4.1.2. Ensure the closed position of the delivery valve. 10.4.1.3. After starting, check the cooling water supply to the turbine 10.4.1.4. Avoid running turbine without cooling water to the brake drum. 10.4.1.5. Keep away from the rotating shaft and avoid touching the shaft by hand 10.4.1.6. Avoid pressure more than 2.5 kg/cm2 to the turbine for stability reasons. 10.4.1.7. Avoid any disturbances to the manometer tubes. 10.4.1.8. Pressure gauge valves should also be closed before pump shut down. 10.4.2 OPERATIONAL (PROCEDURAL) STEPS 10.4.2.1. Prime the pump and start it with closed gate valve. The spear in the turbine inlet and should also be in the closed position while starting the pump in order to avoid sudden falling of water and its impact on the turbine blades. 10.4.2.2. After starting the pump, Run the turbine at full spear opening by opening the spear gradually. 10.4.2.3. Keep the constant head acting on the turbine as 1.0 kg/cm2 by adjusting the delivery valve just above the turbine. The flow rate (can be found by Venturimeter pressure heads (p1,p2) ) and head are maintained constant during the testing of turbine. 10.4.2.4. Load the turbine from no load to 8 kg with 2 kg incremental weights. 10.4.2.5. Note the following: Turbine speed (N) by torching on the shaft sensor strip with the non contact digital tachometer, Brake weight (Dead wt. + hanger and rope wt.) (W1 ) Spring balance reading(W2). 10.4.2.6. Increase the weights from 0 kg as 0, 2 , 4, 6, 8 kg and note down the speed and spring balance readings. No need to vary the flow rate and head. 10.4.2.7. First remove all the dead weights on the hanger. Close the delivery valve and then switch off the pump power supply in order to stop the turbine. 10.5 OBSERVATIONS 10.5.1 FORMULAE / CALCULATIONS 10.5.1.1 Input Power, IP = (g Q H (W) Where (g = Specific weight of water = 9.81 kN/m3 Q = Discharge in m3/sec Q = K "h = 3.183 x 10-3 "h (h in m ) Size of Venturimeter : 50mm and Throat Diameter : 29.58mm Where  K Value = (a1 a2 (2g ) / ( (a12  a2 2 = 3.183 x 10-3 Where h = Venturimeter head in m of water h = (p x105/ (g = (p1  p2) x105/ ((g) (m) H = Supply head in m = Input total head in m H = P x105/ ((g ) 10.5.1.2. Output (Brake) Power, OP = 2( N T / 60 (W) Where N = Turbine speed in RPM., T = W Re g = Torque in N-m Brake drum dia D =0.2m , Rope dia d =0.015m Effective radius of Brake Drum, Re = (D/2 )+d) = 0.115m Weight of rope & hanger = 1kg. Brake drum Net load W =(W1 + weight of rope hanger) W2 kg = ( 5+1) 2 = 4 kg 10.5.1.3 Efficiency of turbine, ( = (OP/IP ) x 100% 10.5.2 TABULATION Sl NPressure gauge reading PPressure Gauge readingVenturi -meter Head hDischarge QWeight on hanger W1Spring balance reading W2Net Load WSpeed NInput IPOutput OPEfficiency ( p1 p2 (P = p1-p2kg/cm2kg/cm2mm3/seckgkgkgrpmkWkW%1.2.3.4.5.6. 10.5.3 GRAPH: Speed Vs Output, Efficiency  POST-LAB QUESTIONS 10.6.1 What do you meant by impulse turbine? How do you regulate the flow of water to the turbine? What is the energy conversion from nozzle to turbine? Why is braking jet used? What is the spear and nozzle? What is the pressure inside the turbine casing? What is mechanical efficiency? 10.6.8 What do you meant by volumetric efficiency? 10.7 INFERENCES 10.8 RESULT: The performance of Pelton turbine is studied. EXPERIMENT No.11 PERFORMANCE TEST ON FRANCIS TURBINE 11.1 AIM: To study the performance of Francis turbine. 11.2 EQUIPMENTS REQUIRED: Francis turbine test rig, Stop watch, Weights, tachometer. 