ÐÏࡱá>þÿ ›þÿÿÿ™šôuù]ÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿì¥Áq` ø¿ÚÜbjbjqPqP 4::ÓlpÏÿÿÿÿÿÿ¤TTTT˜˜˜ø ô94545458l5dÐ5dìDïz*@7|¼7:ö7ö7ö7JXJXJX‰u‹u‹u‹u]èulTwlÀx$|h~´äxŘ [HR¤ìW^ [ [äxTTö7ö7R©z8q8q8q [àTZö7˜ö7‰u8q [‰u8q8qªür®ê˜;uö747 ñ©‘sÇ45j|umu¿z0ïz)u5|p¦5$;u5˜Iu$JX’ÜXh8qDYT˜YˆJXJXJXäxäx"qJXJXJXïz [ [ [ [ìDìDìDä{ÐÀdtìDìDìDÐÀ¬° Dô TTTTTTÿÿÿÿ  Learn Visual Basic 6.0 2. The Visual Basic Language Review and Preview Last week, we found there were three primary steps involved in developing an application using Visual Basic: Draw the user interface Assign properties to controls Attach code to events This week, we are primarily concerned with Step 3, attaching code. We will become more familiar with moving around in the Code window and learn some of the elements of the Basic language. A Brief History of Basic ·ð Language developed in early 1960's at Dartmouth College: B (eginner's) A (All-Purpose) S (Symbolic) I (Instruction) C (Code) Answer to complicated programming languages (FORTRAN, Algol, Cobol ...). First timeshare language. In the mid-1970's, two college students write first Basic for a microcomputer (Altair) - cost $350 on cassette tape. You may have heard of them: Bill Gates and Paul Allen! Every Basic since then essentially based on that early version. Examples include: GW-Basic, QBasic, QuickBasic. ·ð Visual Basic was introduced in 1991. Visual Basic Statements and Expressions ·ð The simplest statement is the assignment statement. It consists of a variable name, followed by the assignment operator (=), followed by some sort of expression. Examples: StartTime = Now Explorer.Caption = "Captain Spaulding" BitCount = ByteCount * 8 Energy = Mass * LIGHTSPEED ^ 2 NetWorth = Assets - Liabilities The assignment statement stores information. Statements normally take up a single line with no terminator. Statements can be stacked by using a colon (:) to separate them. Example: StartTime = Now : EndTime = StartTime + 10 (Be careful stacking statements, especially with If/End If structures. You may not get the response you desire.) If a statement is very long, it may be continued to the next line using the continuation character, an underscore (_). Example: Months = Log(Final * IntRate / Deposit + 1) _ / Log(1 + IntRate) ·ð Comment statements begin with the keyword Rem or a single quote ('). For example: Rem This is a remark ' This is also a remark x = 2 * y ' another way to write a remark or comment You, as a programmer, should decide how much to comment your code. Consider such factors as reuse, your audience, and the legacy of your code. Visual Basic Operators ·ð The simplest operators carry out arithmetic operations. These operators in their order of precedence are: Operator Operation ^ Exponentiation * / Multiplication and division \ Integer division (truncates) Mod Modulus + - Addition and subtraction ·ð Parentheses around expressions can change precedence. ·ð To concatenate two strings, use the & symbol or the + symbol: lblTime.Caption = "The current time is" & Format(Now,  hh:mm ) txtSample.Text = "Hook this  +  to this There are six comparison operators in Visual Basic: Operator Comparison > Greater than < Less than >= Greater than or equal to <= Less than or equal to = Equal to <> Not equal to ·ð The result of a comparison operation is a Boolean value (True or False). ·ð We will use three logical operators Operator Operation Not Logical not And Logical and Or Logical or ·ð The Not operator simply negates an operand. ·ð The And operator returns a True if both operands are True. Else, it returns a False. ·ð The Or operator returns a True if either of its operands is True, else it returns a False. Logical