ࡱ> WYVY bjbj[[ 49 \9 \ ^^?!0000     $"%       00 www .00 w  wwVd@( 0$9^ !0?!xg&pg&( ( >g&f D  w      p   ?!    g&         ^> : MOTION: Velocity and Acceleration Test Study Guide You will need to know: The difference between distance and displacement How to draw or read a motion map (the dots) . . . . . . That velocity and speed are basically the same, but velocity has a direction How to read a distance / time graph How to read a velocity / time graph How to calculate the average velocity of a given timeframe How to use the formula for velocity to calculate velocity, distance or time v = d t How to calculate the acceleration of an object, or be able to use the formula for acceleration to find the unknown variable a = vf-vi t Below is a position (distance)/time graph Average velocity is the total distance divided by the total time (in a given time frame) For example: If I gave you a graph like the one below and asked you to calculate the average velocity of Charlies run, you would take the total distance run and divide by the total time. V= 100m / 17 seconds = 5.88m/s BUT if I asked you to calculate the average velocity for the first part of his run from start to 8 seconds, you would calculate v= 50m/8s = 6.25 m/s  When looking at a velocity / time graph, you can tell if something is going a constant velocity or accelerating based on the shape of the line. Look at the graph below to answer the following questions: Which segments show a constant velocity? _____________ Which segments show a positive acceleration (speeding up)? ____________ Which segments show a negative acceleration (slowing down)? ____________  INCLUDEPICTURE "http://www.bbc.co.uk/scotland/education/bitesize/standard/img/physics/forces_and_motion/speed-time/bus-graph.gif" \* MERGEFORMATINET  In the graph above, if I asked: Calculate the acceleration for segment D-E, you would take the final velocity at E (5m/s) and subtract the velocity at D (0m/s), then divide by the time of that segment which is 5s. 5 - 0 a= 5 a= 1m/s2 Things to remember The slope of the line (how steep it is) will tell us if something is going faster or slower. The steeper the slope, the faster the object Velocity is a rate, so you will always have some unit per time unit : m/s, km/hr, etc. Acceleration is a rate of velocity, so the time unit will usually be squared: km/hr2 m/s2 etc. If you have access to the internet, remember that I have the powerpoints and some of our worksheets we practiced with. 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