11.3 PREPARATION 11.3.1 THEORY The Francis turbine is an inward-flow  HYPERLINK "http://en.wikipedia.org/wiki/Reaction_turbine" \o "Reaction turbine" reaction turbine that combines radial and axial flow concepts. Francis turbines are the most common water turbine in use today. They operate in a  HYPERLINK "http://en.wikipedia.org/wiki/Head_(hydraulic)" \o "Head (hydraulic)" head range of 10 m 650 m and are primarily used for electrical power production. The power output ranges from 10 to 750MW. Runner diameters are between 1 and 10 meters. The speed range of the turbine is from 83 to 1000 rpm. Medium size and larger Francis turbines are most often arranged with a vertical shaft. The Francis turbine is a  HYPERLINK "http://en.wikipedia.org/wiki/Reaction_(physics)" \o "Reaction (physics)" reaction turbine, which means that the working fluid changes pressure as it moves through the turbine, giving up its energy. The inlet is spiral shaped. Guide vanes direct the water tangentially to the turbine wheel, known as a runner. This radial flow acts on the runner's vanes, causing the runner to spin. The guide vanes (or wicket gate) may be adjustable to allow efficient turbine operation for a range of water flow conditions. PRE-LAB QUESTIONS What are the types of hydraulic turbines? What is the use of draft tube? What is the flow direction in reaction turbine? What is the use of guide vanes? Which Newtons law is applicable to reaction turbine? TECHNICAL SPECIFICATIONS 11.3.3.1 FRANCIS TURBINE: Rated Supply Head: 10 meters, Discharge: 1000 LPM, Rated Speed: 1250 rpm Power Output: 1 kW, Runaway Speed: 1750RPM Runner diameter: 160mm 11.3.3.2 PUMPSET: Rated Head: 10m, Discharge: 1200 lpm, Normal Speed: 1440 rpm, Power input: 5 HP 11.4 PROCEDURE 1. Prime the pump and start it with closed gate valve. The spear in the turbine inlet and should also be in the closed position while starting the pump. 2. After starting and running the turbine at normal speed for some time, load the turbine and take readings. Note the following: Net supply head, Discharge (pressure gauge readings), Turbine shaft speed, Brake weight (Dead Weights plus hanger and rope weight) (1kg) and Spring balance reading. 3. Before switching off the supply pump set, first remove all the dead weights on the hanger. 11.5 OBSERVATIONS 11.5.1 FORMULAE / CALCULATIONS 11.5.1.1 Input Power, IP = (g Q H (W) Where (g = Specific weight of water = 9.81 kN/m3 Q = Discharge in m3/sec Q = K "h = 3.183 x 10-3 "h (h in m ) Size of Venturimeter : 50mm and Throat Diameter : 29.58mm Where  K Value = (a1 a2 (2g ) / ( (a12  a2 2 = 3.183 x 10-3 Where h = Venturimeter head in m of water h = (p x105/ (g = (p1 p2) x105/ ((g) (m) H = Supply head in m = Input total head in m H = P x105/ ((g ) 11.5.1.2. Output (Brake) Power, OP = 2( N T / 60 (W) Where N = Turbine speed in RPM., T = W Re g = Torque in N-m Brake drum dia D =0.2m , Rope dia d =0.015m Effective radius of Brake Drum, Re = (D/2 )+d) = 0.115m Weight of rope & hanger = 1kg. Brake drum Net load W =(W1 + weight of rope hanger) W2 kg = ( 5+1) 2 = 4 kg 11.5.1.3 Efficiency of turbine, ( = (OP/IP ) x 100% Input Power = ( g QH in kW Where ( = Density of water = 1000 kg/m3 g = Acceleration due to gravity (9.81m/sec2) Q = Discharge in m3/sec. H = Supply head in meters. 2( NReW x 9.81 Brake Power =------------------- kW 60000 Output Efficiency = ------------- x 100% Input Where N = Turbine speed in RPM. T= Torque in kgm, (effective radius of the brake drum in meters (0.165m) Sl. No.Pressure gauge readingPressure Gauge Reading Orifice meter head Discharge  Speed Weight on hangerSpring balance reading Net load  Output  Input  Efficiency P.Skg/cm2hQNW1W2WOPIP(kg/cm2p1p2dpm m3/secRPMkgkgkgkWkW%12345 FRANCIS TUBRINE Orificemeter Head h in m of water h=(p1-p2)x 10m of water Effective Radius of = (D/2 + t) Discharge Q = K(h (h in m of water) Input power IP =( x H x Q kW (H in m of water) Brake drum Re = 0.115m Brake Drum net load W = (W1 + weight of rope & hanger) W2 kg Weight of rope & hanger = 1kg Turbine output OP =(2( NWRe x 9.81)/ 60000 kW Guide Vane opening = 0.5 Efficiency ( = (output / Input) x 100% K value : 9.11 x10-3 Inlet diameter of Orificemeter: 80mm , Orificemeter diameter : 60 mm Meter constant for Orificemeter: K=9.11 x10-3 h , h in m of water Brake drum dia D=0.23m Rope Dia t = 0.015m Input total head H in m of water = Pressure gauge reading in kg/cm2x 10 GRAPH: Discharge Vs Speed, output, Input, Efficiency  POST-LAB QUESTIONS 11.6.1 What is the energy conversion across the turbine? Differentiate stator and rotor vanes or blades? What do you meant by runner? What is the pressure inside the turbine casing? What do you meant by reaction turbine? List out different component efficiencies used? What do you meant by brake power? What do you meant by cavitation? 