operators follow arithmetic operators in precedence. Visual Basic Functions ·ð Visual Basic offers a rich assortment of built-in functions. The on-line help utility will give you information on any or all of these functions and their use. Some examples are: Function Value Returned Abs Absolute value of a number Asc ASCII or ANSI code of a character Chr Character corresponding to a given ASCII or ANSI code Cos Cosine of an angle Date Current date as a text string Format Date or number converted to a text string Left Selected left side of a text string Len Number of characters in a text string Mid Selected portion of a text string Now Current time and date Right Selected right end of a text string Rnd Random number Sin Sine of an angle Sqr Square root of a number Str Number converted to a text string Time Current time as a text string Timer Number of seconds elapsed since midnight Val Numeric value of a given text string A Closer Look at the Rnd Function In writing games and learning software, we use the Rnd function to introduce randomness. This insures different results each time you try a program. The Visual Basic function Rnd returns a single precision, random number between 0 and 1 (actually greater than or equal to 0 and less than 1). To produce random integers (I) between Imin and Imax, use the formula: I = Int((Imax - Imin + 1) * Rnd) + Imin The random number generator in Visual Basic must be seeded. A Seed value initializes the generator. The Randomize statement is used to do this: Randomize Seed If you use the same Seed each time you run your application, the same sequence of random numbers will be generated. To insure you get different numbers every time you use your application (preferred for games), use the Timer function to seed the generator: Randomize Timer Place this statement in the Form_Load event procedure. Examples: To roll a six-sided die, the number of spots would be computed using: NumberSpots = Int(6 * Rnd) + 1 To randomly choose a number between 100 and 200, use: Number = Int(101 * Rnd) + 100 Example 2-1 Savings Account 1. Start a new project. The idea of this project is to determine how much you save by making monthly deposits into a savings account. For those interested, the mathematical formula used is: F = D [ (1 + I)M - 1] / I where F - Final amount D - Monthly deposit amount I - Monthly interest rate M - Number of months 2. Place 4 label boxes, 4 text boxes, and 2 command buttons on the form. It should look something like this:  3. Set the properties of the form and each object. Form1: BorderStyle 1-Fixed Single Caption Savings Account Name frmSavings Label1: Caption Monthly Deposit Label2: Caption Yearly Interest Label3: Caption Number of Months Label4: Caption Final Balance Text1: Text [Blank] Name txtDeposit Text2: Text [Blank] Name txtInterest Text3: Text [Blank] Name txtMonths Text4: Text [Blank] Name txtFinal Command1: Caption &Calculate Name cmdCalculate Command2: Caption E&xit Name cmdExit Now, your form should look like this:  4. Declare four variables in the general declarations area of your form. This makes them available to all the form procedures: Option Explicit Dim Deposit As Single Dim Interest As Single Dim Months As Single Dim Final As Single The Option Explicit statement forces us to declare all variables. 