ࡱ> wyrstuvs[[[[ bjbj RmKKcccwwwwd wQD \C&C&C&C&~N$7jcj ~KKC&C&' KC&cC&lC&x"w!0Qc Q :  Chapter 3 Problems OPEN(ENDED PROBLEMS FOR PORTFOLIO PROJECTS A problem is an unresolved mathematical situation of likely interest to the student, at least a bit beyond the level of classroom instruction, the solution for which not readily apparent, the solution calling for independent decisions by the student. To summarize: A. Description of a problem 1. Just beyond level of instruction 2. Of likely interest to students 3. Student decisions needed for solution The purposes of problem-solving are these: problem-solving is a necessary life skill; students need practice in making decisions; and success gives students a thrill of self-sufficiency not present when working standard exercises, thereby bringing confidence and pleasure to the study of mathematics. To summarize: B. Purposes of problem-solving 1. Life skill 2. Practice needed in making mathematics decisions 3. Thrill of self-sufficiency Teacher treatment of problems should be different from teacher treatment of standard exercises. Teachers should not have time limits on how soon problems should be solved. Teachers should never divulge solutions to problems -- only encouragement and hints, and those hints only to students who have made attempts. In light of the need for students to be taught new material and remember/ synthesize old material during the precious classroom time, teachers should seriously consider having students attempt solving problems at home, or otherwise outside the classroom. To summarize: C. Teacher treatment of problems 1. No deadlines 2. Teacher does not divulge solution 3. Place and time: at home The reaction of the typical student to being confronted with a problem might be to raise the hand almost immediately and say, "Teacher, help me. You've never shown us how to do anything like this." And the teacher should respond, "Yes, I know, but this is something you can figure out on your own without my help. You need to be patient, try it for a while, stop when you're stuck, sleep on it, keep trying off and on for several days if needed." Problem-solving can begin in the earliest grades with first objectives. Standard curriculum provides pattern problems involving shapes and number sequences. Example: complete: 7, 5, 10, 8, 13, 11, 16, ____, ____ Teachers should also be alert to patterns in multiplication tables. Pascals triangle has patterns that can be suggested to students in upper grades. Fibbonacci numbers also give non-standard patterns. Dale Seymour Publications and professional journals have books and articles detailing these. Geometric and arithmetic limits can be discovered as take-home problems also. See methods textbook, pages 92-93. Surface area of a box (rectangular prism) is a problem for students who know how to find rectangle area. Surface area is an important idea anyway, and is always such a struggle with direct teaching that students may as well struggle with it at home for a week or more. OPEN-ENDED PROBLEMS Open-ended problems as presented here differ from other non-standard problems in that they are 1. Amenable to modifications. First, the teacher presents the standard problem, often a classic. Second, after the student has solved the original, the teacher shows a modification of the original problem, that the student also solves. Finally, the student creates a new modification, and solves again. 2. Of lasting interest (months or years). Mathematicians often work for weeks, months, years, and lifetimes on problems, sometimes without success. A problem originally shown to a third-grader may become a competition project in junior high or high school. Which brings up the next point: 3. Of possible use in Science Fair (ISEF) or Count On Domino's competitions. ISEF has a mathematics division; Domino's is entirely mathematics. These competitions give students awards for efforts that will give adults quite valuable rewards. Students can't see the eventual benefit, so short-term competition benefit is a good incentive. 4. Opportunities for student generalization, the essence of mathematics discovery. Polya's Strategies Polya's classic How To Solve It lists universal heuristics (tricks?) for solving problems, open-ended or otherwise. The following list is based on Polyas inventory of problem-solving strategies from How to Solve It. 1. Draw a picture (or build a model) 2. Guess and check 3. Work an easier, related problem 4. Look for unseen data 5. Try an equation 6. Look for a pattern 7. Use the data somehow (reasons unknown at that point). 8. Work backwards 9. Change form10. Use partial results 11. Use a variable 12. Use an auxiliary element 13. Use a convenient (ideal?) case 14. Make a chart; use counting strategies 15. Look for an inhibiting assumption 16. Use a formula 17. Use a spreadsheet 18. List and eliminate possibilities (constrain search) 19. Use transformations Excellent resources A. Creative Puzzles of the World is a wonderful anthology of string, sliding-block, tangram, maze, Tavern, and other puzzles. The book is out of print but Dale Seymour has a revision. The one flaw (!) is that answers are provided. Also provided are directions for making puzzles. B. Tucker-Jones House sells Tavern Puzzles, ideal problem-solving practice even for those who have no background in mathematics. A catalog may be obtained from (516) 751-8960 or 9 Main Street, Setauket, NY 11733 C. Any books by Martin Gardner or Sam Loyd D. www.puzzles.com E. MATHCOUNTS F. Put on your hat, go out, walk around, and look. EXAMPLES OF OPEN-ENDED PROBLEMS #1. String Puzzles; Tavern Puzzles The basic wrist problem is shown below. The object is to separate the two people (so as to eat in separate restaurants) without cutting or untying string, or slipping string off wrists. One variation to be shown to successful students is also shown.    \ / \ /   ? ! Other variations include removing a vest while still wearing a sports coat over the vest, and a famous variation of that exemplified by an actress in "Crocodile Dundee." A sequence of a gradual progression of these puzzles, would make a winning project. #2 The Sleep Stopper is pictured here. The object is to get the beads together on the same segment of string. One variation would involve more holes and beads. An unnamed variation has the string anchored within one hole.   Jumping games #3 The first example (The Old Timer) is derived from a puzzle usually made from an eight-inch piece of 1/2" x 1/2" piece of wood with nine evenly-spaced holes drilled into it in a row. Four golf tees of one color occupy the first four holes, and four tees of another color occupy the last four, with one hole left in between. The objective is to exchange one color for another using "forward" checker moves (one hole at a time), jumping over, but not removing, tees of the other color, with a minimum of moves. This game can be modified to rows of squares with other objects besides golf tees, thus making it possible for the student to work on the problem/puzzle whenever there is boredom. The puzzles objective is to change the coins from one side to the other in as few moves as possible. There are rules: 1. You may move a coin (or bean) one space either way. 2. You may jump one coin (or bean) over another, but only over one other coin (or bean), and only if the square on the other side is unoccupied before the jump. The classic game begins with nine positions:  A better starting point for some students is the minimum game, with only three squares and only one coin of each kind. Three moves finish the task.  From here, the student tries a five-square, four-coin game, etc. The projects objective is to count how many moves for each size of game. Find pattern. Later: find a formula to predict the minimum number of moves needed for n of each coin. Once the student has found the pattern for the classic game, the teacher variation might be to have two squares in the middle. Students can easily vary other rules or arrangements, including three dimensions, and find a pattern for those variations. #4 The next jumping game is a classic triangle configuration of 15 positions as shown. Markers are placed in 14 positions, and checker-style jumping is used to eliminate all but one marker, the last marker resting where there was no marker initially. Again, the typical game is played with a wooden triangle with holes and golf tees, but coins and a drawing will suffice.   ((( first level -- three holes, two tees. No game.((( second level -- six holes, five tees. One automatic game.(((( third level -- ten holes. Two games. Outcomes?((((( fourth level -- how many games? Outcomes? The original classic game can be varied, as there are four distinct kinds of initial positions to leave open. Once students have mastered the original game, which may take years, the game can be reduced to a "minimum game" of only three positions, two marked. This game is quickly seen as impossible to even start-- a "no game." The next game has six possible positions, two possible opening variations, one a "no game", the other impossible. The next game has ten positions and three possible openings -- a pattern for number of possible openings is one of several patterns that may emerge. Student variations might include three dimensions again. #5. Pool Hall numbers Of possible interest to only mediocre pool players is the fact that the set of 15 numbered balls makes a triangle, and when finished, these 15 are joined by the cue ball to make 16, a perfect square. If 15 is then called a Pool Hall Number, the questions arise. Are there others? The student must only begin with the triangular numbers, adding one and checking to see if the sum is a perfect square. It is not difficult for a student with elementary knowledge of BASIC to write a nine-step program that will allow a computer to explore this question. After this might come the usual questions: How many pool hall numbers exist? Is there a pattern? Is there a formula? What about three (and more?) dimensions? These questions have caught the attention of no less than John Dossey, former President of NCTM and a decent mathematician as well as an outstanding mathematics educator and leader. #6 This has been called the Fore and Aft Game by Sam Loyd, based on The Old Timer. The goal is to exchange the pennies and nickels. The pennies can be moved only down and to the right. The nickels move only to the left and up. A coin may be moved to an adjacent empty square, but never diagonally. A coin may jump one coin of the other kind.  P P P P P P P P N N N N N N N N#7 Rearrange the coins from formation 1 to formation 2 exactly (as if the dotted circle was a fifth coin) and by sliding one coin to a new position without disturbing another, keeping the coins flat. Solution is possible in two moves.  formation 1 formation 2 #8 Tower of Hanoi Also called the Tower of Brahma, this is reputed to be the oldest mathematical game or puzzle. Students involved in a project will find rich reading in the library on this topic. The traditional game involves disks with holes in their centers and three posts, one the starting post, another a resting post, and the last the finish post. The disks are of different diameters and are placed on the post in order of size, with the largest on the bottom. Again, coins of varied diameters and three circles drawn on paper or on bare ground will suffice. The Idea: Move the coins from the start position to the end position in as few moves as possible.The Rules: 1. Move one coin at a time. 2. Never put a coin on top of a smaller coinThe Project:Count how many moves for each size of game. Find a pattern. Write a formula that will give the minimum number of moves when the number of coins is given.  