11.6.9 What are the methods to avoid cavitation? INFERENCES RESULTS The performance test on Francis turbine is conducted. EXPERIMENT No.12 PERFORMANCE TEST ON CENTRIFUGAL PUMP 12.1 Aim: To study the performance of centrifugal pump at constant speed. EQUIPMENTS Required: Centrifugal pump test rig, Stop watch 12.3 PREPARATION 12.3.1 THEORY A centrifugal pump is a rotodynamic pump that uses a rotating  HYPERLINK "http://en.wikipedia.org/wiki/Impeller" \o "Impeller" impeller to increase the pressure and flow rate of a fluid. Centrifugal pumps are the most common type of pump used to move liquids through a piping system. The fluid enters the pump impeller along or near to the rotating axis and is accelerated by the impeller, flowing radially outward or axially into a diffuser or  HYPERLINK "http://en.wikipedia.org/wiki/Volute" \o "Volute" volute chamber, from where it exits into the downstream piping system. Centrifugal pumps are typically used for large discharge through smaller heads. The priming of the pump is necessary in order to get discharge. The priming can be done by filling the impeller with water in order to provide continuous water column from the sump water level to pump. PRE-LAB QUESTIONS What is the purpose of pump? What do you meant by centrifugal force? What is type of flow in centrifugal pump? What is the use of volute casing? 12.3.2.5 What do you meant by priming? 12.4 PROCEDURE N.B.: If the pump is not delivering water output (discharge), prime the pump and then start the motor. Ensure the complete opened position of delivery valve. Start the pump power supply. Vary the flow rate (discharge) by closing the delivery valve. Note down pressure gauge reading for 0.5 kg/cm2 and vacuum gauges readings. Measure height of the pressure gauge above the vacuum gauge. (Z) Note down time taken (t) for h cm rise of water (10 cm) in collecting tank. Note down the time taken (T) for n revolutions for energy meter (3 rev) disc. Repeat the procedure for 0.5, 1.0, 1.5, 2.0, 2.5 kg/cm2 in the pressure gauge reading by gradual closing of delivery valve. Switch off the power supply after opening the delivery valve completely. 12.5 OBSERVATIONS 12.5.1 FORMULAE / CALCULATIONS 12.5.1.1. Total head, H = [ P + (V/760) ] x 105 / (( g ) + Z (m) Where P Pressure gauge reading in kg/cm2, V- Vacuum gauge reading in mm Hg, Z Datum level between Pressure gauge and Vacuum gauge g = Gravitational acceleration = 9.81 m2/s ( = Density of fluid (water) = 1000 kg/m3 N.B.: For V, 1 mm Hg/ 760 = 1 bar For P, 1 bar = 1 kg/ cm2 12.5.1.2. Discharge, Q = (A h )/ t (m3/sec) Where A- Collecting tank area = l x b in m2, t - time for 10 cm rise of water level in the collecting tank (sec) h Rise of water level in the collecting tank = 0.10 m 12.5.1.3. Output in kW, OP = ( g Q H / 1000 12.5.1.4. Input in kW, IP = (n rev of energy meter x 3600 x Efficiency of motor) / (Energy meter constant in Rev/kW-hr x Time for n revolutions) = (n x 3600 x (m ) / (Ec x T) Where Ec = Energymeter constant in Rev /kW hr = 1200 rev / kWh n = Number of revolution taken in energymeter T = Time required to complete n revolution in sec (m = Efficiency of motor = 0.8 12.5.1.5. Efficiency of Pump, ( = (Output / Input) x 100 % 12.5.2 TABULATION Motor Efficiency (m : 0.8, Energy meter Constant = 200 rev/kWh, Hight between the pressure gauges, Z = 500mm, Collecting tank Area, A = 0.5 x 0.5 m2 Sl. No.Pressure gauge reading PVacuum gauge reading VTime for 10cm rise of water tTime for 3 rev of energy meter disc T Head H Discharge QInput power IPOutput power OPEfficiency (kg/cm2mm of hgSecSecmm3/seckWkW%1.0.5213.1.54252.5 GRAPH: Disharge Vs Head, Output, Efficiency  Post-Lab Questions What is the energy conversion across the impeller? List out the different heads used in centrifugal pump? What do you meant by manometric head? What is the pressure inside the pump casing? 