5. Attach code to the cmdCalculate command button Click event. Private Sub cmdCalculate_Click () Dim IntRate As Single ‘Read values from text boxes Deposit = Val(txtDeposit.Text) Interest = Val(txtInterest.Text) IntRate = Interest / 1200 Months = Val(txtMonths.Text) ‘Compute final value and put in text box Final = Deposit * ((1 + IntRate) ^ Months - 1) / IntRate txtFinal.Text = Format(Final, "#####0.00") End Sub This code reads the three input values (monthly deposit, interest rate, number of months) from the text boxes, computes the final balance using the provided formula, and puts that result in a text box. 6. Attach code to the cmdExit command button Click event. Private Sub cmdExit_Click () End End Sub 7. Play with the program. Make sure it works properly. Save the project. Visual Basic Symbolic Constants Many times in Visual Basic, functions and objects require data arguments that affect their operation and return values you want to read and interpret. These arguments and values are constant numerical data and difficult to interpret based on just the numerical value. To make these constants more understandable, Visual Basic assigns names to the most widely used values - these are called symbolic constants. Appendix I lists many of these constants. As an example, to set the background color of a form named frmExample to blue, we could type: frmExample.BackColor = 0xFF0000 or, we could use the symbolic constant for the blue color (vbBlue): frmExample.BackColor = vbBlue It is strongly suggested that the symbolic constants be used instead of the numeric values, when possible. You should agree that vbBlue means more than the value 0xFF0000 when selecting the background color in the above example. You do not need to do anything to define the symbolic constants - they are built into Visual Basic. Defining Your Own Constants You can also define your own constants for use in Visual Basic. The format for defining a constant named PI with a value 3.14159 is: Const PI = 3.14159 User-defined constants should be written in all upper case letters to distinguish them from variables. The scope of constants is established the same way a variables’ scope is. That is, if defined within a procedure, they are local to the procedure. If defined in the general declarations of a form, they are global to the form. To make constants global to an application, use the format: Global Const PI = 3.14159 within the general declarations area of a module. Visual Basic Branching - If Statements ·ð Branching statements are used to cause certain actions within a program if a certain condition is met. The simplest is the If/Then statement: If Balance - Check < 0 Then Print "You are overdrawn" Here, if and only if Balance - Check is less than zero, the statement  You are overdrawn is printed. ·ð You can also have If/Then/End If blocks to allow multiple statements: If Balance - Check < 0 Then Print "You are overdrawn" Print "Authorities have been notified" End If In this case, if Balance - Check is less than zero, two lines of information are printed. ·ð Or, If/Then/Else/End If blocks: If Balance - Check < 0 Then Print "You are overdrawn" Print "Authorities have been notified" Else Balance = Balance - Check End If Here, the same two lines are printed if you are overdrawn (Balance - Check < 0), but, if you are not overdrawn (Else), your new Balance is computed. ·ð Or, we can add the ElseIf statement: If Balance - Check < 0 Then Print "You are overdrawn" Print "Authorities have been notified" ElseIf Balance - Check = 0 Then Print "Whew! You barely made it" Balance = 0 Else Balance = Balance - Check End If Now, one more condition is added. If your Balance equals the Check amount (ElseIf Balance - Check = 0), a different message appears. In using branching statements, make sure you consider all viable possibilities in the If/Else/End If structure. Also, be aware that each If and ElseIf in a block is tested sequentially. The first time an If test is met, the code associated with that condition is executed and