start rest finish The student may start with two coins, then three, and so on, backing up to one coin also in search of a pattern, so that the number of moves for n coins can be predicted by formula. A teacher variation might be to double the number of coins of each type, so that where there might have been a tower of one dime, one nickel, and one quarter in the original game, there are now two of each, plus an extra resting place. The only new rule is that a coin cannot be places on the other of its kind until the final stacking at the finish. Another pattern and another formula emerge. Whereon the number of coins might be tripled from the original game, and another resting place drawn, and another formula emerges. With some inspection, the student can look at all three formulas and come up with a grandparent formula that turns into each individual formula when the number of multiples is supplied. Other variations are possible. #9. A ninth problem is to create artwork involving the Impossible E, Impossible Triangle (Roger Penroses Triangle), or the Impossible Cage, as done with Eschers Waterfall and Belvedere or this writers boring faculty meeting doodles on another page. The Impossible E, Impossible Triangle, and Impossible Cage appear below.          Most of the Polya-style heuristics listed above are in one or more of problems 10(28 below. 10. A truck show features normal pickups (four tires and one steering wheel) and "dualies" (one steering wheel, six tires). If there are 230 tires on all and 48 steering wheels, how many trucks are there of each type? 11. A man has a fox, a chicken. and a bag of corn that must be rowed across a pond. But his boat can carry only one thing at a time. If he takes the fox across first, the chicken will eat the corn. If he takes the corn across first, the fox will eat the chicken. The fox won't eat the corn. How can he row all three across without leaving any of his possessions in danger of being eaten by another at any stage? 12. A hobo can make a cigarette out of every five butts. How many can this person make out of 25 butts? 13. How many squares are there (of any size) in a standard checkerboard? How many rectangles? 14. How many different combinations of coins can be used to make thirty cents? 15. Find the smallest number that has a remainder of 3 when divided by 4 or by 5 or by 6 . 16. A point P is chosen on one side of a 3 x 4 rectangle, and this point is connected to the two ends of the side across from the side containing P. Find area of the triangle formed by P and the two opposite ends. 17. A vertical yard-stick casts a four-foot shadow while a nearby tree casts an 80-yard shadow. How tall is the tree? 18. A child's bank has dimes and quarters (37 coins in all), with total value $6.40 . How many dimes does the bank contain? 19. Which is greater, the height of a can of three tennis balls, or the distance around the base of the can? 20. Find the volume of a cube with surface area (total) 150 square units. 21. The population of scum in a scum pond triples every hour. At 10:00, the population was 8,730,000 organisms. When was the population 970,000 organisms? 22. Draw a path (if possible) through the doors of this house so that every door is used exactly once. 23. A square of maximum size is drawn inside a quarter-circle of radius .76 . Find the length of a diagonal of the square. 24. A person travels 60 miles per hour for a certain number of hours and then 40 miles per hour for the return trip. What is the average speed? 25. Suddenly, we've lost the digit 7. This means we've also lost 17, 27, all of the 70(71(72(... , all of the 700's, and so on. What fraction of the natural numbers have we lost? 26. A man and a woman leave a stockholders' meeting armed with data needed by their respective agencies. One seat is left on the plane; the race is on. Each makes a public restroom stop before leaving the building. What is the probability that one will be delayed because of a lack of gender consideration on the part of the building architect?27. Es Puzzle The task is to use the pieces given to make another letter E, congruent to the original (same shape and size). No cutting or tearing is allowed. All of the given pieces must be used entirely and as given. 28. Logic puzzle 1. Angie, Becky, Cindy, Doreena, and Evelyn are the starting basketball team for their school. 2. The tallest is the center. 3. Becky, Cindy, and Doreena all play different positions. 4. One of the forwards is new to the school this year. 5. The two guards want to room together in college. 6. Doreena has never tried out to be a guard. 7. Doreena is the second-smallest player on the team. 8. Angie, Becky, Cindy, and Doreena are returning teammates from last years squad. 9. Angie and Becky do not get along as well with one another as the coach would like. 10. Becky got the position that Evelyn wanted, and Evelyn got the position that Cindy wanted. Problem: name the center. Problems 29-49 are from Foundations of Mathematics by Denbow and Goedecke 29. A horseman starts from the rear of a column of troops, 4 miles long, and rides to the head of the column. Then he forthwith rides back at the same rate to the rear. During this time the column advanced 6 miles. How far did the horseman ride? 30. Two men are walking through a railroad tunnel, from north to south. They are three-eighths of the way through the tunnel when they hear a train approaching the tunnel from the north, at a rate of 60 miles per hour. One man runs north and just meets the train at the north entrance; the other runs south, at the same rate, and the train overtakes him at the south entrance. How fast can the men run? (Adapted from Mathematics Magazine, May-June 1955, p.289.) 31. A business manager wished to hire a man for an important position, requiring the greatest possible intelligence. He narrowed the field to three applicants, who appeared to be equally intelligent, and decided to give them the following test to choose the brainiest of the three. He seated them all at a table and blindfolded them. Then he told them: I am going to draw a brush across the forehead of each of you but I wont tell you whether it has been dipped in water or in ink. Then I will remove the blindfolds. I want each of you to rap on the table if you see a blue mark on either of the other two. Then figure out if you yourself have a blue mark. The first man who can tell me whether he had a blue mark on his own forehead, and prove it, gets the job. So saying he made blue marks on all three foreheads, removed the bandages, and left. Each man saw blue marks on the others; each man rapped. For a few minutes each man sat trying to see what he could deduce about his own forehead, then suddenly one man jumped up, went to the manager, and said, I have a blue mark on my own head and I can prove it. His reasoning was correct and he got the job. Explain. 32. A pasture will feed 22 cows for 5 weeks, or 14 cows for 10 weeks, the grass growing continuously all the time. How many cows would it feed for 20 weeks? 33. A balance scale is usually equipped with a set of weights consisting of at least five 1-gram weights, several fives, several tens, and so forth. You could manage with far fewer weights. For example, to weigh out 4 grams of a chemical you could place a 1-gram weight on one pan and a 5-gram weight on the other, and pour the chemical on the 1-gram side until the two sides balanced. With the most efficient possible system what is the number of weights needed to weigh anything from 1 to 100 grams, to the nearest gram? From 1 to 1000 grams? 34. One day a man named Smith went for a walk in a park and unexpectedly met an old friend, whom he had not seen or had any news about for 20 years. After they had exchanged greetings, the old friend said: I have married since I knew you, to someone you never met, and we have a little girl now, and she is here with me in the park. The old friend called the girl over and said: Daughter, I want you to meet Mr. Smith. The girl was too shy to answer, and Smith said: Hello, little girl, whats your name? The girl finally overcame her shyness and answered: My name is the same as my mothers Smith then said: Oh, then your name must be Patricia. Now what is the simplest possible explanation of the fact that smith knew that the girls name was Patricia? (This problem is not a trivial one. It is based on an important principle of psychology. If you have failed to solve it, it is because you have introduced into your picture of the situation a pure assumption which is not justified by anything in the problem, and which prevents you from seeing the solution. To solve it you must try too locate this unwarranted assumption which you have introduced. This is difficult because the more you go over it, the deeper becomes the groove in your mind which makes you repeat the mistake. To overcome this difficulty you must reread the problem and construct your mental picture over again, being careful not to insert anything in the picture which the problem does not require you to insert. Ability to locate hidden assumptions is important in mathematical and logical reasoning.) 35. An unemployed boomerang repairer finds that he is reduced to pawning a watch chain, a family heirloom, in order to protect his wife and children from starvation. Hoping from day to day to find work, he pawned only one link of the chain per day, until he had pawned all its 63 links. But in the meantime he provided us with an excellent puzzle. Each day he made a cut in a new link, in order to remove it from the chain and take it to the e pawnshop, thus wasting a number of cuts. For example, if he had looked ahead and started by cutting the third link from one end, he could have pawned this cut link the first day, then taken the two-link piece to the pawnshop on the second day and traded it for the cut link already at the pawnshop, and so forth. What is the fewest number of cuts which would have sufficed for a daily pawning of one link? 36. A man hired a rowboat and rowed upstream until he was a mile above his starting point. At this point the boat struck a bottle floating in the water. He continued rowing upstream for an hour after he struck the bottle. Then his curiosity about the contents of the bottle overcame him and he turned and rowed back downstream. He overtook the bottle (which he found to be empty) just as he reached his original starting point. How fast is the current of the river flowing? 37. A druggist uses a balance scales to weigh all the drugs he sells. One arm of the balance is longer than the other, but the druggist does not know this, and so he puts the weights sometimes on one pan and sometimes on the other, indifferently. Does the error balance out on the average, or does the druggist systematically cheat himself, or does he systematically cheat his customers? 38. A man has a barrel of water and a cask of wine. He takes a cup of wine from the cask and adds it to the barrel of water. He then takes a cup of this mixture from the barrel and empties it back into the cask, thus returning some of the wine to the cask. Compare the net amount of water transferred from the barrel to the cask with the net amount of wine transferred from the cask to the barrel. Is it larger, or smaller, or are they the same? 39. If an aviator flies around the earth at the equator, keeping a constant altitude of 2 miles, how many more miles will he travel than one who goes around the equator at an altitude of 1 mile? (Assume that the equator is a perfect circle, 25,000 miles in circumference.) 40. Arrange six matches so that they form four equilateral triangles, each a match length on each side. (Do not break or bend the matches.) 