12.6.5 What do you meant by manometric efficiency? 12.6.6 What do you meant by cavitation, its effects and its prevention? 12.7 INFERENCES: 12.8 RESULT The performance test on centrifugal pump is completed and the performance characteristics are studied. EXPERIMENT No.13 IMPACT OF JET OF WATER ON VANES 13.1 Aim: To determine the coefficient of impact of water jet on different vanes 13.2 EQUIPMENTS Required: Jet on vane apparatus, Weighing machine, Flat vane, Flat vane with oblique impact, Conical vane, stop watch 13.3 Preparation 13.3.1 Theory Water turbines are widely used throughout the world to generate power. In the type of water turbine referred to as a Pelton wheel, one or more water jets are directed tangentially on to vanes or buckets that are fastened to the rim of the turbine disc. The impact of the water on the vanes generates a torque on the wheel, causing it to rotate and to develop power. Although the concept is essentially simple, such turbines can generate considerable output at high efficiency. To predict the output of a Pelton wheel, and to determine its optimum rotational speed, we need to understand how the deflection of the jet generates a force on the buckets, and how the force is related to the rate of momentum flow in the jet. In this experiment, we measure the force generated by a jet of water striking a flat plate or a hemispherical cup, and compare the results with the computed momentum flow rate in the jet.  Fig. Impact of Water jet on flat vane Pre-lab Questions What is the water jet? What is the effect of water jet on vanes? What do you meant by impact? List out different types of vanes? PROCEDURE Switch on the power supply. Open the gate valve and note down the reading from the weight balance. Then note the time for h m rise in collecting tank. Repeat the procedure for different gate valve openings. 13.4.5 Take readings for different vanes and nozzles also. 13.5 OBSERVATIONS 13.5.1 FORMULAE / CALCULATIONS 13.5.1.1 Actual discharge, Q = Volume of collecting tank/ time taken = A h / t Where, A - Area of collecting tank = length x breadth h - Water level rise in the collecting tank = 10 cm t - Time taken for h cm rise of water in the tank in sec 13.5.1.2 Theoretical force Ft = (( AN V 2)/ g Density of water, ( = 1000 kg/m3 Area of nozzle, AN = ( d2/4 Gravity, g = 9.81 m/s2 13.5.1.3 Velocity V = Q/ [Cc. AN] 13.5.1.4 Co-efficient of Impact, Ci = Fa / Ft Where Fa = Actual force acting on the Disc shown from Dial Gauge. 13.5.2 TABULATION Measuring area in tank = 0.5 x 0.4 m2 Dia of jet = 15mm Type of vane = Flat vane / Conical vane Co-efficient of Contraction, Cc = 0.97 Sl. No. Type of VaneTime for 10 cm rise of water (sec)Actual force, Fa in kgTheoretical Force, Ft in kgCo-efficient of impact, Ci123456 POST-LAB QUESTIONS How do you compare different vanes? What do you meant by co-efficient of impact? How do you measure the force of the jet? How do you measure actual flow rate? 13.6.5 How do you measure theoretical flow rate? INFERENCES 13.8 RESULT The co-efficient of impact of the given vane = ___________ EXPERIMENT No.14 FLOW VISUALIZATION - REYNOLDS APPARATUS 14.1 Aim: To demonstrate the flow visualization laminar or turbulent flow. 14.2 EQUIPMENTS Required: Reynolds Experimental set up, stop watch 14.3 Preparation 14.3.1 Theory The flow of real fluids can basically occur under two very different regimes namely laminar and turbulent flow. The laminar flow is characterized by fluid particles moving in the form of lamina sliding over each other, such that at any instant the velocity at all the points in particular lamina is the same. The lamina near the flow boundary move at a slower rate as compared to those near the center of the flow passage. This type of flow occurs in viscous fluids , fluids moving at slow velocity and fluids flowing through narrow passages. The turbulent flow is characterized by constant agitation and intermixing of fluid particles such that their velocity changes from point to point and even at the same point from time to time. This type of flow occurs in low density fluids, flow through wide passage and in high velocity flows.  