the If block is exited. If a later condition is also True, it will never be considered. Key Trapping ·ð Note in the previous example, there is nothing to prevent the user from typing in meaningless characters (for example, letters) into the text boxes expecting numerical data. Whenever getting input from a user, we want to limit the available keys they can press. The process of interecepting unacceptable keystrokes is key trapping. ·ð Key trapping is done in the KeyPress procedure of an object. Such a procedure has the form (for a text box named txtText): Sub txtText_KeyPress (KeyAscii as Integer) . . . End Sub What happens in this procedure is that every time a key is pressed in the corresponding text box, the ASCII code for the pressed key is passed to this procedure in the argument list (i.e. KeyAscii). If KeyAscii is an acceptable value, we would do nothing. However, if KeyAscii is not acceptable, we would set KeyAscii equal to zero and exit the procedure. Doing this has the same result of not pressing a key at all. ASCII values for all keys are available via the on-line help in Visual Basic. And some keys are also defined by symbolic constants. Where possible, we will use symbolic constants; else, we will use the ASCII values. ·ð As an example, say we have a text box (named txtExample) and we only want to be able to enter upper case letters (ASCII codes 65 through 90, or, correspondingly, symbolic constants vbKeyA through vbKeyZ). The key press procedure would look like (the Beep causes an audible tone if an incorrect key is pressed): Sub txtExample_KeyPress(KeyAscii as Integer) If KeyAscii >= vbKeyA And KeyAscii <= vbKeyZ Then Exit Sub Else KeyAscii = 0 Beep End If End Sub ·ð In key trapping, it's advisable to always allow the backspace key (ASCII code 8; symbolic constant vbKeyBack) to pass through the key press event. Else, you will not be able to edit the text box properly. Example 2-2 Savings Account - Key Trapping 1. Note the acceptable ASCII codes are 48 through 57 (numbers), 46 (the decimal point), and 8 (the backspace key). In the code, we use symbolic constants for the numbers and backspace key. Such a constant does not exist for the decimal point, so we will define one with the following line in the general declarations area: Const vbKeyDecPt = 46 Add the following code to the three procedures: txtDeposit_KeyPress, txtInterest_KeyPress, and txtMonths_KeyPress. Private Sub txtDeposit_KeyPress (KeyAscii As Integer) ‘Only allow number keys, decimal point, or backspace If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then Exit Sub Else KeyAscii = 0 Beep End If End Sub Private Sub txtInterest_KeyPress (KeyAscii As Integer) ‘Only allow number keys, decimal point, or backspace If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then Exit Sub Else KeyAscii = 0 Beep End If End Sub Private Sub txtMonths_KeyPress (KeyAscii As Integer) ‘Only allow number keys, decimal point, or backspace If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then Exit Sub Else KeyAscii = 0 Beep End If End Sub (In the If statements above, note the word processor causes a line break where there really shouldn’t be one. That is, there is no line break between the words Or KeyAscii and = vbKeyDecPt. One appears due to page margins. In all code in these notes, always look for such things.) Rerun the application and test the key trapping performance. Select Case - Another Way to Branch SYMBOL 183 \f "Symbol" \s 10 \h In addition to If/Then/Else type statements, the Select Case format can be used when there are multiple selection possibilities. Say we've written this code using the If statement: If Age = 5 Then Category = "Five Year Old" ElseIf Age >= 13 and Age <= 19 Then Category = "Teenager" ElseIf (Age >= 20 and Age <= 35) Or Age = 50 Or (Age >= 60 and Age <= 65) Then Category = "Special Adult" ElseIf Age > 65 Then Category = "Senior Citizen" Else Category = "Everyone Else" End If The corresponding code with Select Case would be: Select Case Age Case 5 Category = "Five Year Old" Case 13 To 19 Category = "Teenager" Case 20 To 35, 50, 60 To 65 Category = "Special Adult" Case Is > 65 Category = "Senior Citizen" Case Else Category = "Everyone Else" End Select Notice there are several formats for the Case statement. Consult on-line help for discussions of these formats. The GoTo Statement ·ð Another branching statement, and perhaps the most hated statement in programming, is the GoTo statement. However, we will need this to do Run-Time error trapping. The format is GoTo Label, where Label is a labeled line. Labeled lines are formed by typing the Label followed by a colon. GoTo Example: Line10:  . . GoTo Line10 When the code reaches the GoTo statement, program control transfers to the line labeled Line10. Visual Basic Looping ·ð Looping is done with the Do/Loop format. Loops are used for operations are to be repeated some number of times. The loop repeats until some specified condition at the beginning or end of the loop is met. ·ð Do While/Loop Example: Counter = 1 Do While Counter <= 1000 Debug.Print Counter Counter = Counter + 1 Loop This loop repeats as long as (While) the variable Counter is less than or equal to 1000. Note a Do While/Loop structure will not execute even once if the While condition is violated (False) the first time through. Also note the Debug.Print statement. What this does is print the value Counter in the Visual Basic Debug window. We'll learn more about this window later in the course. ·ð Do Until/Loop Example: Counter = 1 Do Until Counter > 1000 Debug.Print Counter Counter = Counter + 1 Loop This loop repeats Until the Counter variable exceeds 1000. Note a Do Until/Loop structure will not be entered if the Until condition is already True on the first encounter. ·ð Do/Loop While Example: Sum = 1 Do Debug.Print Sum Sum = Sum + 3 Loop While Sum <= 50 This loop repeats While the Variable Sum is less than or equal to 50. Note, since the While check is at the end of the loop, a Do/Loop While structure is always executed at least once. ·ð Do/Loop Until Example: Sum = 1 Do Debug.Print Sum Sum = Sum + 3 Loop Until Sum > 50 This loop repeats Until Sum is greater than 50. And, like the previous example, a Do/Loop Until structure always executes at least once. ·ð Make sure you can always get out of a loop! Infinite loops are never nice. If you get into one, try Ctrl+Break. That sometimes works - other times the only way out is rebooting your machine! ·ð The statement Exit Do will get you out of a loop and transfer program control to the statement following the Loop statement. Visual Basic Counting ·ð Counting is accomplished using the For/Next loop. Example For I = 1 to 50 Step 2 A = I * 2 Debug.Print A Next I In this example, the variable I initializes at 1 and, with each iteration of the For/Next loop, is incremented by 2 (Step). This looping continues until I becomes greater than or equal to its final value (50). If Step is not included, the default value is 1. Negative values of Step are allowed. ·ð You may exit a For/Next loop using an Exit For statement. This will transfer program control to the statement following the Next statement. Example 2-3 Savings Account - Decisions 1. Here, we modify the Savings Account project to allow entering any three values and computing the fourth. First, add a third command button