41. Without lifting your pencil from the paper, draw a set of four straight lines, that go through the nine points shown. (No retracing permitted)( ( ( ( ( ( ( ( (42. A missionary lands on an island that is known to be inhabited by two tribes. Members of tribe A always tell the truth, and members of tribe B always lie. The missionary meets a native, but does not know whether he is from tribe A or tribe B. He wishes to know whether the man is a Christian or not. His interpreter tells him that the native is willing to answer exactly one question. How can the missionary phrase one single question which will enable him to discover whether the man is a Christian or not? 43. Two prisoners wish to divide a cake between them, and they decide that a fair division will be insured if one of them divides the cake as evenly as possible, and then the other takes his choice of the two halves, so that neither could complain of being treated unfairly. But before they carry out the plan they are joined by a third prisoner. How can they modify their plan to insure a fair division into three pieces? 44. Three men enter a dark closet, which they know to contain two black hats and three white hats. Each dons a hat, without seeing its color, and they emerge into the light. It occurred to one of them that the situation provided an excellent puzzle, and he proposed that each one look at the others hats, and then try to deduce the color of his own. The first man said, I dont know the color of my hat, the second said, I dont know the color of my hat either, and the third man said, My hat is ______, and I can prove it. The third man was blind. State the color of his hat, and show how he proved it. 45. Some burglars stole a dozen quarts and a dozen pints of wine. They drank five quarts and five pints and then divided the rest. The bottles were of value also and so they also were divided, each man getting the same amount of wine, the same number of quart bottles, and the same number of pint bottles. No wine is transferred from one bottle to another in the process of division. How many burglars were there, and how was the division made? 46. A man gambles with another by flipping a coin, gambling half of the money in his possession on each toss, and betting on heads each time. During the game there are as many heads as tails. Does the man win or lose, and how much per double throw? 47. A dairyman uses a can marked A, partially filled with milk, and a can marked B, partially filled with water. From can A he pours enough to double the contents of can B then from can B he pours enough to double the contents of can A, then from A he pours into can B until their contents are equal. Now what is the proportion of milk to water in can A? 48. A commuter was accustomed to having his wife pick him up at the station. From long experience his wife started from home each day just in time to reach the station as the train arrived. One day the commuter took an early train, which arrived an hour earlier than usual. The man started walking homeward from the station, and met his wife on the road. She picked him up and drove home, and he noticed that he had reached home twenty minutes earlier than usual. How long had he been walking when she picked him up? 49. A wine merchant has two customers, one with a five-pint measure and one with a three-pint measure, each wishing to buy one pint of wine. The merchant has mislaid his measuring cup. How can he place an exact pint in each measure? 50. Ray Trickshot arranges mirrors for a laser-gun stunt according to these rules: Mirror One must be located on an East-West line 100 yards north of Ray, facing away from Ray. Mirror Two must be located on an East-West line 150 yards north of Ray, facing Ray. Mirror Three must be located on an East-West line 200 yards north of Ray, facing Ray. Rays laser-beam must hit all three mirrors and then hit a target that is 100 yards directly east of Ray. Rays laser-beam must travel a path of minimum length. Problem: What is the length of that path? 51. A hungry spider settles down on the floor in the corner of a room for a midday nap. Suddenly he spies a fly resting on the floor in the opposite corner. What a yummy snack the fly would be, thinks the spider. The spider sets out to trap the fly. The spider is clever. He takes the shortest path without walking on any part of the floor. (No chance of getting squished!) (a) What is the shortest path if the room is 6 meters long, 5 meters wide, and 3 meters high? (b) What is the shortest path if the room is 10 meters long, 6 meters wide, and 3 meters high? 52. (From Angel and Porter). a) There are five houses. b) The green house is directly to the right of the ivory house. c) The Scot has the red house. d) The dog belongs to the Spaniard. e) The Slovak drinks tea. f) The person who eats cheese lives next door to the fox. g)The Japanese eats fish.h) Milk is drunk in the middle house. i) Apples are eaten in the house next to the horse. j) Ale is drunk in the green house. k) The Norwegian lives in the first house. l) The peach eater drinks whiskey. m) Apples are eaten in the yellow house. n) The banana eater owns a snail. o) The Norwegian lives next door to the blue house.Find: 1) the color of each house, 2) the nationality of the occupant, 3) the type of food eaten in each house, 4) the owners favorite drink, 5) the owners pet, and 6) Finally, the crucial question is: Does the zebras owner drink vodka or ale? 53. Place four nickels and four pennies in a circle so that when you start with the top one and count clockwise, and remove every fifth coin, the first four coins removed will be the pennies, but if you remove every ninth coin, the first four coins removed will be the nickels. PRIVATE  54. How many diagonals will a polygon of n sides have? 55. A tree frog at the bottom of a 30foot well can make a jump of five feet, but rests between jumps, and while resting, slides back three feet. How many jumps are needed to get out of the well? 56. When a number is divided by 2, the remainder is 1. When the same number is divided by 3, the remainder is 2; when it's divided by 4, the remainder is 3; when it's divided by 5, the remainder is 4; when it's divided by 6, the remainder is 5. However, when it is divided by 7, there is NO remainder. What is the smallest number that works here? 57. Which is heavier, a pound of feathers or a pound of gold? 58. How many lines are determined by n non-collinear points? 59. How many intersection points are produced by n non-parallel lines in a plane, no three of which are concurrent? 60. A barnyard has cows and chickens. Among them are 80 feet and 31 heads. How many chickens are there? 61. The number abcde becomes edcba when multiplied by 4. What is abcde? 62. Exchange the positions of the coins shown using the fewest moves.. You may slide a coin to an adjacent unoccupied square, or jump over one or two other coins to an unoccupied square. You may jump in either direction and a coin may jump over coins of either value. Try for ten moves or less.   1 1 1 2 2 2 63. Identify the digits represented by each different letter in these arithmetic statements: SEND + MORE = MONEY I + M = ME AT + A = TEE 64. How many regions are formed by the diagonals of a polygon of n sides, if no pair of diagonals are parallel and no three are concurrent? 65. What are checkerboard dimensions wherein each square can be visited exactly once by a knight? 66. Number the corners of a cube from 18 so that the sum of the numbers at each face add to 18. 67. The combined volumes of two cubes is equal to the sum of all their edges. What are those edges? 68. If the can of pop costs 50 cents and the pop costs 30 cents more than the empty can, how much does the can cost? 69. Two bottles of equal volume contain a mix of alcohol and water, in ratios of 3:1 and 2:1 respectively. When the contents are mixed, what is the alcohol:water ratio? 70. At a mathematical potluck, three people shared each meat dish, four shared each vegetable dish, and there was enough for five in each rice dish. If the caterer used 141 dishes in all to serve the meat, veggies, and rice, how many people attended the potluck? 71. How many equally shortest pathways exist between points A and B?  A (  ( B 72. Consider these triangles made of matchsticks.  3 matchsticks; bottom has one. 9 matchsticks; bottom has two.  18 matchsticks; bottom has three. Problem: How many matchsticks will be needed to continue this pattern until the bottom has ten? 73. What is the tens digit of 511 ? 74. What is the remainder when 291 is divided by 5 ? 75. How many squares can be made with four of these dots as corners? ((((((((((((((((  76. For the dartboard shown, what is the 4 9 highest possible score that a player cannot get? 77. Find the 50th letter of ABBCCCDDDD. . . 78. Imagine a cube that looks like a Rubics Cube, made up of 27 smaller cubes glued together. How many small cubes have exactly one side painted? Exactly two sides painted?  1 1 1 79. Five robots can make 5 parts in five minutes. How many parts can 10 robots make in 100 minutes?  2 2 80. Find the surface area of the solid shown at right. 3 (------- 2 ------- 81. The squares below are attached at their edges. Up to transformation, how many different patterns can be made in this way using four squares? 3 3  82. The postage stamps at right are attached at their edges. Up to transformation, how many different patterns can be made in this way using four postage stamps?  9 9 9 983. By single moves to unoccupied squares or jumps over single coins, reverse the order of the coins.  1 2 3 4 5 6 7 8 Problems 84 ( 98 are from Charles Barry Townsend collections. 84. The figure below is made from 36 identical segments or sticks. Remove 8 sticks so that six squares (of any size) remain.  85. Move one of the sticks in the figure on the right to make six squares (of any size). 86. With two straight cuts, cut a square of paper into pieces that are either perfect squares or can be joined to make perfect squares. After the joinings, you should have three perfect squares. 87. One of nine coins is lighter than each of the other identical eight coins. Show how to use a balance scale to find out which one is the lighter one with just two weighings.  88. Cut this sheet into five pieces, each of which contains each of the five vowels. 89. Place seven of each of the letters A through G in a 7 ( 7 square grid so that no two letters of any kind appear twice in any row or column or long diagonal.  E U O A U O A I O E A I E A I O U I U A E U I O E 90. Cut out a square of cardboard that is just big enough to cover four of the numbered squares below. Discover a method for telling someone the sum of any four numbers that they cover up with the cardboard without your seeing the numbers. 311810271431181027141224162820122416282013302292613302292619112315321911231532251729218251729218311810271431181027141224162820122416282013302292613302292619112315321911231532251729218251729218 92. How do you time the fifteen-minute boiling of a very large egg if you have only an eleven-minute sand timer and a seven-minute sand timer? 93. Move three of the sticks so that you have four identical triangles. 94. Arrange the numbers 1-9 in the squares so that the sum of the numbers along any side of the triangle is 20. ----- ----- ----- 95. Lay out 12 coins on the table with heads and tails as shown. By touching only one of the coins, make the four vertical columns either all heads or all tails.  H T H T T H T H H T H T 96. The area of the flap is the same as the area of the two cutout parts. The figure shown was made from one single sheet of paper. How was the paper cut (etc.) to make the figure shown? 97. It takes 25 seconds to ring 5:00 with five evenly-spaced bell rings. How long will it take to ring 10:00 ? 98. Three crates contain tennis balls. Crate A is labeled while only, crate B is labeled yellow only, and crate C is labeled white and yellow. All three labels belong on a different crate. Tell how to know which crate is which by drawing only one ball from one crate. 99. A lighthouse has a circular floor with a circular rug concentric to the floor. A 14-foot fishing pole lies tangent to the carpet and is a chord of the circle border of the floor. Find the area of the floor not covered by the carpet. (The name for this two-dimensional-donut shape is annulus.) 