ࡱ> a bjbj** 2H=bH=b+ DDDDDXXX8<\X(:b(eeeKMMMMMM$z"dqDeeeeeqDD!!!eRDDK!eK!!!`H5Rv!70!"-"!!&"DGee!eeeeeqqKeeeeeee"eeeeeeeee B : Name: PHYSICS 201 LAB 7 Part 1. RC Circuit  Find the equivalent resistance of the charging circuit. Show work.  Find the equivalent capacitance of the charging circuit. Show work.  Find the theoretical time constant of the charging circuit. Show work.  Find the equivalent resistance of the discharging circuit. Show work.  Find the equivalent capacitance of the discharging circuit. Show work.  Find the theoretical time constant of the discharging circuit. Show work. Determine the simulated charging time constant. Paste the appropriate oscilloscope screen.  Determine the simulated discharging time constant. Paste the appropriate oscilloscope screen.  Part 2. Digital to Analog Conversion. Build the following circuit. The VDAC (voltage digital to analog converter) can be found under the MIXED button.  A digital (eight-bit) number is entered in the top inputs. The output is an analog voltage that corresponds to a fraction of the maximum voltage. In particular, the fraction of the voltage is the fraction represented by the bits. This should remind you of the mantissa of a float. Fill in the table below. 76543210Voltage% of Vmax111111111000000001000000001100110101010110101010 Part 3. Rewire your parallel loading register (shown below) to turn it into a parallel loading shift register. Have zeros fed in while the shifting occurs. Paste a copy of your shift register in this document.  Part 4. Baby CRC The circuit below is a small example of a CRC generator. The data is fed in using the data switch D. The clock C must go through a cycle (in particular go through a positive edge) for the shifting to occur. When the binary string 11000001010 is fed into the CRC generator (starting with the leftmost bit), the generator has the string 1010 at the end. Build the circuit below and check this. Change a bit in the binary string and enter it into the CRC and see if the result is different. And so on.  InputCRC outputA. 110000010101010Change one of the bits above B. Add four 0s to the end Input A C. 110000010100000Add the output of part C to the end of Input A D. Change two consecutive bits above E. Part 5. Multiplication Perform the following multiplication in detail. 1011(1011 1101(1010 Part 6. Float conversions. Express 5768.903 as a float. Use 1 bit for the sign, 23 bits for the mantissa, and 8 bits for the exponent. Use a bias of 127 for the exponent. Write an expression for 8675. Ignoring any leading zeros, how many bits does it use? 5768 in binary: # of bits for whole number: If we are going to use 24 bits (23 stored & one implied), how many are left for the fractional part? Write an expression for the fraction. This time include any leading zeros. # of bits for fraction: Binary expression for .903:  How many shifts are required to move the dot separating whole number and fraction to where there is only one digit (a 1) in the whole number? What is the effect of biasing on the number? Number of shifts: Effect of biasing Put the pieces together. Sign  Exponent  Mantissa  Paste below a screen capture from  HYPERLINK "https://www.h-schmidt.net/FloatConverter/IEEE754.html" https://www.h-schmidt.net/FloatConverter/IEEE754.html showing the check on your answer produces a result close to the original 5768.903. Part B. Express 0.0001066 as a float. Use 1 bit for the sign, 23 bits for the mantissa, and 8 bits for the exponent. Use a bias of 127 for the exponent. Multiply the number by 2^24 and convert the whole number portion of the result to binary. How many bits are you short of the desired 24? Multiply and convert: How many bits missing? Repeat above but multiply by 2^(24+missing_number).  Use the missing_number and the bias of 127 to determine the exponent.  Put the pieces together. Sign  Exponent  Mantissa  Paste below a screen capture from  HYPERLINK "https://www.h-schmidt.net/FloatConverter/IEEE754.html" https://www.h-schmidt.net/FloatConverter/IEEE754.html showing the check on your answer produces a result close to the original 0.0001066. Part C. Express the following float as a decimal number. Sign 1 Exponent 00110001 Mantissa 01110111011101110111011 The decimal number can be expressed as (-1)^(sign)*(number between 1 and 2 from mantissa)*2^(number from un-biasing the exponent) number between 1 and 2 from mantissa number from un-biasing the exponent  Put the pieces together and calculate  Paste below a screen capture from  HYPERLINK "https://www.h-schmidt.net/FloatConverter/IEEE754.html" https://www.h-schmidt.net/FloatConverter/IEEE754.html showing the check on your answer.      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