that will clear all of the text boxes. Assign the following properties: Command3: Caption Clear &Boxes Name cmdClear The form should look something like this when you’re done:  2. Code the cmdClear button Click event: Private Sub cmdClear_Click () ‘Blank out the text boxes txtDeposit.Text = "" txtInterest.Text = "" txtMonths.Text = "" txtFinal.Text = "" End Sub This code simply blanks out the four text boxes when the Clear button is clicked. Code the KeyPress event for the txtFinal object: Private Sub txtFinal_KeyPress (KeyAscii As Integer) ‘Only allow number keys, decimal point, or backspace If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then Exit Sub Else KeyAscii = 0 Beep End If End Sub We need this code because we can now enter information into the Final Value text box. The modified code for the Click event of the cmdCalculate button is: Private Sub cmdCalculate_Click() Dim IntRate As Single Dim IntNew As Single Dim Fcn As Single, FcnD As Single ‘Read the four text boxes Deposit = Val(txtDeposit.Text) Interest = Val(txtInterest.Text) IntRate = Interest / 1200 Months = Val(txtMonths.Text) Final = Val(txtFinal.Text) ‘Determine which box is blank ‘Compute that missing value and put in text box If txtDeposit.Text = "" Then ‘Deposit missing Deposit = Final / (((1 + IntRate) ^ Months - 1) / IntRate) txtDeposit.Text = Format(Deposit, "#####0.00") ElseIf txtInterest.Text = "" Then ‘Interest missing - requires iterative solution IntNew = (Final / (0.5* Months * Deposit) - 1) / Months Do IntRate = IntNew Fcn = (1 + IntRate) ^ Months - Final * IntRate / Deposit - 1 FcnD = Months * (1 + IntRate) ^ (Months - 1) - Final / Deposit IntNew = IntRate - Fcn / FcnD Loop Until Abs(IntNew - IntRate) < 0.00001 / 12 Interest = IntNew * 1200 txtInterest.Text = 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„h„˜þ^„h`„˜þŒ<<˜<¾<Ö>Þ>"?(?N?Z?ì@ò@,CHCLCPCÐEèEðEôEFFlFsF³F´FpGxGJJ^JrJnKzKŒK˜KúKLºM¾MBNKN¯NºNÛNP PPP#P9PlPPP•P›P­P±PæPçPÚS|T~TT‡TŒT˜T6UYU[UöìáìáìöìáìáìáìöìáìöìáìáìáìáìöìáìáìáìáìöìáìÔÉìáìáì¾ìáìáìáì¾ì¾ìáìáìáìáìhRkê5CJOJQJhRkê5CJOJQJhRkê5>*CJOJQJhRkê5CJOJQJhRkêCJOJQJhRkêCJOJQJEâ=ò=ö= ?"?r?v?°?ê?@@@d@s@y@–@ž@ @&A'A,C.C0CJCLCìEðEõëåëëëõõõõõõõõõëååÝÛÛÛÛëë & Fgds‰„h^„h „h„˜þ^„h`„˜þ „Є0ý^„Ð`„0ýðEvFwF¢F¥F¨F«F³F´F3I4ItLvLÐL:MTMbM„M–M¨M¸MºM­N®N»N¼NÛNõóíííííóçóõóíííííííííõóâóâ$a$„h^„h„Ð`„Ð „h„˜þ^„h`„˜þÛNÜN!P"P9P;P¯P°PèPQ„QQ–Q¥Q¬Q´Q½Q¿Q÷Q-R“RŸR¥R´R»RÃRÌRÎRýóóóóëóóóóóóóóóóóóóóóóóóóóó & Fgds‰ „h„˜þ^„h`„˜þÎRS;S¡S­S³SÂSÈSÐSÙSÛS÷TøT5UZU[UþUÿU3V5VFVdV‰V¢VõõõõõõïõõõåõÝÛõõõÓõÉÉÉÉ „Є0ý^„Ð`„0ý & Fgds‰ & Fgds‰ „h„h]„h^„h„h^„h „h„˜þ^„h`„˜þ[U\U{U|U®U¹U%V'VWšW+Y,Y@YZ¶Z¾Zj[t[~[Ž[˜[\\N\V\n\t\„\†\p]˜]œ] ]Ò]â]>_B_\_1`6`ù`a—abb ccDdHdbd"e,etfxf’fBhFhi&iÎiÒiîiüiÎjüjkkñçñçÜçÜçÜçÒÜÒçÜçÜÅçÅçºçÜç¨ç¨çÜçÒçÜçÒÜçÜçÜçÒÜçÜçÒÜçÜçÒÜçÒçÜçÒçÜçÜçÒ"jhRkêOJQJUmHnHuhRkê6CJOJQJhRkê56CJOJQJhRkêCJOJQJhRkê5CJOJQJhRkêCJOJQJjhRkêCJOJQJUB¢VòVW&WEWKWiWqWsW¥W§W¸WÂWâWóWX-XMX]X~X‹X«X·X¹X*Y+Y,Yõõõõõõõëåëõõõõõõõõõõõõëåëë„h^„h „h„˜þ^„h`„˜þ „Є0ý^„Ð`„0ý,Y@YAYJ\N\j\n\„\Œ\’\ª\¬\l]n]p]š]œ]<_>_p_r_Š_¼_è_ `õõõõíõããããáÛááááõáõáÕÕÕÕ„Ð^„Єh^„h ÆÀ„ ^„  & Fgds‰ „h„˜þ^„h`„˜þ ```–a—a2b4bLb~bªbÚbäbæbBdDdvdxdˆdŽd²dÒdüdþdrftf¦f¨fù÷ñ÷ç÷ááááá÷ñ÷ç÷ááááá÷ñ÷ç÷„Ð`„Ð „h„˜þ^„h`„˜þ„h^„h„Ð^„Шf¸f¾fâfg*g,g@hBhÊiÎiÌjÎjÐjþjkhkjkzk|kªkÂkâkðkòk$m%mùùùùù÷ññççç÷÷÷÷ç÷ñ÷ùùùù÷ñ÷ „h„˜þ^„h`„˜þ„h^„h„Ð`„ÐkJkZkjkxknlrlnnPn`nþno"o*CJOJQJhRkêCJOJQJhRkê5CJOJQJhRkêCJOJQJ:%mo o:o & F„h„˜þ>ÆT€h.Tfÿ^„h`„˜þgds‰ & F gds‰ „h„˜þ^„h`„˜þ & F gds‰„h^„ht5tJtlt†t¥tÆtàtýtu6ufuƒu”uÑuv$vTvŽv“v¨vév,wÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀ> & F„h„˜þ>ÆT€h.Tfÿ^„h`„˜þgds‰,wNw€w›wËwëwûwAÀlÀ‹À ÀÛÀÁÁÁÁÀÀÀÀÀÀÀÀÀÀÀÀÀÀÀ> & F„h„˜þ>ÆT€h.Tfÿ^„h`„˜þgds‰ Months = Log(Final * IntRate / Deposit + 1) / Log(1 + IntRate) txtMonths.Text = Format(Months, "###.0") ElseIf txtFinal.Text = "" Then ‘Final value missing Final = Deposit * ((1 + IntRate) ^ Months - 1) / IntRate txtFinal.Text = Format(Final, "#####0.00") End If End Sub In this code. we first read the text information from all four text boxes and based on which one is blank, compute the missing information and display it in the corresponding text box. Solving for missing Deposit, Months, or Final information is a straightforward manipulation of the equation given in Example 2-2. If the Interest value is missing, we have to solve an Mth-order polynomial using something called Newton-Raphson iteration - a good example of using a Do loop. Finding the Interest value is straightforward. What we do is guess at what the interest is, compute a better guess (using Newton-Raphson iteration), and repeat the process (loop) until the old guess and the new guess are close to each other. You can see each step in the code. Test and save your application. Go home and relax. Exercise 2-1 Computing a Mean and Standard Deviation Develop an application that allows the user to input a sequence of numbers. When done inputting the numbers, the program should compute the mean of that sequence and the standard deviation. If N numbers are input, with the ith number represented by xi, the formula for the mean ( EMBED Equation.2 ) is: EMBED Equation.2   EMBED Equation.2  = ( EMBED Equation.2 )/ N and to compute the standard deviation (s), take the square root of this equation: s2 = [N EMBED Equation.2  - ( EMBED Equation.2 )2]/[N(N - 1)] The Greek sigmas in the above equations simply indicate that you add up all the corresponding elements next to the sigma. My Solution: Form:  Properties: Form frmStats: Caption = Mean and Standard Deviation CommandButton cmdExit: Caption = E&xit CommandButton cmdAccept: Caption = &Accept Number CommandButton cmdCompute: Caption = &Compute CommandButton cmdNew: Caption = &New Sequence TextBox txtInput: FontName = MS Sans Serif FontSize = 12 Label lblStdDev: Alignment = 2 - Center BackColor = &H00FFFFFF& (White) BorderStyle = 1 - Fixed Single FontName = MS Sans Serif FontSize = 12 Label Label6: Caption = Standard Deviation Label lblMean: Alignment = 2 - Center BackColor = &H00FFFFFF& (White) BorderStyle = 1 - Fixed Single FontName = MS Sans Serif FontSize = 12 Label Label4: Caption = Mean Label lblNumber: Alignment = 2 - Center BackColor = &H00FFFFFF& (White) BorderStyle = 1 - Fixed Single FontName = MS Sans Serif FontSize = 12 Label Label2: Caption = Enter Number Label Label1: Caption = Number of Values Code: General Declarations: Option Explicit Dim NumValues As Integer Dim SumX As Single Dim SumX2 As Single Const vbKeyMinus = 45 Const vbKeyDecPt = 46 cmdAccept Click Event: Private Sub cmdAccept_Click() Dim Value As Single txtInput.SetFocus NumValues = NumValues + 1 lblNumber.Caption = Str(NumValues) ‘Get number and sum number and number-squared Value = Val(txtInput.Text) SumX = SumX + Value SumX2 = SumX2 + Value ^ 2 txtInput.Text = "" End Sub cmdCompute Click Event: Private Sub cmdCompute_Click() Dim Mean As Single Dim StdDev As Single txtInput.SetFocus ‘Make sure there are at least two values If NumValues < 2 Then Beep Exit Sub End If ‘Compute mean Mean = SumX / NumValues lblMean.Caption = Str(Mean) ‘Compute standard deviation StdDev = Sqr((NumValues * SumX2 - SumX ^ 2) / (NumValues * (NumValues - 1))) lblStdDev.Caption = Str(StdDev) End Sub cmdExit Click Event: Private Sub cmdExit_Click() End End Sub cmdNew Click Event: Private Sub cmdNew_Click() 'Initialize all variables txtInput.SetFocus NumValues = 0 lblNumber.Caption = "0" txtInput.Text = "" lblMean.Caption = "" lblStdDev.Caption = "" SumX = 0 SumX2 = 0 End Sub txtInput KeyPress Event: Private Sub txtInput_KeyPress(KeyAscii As Integer) 'Only allow numbers, minus sign, decimal point, backspace, return keys If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyMinus Or KeyAscii = vbKeyDecPt Or KeyAscii = vbKeyBack Then Exit Sub ElseIf KeyAscii = vbKeyReturn Then Call cmdAccept_Click Else KeyAscii = 0 End If End Sub Exercise 2-2 Flash Card Addition Problems Write an application that generates random addition problems. Provide some kind of feedback and scoring system as the problems are answered. My Solution: Form:     Properties: Form frmAdd: BorderStyle = 1 - Fixed Single Caption = Flash Card Addition CommandButton cmdNext: Caption = &Next Problem Enabled = False CommandButton cmdExit: Caption = E&xit TextBox txtAnswer: FontName = Arial FontSize = 48 MaxLength = 2 Label lblMessage: Alignment = 2 - Center BackColor = &H00FFFF00& (Cyan) BorderStyle = 1 - Fixed Single FontName = MS Sans Serif FontBold = True FontSize = 24 FontItalic = True Label lblScore: Alignment = 2 - Center BackColor = &H0000FFFF& (Yellow) BorderStyle = 1 - Fixed Single Caption = 0 FontName = Times New Roman FontBold = True FontSize = 36 Label Label1: Alignment = 2 - Center Caption = Score: FontName = MS Sans Serif FontSize = 18 Label Label4: Alignment = 2 - Center Caption = = FontName = Arial FontSize = 48 Label lblNum2: Alignment = 2 - Center FontName = Arial FontSize = 48 Label Label2: Alignment = 2 - Center Caption = + FontName = Arial FontSize = 48 Label lblNum1: Alignment = 2 - Center FontName = Arial FontSize = 48 Code: General Declarations: Option Explicit Dim Sum As Integer Dim NumProb As Integer, NumRight As Integer cmdExit Click Event: Private Sub cmdExit_Click() End End Sub cmdNext Click Event: Private Sub cmdNext_Click() 'Generate next addition problem Dim Number1 As Integer Dim Number2 As Integer txtAnswer.Text = "" lblMessage.Caption = "" NumProb = NumProb + 1 'Generate random numbers for addends Number1 = Int(Rnd * 21) Number2 = Int(Rnd * 21) lblNum1.Caption = Format(Number1, "#0") lblNum2.Caption = Format(Number2, "#0") 'Find sum Sum = Number1 + Number2 cmdNext.Enabled = False txtAnswer.SetFocus End Sub Form Activate Event: Private Sub Form_Activate() Call cmdNext_Click End Sub Form Load Event: Private Sub Form_Load() Randomize Timer NumProb = 0 NumRight = 0 End Sub txtAnswer KeyPress Event: Private Sub txtAnswer_KeyPress(KeyAscii As Integer) Dim Ans As Integer 'Check for number only input and for return key If (KeyAscii >= vbKey0 And KeyAscii <= vbKey9) Or KeyAscii = vbKeyBack Then Exit Sub ElseIf KeyAscii = vbKeyReturn Then 'Check answer Ans = Val(txtAnswer.Text) If Ans = Sum Then NumRight = NumRight + 1 lblMessage.Caption = "That's correct!" Else lblMessage.Caption = "Answer is " + Format(Sum, "#0") End If lblScore.Caption = Format(100 * NumRight / NumProb, "##0") cmdNext.Enabled = True cmdNext.SetFocus Else KeyAscii = 0 End If End Sub This page intentionally not left blank.     2- PAGE 10 Learn Visual Basic 6.0  The Visual Basic Language 2- PAGE 11  2- PAGE 1 lblNumber txtInput cmdCompute cmdExit lblMean lblStdDev Label1 cmdAccept cmdNew Label6 Label4 Label2 lblNum2 Label4 Label2 txtAnswer lblMessage lblNum1 Label1 lblScore cmdNext cmdExit ÁUÂVÂÄÄCÄQÄRÄzÄ{ÄÈÅÿÅƼ¼}}upppnnpp$a$ & F gds‰> & F„h„˜þ>ÆT€h.Tfÿ^„h`„˜þgds‰B & F„h„h„˜þ>ÆT€h.Tfÿ]„h^„h`„˜þgds‰ •Å¨Å©ÅªÅ«Å°Å±ÅÄÅÅÅÆÅÇÅÈÅÉÅÜÅÝÅÞÅßÅãÅäÅ÷ÅøÅùÅúÅýÅÆTÆUÆYÆZÆöåÓÅöÅö´¢ÅöÅö‘ÅöÅön\ÅöUöJöUhRkêCJH*OJQJ hRkê6CJ"jé E6 hRkêCJEHäÿOJQJU jé E6 hRkêUVmHnHu"jê E6 hRkêCJEHüÿOJQJU jê E6 hRkêUVmHnHu"jì E6 hRkêCJEHöÿOJQJU jì E6 hRkêUVmHnHujhRkêCJOJQJU"jí E6 hRkêCJEHüÿOJQJU jí E6 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