100. A ten-inch-long hole is drilled through the center of a sphere. What is the volume of the sphere that remains? 101. Position eight queens on a chessboard, none of which share a row, column, or diagonal. Problems 102 ( 110 are from Charles Barry Townsend collections 102. Four equations are shown here, one vertical and three horizontal. Rearrange the numbers 1-9 so that all four equations are correct. 1 ( 3 = 2 ( 4 ( 5 = 6 || 7 + 8 = 9 103. Remove four sticks so that only five squares remain. 104. Arrange nine coins in ten rows with three coins in each row. 105. A customer purchased a book for $12 and paid with a $20 bill. The clerk was out of singles and so went next door to the bank to change it. Then he gave the customer the book and $8 change, and noted that he had made a $6 profit on the book. Fifteen minutes later the banker came in and said that the $20 was counterfeit. The clerk gave the banker two $10 bills from the register. How much has the bookstore clerk lost? 106. Move two coins to obtain four rows with four coins in each.   107. Place the numbers 1-12 in the circles shown so that the sum of the eight outer-circle numbers is twice the sum of the four inner-circle numbers and the inner-circle numbers are consecutive integers.  108. Connect the water, gas, and electricity lines to the three houses without any of the lines crossing over, under, or through either of the other lines. GAS WATER ELECTRIC  HOUSE HOUSE HOUSE ONE TWO THREE  109 . Place eight coins on the diagram so that each circle has exactly two, and each straight line has two.  110. Write the digits 1(9 in one of two columns so that the sums of the two columns are the same.  111. The object of the puzzle at the right is to remove eight disks, leaving one on the center square, using the fewest possible moves. A move consists of (1) moving a disk to any adjacent square, up, down, left, right, or diagonally, or (2) jumping a disk as in checkers except that the jump can also be in any direction. The jumped disk is then removed. 112. Place ten coins in a 4(4 grid so as to form the largest number of rows (horizontal, vertical, or diagonal) with an even number of coins. 113. Two customers each want two quarts of milk. One customer has a five-quart pail and the other has a four-quart pail. The milkman has only two ten-gallon cans, each full of milk. How can the correct measure be done? 114. A farmer has six pieces of chain. Each piece had five links. He wants an endless piece of thirty consecutive links. It costs eight cents to cut a link open and eighteen cents to weld it shut again. A new endless chain of thirty links costs $1.50. How much can be saved by the most economical cutting/welding plan?  115. How can these megaphones be rearranged so that the digits marked on 3 1 6 them will form a three-digit number exactly divisible by seven? 116. I started two watches at the same time and found that one of them went two minutes an hour too slow and the other went one minute an hour too fast. When I looked at them again, the faster watch was exactly one hour ahead of the other. How long had the watches been running? 117. How many different equilateral triangles are in the design?  118. A bottle and a glass balance a pitcher. A bottle balances a glass and a saucer. Two pitchers balance three saucers. How many glasses balance a bottle? 119. Mother Hubbards three shelves each had twenty quarts of black rasberry jam. The top shelf has one large jar, three medium jars, and three small jars. The second shelf has six small jars and two large jars. The bottom shelf has four medium jars and six small jars. How much jam does each size hold?  120. Transpose the nickel and dime by moving one coin at a time to a vacant square. 5 25 10 1 1  121. Place sixteen checkers on a regular 8(8 checkerboard so that there are no more than two in any row -- horizontal, vertical, diagonal. One stipulation: the first two men must be placed on two of the four center squares of the board. 122. Place the largest number of eggs in a 6(6 egg carton so that there are no more than two eggs in any single row -- horizontal, vertical, diagonal. One stipulation: the first two eggs places must be at opposite ends of one of the long diagonals. 123. The bulls eye of an archery target is worth 40. The next ring (annulus) is worth 39; the next, 24; the next, 23; the next, 17; and the last, 16. How many arrows are needed to score exactly 100?  124. Fill in the circles using the numbers 1 through 9 exactly once each, so that the sum along each of the five rows is 17. 125. With two cuts, divide either vase figure into figure into three parts that can be reassembled as a square. Hint: try five pieces to start. 126. These are from Berloquin, 100 Perceptual Puzzles, and Gardner, ah! Insight. Cut these figures with one line (curved or straight or both) so as to make two identical parts.  example: solution:   A B C D D ED    E   F G H I  J     K   L M   Halve white N  region only.  Problems K, L, M, O, P, Q, R, S, and T are from a Games collection, many published elsewhere. The Games editors stipulated that the two halves for these problems must be congruent without any reflecting. The obvious solution to S, the one that resembles an angel, is not allowed.    O P Q    R S  R   T  . .    127. Use weights 1 through 8 exactly once each in the triangular balance positions. Distance between weight and balance point is important; for example, a weight of ten at a distance of three from the balance point will balance with a weight of six at a distance of five from the balance point. The weights of ten and six combined for a force of sixteen as a sub-system at the point where the whole sub-system hangs.      128. One slice will cut a pizza into two regions. Two intersecting slices will cut the pizza into four regions. How many regions are produced by five slices, no two of which are parallel and no three of which are concurrent? 129. A knight moves by sliding two squares straight up or down, and then one square left or right. OR, it may move two squares left or right, and then one space up or down. Using a minimum number of knight moves, replace the white knights with black, and vice versa.   140( 130. Find the number of degrees in angle X. X 106(  131. Four equations are shown here, one vertical and three horizontal. Rearrange the numbers 1-9 so that all four equations are correct. 1 ( 3 = 2 ( 4 ( 5 = 6 ( 7 + 8 = 9  EMBED Equation.3 132. Solve for x:  EMBED Equation.3  133. Three jealous husbands and their wives have to cross a river at a ferry. They find a rowboat so small that it can contain no more than two persons. Find the simplest schedule of crossings that will permit all six people to cross the river, and none of the women shall be left in the company of anothers husband unless her own husband is present also. All passengers on the boat get out before the next trip. At least one person has to be in the boat for each crossing. Each woman can row. 134. Tell how to measure nine minutes with a four-minute hourglass and a seven-minute hourglass. 135. Recall from The Riddle of Scheherazade that Mazdaysians never lie and Aharmanites always lie. All members of any one family are of the same type, Mazdaysians or Aharmanites. Thus, any pair of brothers are either both truthful or both liars. Bahman and Perviz are brothers of each other. They were both asked if they were married. They gave the following replies: Bahman: We are either both married or both unmarried. Perviz: I am not married. If possible, tell the marital status of each. 136.  Semicircles are drawn in the square as shown. The area of the square is 100. What is the area of the shaded region?  137. Joe throws an ordinary six-sided die (singular of dice) and Moe throws another. What is the probability that Joe throws a higher number than Moe? 138. Divide 100 by and add three. 139. Toody bought nine donuts and ate all but six. How many were left? 140. You may pick up only one of these six glasses. Tell which, and what is done, so that the six glasses will alternate empty and full. 141. To solve this cross-number puzzle from GAMES, place each of the numbers 1-9 exactly once in the empty spaces to make true equations. As with many of the previous problems, pay attention to your thinking as you go, and describe that thinking. ((= 4( +( +(= 1+ (( (+= 9= 8 = 4= 2  142. Wasons selection task. A M 6 3 Given the cards as shown and the statement, If a card has a vowel on one side, then it has an even number on the other side. Which cards need to be turned over to check on the truth of this statement? 143. Place pennies and dimes on the indicated circles. Moving coins one at a time along the dotted lines only, switch dimes and pennies. No two coins can be on the same circle at one time. The coins can be moved one or two or three spaces during a given move, but along empty spaces only, never over another coin. Try for ten moves or less.  P D P D  144. Divide the square into four identical regions -- same shape and area -- so that the numbers contained therein sum to 45. Note that the numbers 1-9 sum to 45. 145. Four pennies are positioned at the vertices (corners) of a square. Reposition two of the four pennies so that a new square is formed that is half the area of the original. 3 9 5 1 4 3 8 6 2 7 5 8 9 7 1 8 3 1 4 5 3 9 7 6 2 6 8 6 1 2 7 4 5 2 9 4 146. A Mars explorer must hike six days from the Heywood Floyd Observatory to the Hal Crater. He and his astronaut buddies each can only carry food and water for four days. How many buddies will have to start the trip with him, and how far will each go, so that the buddies can return safely to the Observatory and the explorer can get to the Crater? 147. This vertical diamond of nine circles has four smaller vertical diamonds. Switch the smallest number of numbers so that the sum of the four numbers in each of the four smaller diamonds is the same. (From Steve Ryan.)  1 8 6  4 3 2 9 7 5  148. A transport company does not allow packages longer than five feet. Matey Oldbloke has a six-foot didgeridoo. How can Matey ship his didgeridoo? 149. How can we get to the castle across the 12-foot-wide moat if all we have is two sturdy boards of length 11.5 feet but nothing to tie them together?  12 Moat 150. (Meyer, PQ&SF) Put nine pigs in four pens so that there is an uneven number of pigs in each of the four pens.  151. (Meyer, PQ&SF) Start with any circle shown and count 1-2-3, placing a dot in the third circle. Keep repeating this process, starting with any open circle. Try to place a dot in each circles except one. When finished, you will have six circles with dots. 152. (Meyer, PQ&SF) Draw a square. Dissect it into five squares of equal area, the sum of whose areas equals the original square. 153. A sports icon died and left his seventeen cars to his three children. The eldest was to get four-ninths of the cars, the second was to get one-third, and the youngest was to get one-sixth. As the children contemplated where to find an automobile chop-shop, the icon's agent drove up, and solved the problem quickly. What was his solution? (Adapted from antiquity) (Problems 154-165 are adapted from Heafford, The Math Entertainer) 154. Find the length of this vacation: it rained thirteen days, and rain came only in the morning or afternoon, never both. There were eleven dry mornings and twelve dry afternoons. 155. Three paper-bound books, each one inch thick, stand upright and in order from left to right. Leftmost is The Fellowship of the Ring, then The Two Towers in the middle, and rightmost is The Return of the King. A mutated bookworm starts at the front of The Fellowship of the Ring, and eats its way to the end of The Return of the King. How far does it eat? 156. A three-digit number has 9 and 5 for two if its digits. If the digits are reversed and the resulting number subtracted from the original, an answer will be obtained that uses the same three digits in yet another order. What is the missing digit? 