Fig. Reynolds Experimental Set-up Reynolds conducted an experiment for observation and determination of these regimes of flow. By introducing a fine filament of dye in to the flow of water through the glass tube ,at its entrance he studied the different types of flow. At low velocities the dye filament appeared as straight line through the length of the tube and parallel to its axis, characterizing laminar flow. As the velocity is increased the dye filament becomes wavy throughout indicating transition flow. On further increasing the velocity the filament breaks up and diffuses completely in the water in the glass tube indicating the turbulent flow. There are two different types of fluid flows laminar flow and Turbulent flow. The velocity at which the flow changes laminar to Turbulent is called the Critical Velocity.  INCLUDEPICTURE "http://t2.gstatic.com/images?q=tbn:ANd9GcStwiMSwgldDszRE4pRzNDiivdjDPemn2JIAgGLdA_CaasAVrKkdQ&t=1" \* MERGEFORMATINET  Fig. Types of internal (pipe) flow Reynolds number determines whether any flow is laminar or Turbulent. Reynolds number corresponding to transition from laminar to Turbulent flow is about 2,300. Pre-lab Questions What do you meant by fluid? What are the types of flow? Define Reynolds number? What is laminar flow? 14.3.2.5 What is turbulent flow? PROCEDURE 1. Switch on the power supply. Adjust the water inflow slowly by flow control valve ( delivery valve). 2. Inject a filament of dye into the water stream by opening the value from dye tank. 3. When the flow is laminar, the colored stream of dye does not mix with the stream of water and is apparent long the whole length of the pipe. Increase the velocity of the stream gradually by opening the flow control valve, to see the turbulent flow. The stream of dye begins to oscillate and then diffused. This velocity of water in the pipe is Critical Velocity. 14.5 OBSERVATIONS 14.5.1 FORMULAE / CALCULATIONS Discharge, Q = (A h )/ t (m3/sec) Where A- Collecting tank area = l x b in m2, t - time for 10 cm rise of water level in the collecting tank (sec) h Rise of water level in the collecting tank = 0.10 m Reynolds number for pipe flow, Re = ( V D)/ ( Where V= Velocity of the fluid (m/s), D= diameter of the pipe (m) ( = Kinetic viscosity of the fluid (m2/s) 14.5.2 TABULATION Internal plan area of collecting tank = 0.3 x 0.3m2 Diameter of pipe D = 32 mm , Kinematics viscosity of fluid (water) = 1.01 x 10-6 m2/sec Sl. 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Mention the Reynolds no for laminar and turbulent flow? What do you meant by steady and unsteady flow? What do you meant by path line? 14.6.5 What do you meant by uniform and non-uniform flow? 14.7 INFERENCES 14.8 RESULT The flow visualization test is conducted.     PAGE  PAGE 46 7YZ+kdL$$Iflֈ  `A,"<<<<<< t0644 layt $IfgdZ\]^_`a $If`gdabdef8''' $If`gdkd $$Iflֈ  `A,"<<<<<< t0644 laytfghij'kd $$Iflֈ  `A,"<<<<<< t0644 layt $If`gdjlmnopq $If`gdqrtuv8''' $If`gdkd!$$Iflֈ  `A,"<<<<<< t0644 laytvwxyz'kdX"$$Iflֈ  `A,"<<<<<< t0644 layt $If`gdz{#C~ hdh^hgdoe dh`gd!dhgd!hhdh^h`hgd5Pdhgd!! dh^gd!!dhgdi & F1dhgd  & F0dhgd dhgdL hdh^hgdoe &`#$gd"%zh!h380JmHnHuh h0Jjh0JUh^K6&P1h:p// =!"[#$% 21h:pl:/ =!"#$% n ;zn gp~PNG  IHDRsRGBIDATx^]u}3ٲd2ɖcp8im@r33K$qF3>Wiڴ i'7]8}^{ JE~  _gtG`xG@F`6 ?#0<#0l9  ۦg`xGqm_]>a4 5mk+4<#`7A&1LVA(FU< ?9V*xx_,f~,I xϋ{37d?;nvP(X, $5X HH3/X6IGWJF`6܈?i 0Cp ҿ;D\Om>Nܟ{a/:V5}>Ǭ'8Κn~0 qhC[m;uVDR #??oʮq6F7r?'9ſ67; @I/ٰ/cXssN5Խ¨1C Na{x6=聛n Rԁ\vwGGǵ^;g! 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