157. In a mile race, the fox beats the hare by 20 yards, and the fox beats the mink by 40 yards. By how much will the hare beat the mink? 158. How many guests were present at an Eastern party if every two guests used a dish of rice between them, every three used a bowl of broth, every four had a platter of meat, and there were 65 dishes altogether? 159. A cathedral tower 200 feet high is 250 feet from a church tower 150 feet high. A purple martin flies off of the top of each tower at the same and rate directly to a mosquito on the level straight road joining the towers, the birds meeting the insect at the same time. How far is the mosquito from the foot of the cathedral tower? 160. Use the symbols + , ( , ( , ( , ( , etc., and all of the digits 9, 9, and 9 to make (a) 1 (b) 4 (c) 6 161. How many win lose draw predictions must be made for a set of four football games to ensure that one set of predictions will be correct? 162. Of eight men in a racing crew, three are stroke-side oarsmen only and two are bow-side oarsmen only. The arrangements of front-to-back positions must be considered. In how many ways can the crew be arranged? 163. If five girls pack five boxes of flowers in five minutes, how many girls are required to pack fifty boxes in fifty minutes? 164. A boy has a 48-cm cardboard strip 1 cm wide, marked in 1 cm intervals. He needs to cut at each mark to make 48 square cardboard cm. If he makes one cut every second, how long will this take? 165. Identify X , Y , and Z in this addition problem: X X X X Y Y Y Y Z Z Z Z ------------- X Y Y Y Z (Problems 166-169 are adapted from Berloquin, 100 Perceptual Puzzles) 166. When sawing a cube into 27 identical cubic parts, how many cuts are needed? How can this be justified simply? 167. Ten coins in a row have five heads on the right and five tails on the left. The task is to rearrange the coins so that heads and tails alternate, with as few moves as possible. The only move permitted takes two adjacent coins and places them in a space large enough to accommodate two coins, with no change in the order of the two coins moved. If there are no such gaps, two coins may be moved to an end of the row. 168. Nine coins are in a row, all heads up. By flipping over any six coins each turn, change all coins to tails up, if possible. 169. How many quadrilaterals are in a pentagram? 170. Place a piece of string, yarn, or rope on a table or desk. Grab on end in each hand. Tie a knot in the rope without releasing either end. (Problems 171-179 are adapted from Pentagram, More Puzzlegrams.) 171. Four triangles are shaded in this drawing of six straight lines. Draw six straight lines likewise but forming seven triangles.  ( (172. How many squares can be made ( ( with these evenly-spaced dots as vertices? ( ( ( ( ( ( ( ( ( ( ( ( 173. THE LONG WAY HOME. ( ( Find the longest route from A to B. ( ( No path is to be taken twice. A  B 174. Five containers hold 100 balls each, one container with white balls, one red, one blue, one yellow, and one green. One color of ball is 2.1 ounces per ball while each of the other colors are 2.0 ounces. Using a one-pan balance scale accurate to the nearest tenth of an ounce but with a maximum load of 20 ounces, how can the heavy color be detected with just one weighing? 175. Find five different ways of dividing a 4 ( 4 grid into four equal and congruent pieces. Division lines must be along the grid lines. Two of these ways involve the same shape but different division patterns. 176. Use six segments to intercept (once each) sixteen points placed in a 4 ( 4 grid, without lifting the pencil.  177. These circles have six intersection points. Place the numbers 1-6 on these intersections so that the sum of the numbers on any circle equals the sum on any other.  178. Distribute the numbers 1-12 on the edges of a cube so that the sum of the four numbers around any face equals 26.  179. The Pre-Magic Square Wheel. Distribute the numbers 1-9 so that the sum of the three numbers on any segment through the center is 15. 180. Prepare a pencil and string loop as shown below, with the loop being definitely shorter (10-20% shorter) than the pencil. Then thread the pencil through a button-hole in such a way that the string will be threaded through its own loop as also shown below. Do not break untie, or remove the string from the pencil. jacket lapel (Problems 181-195 are adapted from Gardner, Mathematical Puzzles of Sam Loyd, Volume Two.) 181. Two boats of differing speeds start from opposite sides of a lake simultaneously, each heading for the others point of disembarkation. They meet at a point that is 720 meters from the nearest shore. Arriving at their destinations, each conducts business for an hour and then heads back, meeting the other at a point 400 meters from the nearest shore. How far apart are these destinations? (Try without algebra.) 182. When clocks are advertised, illustrations often show the hands at approximately 8:20 because of symmetry, etc. If each hand is the same distance from high noon, exactly what time is shown in the ads? 183. A 210-lb. man, 90-lb son, 60-lb. daughter, and 30 lb. dog are stuck on a ski lift. Rescuers on the ground below have tied two barrels to ends of a rope through a pulley hooked to the cable. For safety, neither barrel should hold 30 pounds more than the other in transit. Each barrel is big enough to hold all, but passage can be done most quickly by using only those stranded (no other weights such as snow). Neither dog nor daughter can climb in or out of the barrels without assistance, and the rescuers have left to help others stranded. What is the most efficient rescue sequence? (Per Gardner, this is derived from Carroll, The Lewis Carroll Picture Book.) 184. Barrels of either oil or vinegar are marked with these numbers of gallons: 8, 13, 15, 17, 19, and 31. The oil sells for twice the price of vinegar. A buyer buys $150 of each commodity. Which barrel remains? 185. A game begins with 13 bottle caps. Two players take turns taking either one or two (adjacent) caps. (a) The last player to take loses. Can the first or second player always win, and if so, how? (b) Does this differ if the last player to take is the winner? 186. Less than 36 sheep are quartered in a square pen with one fence post (regularly spaced) per sheep. An oblong pen with the same area has two more posts. How many sheep were quartered therein? A 187. Five guards are represented in the checkerboard by the letters A, B, C, D, E. At sunset, guards A, B, C, and D march through the doors indicated and exit by their correspondingly marked exits (e.g., A goes through exit A, etc.). Guard E moves to cell F. How can these guards march so that no one crosses the path of another? C  D F     C  B  E  A  D B    188. A cyclist rides a mile in three minutes with the wind and in four minutes against it. How fast can she ride a mile with no wind? (Try without algebra. Algebraists: try to connect result.)  189. D  C B    A  The train engine on the left has lost most of its stack and cant operate. The train on the right has to get past it. Track sections A, B, C, and D will each accommodate at most one train car or engine at a time. The broken engine must be pulled or pushed as a car. The good engine can run both forward and backward, and can either push or pull any thing in any combination from either its front or rear end. When finished in the minimum number of moves, the trains must be headed in the same directions and be assembled in the same order as before. 190. An English tourist in the days of the Wild West was told at the hotel that he had four choices for traveling to Dodge. (A) He could ride the stage all the way; this included a half-hour stopover at the Wayhouse, somewhere between the hotel and Dodge. (B) He could walk all the way. The stage would beat him by a mile to Dodge if they left the hotel simultaneously. (C) He could walk to the Wayhouse and then ride the stage. If he and the stage left the hotel simultaneously, the coach would arrive at the Way house when he had walked four miles. He would arrive at the Wayhouse when the stage was done with the half-hour stopover. (D) He could ride the stage to the Wayhouse, then walk. This would get him to Dodge fifteen minutes ahead of the stage.  What is the distance from the hotel to Dodge?  191. Place the maximum number of Xs in the grid so that no more than two are in any row or column or diagonal, including the short ones. Two Xs are already placed.  192. Three Graces each with roses of four different colors -- yellow, red, white, and blue -- met nine Muses with golden apples. Each Grace gave roses to each Muse; each Muse gave apples to each Grace. After, each woman had the same number of apples, the same number of red roses, the same number of white roses, the same number of yellow roses, and the same number of blue roses. The total number of roses that each had equaled the number of apples that each had. What are the smallest numbers of each of these quantities that will satisfy these conditions? 193. The jewelry shown has 25 diamonds. The owner counted down from the top to the center and then either from the center to the left, or right, or bottom, and if thirteen jewels were counted, the jewelry was thought to be complete. The owner gave the jewelry to a dishonest jeweler for repair, sharing the counting method. When the pin was returned, the jeweler counted the jewels, and the owner was happy. But the jeweler had stolen two of the jewels. How?   194. Dr. Hendrix sold two guitars for $2100. On one he made a ten per cent profit and on the other he lost ten per cent. On the whole deal he made 5%. How much did each guitar cost him originally? 195. Eight coins in a row alternate heads and tails. The task is to rearrange the coins so that heads and tails are sorted and close together, with only four moves. The only move permitted takes two adjacent coins and places them in a space large enough to accommodate two coins, with no change in the order of the two coins moved. If there are no such gaps, two coins may be moved to an end of the row. 196. A very old nursery rhyme mentions small hot-cross buns that sell for three for a penny, medium buns that sell for two for a penny, and large buns that sell for one for a penny. The man in the rhyme has as many daughters as sons, and they each get the same number of the same size of buns. The man spends seven cents for all buns together. How many buns of which kinds did each get? From Mathematical Puzzles of Sam Loyd, Volume II by Gardner  197. By cutting only along the lines, divide this polygon into two pieces that can be fitted together to make an 8(8 square. 198. Refer to the initial shape from the previous problem. Cut the shape into two congruent pieces. Transformation is allowed. 199. The outer wheels of a cart are turning twice as fast as the inner wheels as the cart makes a very small circle. If the distance between inner and outer wheels (along the axel) is two meters, what is the circumference of the outer circle? 200. A chessboard of 64 squares is made up of the largest number of different pieces that themselves are made up of the same squares (no fractions of squares allowed). What is the largest number of different pieces that can make such a chessboard? (All pieces made of two squares are alike, so no more than one of those can be used. A black one-square piece differs from a white one-square piece. Strips of three can have a white middle, which differs from one with a black middle.) 201. The sides of a 4 ( 4 square fell apart at the vertices and got mixed with the similarly discombobulated sides of an 8 ( 8 square, and the result, in a plane, is three congruent squares. How? 202. This 5 ( 5 mosaic can be cut into a minimum number of pieces that can be reassembled into two perfect squares. Cutting is to be along the given lines (no diagonals, etc.) No heads will be cut or even turned. 203. A fishing pole was dropped into a pond and momentarily stood perfectly upright, its heavy end on the bottom and   :::  ....  ==the tip extended ten inches above the surface of the pond. Then the pole fell over slowly, until its tip was at the surface of the water, 21 inches away from the spot on the surface where it once protruded vertically. How deep is the pond? The following are from Mathematical Nuts by Samuel I. Jones. 204. I entered a fruit stand with a friend and bought fruit amounting to exactly 34 cents. When I went to pay, I found that I did not have the change. I only had a dollar, a 3-cent piece, and a 2-cent piece. The merchant could not make the change. He only had a 50-cent piece, and a 25 cent-piece. My friend wishing to assist us offered to lend us all he had. He had 2 dimes, 1 nickel, a 2-cent piece, and a 1- cent piece. I was thus enabled to pay for the fruit and in addition each one received what was due him in full. Show how the transaction was made. 205. Four boys are given three equally-thick round pies of different radii a, b, and c. They wish to divide them equally among them by making as few pieces as possible. Make the division, given that a2 = b2 + c2. 206. In going from his house to his barn, Mr. Jones carried two buckets. He went to the brook and filled one bucket; proceeded to the river and filled the second; and then proceeded for the barn. How far did you go? Jones was ask. He replied, I do not know, but remember that the river and brook were parallel and 20 rods apart. Also in leaving the brook I observed that the line in which I was traveling made an angle with it whose sine was 4/5. How far did Jones go, provided he took the shortest route? River  River  Barn  12 rods   4 rods Brook  Brook 207. Two trains start at the same time, one from Dallas to Houston, the other from Houston to Dallas. If they arrive at their destinations one hour and four hours (respectively) after passing one another, how much faster is one train running than the other? 208. Divide a circular piece of land into four congruent tracts, each tract to be bounded by arcs. 209. A father wills a circular tract of land of 1000 acres to his four sons. On this tract are located two fine artesian wells; one on the extreme eastern point of the boundary line and the other on the extreme western point. The father requests that each son must have the same amount of land and also that each must have access to each well. In making the division it was necessary to call in a mathematician. Can you make the division? 210. Two baseball teams, presumably of equal merit, are playing a series of games with the understanding that the first team winning four games wins the series. They have played two games, both won by A. What are the odds in favor of As winning the series? 211. A man has nine pieces of chain. Three have three links each (as shown in the illustration), three more pieces have four links each, and three more have five links each. He wishes to unite them into a straight chain or endless chain, depending upon the cost. What will be the cost in each case, provided he pays 2 cents for each cut and 2 cents for each weld? B (  River Dance A(  EMBED MSPhotoEd.3  EMBED MSPhotoEd.3  EMBED MSPhotoEd.3  River 212. A and B live between two rivers which Kleenix meet. A wishes to visit B and desires to take the shortest possible path so as to carry B a bucket of water from each river. Mark As path. 213. Can you place 4 marbles equidistant apart? 214. How many equilateral triangles can be formed form nine matches, the side of each triangle being the length of a match? 215. Two monkeys are balanced on a rope, which goes over a pulley. One remains stationary while the other climbs the rope. What happens? 216. Johnsons Cat Johnsons cat went up a tree, Which was sixty feet and three; Every day she climbed eleven, Every night she came down seven. Tell me, if she did not drop, When her paws would touch the top. 217. A hunter walked around a tree to kill a squirrel; the squirrel kept behind the tree from the hunter. Did he go around the squirrel? 218. A camper pitched a square tent between four trees A, B, C, and D, forming a square. After his departure another camper came along and also pitched a square tent with twice the floor space between the same trees? How was it done? 219. A man has a square plot of ground with 12 posts equally spaced on each side. What is the total number of posts? 220. Some horses and chickens are in a barn; the total number of heads and wings equals the number of feet. What is the ratio of horses to chickens? 221. Two boys sit down to eat, one with 5 cakes and the other with 3, all the cakes having the same value. A third boy comes along and eats with them, paying 8 cents for his part of the meal. If they eat equally and consume all the cakes, how should the 8 cents be divided? 222. A man is twice as old as his wife was when he was an old as she is now. When she is as old as he is now, the sum of their ages will be 100 years. Find their ages now. 223. A number should have been multiplied by 6. Instead, it was divided by 6. The result was 15. What was the correct answer? 224. A melon placed in one of the scales of a false balance was found to weigh 16 pounds. When placed in the opposite scale, it weighed only 9 pounds. What was the correct weight of the melon? 225. Two autos A and B start from the points C and D opposite each other across a lake. They start towards each other and maintain uniform speeds. They meet 421 feet from D, but continue their speed and meet again 221 ft. from C. What is the diameter of the lake? 226. Find the smallest number, which being divided by 2,3,4,5,6,7,8,9, will respectively leave remainders of 1,2,3,4,5,6,7,8. 227. A man who feels his death approach bequeaths to his young wife one third of his fortune, and the remaining two thirds to his son, if such should be born; but one half of it to the widow and the other half to his daughter, if such should be born. After his death twins are born, a son and a daughter. How should the fortune be divided amongst the three? 228. A cow is tethered to the corner of a barn 25 feet square, by a rope 100 feet long. How many square feet can she graze? 229. On a hillside, which slopes 11 feet in 61 feet of its length stands an upright pole. If this pole should break at a certain point, and fall up hill, the top would strike the ground 61 feet from the base of the pole; but if it should fall down hill, its top would strike the ground  EMBED Equation.3  feet from the base of the pole. Find the length of the pole. 230. Two men were walking along a railway track, each at the rate of 3 miles per hour, and in opposite directions. A passing train ran completely by one a 5 seconds and by the other in 6 seconds. How many feet long was the train? 231. Divide a circle into a) two equal parts b) three equivalent parts c) four equivalent parts Each division must be made using semicircles only -- all boundaries must be semicircles. 232. Twelve oxen are turned into a pasture of 3 acres and eat all the grass in four weeks so that the pasture is bare. Twenty-one oxen are turned into a pasture of ten acres and eat all the grass in nine weeks. How many oxen will eat all the grass of 24 acres in just exactly 18 weeks, it being assumed that the grass in all the pastures is at the same height when the oxen are turned in, and that the grass grows at a uniform rate? 233. Two equal circles, largest possible, are inscribed in a circle whose circumference is 640 feet; then two other circles, largest possible, in the two remaining spaces. Find circumference of a small circle and the area not included in the four inscribed circles. Problems 234-253 are based on The Worlds Most Incredible Puzzles and The Worlds Most Baffling Puzzles by Charles Barry Townsend. 234. Arrange eight 8s so that when they are added up they will total 1,000. 235. After dinner, three weary travelers ordered a plate of chocolates to be shared equally. Before the candy arrived, all fell asleep. The first woke, ate an equal share, and fell back to sleep. The second then awoke and ate what appeared to be an equal share and promptly went back to sleep. Finally, the third woke and ate what appeared to be an equal share, and then fell asleep again also. While they slumbered, the waiter removed the dish, which had eight pieces left. How many pieces were originally brought to the table? 236. Four black and four white counters are placed on a puzzle board as shown. The task is to make these eight pieces change place in exactly ten moves. The rules? Black moves down the board and white moves up. All pieces must either move forward to an empty square or jump over one or two counters to get to an empty square. 237. In the Clifford family, each daughter has the same number of brothers as she has sisters. Also, each of the boys has twice as many sisters as he has brothers. Using this information, figure out how many children there are.     238. Farmer Roche had a 16 km2 plot of land as shown. He had it fenced in with sixteen 1 km sections of fence. He proposed to divide this plot into four smaller plots. Each plot was to contain four square- shaped km2 of farmland. He did this by adding an odd number of fence sections within the existing fencing. Can you determine where he placed them? 239. Move two of the segments to new positions so that there are four equilateral triangles instead of three. 240. Arrange 13 threes to equal 100. 241. Stack five regular house-builders bricks (or same-sized pieces of wood) so that the entire stack can be picked up with one hand only. 242. What number replaces the question mark? 243. Change the H of coins into the O of coins in just five moves. A move consists of sliding one coin at a time to a new position without disturbing any of the other coins. When the coin reaches its new position, it must be touching two other coins.  244. A builder divided up a 32-acre plot of land into eight building lots and put up a house on each one. Every lot in his development was exactly the same size and shape. The problem is that someone stole all the boundary markers from the lots and the estate plans are missing. Can you help determine where the original boundaries of each lot were? (The Xs indicate where each house was built.) XXXXXXXX 245. Move two matchsticks so that there are three congruent squares. 246. Cut a 13 ( 13 grid into eleven squares of differing sizes, though some will be congruent to some of the others.  247. Change the arrangement as shown in only four moves, each of which consists of moving two adjacent coins to any two empty squares. 248. Rearrange these numbers in the circles so that no two consecutive numbers will be joined by any one of the lines.  1  2  3  4 5  6  7 8 249. How many triangles?  250. Arrange 16 coins in 15 rows with four coins in each row. 251. Insert three + signs and one ( sign into 9 8 7 6 5 4 3 2 1 so that the result is 100. 252. In terms of Roman numerals, the equation shown is wrong. Shift one segment so that a true arithmetic fact appears. 253. On a playing board (as shown), place ten coins on the indicated squares. Remove nine coins by jumping one over another as in checkers, but jumping only horizontally or vertically. To begin, slide one coin to any empty square. From there, use only jumping moves. 1  2  EMBED Word.Picture.8  3   4  5   6 78  9   10 11 12  13   14  15 16 Shaded Regions Perimeters and Areas Two pages of Shaded Areas problems follow. All were constructed using only compass-and-straight-edge construction. Students should also try to find the perimeters. Each square has edge 2 units. Not all of these have been solved; all that have been attempted have been solved. Many are presented as solvable based only on this writers sons hypothesis: Dad, if you can draw it, you can find the area. The Lunes of Hippocrates and the Sickle of Archimedes are two theorems from geometry that can be made into problems of verification. Shaded regions are the heart of these theorems, indicating that while the problems that follow on the next two pages can be very sophisticated, there are related principles that also have historical attached. Constructing the Lunes of Hippocrates 1. Draw a 2/3 or 3/4 circle; label center O. 2. Draw diameter  EMBED Equation.DSMT4 through O. 3. Mark point P on semicircle; draw  EMBED Equation.DSMT4  and  EMBED Equation.DSMT4 . 4. Bisect  EMBED Equation.DSMT4  and  EMBED Equation.DSMT4 ; call midpoints X and Y. 5. Draw semicircular arcs  EMBED Equation.DSMT4 and  EMBED Equation.DSMT4 using X and Y as centers. The sum of the areas of the moons or lunes thus constructed equals the area of APB This may be one of the least intuitive theorems in all of mathematics. Students can discover or demonstrate this theorem. Prerequisites include circle area formula and the Pythagorean Theorem. Constructing the Sickle of Archimedes 1. Choose a point O for the center of a semicircle, and draw semicircle. 2. Draw the diameter  EMBED Equation.3 . Radius of O is c . 3. Pick any point on the diameter, and mark it and call it P. (Close to, but not on, the center O will give you more room to think and see.) 4. Bisect  EMBED Equation.3  and  EMBED Equation.3  Call the bisection points M and N respectively. 5. Draw semicircles with centers M and N and radii a = AM and b = BN. 6. Shade portion of original semicircle outside of two new semicircles. The shaded portion is called the Sickle of Archimedes. Show that its area is  EMBED Equation.3 = area of circle with diameter d, where d is length of the perpendicular to  EMBED Equation.3  at P from the original semicircle.   Hints, Solutions, Encouragement 3. See pp. 156-58 4. Work backwards, using ending scenarios. 5. First 19 Pool Hall Numbers are 3 15 120 528 4095 17955 139128 609960 4726275 20720703 160554240 703893960 54541179903 23911673955 185279454480 812293020528 6294047334435 27594051024015 213812329916328 6. See pp 156-58 for Old Timer version of this problem. 7. Coin at 11:00 moves to 3:00. Center coin moves to 11:00. 8. Two disks takes 3 steps. Three disks: 7 steps; 4 disks: 15 steps. 9. See authors doodles elsewhere on his website. 10. Elementary students should use guess and test. Ideal cases (48 regular pickups or 48 dualies) will allow for a fast correction. Algebra students may use a linear equation or a system of two equations in two unknowns. 11. Dont fear doing work that seems counterproductive at the time. 12. As a friend said, the answer cant just be five, otherwise, the question wouldnt be worth asking. What happens after the five cigarettes are made? 13. Look for a pattern. Domain knowledge: fluency with arithmetic facts, yet another point against a calculator-dominated grade-school experience. 14. Use a chart. 15. Start without the six (easier, related problem). 16. Use a formula, ideal case, or easier case (put P at corner or middle). 17. Use 3 ft. = 1 yard. (For many, this is unseen data.) 18. Use chart or system of equations. 19. Use formula: C = (d. Can height = 3d < (d. 20. Use data somehow. Area of each face = 150 ( 6 = ... 21. Word backwards by thirds. 22. Impossible. See p. 135. 23. Draw both diagonals and look. Both diagonals are the same length. 24. Average speed = harmonic mean =  EMBED Equation.2  ? Arithmetic mean (average) of 60 and 40 is incorrect as more time is spent at the slower speed. 25. All or 100%. Reasoning at the elementary level will produce this answer. For secondary students, the sum to infinity of a geometric series will do it. 26. This is an unsolved but very practical question that has attracted the attention of builders since the author first proposed the problem in 1993. 27. Cut out the pieces and try. Then look for a hidden assumption. 28. Becky. 29. See pp. 136-138. A fabulous problem. Peek in stages as indicated. 30. Consider the problem from the point where the train enters the tunnel. 31. The man assumes he has no mark, and finds a contradiction based on the fact that neither of the other men can resolve the issue. 32. Ten See MATHCOUNTS Outline (p. 31, end) for Newtons process. 33. See p. 156. 34. See notes on the Hidden Assumption strategy page, p. 47. 35. See p. 155. 36. 37. He cheats himself. 38. Same. 39. 2( 40. Hint: use three dimensions. 41. The original think outside the box problem, and that should be a sufficient hint. 42. If I had asked you yesterday about this question, what would you have said? will get a guaranteed truthful answer. If I asked someone who is not of your tribe about this question, what would they have said? will get a guaranteed false answer. 43. A cuts off a third. B chooses between As piece and dividing the remainder with C. If B chooses As piece, either A or C cuts the remainder and the other chooses. If B declines As third, C gets the same choice. If neither wants As piece, then either B or C cuts the remainder and the other chooses. 44. See discussion, p. 153. 45. First man: 3 full pints, 2 full quarts, 1 empty pint, 2 empty quarts. Second person: 3 full pints, 2 full quarts, 1 empty pint, 2 empty quarts. Third person: 1 full pint, 3 full quarts, 3 empty pint, 1 empty quart. 46. Loses  EMBED Equation.2  per double throw. 47. 1 to 3. 48. 50. 49. Persist! Just keep trying. 50. Use transformations. Solution is 100 EMBED Equation.2  51. Hints: get a shoe box, pretend it is a room, write in the dimensions, and then imagine how pieces could be hinged. For example, hinging the north and east walls will give one answer. Hinging the north wall and floor will give another. Answers: (a) 10 (b)  EMBED Equation.DSMT4  52. Make a huge chart, of course. When completed, be certain that youve looked at all of the questions, as some ideas are supplied there that are not in the problem. You will still be stuck. So make an assumption. If its wrong, it will lead to a contradiction, and that contradiction will point the way. A great, great problem, and not to be spoiled by the solution being given here. 53. P 54. See chart. P N N P 55. Fourteen. P N N 56. Start with 2, then 2 and 3., then 2, 3, 4. It should be apparent that the needed number is LCM ( 1. Answer to the problem is of the form n ( LCM (6, 5, 4) ( 1. In other words, LCM (6, 5, 4) ( 1 = 59. But 7 does not divide 59. So try 59 + 60, then 59 + 120, then 59 + 180, etc. 57. The feathers are heavier. Check the dictionary under measure for the distinction between Troy (jewelry* and Avoirdupois (standard) weight. 58. See Differences Strategy page, p. 142. 59. See Differences Strategy page, p. 142. 60. See #10. 61. Use a chart. a = 2 b = 1 c = 9 d = 7 e = 8 62. This writer is still trying for 10 moves. 63. See #61. A great genre. 64. See p. 147-51. 65. 3 ( 4 is the minimum. 4 ( 4 is impossible. All 5 ( 5, 6 ( 6, etc., are possible. Chess problems are time-honored, and learning chess is recommended for all, especially for the problem-solver. 66. Just keep trying. 67. Make two charts. 68. Not 20 cents. Guess and test or use algebra. 69. Use a common multiple for each bottles total units (4 and 3) like 12, and give each bottle 12 units. 70. The lowest common multiple of three, four, and five is 60. The numbers of corresponding dishes for 60 is 20, 15, and 12. The sum of these numbers of dishes is 47. Three times 47 is 141. Three times 60 is the needed result. 71. 1 1 1  1 1 2 2 3 3 4 1 2 4 7 11 is the answer. Below and to the right of each intersection is the number of ways of arriving at that intersection. The 4 at the extreme right is the sum of the 1 above and the 3 to the left. Each number after the initial sum is likewise the result of such summing of the number immediately above and immediately to the left. This strategy is a great shortcut that always works regardless of the configuration. 72. See chart, pp. 143-5, and follow steps. 73. Start with  EMBED Equation.2 , look for a pattern, and remember what the problem asks for. 74. Start with  EMBED Equation.2 , look for a pattern, and remember what the problem asks for. 75. Fourteen is a good start. Twice the square of three is close. Five times the square of 2 is the solution. Only encourage students to keep trying. 76. Elimination is eased by this table. Bolded scores can be obtained by hitting only fours or only nines. The other sums can be obtained with combinations of those.481216202428913172125293337182226303438424627313539434751553640444852566064 To solve the problem, students should write all of the numbers through 40 or 50 or so, and eliminate the attainable scores using this table. The largest survivor is the solution. NOW: Students should try for a formula any m and n, where m and n are relatively prime, that is, m and n have no common divisions except 1. When done with that, students should try the same problem with three relatively prime numbers such as 4, 5, and 7. 77. Just count from the pattern. 78. Six have only one side painted (the one in the center of each face). Twelve have two sides painted (the center of each edge). Eight have three sides painted, and one (the center of the cube) has no sides painted. 79. Useful concept, for practical use and for modeling direct and inverse variation: CONSTANT is  EMBED Equation.2  and x = . 80. 54 + 16 + 4 = 74 . 81. 82. One of Eight of Four of Four of Two of 83. Just play. Start with a few squares and look for a pattern, as with the Old Timer.  x y 84. 85. 86. where x = 2y   87. Start with three on each side.   If they balance, weigh two If one side is lighter, weigh  of the final unweighed three. two of those final three.  If one side is lighter, there it is. If both sides balance, the unweighed of the final three is the lighter. 88. 89. a b c d e f g  d e f g a b c  g a b c d e f  c d e f g a b f g a b c d e b c d e f g a e f g a b c d 90. Starting from any corner of the cardboard square, move one diagonal length away from the center of the cardboard, over one uncovered number, to the next uncovered number. That second uncovered number on the diagonal must be subtracted from 100, and that result is the needed sum.  92. Just keep working. 93.  94. If top is 5, then 7 and 3 are next on each side. Below the 7 is 6, then 2 in the corner. Below the 3 is 4 and then 8 in the corner. The 9 and 1 complete the bottom row between the corners of 8 and 2. 95. Slide the T from the left end of the middle row. Move it to the other end of the second row, and shove it and the other three over until the desired alignment has been achieved.  96. Cut on the solid lines; fold on the dotted line.  97. Four intervals between five rings over 25 seconds means nine intervals between 10 rings for X seconds. So  EMBED Equation.2 . Solve for X. 98. Draw one ball from the crate that should be mixed (crate C). The color of that ball tells what crate it really is. Deduction solves the rest. 99. Assume an ideal case. Radius of the rug = 0. Radius of the lighthouse is 7. Then -- ? 100. Assume an ideal case. Radius of the hole is zero. Radius of the sphere is 5. Then -- ? 101.    102. Use constraints to restrict choices. All four operations imply constraints given the digits to work with. 103. Remove the four at the center. 104.  105. The store has lost $14 -- the book cost $6 and $8 change was given to the customer.  106. 107. The sum of the numbers is 78, so the inner sum must be 26 and the outer must be 52. The inner numbers are 5, 6, 7, and 8.  108. Hint: Run one of the lines through one of the houses. 109. Hint: Each pair for a given circle should be across the center from each other. 110. Hint: Let the two columns cross each other, as to make an X. Second hint: Let the digit 1 be the center of the X, thus belonging to both columns. 111. With the pieces lettered as shown, 1. E jumps F, C, A, and G 2. B jumps D 3. I jumps H 4. B jumps I 5. E jumps B A four-move solution exists in Dudeney, Amusements in Mathematics, problem 229.   ABC DEF GHI  112. Sixteen even rows:    113. StepsFive-quart pail resultFour-quart pail result1. Fill five-quart pail from milk can 1.502. Fill four-quart pail from five quart. 143. Empty four-quart pail into can 1104. Empty five-quart into four-quart015. Fill five-quart from milk can 1516. Fill four-quart pail from five-quart pail247. Empty four-quart pail into can 1, which is now two quarts short of full. 208. Fill four-quart pail from milk can 2249. Pour from four-quart into can 1 until full.22 114. Twenty cents. Take one piece and open all five links, and use these to bind the remaining five pieces. 115. Hint: the boy with the 9 on his shirt must stand on his head (first, removing his cap, which is now undeserved). 116. Twenty. 117. Hints: be systematic. Remember inverted triangles. Total is 75. 1 biggest triangle, 4 that are six smallest edges per side. 3 that are five sm. edges, 6 that are 4 sm. edges, 11 (one inverted) that are 3 sm edges, 21 (six inverted) that are 2 sm edges per side, + 36 smallest. 118. Five 119. Small = EMBED Equation.2 quarts. Medium =  EMBED Equation.2 quarts. Large =  EMBED Equation.2  120. Just keep trying. Seventeen moves are needed.  121.122. 123. Six. 4 ( 17 + 2 ( 16.  124. See detailed solution. 125. 126. Suggested strategy: copy the page onto an overhead projector transparency, and cut each problem apart from the others. Move the transparency for each problem over the original until a solution appears. With some success, others become easier. Not all of these examples can be solved this way. 127. See detailed solution. 128. See detailed solution. 129. See detailed solution. 130. Draw a line through X parallel to the given parallel lines. (Other auxiliary lines will also lead to the solution of 114.) 131. Keep trying. Look for constraints. 132. See Cantor strategy discussion. 133. Proceed sequentially. 134. Keep trying. 135. Bahman is not married. Nothing can be deduced about Perviz. 136. Area of the two semicircles is based on a radius of 5. Solution is 100 - 25( . 137. Draw a 6 ( 6 grid for a sample space for two dice, one for Joe and one for Moe. Mark where Joes is higher. Count the number of marks and write this over 36 for the needed probability. 138. 200 + 3 = 203 139. Six. 140. Lift the second glass, empty it into the fifth, and replace. 141. Use constraints. 142. The A card, of course, and also the 3. If there is a vowel on the other side, the rule has been violated. This an exercise in the principle of the contrapositive in logic. 143. Eight moves will do. Use two top circles initially.  144. With a bit of effort, a strip of six attached to a strip of three clearly wont work. So start with corners, and grow your patterns from there. Each shape needs as middle number. Answer piece: 145. The top two pennies will be the diagonal of the new square. Move the two bottom pennies so that they will be on the perpendicular bisector of that diagonal and form the square. 146. Three assistants, one of whom goes back each day. 147. Exchange the 3 and 9. 148. Make a rectangular package five feet by 3.5 feet. The instrument will fit on the diagonal.  149. Note the position of the first board in the drawing.  150. Some pens are inside other pens. P PP P PPPP  Another solution: P PP PP PP   151. Each time after the first, start with 152. the circle that is two circles away from the last starting circle.  153. The agent donates his car temporarily, making 18 cars. The fractions are computed, and the three children take their 17 cars. The agent drives away in his own car. 154. 18 days. 155. One inch. Draw the books as specified, and recall where the indicated front and back of the books are. 156. 4 157.  EMBED Equation.2  158. 60 159. 90 160. (a)  EMBED Equation.2  (b)  EMBED Equation.2  (c)  EMBED Equation.2  161. 81 162. 1728 163. 5 164. 47 165. x = 1, y = 9, z = 8 166. Six cuts. Justification: The center cube will need a cut for each of its faces. 167. Five moves: T T T T T H H H H H T T T H H H H H T T T H H T T H H H T T T H H H H T H H T T T H H T H T H T H T H T H T H T H T H T 168. Impossible 169. Five convex kites, five concave. There are five more if edges are allowed to cross, which violates the concept of the simple closed curve.  170. Crossing ones arms before picking 171. up the ends of the rope will solve this.  172. 21. With horizontal distance between two top points equal to one, there are nine 1 ( 1 squares. Four squares have edges  EMBED Equation.2  . Four squares have edges  EMBED Equation.2  . Two squares have edges  EMBED Equation.2 . Two have  EMBED Equation.2 . Pentagrams key is missing a segment. 173.       174. Choose one ball of (for example) white. two of yellow, three of red, etc. The amount of error in the weight tells which color is too heavy. 175.           176. 177.         178. 179.      180. The flexible lapel must be folded along the line of the closed button hole, and pulled through the loop to compensate for the needed length. 181. 1760 meters 182. 8:18 EMBED Equation.2  or 8:18:27 EMBED Equation.2  183. Lower the dog, then the daughter is lowered while the dog is raised. The son is lowered while the daughter is raised. The dog is lowered again. The daughter is lowered again while the dog is raised again. The dog is lowered again, and all but the man and down. The man is lowered while all others are raised. The process continues in like fashion. Note the connection to the Tower of Hanoi. 184. The 19-gallon barrel is not purchased. 185. (a) The second player can always win by taking one when the first player takes two, and vice versa. (b) The first player takes one. When the second player takes two, the first takes one, and vice versa. (c) Students should now try this. The 13 are in a circle, and only two can be taken when next to each other. If the game is take the last, the second players first move is to make two segments of five each. Then the second player imitates the first players moves until the game ends. 186. Eight. 187. Just keep trying. Each failure will yield further constraints on the search for a solution. 188. Three and three-sevenths minutes. 189. Label the cars and engines A, B, C, D, U, W, G, H, and I from left to right. U is the unworkable engine and W is the working engine. W pulls U to section D. W goes through switch and pulls D to section D, pushing U to the right. This pattern continues until A has been pulled to section D and B is pushed to the right. W goes through the switch and moves to the right, pushing and hooking A, B, C, D, U, and G together. W pulls this collection to the left, then pushes G to section A. W pulls ABCDU to the left, then to the right. W then moves to the left, then back to G, hooks it, pulls to the left, and ten back to the right against A. Hooking ALL cars, W moves everything to the left, and then backs H and I to sections A and B of the switch.  W pulls GABCDU to the left, then pushes them to the right. W pulls G to the left, backs up into H and I, and continues on its way. All solution constraints have been satisfied.  190. Nine miles 191.   192. The muses each have 48 apples and the Graces each have 144 flowers, three per color. 193. Steal a stone from each of the left and right ends, and move the bottom diamond to the top. 194. $1500 and $500. 195. Letter the coins A, B, C, D, E, F, G, and H from left to right. Move B and C to the right end. Replace them with E and F. Replace these with H and B. Replace these with A and E. 196. Three boys and three girls each got one of the two-per-penny buns and two of the three-per-penny buns. 197. 198. Gardners best solution:     To assemble, spin second piece 90( clockwise and slide left.  199. 20( 200.  201.    202.    203. 17.05 inches. 204. The friend got the quarter and the three-cent pieces. I got the fifty-cent piece, two dimes, and one penny. The merchant got the dollar and the five-cent and two-cent pieces. 205. With b > c, and (a2 = (b2 + (c2 , two boys split the left side of the equation, getting  EMBED Equation.2  each. The other two split the right side of the equation. This can be accomplished by splitting each of the smaller pies in half, each getting half of each. Jones solution may be simpler given his interpretation of the directions, but it is certainly more trouble. He suggested that the smaller pie with radius c be placed concentrically on top of the larger pie with radius b, that the difference (annulus) be cut from the larger of these two pies, and that the annulus be divided in half and shared, as the two small pies are also shared between the two.. 206. 40 rods. This problem is most easily solved by transformation. Draw the eight-rod segment from the barn to the river, and then reflect just that eight-rod segment across the river. Call the northmost end P. Likewise reflect the four-rod segment to the brook across the brook. Call the southmost end Q. The length PQ is the length of the shortest path. 207. One is twice as fast as the other. Let d be the total distance between Dallas and Houston and other representations as shown below. ratetime to first meetingdistance to first meetingfast trainRftRf (tslow trainRstRs(t ratetime for remaining tripdistance for remaining tripfast trainRf1Rf slow trainRs44Rs First distance for fast train = second distance for slow train: Rf (t = 4Rs and First distance for slow train = second distance for first train: Rs (t = Rf .  Dividing these equations produces  EMBED Equation.2   EMBED Equation.2   EMBED Equation.2   EMBED Equation.2   EMBED Equation.2  208. 209.    210. 13:3 211. Six cuts/welds for a straight chain = 24 cents. Seven cuts/welds for an endless chain = 28 cents. 212. Draw  EMBED Equation.2  perpendicular to River Dance and reflect it for  EMBED Equation.2 . Draw  EMBED Equation.2  perpendicular to River Kleenix and reflect it for  EMBED Equation.2 . Draw  EMBED Equation.2  and its intersection with River Dance at D and River Kleenix at K. The shortest path is from A to D to K to B. 213. Think of a regular tetrahedron 214. Think of two regular tetrahedrons with a common base. 215. If the weight of the rope is disregarded, along with inertia, jerks, and elasticity, both rise together. If the weight of the rope is considered, the climbing monkey sinks.  216. Fourteen days. 217. No. 218. 219. Forty-four 220. There are three chickens for every horse. 221. Seven cents to the boy with five and one cent to the boy with three. 222.  EMBED Equation.2  223. 540 224. Five hundred forty. 225. Six hundred sixty-three feet. 226. LCM (2,3,4,,9) ( 1 = 2,519. 227. Son gets , widow gets , daughter gets . 228. 30,290 ft2 . 229. One hundred one feet. 230. Two hundred sixty-four. 231. The solutions to #208 and #209 above should provide sufficient inspiration. 232. Thirty-six. 233. 9054.13 234. 8 + 8 + 8 + 88 + 888 = 1000 235. Twenty-seven 236. Letter the five left column squares from top to bottom with A through E. A jumps to C; D jumps to A. B jumps to D. E jumps to B. C jumps to F. The right column mirrors these jumps. 237. There are four daughters and three sons.  238. 239.   240. Two solutions different from Townsends: 33 ( 3 +  EMBED Equation.2  33 ( 3 +  EMBED Equation.2  Others of this format are likely.  241. Bottom brick: Bottom with next two on top:    All five:  242. Eighteen. Each bottom number is the square of the top number with the digits reversed. 243. 4 Move #4 to above #1. Move #5 above #2.  Move #2 to below #1. Move #1 below #5. 1 2 3 Last, move #3 below #1.  5 244.    Not a solution: not IDENTICAL Correct solution  245. 246.      247. Move from 2-3 to 9-10. Move from 5-6 to 2-3. Move from 8-9 to 5-6. Move 1-2 to 8-9.  248. 249. Small: 7 Medium: 3 Large: 3  Biggest: 1  Total: 14   250.      251. 98 ( 76 + 54 + 3 + 21 = 100 252. 1 ( 1 = 1 253. Hint: First move the coin in the second row, last column, to the space in the third row, second column. 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